£¨08Ä꺣ÄÏ¾í£©(11·Ö)ÈçºÎ·ÀÖ¹ÌúµÄÐâÊ´Êǹ¤ÒµÉÏÑо¿µÄÖصãÄÚÈÝ¡£ÎªÑо¿ÌúÐâÊ´µÄÓ°ÏìÒòËØ£¬Ä³Í¬Ñ§×öÁËÈçÏÂ̽¾¿ÊµÑ飺

 

ÐòºÅ

ÄÚÈÝ

ʵÑéÏÖÏó

1

³£ÎÂϽ«ÌúË¿·ÅÔÚ¸ÉÔï¿ÕÆøÖÐÒ»¸öÔÂ

¸ÉÔïµÄÌúË¿±íÃæÒÀÈ»¹âÁÁ

2

³£ÎÂϽ«ÌúË¿·ÅÔÚ³±Êª¿ÕÆøÖÐһСʱ 

ÌúË¿±íÃæÒÀÈ»¹âÁÁ 

3

³£ÎÂϽ«ÌúË¿·ÅÔÚ³±ÊªµÄ¿ÕÆøÖÐÒ»¸öÔÂ

ÌúË¿±íÃæÒѱäµÃ»Ò°µ

4

½«³±ÊªµÄÌúË¿·ÅÔÚ³£ÎµÄÑõÆøÁ÷ÖÐһСʱ

ÌúË¿±íÃæÂÔÏÔ»Ò°µ

5

½«³±ÊªµÄÌúË¿·ÅÔÚ¸ßÓÚ³£ÎµÄÑõÆøÁ÷ÖÐһСʱ

ÌúË¿±íÃæÒѱäµÃ»Ò°µ

6

½«½þ¹ýÂÈ»¯ÄÆÈÜÒºµÄÌúË¿·ÅÔÚ¸ßÓÚ³£ÎµÄÑõÆøÁ÷ÖÐһСʱ

ÌúË¿±íÃæ»Ò°µ³Ì¶È±ÈʵÑé5ÑÏÖØ

 

»Ø´ðÒÔÏÂÎÊÌ⣺                                                        

(1)ÉÏÊöʵÑéÖз¢ÉúÁ˵绯ѧ¸¯Ê´µÄÊÇ(ÌîʵÑéÐòºÅ) __________; Ôڵ绯ѧ¸¯Ê´ÖУ¬¸º¼«·´Ó¦ÊÇ________________; Õý¼«·´Ó¦ÊÇ_______________________£»                                                                                                         

(2)ÓɸÃʵÑé¿ÉÖª£¬¿ÉÒÔÓ°ÏìÌúÐâÊ´ËÙÂʵÄÒòËØÊÇ_________________________£»                                                                                                     

(3)Ϊ·ÀÖ¹ÌúµÄÐâÊ´£¬¹¤ÒµÉÏÆÕ±é²ÉÓõķ½·¨ÊÇ______________(´ðÁ½ÖÖ·½·¨)               

´ð°¸£º(1)3¡¢4¡¢5¡¢6     ¸º¼«£ºFe-2e¡úFe2+  Õý¼«£ºO2+2H2O+4e¡ú4OH-

(2) ζȡ¢Êª¶È¡¢µç½âÖÊ´æÔÚ¡¢O2µÄŨ¶È

(3) ¢ÙÍâ¼Ó±£»¤²ãÈ磺ͿÆᡢ̴ɡ¢µç¶Æ¡¢±íÃæ¶Û»¯¡¢ÓÍÖ¬µÈ¡£

¢Ú¸Ä±ä¸ÖÌúµÄÄÚ²¿½á¹¹£¬Ò±Á¶²»Ðâ¸Ö¡£

½âÎö£º¹¤ÒµÉÏÌúµÄÐâÊ´Ö÷ÒªÊǵ绯ѧ¸¯Ê´£¬·¢Éúµç»¯Ñ§¸¯Ê´µÄÌõ¼þÊÇ£º»îÐÔ²»Í¬µÄÁ½¼«²ÄÁÏ£¬µç½âÖÊÈÜÒº£¬ÐγɱպϻØ·¡£Ó°ÏìÐâÊ´ËٶȵÄÒòËØÓУº»·¾³µÄζȡ¢Êª¶È¡¢µç½âÖÊ´æÔÚ¡¢O2µÄŨ¶ÈµÈ¡£ÊµÑéÌõ¼þΪÓÐÑõ£¬ÎªÎüÑõ¸¯Ê´£º

¸º¼«£ºFe-2e¡úFe2+  Õý¼«£ºO2+2H2O+4e¡ú4OH-

±£»¤¸ÖÌú²»±»¸¯Ê´µÄ´ëÊ©

¢ÙÍâ¼Ó±£»¤²ãÈ磺ͿÆᡢ̴ɡ¢µç¶Æ¡¢±íÃæ¶Û»¯¡¢ÓÍÖ¬µÈ¡£

¢Ú¸Ä±ä¸ÖÌúµÄÄÚ²¿½á¹¹£¬Ò±Á¶²»Ðâ¸Ö¡£

¢ÛÔÚ¸ÖÌúµÄ±íÃæÏâǶ±ÈÌú»îÆõĽðÊôÈçп£¬Ê¹»îÆýðÊô±»Ñõ»¯£¬¶ø¸ÖÌú±»±£»¤¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨08Ä꺣ÄÏ¾í£©15£®·´Ó¦A(g)+B(g)¡¡   C(g) +D(g)¹ý³ÌÖеÄÄÜÁ¿±ä»¯ÈçͼËùʾ£¬»Ø´ðÏÂÁÐÎÊÌâ¡£

 

(1)¸Ã·´Ó¦ÊÇ____________________·´Ó¦(Ìî¡°ÎüÈÈ¡±¡°·ÅÈÈ¡±);

(2)µ±·´Ó¦´ïµ½Æ½ºâʱ£¬Éý¸ßζȣ¬AµÄת»¯ÂÊ______(Ìî¡°Ôö´ó¡±¡°¼õС¡±¡°²»±ä¡±)£¬

Ô­ÒòÊÇ____________________________________________£»

(3)·´Ó¦ÌåϵÖмÓÈë´ß»¯¼Á¶Ô·´Ó¦ÈÈÊÇ·ñÓÐÓ°Ïì?_______________£¬Ô­ÒòÊÇ_________£º

(4)ÔÚ·´Ó¦ÌåϵÖмÓÈë´ß»¯¼Á£¬·´Ó¦ËÙÂÊÔö´ó£¬E1ºÍE2µÄ±ä»¯ÊÇ£ºE1_________£¬E2________(Ìî¡°Ôö´ó¡±¡°¼õС¡¢¡±¡°²»±ä¡±)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨08Ä꺣ÄÏ¾í£©(8·Ö)·´Ó¦A(g)+B(g)¡¡   C(g) +D(g)¹ý³ÌÖеÄÄÜÁ¿±ä»¯ÈçͼËùʾ£¬»Ø´ðÏÂÁÐÎÊÌâ¡£

 

(1)¸Ã·´Ó¦ÊÇ____________________·´Ó¦(Ìî¡°ÎüÈÈ¡±¡°·ÅÈÈ¡±);

(2)µ±·´Ó¦´ïµ½Æ½ºâʱ£¬Éý¸ßζȣ¬AµÄת»¯ÂÊ______(Ìî¡°Ôö´ó¡±¡°¼õС¡±¡°²»±ä¡±)£¬

Ô­ÒòÊÇ____________________________________________£»

(3)·´Ó¦ÌåϵÖмÓÈë´ß»¯¼Á¶Ô·´Ó¦ÈÈÊÇ·ñÓÐÓ°Ïì?_______________£¬Ô­ÒòÊÇ_________£º

(4)ÔÚ·´Ó¦ÌåϵÖмÓÈë´ß»¯¼Á£¬·´Ó¦ËÙÂÊÔö´ó£¬E1ºÍE2µÄ±ä»¯ÊÇ£ºE1_________£¬E2________(Ìî¡°Ôö´ó¡±¡°¼õС¡¢¡±¡°²»±ä¡±)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(08Ä꺣ÄϾí)(10·Ö)A¡¢B¡¢C¡¢D¡¢E¾ùΪÓлú»¯ºÏÎËüÃÇÖ®¼äµÄ¹ØϵÈçͼËùʾ(Ìáʾ£ºRCH=CHR'ÔÚËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖз´Ó¦Éú³ÉRCOOHºÍR'COOH£¬ÆäÖÐRºÍR'ΪÍé»ù)¡£

 

»Ø´ðÏÂÁÐÎÊÌ⣺

 (1)Ö±Á´»¯ºÏÎïAµÄÏà¶Ô·Ö×ÓÖÊÁ¿Ð¡ÓÚ90£¬A·Ö×ÓÖÐ̼¡¢ÇâÔªËصÄ×ÜÖÊÁ¿·ÖÊýΪ0.814£¬ÆäÓàΪÑõÔªËØ£¬ÔòAµÄ·Ö×ÓʽΪ_____________£»

 (2)ÒÑÖªBÓëNaHCO3ÈÜÒºÍêÈ«·´Ó¦£¬ÆäÎïÖʵÄÁ¿Ö®±ÈΪ1£º2£¬ÔòÔÚŨÁòËáµÄ´ß»¯Ï£¬BÓë×ãÁ¿µÄC2H5OH·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ___ ·´Ó¦ÀàÐÍΪ_____£º

 (3)A¿ÉÒÔÓë½ðÊôÄÆ×÷Ó÷ųöÇâÆø£¬ÄÜʹäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«£¬ÔòAµÄ½á¹¹¼òʽÊÇ__________________

 (4)DµÄͬ·ÖÒì¹¹ÌåÖУ¬ÄÜÓëNaHCO3ÈÜÒº·´Ó¦·Å³öCO2µÄÓÐ__________ÖÖ£¬ÆäÏàÓ¦µÄ½á¹¹¼òʽÊÇ__________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨08Ä꺣ÄÏ¾í£©Ð¿ÓëºÜÏ¡µÄÏõËá·´Ó¦Éú³ÉÏõËáп¡¢ÏõËá狀ÍË®¡£µ±Éú³É1 molÏõËáпʱ£¬±»»¹Ô­µÄÏõËáµÄÎïÖʵÄÁ¿Îª£¨ £©

 

           A.    2mol                              B.   1 mol                                 C.   0.5mol                               D.  0.25mol

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸