£¨10·Ö£©³£ÎÂÏÂÒÑÖªpH=2µÄ¸ßµâËᣨHIO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔËáÐÔ£»0.01mol¡¤L-1µÄµâËᣨHIO3£©»ò¸ßÃÌËᣨHMnO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔÖÐÐÔ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸ßµâËáÊÇ £¨Ìî¡°Ç¿Ëᡱ»ò¡°ÈõËᡱ£©£¬ÀíÓÉÊÇ ¡£
£¨2£©0.01mol¡¤L-1µÄµâËᣨHIO3£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏËùµÃÈÜÒºÖÐÓëNa+µÄŨ¶È¹ØϵÊÇ £¨Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©¡£
£¨3£©ÒÑÖª¸ßµâËáºÍÁòËáÃÌ£¨MnSO4£©ÔÚÈÜÒºÖз´Ó¦Éú³É¸ßÃÌËá¡¢µâËáºÍÁòËᣬ´Ë·´Ó¦µÄ»¹Ô¼ÁÊÇ £¬¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ¿É±íʾΪ ¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ìºþÄÏÊ¡ºþÄÏʦ´ó¸½ÖиßÈýµÚÈý´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ
£¨8·Ö£©³£ÎÂÏÂÒÑÖªpH=2µÄ¸ßµâËᣨHIO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔËáÐÔ£»0.01mol¡¤L-1µÄµâËᣨHIO3£©»ò¸ßÃÌËᣨHMnO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔÖÐÐÔ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸ßµâËáÊÇ £¨Ìî¡°Ç¿Ëᡱ»ò¡°ÈõËᡱ£©
£¨2£©0.01mol¡¤L-1µÄµâËᣨHIO3£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏËùµÃÈÜÒºÖÐIO¡ª3ÓëNa+µÄÎïÖʵÄÁ¿µÄ¹ØϵÊÇn(Na+) n(IO-3)£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©¡£
£¨3£©ÒÑÖª¸ßµâËáºÍÁòËáÃÌ£¨MnSO4£©ÔÚÈÜÒºÖз´Ó¦Éú³É¸ßÃÌËá¡¢µâËáºÍÁòËᣬ´Ë·´Ó¦µÄ»¹Ô¼ÁÊÇ £¬¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ¿É±íʾΪ ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêºþÄÏÊ¡¸ßÈýµÚÈý´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ
£¨8·Ö£©³£ÎÂÏÂÒÑÖªpH=2µÄ¸ßµâËᣨHIO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔËáÐÔ£»0.01mol¡¤L-1µÄµâËᣨHIO3£©»ò¸ßÃÌËᣨHMnO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔÖÐÐÔ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸ßµâËáÊÇ £¨Ìî¡°Ç¿Ëᡱ»ò¡°ÈõËᡱ£©
£¨2£©0.01mol¡¤L-1µÄµâËᣨHIO3£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏËùµÃÈÜÒºÖÐIO¡ª3ÓëNa+µÄÎïÖʵÄÁ¿µÄ¹ØϵÊÇn(Na+) n(IO-3)£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©¡£
£¨3£©ÒÑÖª¸ßµâËáºÍÁòËáÃÌ£¨MnSO4£©ÔÚÈÜÒºÖз´Ó¦Éú³É¸ßÃÌËá¡¢µâËáºÍÁòËᣬ´Ë·´Ó¦µÄ»¹Ô¼ÁÊÇ £¬¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ¿É±íʾΪ ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
£¨8·Ö£©³£ÎÂÏÂÒÑÖªpH=2µÄ¸ßµâËᣨHIO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔËáÐÔ£»0.01mol¡¤L-1µÄµâËᣨHIO3£©»ò¸ßÃÌËᣨHMnO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔÖÐÐÔ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸ßµâËáÊÇ £¨Ìî¡°Ç¿Ëᡱ»ò¡°ÈõËᡱ£©
£¨2£©0.01mol¡¤L-1µÄµâËᣨHIO3£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏËùµÃÈÜÒºÖÐIO¡ª3ÓëNa+µÄÎïÖʵÄÁ¿µÄ¹ØϵÊÇn(Na+) n(IO-3)£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©¡£
£¨3£©ÒÑÖª¸ßµâËáºÍÁòËáÃÌ£¨MnSO4£©ÔÚÈÜÒºÖз´Ó¦Éú³É¸ßÃÌËá¡¢µâËáºÍÁòËᣬ´Ë·´Ó¦µÄ»¹Ô¼ÁÊÇ £¬¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ¿É±íʾΪ ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Äê½Î÷Ê¡¸ß°²ÖÐѧ¸ß¶þÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§¾í ÌâÐÍ£ºÌî¿ÕÌâ
£¨10·Ö£©³£ÎÂÏÂÒÑÖªpH=2µÄ¸ßµâËᣨHIO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔËáÐÔ£»0.01mol¡¤L-1µÄµâËᣨHIO3£©»ò¸ßÃÌËᣨHMnO4£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÏÔÖÐÐÔ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸ßµâËáÊÇ £¨Ìî¡°Ç¿Ëᡱ»ò¡°ÈõËᡱ£©£¬ÀíÓÉÊÇ ¡£
£¨2£©0.01mol¡¤L-1µÄµâËᣨHIO3£©ÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏËùµÃÈÜÒºÖÐÓëNa+µÄŨ¶È¹ØϵÊÇ £¨Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©¡£
£¨3£©ÒÑÖª¸ßµâËáºÍÁòËáÃÌ£¨MnSO4£©ÔÚÈÜÒºÖз´Ó¦Éú³É¸ßÃÌËá¡¢µâËáºÍÁòËᣬ´Ë·´Ó¦µÄ»¹Ô¼ÁÊÇ £¬¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ¿É±íʾΪ ¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com