½«0.1 molµÄþ¡¢ÂÁ»ìºÏÎïÈÜÓÚ100mL 2mol¡¤LµÄH2SO4ÈÜÒºÖУ¬È»ºóÔٵμÓ1mol¡¤LµÄNaOHÈÜÒº¡£Çë»Ø´ð£º£¨²»ÐèҪд³ö¼ÆËã¹ý³Ì£©

£¨1£©ÈôÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖгÁµíÖÊÁ¿Ëæ¼ÓÈëNaOHÈÜÒºµÄÌå»ýV±ä»¯ÈçͼËùʾ¡£µ±mLʱ£¬Ôò½ðÊô·ÛÄ©ÖÐ(Mg)=             mol£¬       mL¡£

£¨2£©¢ÙÒªÅäÖÆ100 mL 2mol¡¤LµÄH2SO4ÈÜÒº£¬ÐèÒªµÄÒÇÆ÷³ýÁ¿Í²¡¢ÉÕ±­Í⣬»¹ÓР                   ¡£

¢ÚÏÂÁвÙ×÷»áʹËùÅäµÄÈÜҺŨ¶ÈƫСµÄÊÇ£¨  £©£¨Ìî´úºÅ£©

A£®ÓÃÁ¿Í²Á¿È¡Ò»¶¨Ìå»ýµÄ98%µÄŨH2SO4£¬Ï¡Êͺóδ¾­ÀäÈ´¼´×ªÈëÈÝÁ¿Æ¿ÄÚ

B£®Ï¡ÊÍÁòËáËùÓõÄСÉÕ±­Î´Ï´µÓ

C£®¶¨ÈÝʱ¸©ÊÓÒºÃæ

D£®ÓÃÕôÁóˮϴµÓºóµÄÈÝÁ¿Æ¿Î´¸ÉÔï

E£®¶¨ÈÝÒ¡ÔȺ󣬵¹Èë¸ÉÔïµÄÊÔ¼ÁÆ¿Öд¢´æʱ£¬ÓÐÉÙÁ¿ÈÜҺdz³öÆ¿Íâ

 

¡¾´ð°¸¡¿

£¨1£©0.06  440 

£¨2£©¢Ù²£Á§°ô  100mLÈÝÁ¿Æ¿¡¢½ºÍ·µÎ¹Ü   ¢ÚB

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

½«0.1 molµÄþ¡¢ÂÁ»ìºÏÎïÈÜÓÚ100 mL 2mol/LH2SO4ÈÜÒºÖУ¬È»ºóÔٵμÓ1 mol/L NaOH

ÈÜÒº¡£Çë»Ø´ð£º

¢ÅÈôÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖУ¬³ÁµíÖÊÁ¿mËæ¼ÓÈëNaOHÈÜÒºµÄÌå»ýV±ä»¯ÈçÏÂͼËùʾ¡£µ±

V1£½160mLʱ£¬Ôò½ðÊô·ÛÄ©ÖÐn(Mg)£½¡¡  ¡¡mol£¬V2£½

¡¡¡¡ ¡¡¡¡mL¡£

¢ÆÈôÔڵμÓNaOHÈÜÒº¹ý³ÌÖУ¬ÓûʹMg2£«¡¢Al3£«¸ÕºÃ³ÁµíÍêÈ«£¬ÔòµÎÈëNaOHÈÜ   ÒºµÄÌå»ýV(NaOH)¡¡    ¡¡mL¡£

¢ÇÈô»ìºÏÎïÈÔΪ0.1 mol£¬ÆäÖÐMg·ÛµÄÎïÖʵÄÁ¿·ÖÊýΪa£¬ÓÃ100 mL 2 mol/LµÄÁòËáÈܽâ´Ë»ìºÏÎïºó£¬ÔÙ¼ÓÈë450 mL 1mol/LµÄNaOHÈÜÒº£¬ËùµÃ³ÁµíÖÐÎÞAl(OH)3¡£Âú×ã´ËÌõ¼þµÄaµÄÈ¡Öµ·¶Î§ÊÇ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

½«0.1 molµÄþ¡¢ÂÁ»ìºÏÎïÈÜÓÚ100mL 2mol¡¤LµÄH2SO4ÈÜÒºÖУ¬È»ºóÔٵμÓ1mol¡¤LµÄNaOHÈÜÒº¡£Çë»Ø´ð£º£¨²»ÐèҪд³ö¼ÆËã¹ý³Ì£©

£¨1£©ÈôÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖгÁµíÖÊÁ¿Ëæ¼ÓÈëNaOHÈÜÒºµÄÌå»ýV±ä»¯ÈçͼËùʾ¡£µ±mLʱ£¬Ôò½ðÊô·ÛÄ©ÖÐ(Mg)=             mol£¬       mL¡£

£¨2£©¢ÙÒªÅäÖÆ100 mL 2mol¡¤LµÄH2SO4ÈÜÒº£¬ÐèÒªµÄÒÇÆ÷³ýÁ¿Í²¡¢ÉÕ±­Í⣬»¹ÓР                   ¡£

¢ÚÏÂÁвÙ×÷»áʹËùÅäµÄÈÜҺŨ¶ÈƫСµÄÊÇ£¨  £©£¨Ìî´úºÅ£©

A£®ÓÃÁ¿Í²Á¿È¡Ò»¶¨Ìå»ýµÄ98%µÄŨH2SO4£¬Ï¡Êͺóδ¾­ÀäÈ´¼´×ªÈëÈÝÁ¿Æ¿ÄÚ

B£®Ï¡ÊÍÁòËáËùÓõÄСÉÕ±­Î´Ï´µÓ

C£®¶¨ÈÝʱ¸©ÊÓÒºÃæ

D£®ÓÃÕôÁóˮϴµÓºóµÄÈÝÁ¿Æ¿Î´¸ÉÔï

E£®¶¨ÈÝÒ¡ÔȺ󣬵¹Èë¸ÉÔïµÄÊÔ¼ÁÆ¿Öд¢´æʱ£¬ÓÐÉÙÁ¿ÈÜҺdz³öÆ¿Íâ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

½«0.1 molµÄþ¡¢ÂÁ»ìºÏÎïÈÜÓÚ100mL 2mol/L H2SO4ÈÜÒºÖУ¬È»ºóÔٵμÓ1 mol/L NaOHÈÜÒºÖÁ¹ýÁ¿¡£Çë»Ø´ð£º

£¨1£©Ð´³öÓëÂÁÓйصÄÀë×Ó·½³Ìʽ£º                                                                        

£¨2£©ÈôÔڵμÓNaOHÈÜÒº¹ý³ÌÖУ¬³ÁµíÖÊÁ¿mËæ¼ÓÈëNaOHÈÜÒºµÄÌå»ýV±ä»¯ÈçͼËùʾ¡£µ±V1£½160mLʱ£¬Ôò½ðÊô·ÛÄ©ÖÐn(Mg)£½         mol£¬

V2£½             mL¡£³ÁµíµÄ×î´óÖÊÁ¿ÊÇ           g¡£

£¨3£©ÈôÔڵμÓNaOHÈÜÒº¹ý³ÌÖУ¬ÓûʹMg2£«¡¢Al3£«¸ÕºÃ³ÁµíÍêÈ«£¬ÔòµÎÈëNaOHÈÜÒºµÄÌå»ýV(NaOH)=            mL¡£

£¨4£©Èô»ìºÏÎïÈÔΪ0.1 mol£¬ÆäÖÐMg·ÛµÄÎïÖʵÄÁ¿·ÖÊýΪa£¬ÓÃ100 mL 2 mol/LµÄÁòËáÈܽâ´Ë»ìºÏÎïºó£¬ÔÙ¼ÓÈë450 mL 1mol/LµÄNaOHÈÜÒº£¬ËùµÃ³ÁµíÖÐÎÞAl(OH)3¡£Âú×ã´ËÌõ¼þµÄaµÄÈ¡Öµ·¶Î§ÊÇ£º                        ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄê¹ã¶«Ê¡¸ßÈýÉÏѧÆÚ10Ô·ÝÔ¿¼£¨Àí×Û£©»¯Ñ§¾í ÌâÐÍ£ºÌî¿ÕÌâ

½«0.1 molµÄþ¡¢ÂÁ»ìºÏÎïÈÜÓÚ100mL 2mol/L H2SO4ÈÜÒºÖУ¬È»ºóÔٵμÓ1 mol/L NaOHÈÜÒºÖÁ¹ýÁ¿¡£Çë»Ø´ð£º

£¨1£©Ð´³öÓëÂÁÓйصÄÀë×Ó·½³Ìʽ£º                                                                        

£¨2£©ÈôÔڵμÓNaOHÈÜÒº¹ý³ÌÖУ¬³ÁµíÖÊÁ¿mËæ¼ÓÈëNaOHÈÜÒºµÄÌå»ýV±ä»¯ÈçͼËùʾ¡£µ±V1£½160mLʱ£¬Ôò½ðÊô·ÛÄ©ÖÐn(Mg)£½         mol£¬

V2£½             mL¡£³ÁµíµÄ×î´óÖÊÁ¿ÊÇ           g¡£

£¨3£©ÈôÔڵμÓNaOHÈÜÒº¹ý³ÌÖУ¬ÓûʹMg2£«¡¢Al3£«¸ÕºÃ³ÁµíÍêÈ«£¬ÔòµÎÈëNaOHÈÜÒºµÄÌå»ýV(NaOH)=            mL¡£

£¨4£©Èô»ìºÏÎïÈÔΪ0.1 mol£¬ÆäÖÐMg·ÛµÄÎïÖʵÄÁ¿·ÖÊýΪa£¬ÓÃ100 mL 2 mol/LµÄÁòËáÈܽâ´Ë»ìºÏÎïºó£¬ÔÙ¼ÓÈë450 mL 1mol/LµÄNaOHÈÜÒº£¬ËùµÃ³ÁµíÖÐÎÞAl(OH)3¡£Âú×ã´ËÌõ¼þµÄaµÄÈ¡Öµ·¶Î§ÊÇ£º                        ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸