£¨8·Ö£©£¨1£©ÇëÍê³ÉÏÂÁи÷¿Õ£º

¢ÙpH= aµÄCH3COOHÈÜҺϡÊÍ100±¶ºóËùµÃÈÜÒºpH     a +2£¨Ìî¡°>¡±»ò¡°<¡±£©

¢Ú0.01mol/LCH3COOHÈÜÒºµÄpH      2£¨Ìî¡°>¡±»ò¡°<¡±£©£»

£¨2£©¹Û²ì±È½ÏÒÔÉÏÁ½¸öСÌ⣬ÊÔ²ÂÏëÖ¤Ã÷ijËᣨHA£©ÊÇÈõµç½âÖʵÄÔ­ÀíÓÐÁ½¸ö£º

Ò»ÊÇ£º                                                              £»

¶þÊÇ£º                                                              ¡£

£¨3£©ÇëÄã¸ù¾ÝÒÔÉÏÔ­ÀíÌá³öһЩ·½°¸£¬Ö¤Ã÷HAËáÊÇÈõµç½âÖÊ£º£¨Ö»Ðè¼òÃ÷д³ö·½°¸£¬²»Ðèд³ö¾ßÌå²½Ö裬ÒÔÏÂÏîÄ¿¿É²»ÌîÂúÒ²¿ÉÔö¼ÓÏîÄ¿£©

¢Ù                                                                

¢Ú                                                                 

 

£¨8·Ö£©

£¨1£©¢Ù<£»¢Ú>£»(2·Ö)

£¨2£©Ò»ÊÇ£ºÈÜÒºÖдæÔÚµçÀëƽºâ£»(2·Ö)

     ¶þÊÇ£ºÖ¤Ã÷HA²»ÄÜÍêÈ«µçÀë¡£(2·Ö)

£¨3£©¢Ù¶Ô±ÈµÈÎïÖʵÄÁ¿Å¨¶ÈµÄHAÈÜÒººÍÑÎËáµ¼µçÐÔ¶Ô±ÈʵÑ飻

¢Ú²â0.01mol/LHAÈÜÒºµÄpH>2£»

¢Û²âpH= aµÄHAÏ¡ÊÍ100±¶ºóËùµÃÈÜÒºpH<a +2

¢ÜÖкÍ10mLpH=1µÄHAÈÜÒºÏûºÄpH=13µÄNaOHÈÜÒºµÄÌå»ý´óÓÚ10mL;

ÒÔÉÏÈÎÒâÁ½¸ö»òÆäËûºÏÀí´ð°¸¾ù¿É¡££¨2·Ö£©

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨Ò»£©ÇëÍê³ÉÏÂÁи÷¿Õ£º
£¨1£©pH=aµÄCH3COOHÈÜҺϡÊÍ100±¶ºóËùµÃÈÜÒºpH
£¼
£¼
a+2£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©
£¨2£©0.01mol?L-1CH3COOHÈÜÒºµÄpH
£¾
£¾
2£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©
£¨3£©0.1mol?L-1CH3COONaÈÜÒºµÄpH
£¾
£¾
7£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©
£¨¶þ£©³£ÎÂÏÂÓÐŨ¶È¾ùΪ0.05mol/LµÄËÄÖÖÈÜÒº£º¢ÙNa2CO3 ¢ÚNaHCO3 ¢ÛHCl ¢ÜNH3?H2O£¬»Ø´ðÏà¹ØÎÊÌ⣺
£¨1£©ÉÏÊöÈÜÒºÖУ¬¿É·¢ÉúË®½âµÄÊÇ
¢Ù¢Ú
¢Ù¢Ú
£¨ÌîÐòºÅ£©
£¨2£©ÔÚNaHCO3ÈÜÒºÖУ¬Àë×ÓŨ¶È´óСµÄ¹ØϵÕýÈ·µÄÊÇ
CD
CD
£¨Ìî×Öĸ£©
A¡¢c£¨Na+£©£¾c£¨HCO3-£©£¾c£¨H+£©£¾c£¨OH-£©
B¡¢c£¨Na+£©=c£¨HCO3-£©£¾c£¨H+£©£¾c£¨OH-£©
C¡¢c£¨Na+£©=c£¨HCO3-£©+c£¨H2CO3£©+c£¨CO32-£©
D¡¢c£¨Na+£©+c£¨H+£©=c£¨HCO3-£©+c£¨OH-£©+2c£¨CO32-£©
£¨3£©Ïò¢ÜÖмÓÈëÉÙÁ¿NH4Cl¹ÌÌ壬´Ëʱc£¨NH4+/OH-£©µÄÖµ
Ôö´ó
Ôö´ó
£¨¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±£©
£¨4£©Èô½«¢ÛºÍ¢ÜµÄÈÜÒº»ìºÏºó£¬ÈÜҺǡºÃ³ÊÖÐÐÔ£¬Ôò»ìºÏÇ°¢ÛµÄÌå»ý
СÓÚ
СÓÚ
¢ÜµÄÌå»ý£¨¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©
£¨5£©È¡10mLµÄ¢ÛÈÜÒº¼ÓˮϡÊ͵½500mL£¬Ôò´ËÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©=
10-11
10-11
mol/L£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄêÔÆÄÏÊ¡À¥Ã÷Ò»Öи߶þÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨8·Ö£©£¨1£©ÇëÍê³ÉÏÂÁи÷¿Õ£º
¢ÙpH= aµÄCH3COOHÈÜҺϡÊÍ100±¶ºóËùµÃÈÜÒºpH     a +2£¨Ìî¡°>¡±»ò¡°<¡±£©
¢Ú0.01mol/LCH3COOHÈÜÒºµÄpH     2£¨Ìî¡°>¡±»ò¡°<¡±£©£»
£¨2£©¹Û²ì±È½ÏÒÔÉÏÁ½¸öСÌ⣬ÊÔ²ÂÏëÖ¤Ã÷ijËᣨHA£©ÊÇÈõµç½âÖʵÄÔ­ÀíÓÐÁ½¸ö£º
Ò»ÊÇ£º                                                              £»
¶þÊÇ£º                                                              ¡£
£¨3£©ÇëÄã¸ù¾ÝÒÔÉÏÔ­ÀíÌá³öһЩ·½°¸£¬Ö¤Ã÷HAËáÊÇÈõµç½âÖÊ£º£¨Ö»Ðè¼òÃ÷д³ö·½°¸£¬²»Ðèд³ö¾ßÌå²½Ö裬ÒÔÏÂÏîÄ¿¿É²»ÌîÂúÒ²¿ÉÔö¼ÓÏîÄ¿£©
¢Ù                                                                
¢Ú                                                                 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ìÔÆÄÏÊ¡¸ß¶þÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨8·Ö£©£¨1£©ÇëÍê³ÉÏÂÁи÷¿Õ£º

¢ÙpH= aµÄCH3COOHÈÜҺϡÊÍ100±¶ºóËùµÃÈÜÒºpH      a +2£¨Ìî¡°>¡±»ò¡°<¡±£©

¢Ú0.01mol/LCH3COOHÈÜÒºµÄpH      2£¨Ìî¡°>¡±»ò¡°<¡±£©£»

£¨2£©¹Û²ì±È½ÏÒÔÉÏÁ½¸öСÌ⣬ÊÔ²ÂÏëÖ¤Ã÷ijËᣨHA£©ÊÇÈõµç½âÖʵÄÔ­ÀíÓÐÁ½¸ö£º

Ò»ÊÇ£º                                                               £»

¶þÊÇ£º                                                               ¡£

£¨3£©ÇëÄã¸ù¾ÝÒÔÉÏÔ­ÀíÌá³öһЩ·½°¸£¬Ö¤Ã÷HAËáÊÇÈõµç½âÖÊ£º£¨Ö»Ðè¼òÃ÷д³ö·½°¸£¬²»Ðèд³ö¾ßÌå²½Ö裬ÒÔÏÂÏîÄ¿¿É²»ÌîÂúÒ²¿ÉÔö¼ÓÏîÄ¿£©

¢Ù                                                                

¢Ú                                                                  

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Íê³ÉÒÔÏÂСÌ⣺

£¨1£©ÇëÍê³ÉÏÂÁи÷¿Õ£º

¢ÙpH= aµÄCH3COOHÈÜҺϡÊÍ100±¶ºóËùµÃÈÜÒºpH    a +2£¨Ìî¡°>¡±»ò¡°<¡±£©

¢Ú0.01mol/LCH3COOHÈÜÒºµÄpH      2£¨Ìî¡°>¡±»ò¡°<¡±£©£»

¢Û0.1mol/LCH3COONaÈÜÒºµÄpH      7£¨Ìî¡°>¡±»ò¡°<¡±£©£»

£¨2£©Ä³¹ÌÌåÊÇÓÉNa2CO3¡¢NaOH¡¢MgCl2¡¢AlCl3¡¢BaCl2¡¢Fe2(SO4)3ºÍ(NH4)2SO4ÖеÄÁ½ÖÖ»ìºÏ¶ø³É¡£È¡¸Ã¹ÌÌåÈÜÓÚË®µÃµ½ÎÞÉ«³ÎÇåÈÜÒº£¬Ïò¸ÃÈÜÒºÖмÓÈëÏ¡ÁòËᣬÓа×É«³ÁµíÉú³É£¬¼ÌÐø¼ÓÈëÏ¡ÁòËᣬ³ÁµíÓÖÍêÈ«Ïûʧ£¬ÇÒÕû¸ö¹ý³ÌÖÐÎÞÆøÌå²úÉú¡£Ôò Ô­¹ÌÌåÖк¬ÓÐÎïÖÊÓР         ºÍ                    ¡££¨Ð´»¯Ñ§Ê½£©  K^S*5U.

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸