£¨6·Ö£©ÀûÓá°»¯Ñ§¼ÆÁ¿ÔÚʵÑéÖеÄÓ¦Óá±µÄÏà¹Ø֪ʶ½øÐÐÌî¿Õ
£¨1£©º¬ÓÐ6.02¡Á1023¸öÑõÔ­×ÓµÄH2SO4µÄÎïÖʵÄÁ¿ÊÇ_________?
£¨2£©½«4 g NaOHÈܽâÔÚ10 mLË®ÖУ¬ÔÙÏ¡ÊͳÉ1 L£¬´ÓÖÐÈ¡³ö10 mL£¬Õâ10 mLÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ_______¡£
£¨3£©½«50 mL 0.1 mol¡¤L£­1 NaClºÍ50 mL 0.5 mol¡¤L£­1 CaCl2ÈÜÒº»ìºÏºó£¬ÈôÈÜÒºµÄÌå»ýΪ¶þÕßÌå»ýÖ®ºÍ£¬Ôò»ìºÏÈÜÒºÖÐc (Cl£­)Ϊ?______________¡£

£¨Ã¿¿Õ2·Ö£¬¹²6·Ö£©£¨1£©0.25mol   (2)0.1mol/L   (3)0.55mol/L

½âÎöÊÔÌâ·ÖÎö£º£¨1£©¸ù¾Ý¿ÉÖª£¬º¬ÓÐ6.02¡Á1023¸öÑõÔ­×ÓÎïÖʵÄÁ¿ÊÇ
6.02¡Á1023¡Â6.02¡Á1023/mol£½1mol¡£ËùÒÔ¸ù¾ÝÁòËáµÄ»¯Ñ§Ê½H2SO4¿ÉÖª£¬ÁòËáµÄÎïÖʵÄÁ¿ÊÇ1mol¡Â4£½0.25mol¡£
£¨2£©¸ù¾Ýn£½m/M¿ÉÖª£¬4gÇâÑõ»¯ÄƵÄÎïÖʵÄÁ¿ÊÇ4g¡Â40g/mol£½0.1mol¡£ÒÀ¾Ýc£½n/V¿ÉÖª£¬¸ÃÈÜÒºµÄŨ¶ÈÊÇ0.1mol¡Â1L£½0.1mol/L¡£ÓÉÓÚÈÜÒºÊǾùÒ»µÄ£¬ËùÒÔÈ¡³öµÄ10mlÈÜÒºÆäŨ¶È»¹ÊÇ0.1mol/L¡£
£¨3£©»ìºÏÇ°ÂÈ»¯ÄƺÍÂÈ»¯¸ÆÖÐÂÈÀë×ÓµÄÎïÖʵÄÁ¿·Ö±ðÊÇ0.05L¡Á0.1mol/L£½0.005mol¡¢0.05L¡Á0.5mol/L¡Á2£½0.05mol¡£ËùÒÔ»ìºÏºóÂÈÀë×ÓµÄÎïÖʵÄÁ¿ÊÇ0.005mol£«0.05mol£½0.055mol¡£¶øÈÜÒºµÄÌå»ýÊÇ100ml£¬ËùÒÔ»ìºÏºóÂÈÀë×ÓŨ¶ÈÊÇ0.055mol¡Â0.1L£½0.55mol/L¡£
¿¼µã£º¿¼²éÎïÖʵÄÁ¿µÄÓйؼÆËã
µãÆÀ£ºÔÚ½øÐÐÎïÖʵÄÁ¿µÄÓйؼÆËãʱ£¬¹Ø¼üÊÇÊìÁ·Ó¦Óü¸¸ö¹Øϵʽ¡¢n£½m/M¡¢¡¢£¬Ìرð»¹Òª×¢ÒâÆøÌåĦ¶ûÌå»ýºÍ°¢·ü¼ÓµÂÂÞ¶¨ÂɵÄʹÓÃÌõ¼þ£¬¼´Ö»ÄÜÊÊÓÃÓÚÆøÌ壬ÇÒÖ»ÓÐÔÚ±ê×¼×´¿öÏ£¬ÆøÌåµÄĦ¶ûÌå»ý²ÅÊÇ22.4L/mol¡£Èç¹ûÊǼÆËãÈÜÒºÖÐÀë×ÓŨ¶È£¬»¹ÐèҪעÒâÈÜÖʵĻ¯Ñ§Ê½ÒÔ¼°¶ÔÓ¦µÄµçÀë·½³Ìʽ£¬²ÅÄÜ׼ȷ¼ÆËãijÀë×ÓŨ¶È¡£Èç¹ûÊǼÆËãÀë×ÓµÄÎïÖʵÄÁ¿£¬»¹ÐèҪעÒâÈÜÒºµÄÌå»ý±ä»¯¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÀûÓá°»¯Ñ§¼ÆÁ¿ÔÚʵÑéÖеÄÓ¦Óá±µÄÏà¹Ø֪ʶ½øÐÐÌî¿Õ
£¨1£©ÊµÑéÊÒÐèÒª0.5mol/LµÄÁòËáÈÜÒº500mL£¬ÈôÓÃÖÊÁ¿·ÖÊýΪ98%¡¢ÃܶÈΪ1.84g/cm3µÄŨÁòËáÀ´ÅäÖÆ£¬ÔòËùÐè¸ÃŨÁòËáµÄÌå»ýΪ
13.6
13.6
mL£¨Áгö¼ÆËã¹ý³Ì£©£®
£¨2£©ÔÚ±ê×¼×´¿öÏ£¬ÓÉCOºÍCO2×é³ÉµÄ»ìºÏÆøÌå8.96L£¬ÖÊÁ¿ÊÇ16g£®´Ë»ìºÏÎïÖÐCOºÍCO2µÄÎïÖʵÄÁ¿Ö®±ÈÊÇ
1£º3
1£º3
£¬»ìºÏÆøÌåµÄƽ¾ùĦ¶ûÖÊÁ¿ÊÇ
40g/mol
40g/mol
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©ÏÖÓÐmgijÆøÌ壬ËüÓÉË«Ô­×Ó·Ö×Ó¹¹³É£¬ËüµÄĦ¶ûÖÊÁ¿ÎªMg?mol-1£®Èô°¢·ü¼ÓµÂÂÞ³£ÊýÓÃNA±íʾ£¬Ôò£º
¢Ù¸ÃÆøÌåµÄÎïÖʵÄÁ¿Îª
m
M
m
M
mol£®
¢Ú¸ÃÆøÌåËùº¬Ô­×Ó×ÜÊýΪ
2mNA
M
2mNA
M
¸ö£®
¢Û¸ÃÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ýΪ
22.4m
M
22.4m
M
L£®
¢Ü¸ÃÆøÌåÈÜÓÚ1LË®ÖУ¨²»¿¼ÂÇ·´Ó¦£©£¬ÆäÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪ
m
(m+1000)
¡Á100%
m
(m+1000)
¡Á100%
£®
£¨2£©ÀûÓá°»¯Ñ§¼ÆÁ¿ÔÚʵÑéÖеÄÓ¦Óá±µÄÏà¹Ø֪ʶ½øÐÐÌî¿Õ
¢Ùº¬ÓÐ6.02¡Á1023¸öÑõÔ­×ÓµÄH2SO4µÄÎïÖʵÄÁ¿ÊÇ
0.25
0.25
?mol
¢ÚÓë±ê×¼×´¿öÏÂVLCO2Ëùº¬ÑõÔ­×ÓÊýÄ¿ÏàͬµÄË®µÄÖÊÁ¿ÊÇ
18V
11.2
g
18V
11.2
g
£¨Ó÷Öʽ±íʾ£©
¢ÛÔÚÒ»¶¨µÄζȺÍѹǿÏ£¬1Ìå»ýX2 £¨g£©¸ú3Ìå»ýY2 £¨g£©»¯ºÏÉú³É2Ìå»ý»¯ºÏÎÔò¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ
XY3
XY3

¢ÜÈýÖÖÕýÑεĻìºÏÈÜÒºÖк¬ÓÐ0.2mol Na+¡¢0.25mol Mg2+¡¢0.4mol Cl-¡¢SO42-£¬Ôò
n£¨SO42-£© Îª
0.15
0.15
 mol
£¨3£©¼ÙÈç12CÏà¶ÔÔ­×ÓÖÊÁ¿Îª24£¬ÒÔ0.024kgËùº¬12CÔ­×ÓÊýΪ°¢·ü¼ÓµÂÂÞ³£Êý£¬ÏÂÁÐÊýÖµ¿Ï¶¨²»±äµÄÊÇ
AC
AC
£®
A£®ÑõÆøµÄÈܽâ¶È
B£®ÆøÌåĦ¶ûÌå»ý
C£®Ò»¶¨ÖÊÁ¿µÄÆøÌåÌå»ý
D£®°¢·ü¼ÓµÂÂÞ³£Êý
E£®O2Ïà¶Ô·Ö×ÓÖÊÁ¿
F£®¸ú2mLH2 Ï໯ºÏµÄO2µÄÖÊÁ¿¡¢ÎïÖʵÄÁ¿£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÖÓÐm gijÆøÌ壬ËüÓÉË«Ô­×Ó·Ö×Ó¹¹³É£¬ËüµÄĦ¶ûÖÊÁ¿ÎªM g?mol-1£®Èô°¢·ü¼ÓµÂÂÞ³£ÊýÓÃNA±íʾ£¬Ôò£º
£¨1£©¸ÃÆøÌåµÄÎïÖʵÄÁ¿Îª
m
M
m
M
£®
£¨2£©¸ÃÆøÌåËùº¬Ô­×Ó×ÜÊýΪ
2MNA
M
£¬
2MNA
M
£¬
¸ö£®
ÀûÓá°»¯Ñ§¼ÆÁ¿ÔÚʵÑéÖеÄÓ¦Óá±µÄÏà¹Ø֪ʶ½øÐÐÌî¿Õ£º
£¨3£©º¬ÓÐ6.02¡Á1023¸öÑõÔ­×ÓµÄH2SO4µÄÎïÖʵÄÁ¿ÊÇ
0.25mol
0.25mol
£®
£¨4£©Óë±ê×¼×´¿öÏÂVL CO2Ëùº¬ÑõÔ­×ÓÊýÄ¿ÏàͬµÄË®µÄÖÊÁ¿ÊÇ
1.6Vg
1.6Vg
£®
£¨5£©ÔÚÒ»¶¨µÄζȺÍѹǿÏ£¬1Ìå»ýX2£¨g£©¸ú3Ìå»ýY2£¨g£©»¯ºÏÉú³É2Ìå»ý»¯ºÏÎÔò¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ
XY3
XY3
£®
£¨6£©ÈýÖÖÕýÑεĻìºÏÈÜÒºÖк¬ÓÐ0.2mol Na+¡¢0.25mol Mg2+¡¢0.4mol Cl-¡¢SO42-£¬Ôòn£¨SO42-£© Îª
0.15mol
0.15mol
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêɽ¶«Ê¡¼ÃÄþÊÐÁºÉ½¶þÖиßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨12·Ö£©£®ÏÖÓÐmgijÆøÌ壬ËüÓÉË«Ô­×Ó·Ö×Ó¹¹³É£¬ËüµÄĦ¶ûÖÊÁ¿ÎªMg¡¤mol£­1¡£Èô°¢·ü¼ÓµÂÂÞ³£ÊýÓÃNA±íʾ£¬Ôò£º
(1)¸ÃÆøÌåµÄÎïÖʵÄÁ¿Îª______              __
(2)¸ÃÆøÌåËùº¬Ô­×Ó×ÜÊýΪ                     ¸ö¡£
ÀûÓá°»¯Ñ§¼ÆÁ¿ÔÚʵÑéÖеÄÓ¦Óá±µÄÏà¹Ø֪ʶ½øÐÐÌî¿Õ
(3)º¬ÓÐ6.02¡Á1023¸öÑõÔ­×ÓµÄH2SO4µÄÎïÖʵÄÁ¿ÊÇ_______        
(4)Óë±ê×¼×´¿öÏÂVLCO2Ëùº¬ÑõÔ­×ÓÊýÄ¿ÏàͬµÄË®µÄÖÊÁ¿ÊÇ_____    __
(5)ÔÚÒ»¶¨µÄζȺÍѹǿÏ£¬1Ìå»ýX2£¨g£©¸ú3Ìå»ýY2£¨g£©»¯ºÏÉú³É2Ìå»ý»¯ºÏÎÔò¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ__________     _____
(6)ÈýÖÖÕýÑεĻìºÏÈÜÒºÖк¬ÓÐ0.2 mol Na+¡¢0.25 mol Mg2+¡¢0.4 mol Cl£­¡¢SO42¡ª£¬Ôòn£¨SO42¡ª£©Îª___       ________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2015½ì¸ÊËàÊ¡¸ßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º¼ÆËãÌâ

£¨6·Ö£©ÀûÓá°»¯Ñ§¼ÆÁ¿ÔÚʵÑéÖеÄÓ¦Óá±µÄÏà¹Ø֪ʶ½øÐÐÌî¿Õ

   £¨1£©º¬ÓÐ6.02¡Á1023¸öÑõÔ­×ÓµÄH2SO4µÄÎïÖʵÄÁ¿ÊÇ_________?

   £¨2£©½«4 g NaOHÈܽâÔÚ10 mLË®ÖУ¬ÔÙÏ¡ÊͳÉ1 L£¬´ÓÖÐÈ¡³ö10 mL£¬Õâ10 mLÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ_______¡£

   £¨3£©½«50 mL 0.1 mol¡¤L£­1 NaClºÍ50 mL 0.5 mol¡¤L£­1 CaCl2ÈÜÒº»ìºÏºó£¬ÈôÈÜÒºµÄÌå»ýΪ¶þÕßÌå»ýÖ®ºÍ£¬Ôò»ìºÏÈÜÒºÖÐc (Cl£­)Ϊ?______________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸