ÔÚ2008Äê³õÎÒ¹úÄÏ·½ÔâÓöµÄ±ùÑ©ÔÖº¦ÖУ¬Ê¹ÓÃÁËÒ»ÖÖÈÚÑ©¼Á£¬ÆäÖ÷Òª³É·ÖµÄ»¯Ñ§Ê½ÎªXY2£¬X¡¢Y¾ùΪÖÜÆÚ±íǰ20ºÅÔªËØ£¬ÆäÑôÀë×ÓºÍÒõÀë×ӵĵç×Ó²ã½á¹¹Ïàͬ£¬ÇÒ1 mol XY2º¬ÓÐ54 molµç×Ó¡£

£¨1£©¸ÃÈÚÑ©¼ÁµÄ»¯Ñ§Ê½ÊÇ__________£»XÓëÇâÔªËØÐγɵϝºÏÎïµÄµç×ÓʽÊÇ_____________¡£

£¨2£©ÔªËØD¡¢EÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ2±¶£¬DÓëYÏàÁÚ£¬ÔòDµÄÀë×ӽṹʾÒâͼÊÇ________________£»DÓëEÄÜÐγÉÒ»ÖַǼ«ÐÔ·Ö×Ó£¬¸Ã·Ö×ӵĽṹʽΪ________________£»DËùÔÚ×åÔªËØµÄÇ⻯ÎïÖУ¬·Ðµã×îµÍµÄÊÇ_________________________¡£

£¨3£©ÔªËØWÓëYͬÖÜÆÚ£¬Æäµ¥ÖÊÊÇÔ­×Ó¾§Ìå£»ÔªËØZµÄµ¥ÖÊ·Ö×ÓZ2ÖÐÓÐ3¸ö¹²¼Û¼ü£»WÓëZÄÜÐγÉÒ»ÖÖÐÂÐÍÎÞ»ú·Ç½ðÊô²ÄÁÏ£¬Æä»¯Ñ§Ê½ÊÇ____________________________________¡£

£¨4£©ÔªËØRÓëYͬÖ÷×壬ÆäÇ⻯ÎïÄÜÓÃÓÚ¿ÌÊ´²£Á§£¬R2ÓëNaOHÈÜÒº·´Ó¦µÄ²úÎïÖ®Ò»ÊÇOR2£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ______________________________________________________¡£

 (1)CaCl2 

(2)

(3)Si3N4

(4)2F2+2OH-2F-+OF2+H2O

½âÎö£º±¾ÌâÊÇ¿¼²éÎïÖʽṹÓëÔªËØÖÜÆÚÂÉ֪ʶµÄÌâÄ¿¡£

£¨1£©XY2ÖУ¬XΪ+2¼Û¡¢YΪ-1¼Û£¬ÓÖÑôÀë×ÓÓëÒõÀë×Óµç×Ó²ã½á¹¹Ïàͬ£¬ÇÒ1 mol XY2ÓÐ54 molµç×Ó¿ÉÍÆÖªXΪCa£¬YΪCl¡£ÈÚÑ©¼Á»¯Ñ§Ê½ÎªCaCl2¡£

CaH2µÄµç×ÓʽΪ¡£

£¨2£©ÔªËØD¡¢E×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ2±¶£¬·ûºÏÌõ¼þµÄÔªËØÓÐHe¡¢C¡¢S£¬ÆäÖÐSÓëClÏàÁÚ£¬DΪSÔªËØ£¬S2-½á¹¹Ê¾Òâͼ¡£DÓëEÄÜÐγÉÒ»ÖַǼ«ÐÔ·Ö×Ó£¬¿É֪ΪCS2£¬Æä½á¹¹Ê½ÎªS=C=S¡£Ñõ×åÔªËØµÄÇ⻯ÎïÖÐH2S·Ðµã×îµÍ¡£

£¨3£©WÓëYͬÖÜÆÚ£¬Æäµ¥ÖÊΪԭ×Ó¾§Ì壬¿ÉÖªWΪSiÔªËØ£»ÔªËØZµ¥ÖÊ·Ö×ÓZ2ÖÐÓÐ3¸ö¹²¼Û¼ü£¬¿ÉÖªZΪNÔªËØ¡£SiÓëNÐγɵÄÐÂÐͲÄÁÏΪSi3N4¡£

£¨4£©ÔªËØRÓëYͬÖ÷×壬ÆäÇ⻯ÎïÄÜÓÃÓÚ¿ÌÊ´²£Á§£¬¿ÉÖª£¬RΪFÔªËØ£¬F2ÓëNaOH·´Ó¦·½³ÌʽΪ2F2+2NaOHOF2+2NaF+H2O£¬Àë×Ó·½³ÌʽΪ2F2+2OH-OF2+2F-+H2O¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚ2008Äê³õÎÒ¹úÄÏ·½ÔâÓöµÄ±ùÑ©ÔÖº¦ÖУ¬Ê¹ÓÃÁËÒ»ÖÖÈÚÑ©¼Á£¬ÆäÖ÷Òª³É·ÖµÄ»¯Ñ§Ê½ÎªXY2£¬X¡¢Y¾ùΪÖÜÆÚ±íǰ20ºÅÔªËØ£¬ÆäÑôÀë×ÓºÍÒõÀë×ӵĵç×Ó²ã½á¹¹Ïàͬ£¬ÇÒ1molXY2º¬ÓÐ54molµç×Ó£®
£¨1£©¸ÃÈÚÑ©¼ÁµÄ»¯Ñ§Ê½ÊÇ
CaCl2
CaCl2
£»XµÄÇâÑõ»¯ÎïµÄµç×ÓʽÊÇ
£®
£¨2£©ÔªËØD¡¢EÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ2±¶£¬DÓëYÏàÁÚ£¬DÓëEÄÜÐγÉÒ»ÖֶԳƷÖ×Ó£¬¸Ã·Ö×ӵĽṹʽΪ
S=C=S
S=C=S
£®
£¨3£©ÔªËØWÓëYͬÖÜÆÚ£¬ÆäÑõ»¯Îï¿É×÷Ϊ̫ÑôÄܵç×Ó°åµÄ²ÄÁÏ£»ÔªËØZµÄµ¥ÖÊ·Ö×ÓZ2ÖÐÓÉ3¸ö¹²¼Û¼ü£» WÓëZÄÜÐγÉÒ»ÖÖÐÂÐÍÎÞ»ú·Ç½ðÊô²ÄÁÏ£¬Æä»¯Ñ§Ê½ÊÇ
Si3N4
Si3N4
£®
£¨4£©WµÄÑõ»¯ÎïÊDz£Á§µÄÖ÷Òª³É·Ö£¬Ò×ÓëÉռӦ£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
SiO2+2NaOH=Na2SiO3+H2O
SiO2+2NaOH=Na2SiO3+H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2008?ÖØÇ죩ÔÚ2008Äê³õÎÒ¹úÄÏ·½ÔâÓöµÄ±ùÑ©ÔÖº¦ÖУ¬Ê¹ÓÃÁËÒ»ÖÖÈÚÑ©¼Á£¬ÆäÖ÷Òª³É·ÖµÄ»¯Ñ§Ê½ÎªXY2£¬X¡¢Y¾ùΪÖÜÆÚ±íǰ20ºÅÔªËØ£¬ÆäÑôÀë×ÓºÍÒõÀë×ӵĵç×Ó²ã½á¹¹Ïàͬ£¬ÇÒ1molXY2º¬ÓÐ54molµç×Ó£®
£¨1£©¸ÃÈÚÑ©¼ÁµÄ»¯Ñ§Ê½ÊÇ
CaCl2
CaCl2
£»XÓëÇâÔªËØÐγɵϝºÏÎïµÄµç×ÓʽÊÇ
£®
£¨2£©ÔªËØD¡¢EÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ2±¶£¬DÓëYÏàÁÚ£¬ÔòDµÄÀë×ӽṹʾÒâͼÊÇ
£»DÓëEÄÜÐγÉÒ»ÖַǼ«ÐÔ·Ö×Ó£¬¸Ã·Ö×ӵĽṹʽΪ
S=C=S
S=C=S
£»DËùÔÚ×åÔªËØµÄÇ⻯ÎïÖУ¬·Ðµã×îµÍµÄÊÇ
H2S
H2S
£®
£¨3£©ÔªËØWÓëYͬÖÜÆÚ£¬Æäµ¥ÖÊÊÇÔ­×Ó¾§Ìå£»ÔªËØZµÄµ¥ÖÊ·Ö×ÓZ2ÖÐÓÐ3¸ö¹²¼Û½¡£»WÓëZÄÜÐγÉÒ»ÖÖÐÂÐÍÎÞ»ú·Ç½ðÊô²ÄÁÏ£¬Æä»¯Ñ§Ê½ÊÇ
Si3N4
Si3N4
£®
£¨4£©ÔªËØRÓëYͬÖ÷×壬ÆäÇ⻯ÎïÄÜÓÃÓÚ¿ÌÊ´²£Á§£¬R2ÓëNaOHÈÜÒº·´Ó¦µÄ²úÎïÖ®Ò»ÊÇOR2£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ
2F2+2OH-=2F-+OF2+H2O
2F2+2OH-=2F-+OF2+H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?ÉϺ£Ä£Ä⣩ÔÚ2008Äê³õÎÒ¹úÄÏ·½ÔøÔâÓöµÄ±ùÑ©ÔÖº¦ÖУ¬Ê¹ÓÃÁËÒ»ÖÖÈÚÑ©¼Á£¬ÆäÖ÷Òª³É·ÖµÄ»¯Ñ§Ê½ÎªXY2£¬X¡¢Y¾ùΪÖÜÆÚ±íǰ20ºÅÔªËØ£¬ÆäÑôÀë×ÓºÍÒõÀë×ӵĵç×Ó²ã½á¹¹Ïàͬ£¬ÇÒ1mol XY2º¬ÓÐ54molµç×Ó£®
£¨1£©ÓÃÔªËØ·ûºÅ½«X¡¢YÁ½ÔªËØÌîдÔÚÏÂÃæÔªËØÖÜÆÚ±íÖÐËù¶ÔÓ¦µÄλÖã®

£¨2£©XÔªËØÔ­×ÓºËÍâ¹²ÓÐ
6
6
ÖÖ²»Í¬ÄÜÁ¿µÄµç×Ó£®YÓëÇâÔªËØÐγɵϝºÏÎïµÄµç×ÓʽÊÇ
£®
£¨3£©ÔªËØD¡¢EÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ2±¶£¬DÓëYÏàÁÚ£¬Ð´³öDÀë×ӵĺËÍâµç×ÓÅŲ¼Ê½
1S22S22P63S23P6
1S22S22P63S23P6
£»DÓëEÄÜÐγÉÒ»ÖÖ»¯Ñ§Ê½ÎªED2µÄ·Ö×Ó£¬¸Ã·Ö×ÓÊÇ
·Ç¼«ÐÔ
·Ç¼«ÐÔ
·Ö×Ó£¨Ìî¡°¼«ÐÔ¡±¡°·Ç¼«ÐÔ¡±£©£¬½á¹¹Ê½Îª
S=C=S
S=C=S
£»DËùÔÚ×åÔªËØµÄÇ⻯ÎïÖУ¬·Ðµã×îµÍµÄÊÇ
H2S
H2S
 £¨Ð´ÔªËØÇ⻯ÎïµÄ»¯Ñ§Ê½£©£®Ð´³ö¸ÃÇ⻯ÎïÓë¸ÃÔªËØµÄijÖÖÑõ»¯Îï·´Ó¦µÄ»¯Ñ§·½³Ìʽ
2H2S+SO2¨T3S+2H2O
2H2S+SO2¨T3S+2H2O
£®
£¨4£©D¡¢YÁ½ÔªËØÄÄÖַǽðÊôÐÔ½ÏÇ¿£¿
Y
Y
д³öÖ¤Ã÷ÕâÒ»½áÂÛµÄÒ»¸öʵÑéÊÂʵ£º
ÆøÌ¬Ç⻯ÎïÎȶ¨ÐÔ£¨ºÏÀí¼´¿É£©
ÆøÌ¬Ç⻯ÎïÎȶ¨ÐÔ£¨ºÏÀí¼´¿É£©
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚ2008Äê³õÎÒ¹úÄÏ·½ÔâÓöµÄ±ùÑ©ÔÖº¦ÖУ¬Ê¹ÓÃÁËÒ»ÖÖÈÚÑ©¼Á£¬ÆäÖ÷Òª³É·ÖµÄ»¯Ñ§Ê½ÎªXY£¬X¡¢Y¾ùÎªÔªËØÖÜÆÚ±íǰ20ºÅÔªËØ£¬ÆäÑôÀë×ÓºÍÒõÀë×Ó·Ö±ðÊÇ10µç×ÓºÍ18µç×ӵĵ¥ºËÁ£×Ó£¬ÇÒ1molXYº¬ÓÐ28molµç×Ó¡£

¢Å¸ÃÈÚÑ©¼ÁµÄ»¯Ñ§Ê½ÊÇ__  ____£»XÓëÇâÔªËØÐγɵϝºÏÎïµÄµç×ÓʽÊÇ____________¡£

¢ÆÔªËØD¡¢EÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ2±¶£¬DÓëYÏàÁÚ£¬ÔòDËùÔÚͬÖ÷×åÔªËØµÄÇ⻯ÎïÖУ¬·Ðµã×îµÍµÄÊÇ________£¨»¯Ñ§Ê½£©£»EµÄÔ­×ӽṹʾÒâͼÊÇ_____ _____¡£

¢ÇÔªËØRÓëYͬÖ÷×壬ÆäÇ⻯ÎïÄÜÓÃÓÚ¿ÌÊ´²£Á§£¬R2ÓëH2OÈÜÒº·´Ó¦µÄ²úÎïÖ®Ò»ÊÇO2£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(8·Ö)ÔÚ2008Äê³õÎÒ¹úÄÏ·½ÔâÓöµÄ±ùÑ©ÔÖº¦ÖУ¬Ê¹ÓÃÁËÒ»ÖÖÈÚÑ©¼Á£¬ÆäÖ÷Òª³É·ÖµÄ»¯Ñ§Ê½ÎªXY2£¬X¡¢Y¾ùΪÖÜÆÚ±íǰ20ºÅÔªËØ£¬ÆäÑôÀë×ÓºÍÒõÀë×ӵĵç×Ó²ã½á¹¹Ïàͬ£¬ÇÒ1mol XY2º¬ÓÐ54 molµç×Ó¡£

(1)¸ÃÈÚÑ©¼ÁµÄ»¯Ñ§Ê½ÊÇ__________£»XÓëÇâÔªËØÐγɵϝºÏÎïµÄµç×ÓʽÊÇ__________¡£

(2)ÔªËØD¡¢EÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ2±¶£¬DÓëYÏàÁÚ£¬ÔòDµÄÀë×ӽṹʾÒâͼÊÇ__________£»DÓëEÄÜÐγÉÒ»ÖַǼ«ÐÔ·Ö×Ó£¬¸Ã·Ö×ӵĽṹʽΪ__________£»DËùÔÚ×åÔªËØµÄÇ⻯ÎïÖУ¬·Ðµã×îµÍµÄÊÇ__________¡£

(3)ÔªËØWÓëYͬÖÜÆÚ£¬Æäµ¥ÖÊÊÇÔ­×Ó¾§Ìå£»ÔªËØZµÄµ¥ÖÊ·Ö×ÓZ2ÖÐÓÐ3¸ö¹²¼Û½¡£»WÓëZÄÜÐγÉÒ»ÖÖÐÂÐÍÎÞ»ú·Ç½ðÊô²ÄÁÏ£¬Æä»¯Ñ§Ê½ÊÇ__________¡£

(4)ÔªËØRÓëYͬÖ÷×壬ÆäÇ⻯ÎïÄÜÓÃÓÚ¿ÌÊ´²£Á§£¬R2ÓëNaOHÈÜÒº·´Ó¦µÄ²úÎïÖ®Ò»ÊÇOR2£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ

________________________________________________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸