¹¤ÒµÉÏÒÔÁòÌú¿óΪԭÁÏÖÆÁòËáËù²úÉúµÄÎ²Æø³ýÁ˺¬ÓÐN2¡¢O2Í⣬»¹º¬ÓÐSO2¡¢Î¢Á¿µÄSO3ºÍËáÎí¡£ÎªÁ˱£»¤»·¾³£¬Í¬Ê±Ìá¸ßÁòËṤҵµÄ×ۺϾ­¼ÃÐ§Òæ£¬Ó¦¾¡¿ÉÄܽ«Î²ÆøÖеÄSO2ת»¯ÎªÓÐÓõĸ±²úÆ·¡£Çë°´ÒªÇ󻨴ðÏÂÁÐÎÊÌ⣺

£¨1£©½«Î²ÆøÍ¨È백ˮÖУ¬ÄÜ·¢Éú¶à¸ö·´Ó¦£¬Ð´³öÆäÖпÉÄÜ·¢ÉúµÄÁ½¸öÑõ»¯»¹Ô­·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                ¡¢                            ¡£

£¨2£©ÔÚÎ²ÆøÓ백ˮ·´Ó¦ËùµÃµ½µÄ¸ßŨ¶ÈÈÜÒºÖУ¬°´Ò»¶¨±ÈÀý¼ÓÈ백ˮ»ò̼ËáÇâï§£¬´ËʱÈÜÒºµÄζȻá×ÔÐнµµÍ£¬²¢Îö³ö¾§Ìå¡£¢Ùµ¼ÖÂÈÜҺζȽµµÍµÄÔ­Òò¿ÉÄÜÊÇ              ;¢ÚÎö³öµÄ¾§Ìå¿ÉÓÃÓÚÔìÖ½¹¤Òµ£¬Ò²¿ÉÓÃÓÚÕÕÏàÓÃÏÔÓ°ÒºµÄÉú²ú¡£ÒÑÖª¸Ã½á¾§Ë®ºÏÎïµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª134£¬ÔòÆä»¯Ñ§Ê½Îª            £»¢ÛÉú²úÖÐÍùÍùÐèÒªÏòÈÜÒºÖмÓÈëÊÊÁ¿µÄ¶Ô±½¶þ·Ó»ò¶Ô±½¶þ°·µÈÎïÖÊ£¬ÆäÄ¿µÄÊÇ                    ¡£

£¨3£©ÄÜÓÃÓڲⶨÁòËáÎ²ÆøÖÐSO2º¬Á¿µÄÊÇ                  ¡££¨Ìî×Öĸ£©

A.NaOHÈÜÒº¡¢·Ó̪ÊÔÒº            B.KMnO4ÈÜÒº¡¢Ï¡H2SO4

C.µâË®¡¢µí·ÛÈÜÒº                D.°±Ë®¡¢·Ó̪ÊÔÒº


¡¾´ð°¸¡¿

£¨1£©2H2SO3+O2==2H2SO4    2(NH4)2SO3+O2==2(NH4)2SO4

2NH4HSO3+O2==2NH4HSO4(ÈÎÌîÁ½¸ö)

£¨2£©¢Ù·´Ó¦ÎüÈÈ        ¢Ú£¨NH4£©2SO3¡¤H2O             ¢Û·ÀÖ¹ÑÇÁòËáï§±»Ñõ»¯

£¨3£©BC

¡¾½âÎö¡¿±¾ÌâÖ÷Òª¿¼²é»¯Ñ§Óë»·¾³¡¢»¯Ñ§Ó빤ҵÉú²ú¼°»·¾³ÎÛȾµÄ¹ØÏµ¡£(1)½«SO2ͨÈëµ½°±Ë®ÖÐÊ×ÏÈSO2+H2OH2SO3£¬È»ºóH2SO3Ó백ˮ×÷ÓÿÉÉú³É(NH4)2SO3Ò²¿ÉÉú³ÉNH4HSO3£¬µ±ËüÃÇÓë¿ÕÆøÖеÄO2½Ó´¥Ê±·¢Éú·´Ó¦2H2SO3+O2===2H2SO4£»2(NH4)2SO3+O2===2(NH4)SO4, 2NH4HSO3+O2===2NH4HSO4µÈ¡£(2)ÔÚ(1)ÖÐËùµÃÈÜÒºÖмÓÈëNH3¡¤H2O»òNH4HCO3ÈÜҺζȽµµÍ²¢Îö³ö¾§Ì壬˵Ã÷·´Ó¦¹ý³ÌÎüÊÕÁËÈÈÁ¿£¬Îö³ö¾§Ìå¿ÉÓÃÓÚÔìÖ½¹¤Òµ×÷Ư°×¼Á£¬ÓÖ¿ÉÓÃÓÚÉú²úÏÔÓ°ÒºNa2S2O3£¬ËµÃ÷¸Ã¾§ÌåΪ(NH4)2SO3µÄ½á¾§Ì壬¾­¼ÆËãÖª¸Ã¾§ÌåµÄ»¯Ñ§Ê½Îª(NH4)2SO3¡¤H2O£¬(NH4)2SO3¾ßÓл¹Ô­ÐÔÒ×±»Ñõ»¯£¬¹Ê¼ÓÈëËù¸øÎïÖʵÄÄ¿µÄÊÇ·ÀÖ¹(NH4)2SO3±»Ñõ»¯¡£(3)Òª²â¶¨SO2µÄº¬Á¿£¬¸ÃÊÔ¼ÁÐèÓëSO2·´Ó¦£¬ÇÒÓÐÄÜÃ÷ÏÔָʾ·´Ó¦µÄÖյ㣬·ÖÎöÖª´ð°¸ÎªB¡¢C¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Á×µ¥Öʼ°Æä»¯ºÏÎïÓй㷺ӦÓá£

£¨1£©ÓÉÁ×»Òʯ£ÛÖ÷Òª³É·ÖCa5£¨PO4£©3F£ÝÔÚ¸ßÎÂÏÂÖÆ±¸»ÆÁ×£¨P4£©µÄÈÈ»¯Ñ§·½³ÌʽΪ£º4Ca5£¨PO4£©3F£¨s£©+21SiO2£¨s£©+30C£¨s£©3P4£¨g£©+20CaSiO3£¨s£©+30CO£¨g£©+SiF4£¨g£© ¦¤H

¢ÙÉÏÊö·´Ó¦ÖУ¬¸±²úÎï¿óÔü¿ÉÓÃÀ´___________________________________¡£

¢ÚÒÑÖªÏàͬÌõ¼þÏ£º

4Ca5£¨PO4£©3F£¨s£©+3SiO2£¨s£©====6Ca3£¨PO4£©2£¨s£©+2CaSiO3£¨s£©+SiF4£¨g£© ¦¤H1

2Ca3£¨PO4£©2£¨s£©+10C£¨s£©====P4£¨g£©+6CaO£¨s£©+10CO£¨g£© ¦¤H2

SiO2£¨s£©+CaO£¨s£©====CaSiO3£¨s£© ¦¤H3

Óæ¤H1¡¢¦¤H2ºÍ¦¤H3±íʾ¦¤H£¬¦¤H£½_____________________________¡£

£¨2£©Èý¾ÛÁ×Ëá¿ÉÊÓΪÈý¸öÁ×Ëá·Ö×Ó£¨Á×Ëá½á¹¹Ê½¼ûÏÂͼ£©Ö®¼äÍÑÈ¥Á½¸öË®·Ö×ӵIJúÎÆä½á¹¹Ê½Îª________________________¡£Èý¾ÛÁ×ËáÄÆ£¨Ë׳ơ°ÎåÄÆ¡±£©Êdz£ÓõÄË®´¦Àí¼Á£¬Æä»¯Ñ§Ê½Îª___________________________¡£

£¨3£©´ÎÁ×ËáÄÆ£¨NaH2PO2£©¿ÉÓÃÓÚ»¯Ñ§¶ÆÄø¡£

¢ÙNaH2PO2ÖÐPÔªËØµÄ»¯ºÏ¼ÛΪ________________________¡£

¢Ú»¯Ñ§¶ÆÄøµÄÈÜÒºÖк¬ÓÐNi2+ºÍ£¬ÔÚËáÐÔµÈÌõ¼þÏ·¢ÉúÏÂÊö·´Ó¦£º

(a)__________Ni2++__________+____________________Ni+________+_______

£¨b£©6+2H+====2P+4+3H2¡ü

ÇëÔÚ´ðÌ⿨ÉÏд³ö²¢Å䯽·´Ó¦Ê½£¨a£©¡£

¢ÛÀûÓâÚÖз´Ó¦¿ÉÔÚËÜÁ϶Ƽþ±íÃæ³Á»ýÄøÁ׺Ͻ𣬴Ӷø´ïµ½»¯Ñ§¶ÆÄøµÄÄ¿µÄ£¬ÕâÊÇÒ»ÖÖ³£¼ûµÄ»¯Ñ§¶Æ¡£Çë´ÓÒÔÏ·½Ãæ±È½Ï»¯Ñ§¶ÆÓëµç¶Æ¡£

·½·¨ÉϵIJ»Í¬µã£º_______________£»Ô­ÀíÉϵÄÏàͬµã£º_______________£»»¯Ñ§¶ÆµÄÓŵ㣺_______________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


X¡¢Y¡¢Z¡¢WΪº¬ÓÐÏàͬµç×ÓÊýµÄ·Ö×Ó»òÀë×Ó£¬¾ùÓÉÔ­×ÓÐòÊýСÓÚ10µÄÔªËØ×é³É£¬XÓÐ5¸öÔ­×Ӻˡ£Í¨³£×´¿öÏ£¬WΪÎÞɫҺÌå¡£

ÒÑÖª:X+YZ+W      

(1)YµÄµç×ÓʽÊÇ_________________________¡£

(2)Һ̬ZºÍWµÄµçÀëÏàËÆ£¬¶¼¿ÉµçÀë³öµç×ÓÊýÏàͬµÄÁ½ÖÖÀë×Ó£¬ÒºÌ¬ZµÄµçÀë·½³ÌʽÊÇ_________________________________¡£

(3)ÓÃͼʾװÖÃÖÆ±¸NO²¢ÑéÖ¤Æä»¹Ô­ÐÔ¡£ÓÐÏÂÁÐÖ÷Òª²Ù×÷£º

a.Ïò¹ã¿ÚÆ¿ÄÚ×¢Èë×ãÁ¿ÈÈNaOHÈÜÒº£¬½«Ê¢ÓÐͭƬµÄСÉÕ±­·ÅÈëÆ¿ÖС£

b.ֹˮ¼Ð£¬µãȼºìÁ×£¬ÉìÈëÆ¿ÖУ¬ÈûºÃ½ºÈû¡£

c.´ýºìÁ׳ä·ÖȼÉÕ£¬Ò»¶Îʱ¼äºó´ò¿ª·ÖҺ©¶·ÐýÈû£¬ÏòÉÕ±­ÖеÎÈëÉÙÁ¿Ï¡ÏõËá¡£

¢Ù²½Öècºó»¹È±ÉÙµÄÒ»²½Ö÷Òª²Ù×÷ÊÇ_______________________________________¡£

¢ÚºìÁ׳ä·ÖȼÉյIJúÎïÓëNaOHÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ  ______________________________________¡£

¢Û²½ÖècµÎÈëÏ¡ÏõËáºóÉÕ±­ÖеÄÏÖÏóÊÇ______________________________________

 ____________________________________________________________________¡£

·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ____________________________________________________¡£

(4)Ò»¶¨Î¶ÈÏ£¬½«1 mol N2O4ÖÃÓÚÃܱÕÈÝÆ÷ÖУ¬±£³Öѹǿ²»±ä£¬Éý¸ßζÈÖÁT1µÄ¹ý³ÌÖУ¬ÆøÌåÓÉÎÞÉ«Öð½¥±äΪºìרɫ¡£Î¶ÈÓÉT1¼ÌÐøÉý¸ßµ½T2µÄ¹ý³ÌÖУ¬ÆøÌåÖð½¥±äΪÎÞÉ«¡£Èô±£³ÖT2£¬Ôö´óѹǿ£¬ÆøÌåÖð½¥±äΪºìרɫ¡£ÆøÌåµÄÎïÖʵÄÁ¿nËæÎ¶ÈT±ä»¯µÄ¹ØÏµÈçͼËùʾ¡£

¢ÙζÈÔÚT1¡«T2Ö®¼ä£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_________________________¡£

¢ÚζÈÔÚT2¡«T3Ö®¼ä£¬ÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ£¨±£Áô1λСÊý£©______________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


20ÊÀ¼Í¿ÆÑ§·ÉËÙ·¢Õ¹£¬µ«ÈÔÓÐÐí¶àÎÊÌâÉÐδ½â¾ö¡£Óдý»¯Ñ§¿ÆÑ§½â¾öµÄÄÑÌâÊÇ(   )

A.¼×Íé·Ö×ӽṹµÄÈ·¶¨                     B.¸ß¯Á¶Ìú

C.³£Î³£Ñ¹ºÏ³É°±                           D.¿É³äµç¸Éµç³ØµÄÖÆ×÷

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


AÌâÊʺÏʹÓöþÆÚ¿Î¸Äн̲ĵĿ¼Éú½â´ð£¬BÌâÊʺÏʹÓÃÒ»ÆÚ¿Î¸Ä½Ì²ÄµÄ¿¼Éú½â´ð

26.£¨A£©ÊµÑéÊÒÄ£ÄâºÏ³É°±ºÍ°±´ß»¯Ñõ»¯µÄÁ÷³ÌÈçÏ£º

ÒÑ֪ʵÑéÊÒ¿ÉÓñ¥ºÍÑÇÏõËáÄÆ£¨NaNO2£©ÈÜÒºÓë±¥ºÍÂÈ»¯ï§ÈÜÒº¾­¼ÓÈȺó·´Ó¦ÖÆÈ¡µªÆø¡£

£¨1£©´ÓÏÂͼÖÐÑ¡ÔñÖÆÈ¡ÆøÌåµÄºÏÊÊ×°Öãº

µªÆø         ¡¢ÇâÆø         

£¨2£©µªÆøºÍÇâÆøÍ¨¹ý¼××°Ö㬼××°ÖõÄ×÷ÓóýÁ˽«ÆøÌå»ìºÏÍ⣬»¹ÓР                  ¡¢                   

£¨3£©°±ºÏ³ÉÆ÷³öÀ´¾­ÀäÈ´µÄÆøÌåÁ¬ÐøÍ¨ÈËÒÒ×°ÖõÄË®ÖÐÎüÊÕ°±£¬         £¨¡°»á¡±»ò¡°²»»á¡±£©·¢Éúµ¹Îü£¬Ô­ÒòÊÇ£º                    ¡£

£¨4£©ÓÃÒÒ×°ÖÃÎüÊÕÒ»¶Îʱ¼ä°±ºó£¬ÔÙͨÈë¿ÕÆø£¬Í¬Ê±½«¾­¼ÓÈȵIJ¬Ë¿²åÈëÒÒ×°ÖõÄ×¶ÐÎÆ¿ÄÚ£¬ÄÜʹ²¬Ë¿±£³ÖºìÈȵÄÔ­ÒòÊÇ£º                                     £¬×¶ÐÎÆ¿Öл¹¿É¹Û²ìµ½µÄÏÖÏóÊÇ£º                                             ¡£

£¨5£©Ð´³öÒÒ×°ÖÃÖа±Ñõ»¯µÄ»¯Ñ§·½³Ìʽ£º                            

£¨6£©·´Ó¦½áÊøºó×¶ÐÎÆ¿ÄÚµÄÈÜÒºÖк¬ÓÐH+¡¢OH£­¡¢        ¡¢       Àë×Ó¡£

£¨B£©Ä³¿ÎÍâÑо¿Ð¡×飬Óú¬Óн϶àÔÓÖʵÄÍ­·Û£¬Í¨¹ý²»Í¬µÄ»¯Ñ§·´Ó¦ÖÆÈ¡µ¨·¯¡£ÆäÉè¼ÆµÄʵÑé¹ý³ÌΪ£º

£¨1£©Í­Öк¬ÓдóÁ¿µÄÓлúÎ¿É²ÉÓÃׯÉյķ½·¨³ýÈ¥ÓлúÎï£¬×ÆÉÕʱ½«´ÉÛáÛöÖÃÓÚ
       
ÉÏ£¨ÓÃÒÔÏÂËù¸øÒÇÆ÷µÄ±àºÅÌîÈ룬ÏÂͬ£©£¬È¡ÓÃÛáÛöӦʹÓà       £¬×ÆÉÕºóµÄÛáÛöÓ¦·ÅÔÚ          ÉÏ£¬²»ÄÜÖ±½Ó·ÅÔÚ×ÀÃæÉÏ¡£

ʵÑéËùÓÃÒÇÆ÷£ºa  Õô·¢Ãó    b  ʯÃÞÍø    c  ÄàÈý½Ç    d  ±íÃæÃó    e  ÛáÛöǯ    f  ÊԹܼÐ

£¨2£©ÔÓÍ­¾­×ÆÉÕºóµÃµ½µÄ²úÎïÊÇÑõ»¯Í­¼°ÉÙÁ¿Í­µÄ»ìºÏÎÓÃÒÔÖÆÈ¡µ¨·¯¡£×ÆÉÕºóº¬ÓÐÉÙÁ¿Í­µÄ¿ÉÄÜÔ­ÒòÊÇ           

a  ׯÉÕ¹ý³ÌÖв¿·ÖÑõ»¯Í­±»»¹Ô­      b  ׯÉÕ²»³ä·Öͭδ±»ÍêÈ«Ñõ»¯

c  Ñõ»¯Í­ÔÚ¼ÓÈȹý³ÌÖзֽâÉú³ÉÍ­    d  ¸ÃÌõ¼þÏÂÍ­ÎÞ·¨±»ÑõÆøÑõ»¯

£¨3£©Í¨¹ý;¾¶¢òʵÏÖÓôÖÖÆÑõ»¯Í­ÖÆÈ¡µ¨·¯£¬±ØÐë½øÐеÄʵÑé²Ù×÷²½Ö裺ËáÈÜ¡¢¼ÓÈÈͨÑõÆø¡¢¹ýÂË¡¢        ¡¢ÀäÈ´½á¾§¡¢         ¡¢×ÔÈ»¸ÉÔï

£¨4£©ÓÉ´ÖÖÆÑõ»¯Í­Í¨¹ýÁ½ÖÖ;¾¶ÖÆÈ¡µ¨·¯£¬Óë;¾¶¢ñÏà±È£¬Í¾¾¶¢òÓÐÃ÷ÏÔµÄÁ½¸öÓŵãÊÇ£º                             ¡¢                            

£¨5£©ÔڲⶨËùµÃµ¨·¯£¨CuSO4¡¤xH2O£©ÖнᾧˮxÖµµÄʵÑé¹ý³ÌÖУº³ÆÁ¿²Ù×÷ÖÁÉÙ½øÐР    ´Î

£¨6£©Èô²â¶¨½á¹ûxֵƫ¸ß£¬¿ÉÄܵÄÔ­ÒòÊÇ                         

a  ¼ÓÈÈζȹý¸ß                b  µ¨·¯¾§ÌåµÄ¿ÅÁ£½Ï´ó

c  ¼ÓÈȺó·ÅÔÚ¿ÕÆøÖÐÀäÈ´    d  µ¨·¯¾§Ì岿·Ö·ç»¯

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÖÓÈéʯºÍʯËñµÄÖ÷Òª³É·ÖÊÇ̼Ëá¸Æ£¬ÆäÐγɹý³ÌÈçÏÂͼËùʾ¡£Ëæ×ÅÂÃÓÎÈËÊýµÄÔö¼Ó£¬³±ÊªÈܶ´ÖеÄÖÓÈéʯºÍʯËñÊܵ½¶þÑõ»¯Ì¼ÇÖÊ´£¬Æä»¯Ñ§·½³ÌʽΪ£º_______________________________¡£

51.ijѧÉúÌá³öÒ»¸öÐÞ¸´Èܶ´µ×²¿ÊÜËðʯËñµÄÑо¿·½°¸£¬ÓÉÒÔÏÂÎå²½×é³É£¬ÕýÈ·µÄʵÑé²½ÖèÒÀ´ÎÊÇ_______¡£

¢Ù½«Ê¢ÓмîÈÜÒºµÄÈÝÆ÷ÖÃÓÚʯËñµÄÉϲ¿

¢ÚÅäÖÆÒ»¶¨Å¨¶ÈµÄ¼îÈÜÒº

¢ÛÑ¡ÔñºÏÊʵļî

¢Üµ÷½Ú¼îÈÜҺϵεÄËÙ¶È

¢Ý¹Û²ìʯËñ±íÃæ¸´Ô­Çé¿ö

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


    ¹¤ÒµÉÏÉú²úÁòËáʱ£¬ÀûÓô߻¯Ñõ»¯·´Ó¦½«SO2 ת»¯ÎªSO3ÊÇÒ»¸ö¹Ø¼ü²½Ö衣ѹǿ¼°Î¶ȶÔSO2ת»¯ÂʵÄÓ°ÏìÈçÏÂ±í£¨Ô­ÁÏÆø¸÷³É·ÖµÄÌå»ý·ÖÊýΪ£ºSO7% £¬O2  11%£¬N2   82%£©£º

£¨1£©ÒÑÖªSO2µÄÑõ»¯ÊÇ·ÅÈÈ·´Ó¦£¬ÈçºÎÀûÓñíÖÐÊý¾ÝÍÆ¶Ï´Ë½áÂÛ£¿

                                                       £»

£¨2£©ÔÚ´ó400¡«500¡æÊ±£¬SO2µÄ´ß»¯Ñõ»¯²ÉÓó£Ñ¹¶ø²»ÊǸßѹ£¬Ö÷ÒªÔ­ÒòÊÇ£º

                                                       £»

£¨3£©Ñ¡ÔñÊÊÒ˵Ĵ߻¯¼Á£¬ÊÇ·ñ¿ÉÒÔÌá¸ßSO2µÄת»¯ÂÊ£¿     £¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©£¬ÊÇ·ñ¿ÉÒÔÔö´ó¸Ã·´Ó¦Ëù·Å³öµÄÈÈÁ¿£¿     £¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©£»

£¨4£©ÎªÌá¸ßSO3ÎüÊÕÂÊ£¬Êµ¼ÊÉú²úÖÐÓà     ÎüÊÕSO3£»

£¨5£©ÒÑÖª£º2SO2(g)+O2(g)£½2SO3(g)£»¡÷H£½£­196.6kJ¡¤mol£­1£¬¼ÆËãÿÉú²ú1Íò¶Ö98%ÁòËáËùÐèÒªµÄSO3ÖÊÁ¿ºÍÓÉSO2Éú²úÕâЩSO3Ëù·Å³öµÄÈÈÁ¿¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÒÑÖªX¡¢Y¡¢Z¶¼ÊǶÌÖÜÆÚµÄÔªËØ£¬ËüÃǵÄÔ­×ÓÐòÊýÒÀ´ÎµÝÔö¡£XÔ­×ӵĵç×Ó²ãÊýÓëËüµÄºËÍâµç×Ó×ÜÊýÏàͬ£¬¶øZÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµÄÈý±¶£¬YºÍZ¿ÉÒÔÐγÉÁ½ÖÖÒÔÉÏÆøÌ¬»¯ºÏÎÔò

£¨1£©XÊÇ          £¬YÊÇ          £¬ZÊÇ          ¡£

£¨2£©ÓÉYºÍZ×é³É£¬ÇÒYºÍZµÄÖÊÁ¿±ÈΪ7£º20µÄ»¯ºÏÎïµÄ»¯Ñ§Ê½£¨·Ö×Óʽ£©ÊÇ         ¡£

£¨3£©ÓÉX¡¢Y¡¢ZÖеÄÁ½ÖÖÔªËØ×é³É£¬ÇÒÓëX2Z·Ö×Ó¾ßÓÐÏàͬµç×ÓÊýµÄÁ½ÖÖÀë×ÓÊÇ       ºÍ        ¡£

£¨4£©X¡¢Y¡¢Z¿ÉÒÔÐγÉÒ»ÖÖÑΣ¬´ËÑÎÖÐX¡¢Y¡¢ZÔªËØµÄÔ­×ӵĸöÊý±ÈΪ4£º2£º3£¬¸ÃÑεĻ¯Ñ§Ê½£¨·Ö×Óʽ£©ÊÇ                         ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÒÑÖªµ¥Î»Ìå»ýµÄÏ¡ÈÜÒºÖУ¬·Ç»Ó·¢ÐÔÈÜÖʵķÖ×Ó»òÀë×ÓÊýÔ½¶à£¬¸ÃÈÜÒºµÄ·Ðµã¾ÍÔ½¸ß£®ÔòÏÂÁÐÈÜÒº·Ðµã×î¸ßµÄÊÇ(¡¡¡¡)

A£®0.01 mol/LµÄÕáÌÇÈÜÒº       B£®0.01 mol/LµÄCaCl2ÈÜÒº

C£®0.02 mol/LµÄNaClÈÜÒº      D£®0.02 mol/LµÄCH3COOHÈÜÒº

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸