£¨13·Ö£©Ï±íÊÇÖÜÆÚ±íÖеÄÒ»²¿·Ö£¬¸ù¾ÝA¡«IÔÚÖÜÆÚ±íÖеÄλÖã¬ÓÃÔªËØ·ûºÅ»ò»¯Ñ§Ê½»Ø´ðÏÂÁÐÎÊÌ⣺


 
¢ñA
¢òA
¢óA
¢ôA
¢õA
¢öA
¢÷A
 
0
1
A
 
2
 
 
 
D
E
K
G
 
3
B
 
C
J
F
 
H
I
£¨1£©±íÖÐÔªËØ£¬»¯Ñ§ÐÔÖÊ×î²»»îÆÃµÄÊÇ         ;   ¿ÉÓÃÓÚÖÆ°ëµ¼Ìå²ÄÁϵÄÔªËØÊÇ_______; ·Ç½ðÊôÐÔ×îÇ¿µÄÊÇ          ¡£
£¨2£©×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯Îï¼îÐÔ×îÇ¿µÄÊÇ         £¬¸ÃÎïÖʵÄË®ÈÜÒºÓëC×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯Îï·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                                               
H×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÊÇ                          
£¨3£©ÓÉA¡¢DÁ½ÖÖÔªËØ×é³ÉµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª28ÓлúÎïµÄ¿Õ¼ä¹¹ÐÍÊÇ            £¬
¸ÃÎïÖÊÓëäåË®·¢Éú¼Ó³É·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                                           ¡£

£¨12·Ö£© (1)  A r ;   Si  ;  F  ;  £¨¸÷1·Ö£©
(2)  NaOH £¨1·Ö£©    Al£¨OH£©3 + OH=  AlO2-+2H2O£¨3·Ö£©  HClO4
(3) Æ½ÃæÐÍ £¨2·Ö£©     CH2==CH+ Br2CH2Br¡ªCH2Br  £¨3·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ϱíÎªÔªËØÖÜÆÚ±íµÄÒ»²¿£¬Çë²ÎÕÕÔªËØ¢Ù-¢âÔÚ±íÖеÄλÖã¬Óû¯Ñ§ÓÃÓï»Ø´ðÏÂÁÐÎÊÌ⣺
×åÖÜÆÚ IA 0
1 ¢Ù ¢òA ¢óA ¢ôA ¢õA ¢öA ¢÷A
2 ¢Ú ¢Û ¢Ü ¢Ý
3 ¢Þ ¢ß ¢à ¢á  ¢â
£¨1£©Çëд³ö¢ÚµÄÔªËØ·ûºÅ
Be
Be

£¨2£©Çëд³ö¢ÛµÄ×î¸ß¼ÛÑõ»¯ÎïµÄµç×Óʽ
£®
£¨3£©±È½Ï¢Ý¡¢¢Þ¡¢¢àµÄÔ­×Ó°ë¾¶ÓÉ´óµ½Ð¡µÄ˳ÐòΪ£¨ÓÃÔªËØ·ûºÅ±íʾ£©
Na£¾Al£¾F
Na£¾Al£¾F

£¨4£©±È½Ï¢Û¡¢¢Ü¡¢¢áµÄ×î¸ß¼Ûº¬ÑõËáµÄËáÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ£¨ÓÃËáµÄ»¯Ñ§Ê½±íʾ£©
HNO3£¾H2CO3£¾H2SiO3£¨»òH4SiO4£©
HNO3£¾H2CO3£¾H2SiO3£¨»òH4SiO4£©
£®
£¨5£©Ð´³öÔÚÔªËØ¢Ù-¢âÖÐ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄ×îÇ¿¼îÓë×îÇ¿º¬ÑõËáÖ®¼äµÄ»¯Ñ§·´Ó¦·½³Ìʽ
NaOH+HClO4¨TNaClO4+H2O
NaOH+HClO4¨TNaClO4+H2O

£¨6£©¢ß¢àÁ½ÔªËØÏà±È½Ï£¬½ðÊôÐÔ½ÏÇ¿µÄÊÇ
þ
þ
£¨ÌîÃû³Æ£©£¬¿ÉÒÔÑéÖ¤¸Ã½áÂÛµÄʵÑéÊÇ
£¨b£©£¨c£©
£¨b£©£¨c£©
£¨Ìî±àºÅ£©£®
£¨a£©½«ÔÚ¿ÕÆøÖзÅÖÃÒѾõÄÕâÁ½ÖÖÔªËØµÄ¿é×´µ¥ÖÊ·Ö±ð·ÅÈëÈÈË®ÖÐ
£¨b£©½«ÐÎ×´¡¢´óСÏàͬµÄÕâÁ½ÖÖÔªËØµÄµ¥ÖÊ·Ö±ðºÍͬŨ¶ÈµÄÑÎËá·´Ó¦
£¨c£©½«ÐÎ×´¡¢´óСÏàͬÕâÁ½ÖÖÔªËØµÄµ¥ÖÊ·Ö±ðºÍÈÈË®×÷Ó㬲¢µÎÈë·Ó̪ÈÜÒº
£¨d£©±È½ÏÕâÁ½ÖÖÔªËØµÄÆøÌ¬Ç⻯ÎïµÄÎȶ¨ÐÔ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÕã½­Ê¡¼ÎÐËÊаËУÁª¿¼¸ßÒ»£¨Ï£©ÆÚÖл¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

ϱíÎªÔªËØÖÜÆÚ±íµÄÒ»²¿£¬Çë²ÎÕÕÔªËØ¢Ù-¢âÔÚ±íÖеÄλÖã¬Óû¯Ñ§ÓÃÓï»Ø´ðÏÂÁÐÎÊÌ⣺
×åÖÜÆÚIA
1¢Ù¢òA¢óA¢ôA¢õA¢öA¢÷A
2¢Ú¢Û¢Ü¢Ý
3¢Þ¢ß¢à¢á ¢â
£¨1£©Çëд³ö¢ÚµÄÔªËØ·ûºÅ   
£¨2£©Çëд³ö¢ÛµÄ×î¸ß¼ÛÑõ»¯ÎïµÄµç×Óʽ    £®
£¨3£©±È½Ï¢Ý¡¢¢Þ¡¢¢àµÄÔ­×Ó°ë¾¶ÓÉ´óµ½Ð¡µÄ˳ÐòΪ£¨ÓÃÔªËØ·ûºÅ±íʾ£©   
£¨4£©±È½Ï¢Û¡¢¢Ü¡¢¢áµÄ×î¸ß¼Ûº¬ÑõËáµÄËáÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ£¨ÓÃËáµÄ»¯Ñ§Ê½±íʾ£©    £®
£¨5£©Ð´³öÔÚÔªËØ¢Ù-¢âÖÐ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄ×îÇ¿¼îÓë×îÇ¿º¬ÑõËáÖ®¼äµÄ»¯Ñ§·´Ó¦·½³Ìʽ   
£¨6£©¢ß¢àÁ½ÔªËØÏà±È½Ï£¬½ðÊôÐÔ½ÏÇ¿µÄÊÇ    £¨ÌîÃû³Æ£©£¬¿ÉÒÔÑéÖ¤¸Ã½áÂÛµÄʵÑéÊÇ    £¨Ìî±àºÅ£©£®
£¨a£©½«ÔÚ¿ÕÆøÖзÅÖÃÒѾõÄÕâÁ½ÖÖÔªËØµÄ¿é×´µ¥ÖÊ·Ö±ð·ÅÈëÈÈË®ÖÐ
£¨b£©½«ÐÎ×´¡¢´óСÏàͬµÄÕâÁ½ÖÖÔªËØµÄµ¥ÖÊ·Ö±ðºÍͬŨ¶ÈµÄÑÎËá·´Ó¦
£¨c£©½«ÐÎ×´¡¢´óСÏàͬÕâÁ½ÖÖÔªËØµÄµ¥ÖÊ·Ö±ðºÍÈÈË®×÷Ó㬲¢µÎÈë·Ó̪ÈÜÒº
£¨d£©±È½ÏÕâÁ½ÖÖÔªËØµÄÆøÌ¬Ç⻯ÎïµÄÎȶ¨ÐÔ£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸