µªÑõ»¯ÎïÊÇ´óÆøÎÛȾÎïÖ®Ò»£¬Ïû³ýµªÑõ»¯ÎïµÄ·½·¨ÓжàÖÖ¡£

£¨1£©ÀûÓü×Íé´ß»¯»¹Ô­µªÑõ»¯Îï¡£ÒÑÖª£º

¢ÙCH4 (g)£«4NO2(g)£½4NO(g)£«CO2(g)£«2H2O(g£©?? ¡÷H £½£­574 kJ/mol

¢ÚCH4(g)£«4NO(g£©£½ 2N2(g)£«CO2(g)£«2H2O(g£©? ¡÷H £½£­1160 kJ/mol

ÔòCH4 ½«NO2 »¹Ô­ÎªN2 µÄÈÈ»¯Ñ§·½³ÌʽΪ£º??????????? ???????????? ¡£

£¨2£©ÀûÓÃNH3´ß»¯»¹Ô­µªÑõ»¯ÎSCR¼¼Êõ)¡£¸Ã¼¼ÊõÊÇÄ¿Ç°Ó¦ÓÃ×î¹ã·ºµÄÑÌÆøµªÑõ»¯ÎïÍѳý¼¼Êõ¡£ ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ: ΪÌá¸ßµªÑõ»¯ÎïµÄת»¯ÂʿɲÉÈ¡µÄ´ëÊ©ÊÇ???????? ????????????????????????? £¨Ð´³ö1Ìõ¼´¿É£©¡£

£¨3£©ÀûÓÃClO2 Ñõ»¯µªÑõ»¯Îï¡£Æäת»¯Á÷³ÌÈçÏÂ:? NONO2N2¡£ÒÑÖª·´Ó¦¢ñµÄ»¯Ñ§·½³ÌʽΪ2NO+ ClO2 + H2O £½NO2 + HNO3 + HCl£¬Ôò·´Ó¦¢òµÄ»¯Ñ§·½³ÌʽÊÇ???????? ????? £»ÈôÉú³É11.2 L N2£¨±ê×¼×´¿ö£©£¬ÔòÏûºÄClO2 ??????? g ¡£

£¨4£©ÓûîÐÔÌ¿»¹Ô­·¨´¦ÀíµªÑõ»¯ÎÓйط´Ó¦Îª£ºC£¨s£©+2NO£¨g£©N2 £¨g£©+CO2 £¨g£©¡÷H£®Ä³Ñо¿Ð¡×éÏòijÃܱÕÈÝÆ÷¼ÓÈëÒ»¶¨Á¿µÄ»îÐÔÌ¿ºÍNO£¬ºãΣ¨T1¡æ£©Ìõ¼þÏ·´Ó¦£¬·´Ó¦½øÐе½²»Í¬Ê±¼ä²âµÃ¸÷ÎïÖʵÄŨ¶ÈÈçÏ£º

Ũ¶È/mol?L-1/

ʱ¼ä/min

NO

N2

CO2

0

0.100

0

0

10

0.058

0.021

0.021

20

0.040

0.030

0.030

30

0.040

0.030

0.030

40

0.032

0.034

0.017

50

0.032

0.034

0.017

 

¢ÙT1¡æʱ£¬¸Ã·´Ó¦µÄƽºâ³£ÊýK= ????????? £¨±£ÁôÁ½Î»Ð¡Êý£©£®¢Ú30minºó£¬¸Ä±äijһÌõ¼þ£¬·´Ó¦ÖØдﵽƽºâ£¬Ôò¸Ä±äµÄÌõ¼þ¿ÉÄÜÊÇ ????????????? £®¢ÛÈô30minºóÉý¸ßζÈÖÁT2¡æ£¬´ïµ½Æ½ºâʱ£¬ÈÝÆ÷ÖÐNO¡¢N2¡¢CO2µÄŨ¶ÈÖ®±ÈΪ5£º3£º3£¬Ôò¸Ã·´Ó¦µÄ¡÷H ?? 0£¨Ìî¡°£¾¡±¡¢¡°=¡±»ò¡°£¼¡±£©£®

 

¡¾´ð°¸¡¿

£¨1£©CH4 (g)£«2NO2(g)£½N2(g)£«CO2(g)£«2H2O(g£©?? ¡÷H £½£­867 kJ/mol

£¨2£©Ôö´óNH3µÄŨ¶È»ò¼õС·´Ó¦ÌåϵµÄѹǿ»ò½µµÍ·´Ó¦ÌåϵµÄζȵÈ

£¨3£©2NO2 + 4 Na2SO3=N2 + 4 Na2SO4??? 67.5? £¨4£©¢Ù0.56? ¢Ú ¼õÉÙCO2Ũ¶È? ¢Û £¼

¡¾½âÎö¡¿

ÊÔÌâ·ÖÎö£º£¨1£©£¨¢Ù£«¢Ú£©¡Â2¿ÉµÃCH4 (g)£«2NO2(g)£½N2(g)£«CO2(g)£«2H2O(g£©?? ¡÷H £½£­867 kJ/mol¡££¨2£©ÓÉÓÚ·´Ó¦µÄÕý·´Ó¦ÆøÌåÌå»ýÔö´óµÄ·ÅÈÈ·´Ó¦¡£ËùÒÔÌá¸ßµªÑõ»¯ÎïµÄת»¯ÂʿɲÉÈ¡µÄ´ëÊ©¿ÉÒÔÊÇͨ¹ýÔö´óNH3µÄŨ¶È»ò¼õС·´Ó¦ÌåϵµÄѹǿ»ò½µµÍ·´Ó¦ÌåϵµÄζȵȴëÊ©À´ÊµÊ©¡££¨3£©ÓÉÌâÄ¿ÌṩµÄÐÅÏ¢¿ÉÖªNO2ÓëNa2SO3·¢ÉúÑõ»¯»¹Ô­·´Ó¦£º2NO2 + 4 Na2SO3 =N2 + 4 Na2SO4£¬´Ó¶øÏû³ýÁËNOx¶Ô»·¾³Ôì³ÉµÄÎÛȾ¡£ÓÉ·½³ÌʽµÃ¹Øϵʽ£º2ClO2¡«2NO2 ¡«N2¡£n(N2)=0.5mol,ËùÒÔn(ClO2)=1mol£¬m(ClO2)= 1mol¡Á67.5g/mol=67.5g¡££¨4£©¢ÙT1¡æʱ£¬¸Ã·´Ó¦µÄƽºâ³£Êý.¢ÚÓɱíÖÐÊý¾Ý¿ÉÒÔ¿´³ö30minºó£¬c(CO2)¼õС£¬c(N2)È´Öð½¥Ôö¼Óc(NO)ÓÐËù¼õÉÙ¡£ËµÃ÷¸Ä±äµÄÌõ¼þÊǼõСc(CO2)¡£¢ÛÈô30minºóÉý¸ßζÈÖÁT2¡æ£¬´ïµ½Æ½ºâʱ£¬ÈÝÆ÷ÖÐNO¡¢N2¡¢CO2µÄŨ¶ÈÖ®±ÈΪ5£º3£º3£¬<0.56¡£ËµÃ÷Éý¸ßζȣ¬»¯Ñ§Æ½ºâÏòÄæ·´Ó¦·½ÏòÒƶ¯¡£¸ù¾ÝƽºâÒƶ¯Ô­Àí:Éý¸ßζȣ¬»¯Ñ§Æ½ºâÏòÎüÈÈ·´Ó¦·½ÏòÒƶ¯¡£Äæ·´Ó¦·½ÏòΪÎüÈÈ·´Ó¦£¬ËùÒԸ÷´Ó¦µÄÕý·´Ó¦Îª·ÅÈÈ·´Ó¦¡£Ôò¸Ã·´Ó¦µÄ¡÷H £¼0£®

¿¼µã£º¿¼²é»¯Ñ§·½³Ìʽ¡¢ÈÈ»¯Ñ§·½³ÌʽµÄÊéд¡¢»¯Ñ§Æ½ºâ³£ÊýµÄ¼ÆËã¡¢Íâ½çÌõ¼þ¶Ô»¯Ñ§Æ½ºâÒƶ¯µÄÓ°Ïì¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨2012?ÆÖ¶«ÐÂÇø¶þÄ££©·ÀÖλ·¾³ÎÛȾÊǵ±Ç°»·±£¹¤×÷µÄÖØÒªÑо¿ÄÚÈÝÖ®Ò»£®¶þÑõ»¯ÁòºÍµªÑõ»¯ÎïÊÇ´óÆøµÄÖ÷ÒªÎÛȾÎ
£¨1£©½«1.5mol SO2ÓÃÇâÑõ»¯ÄÆÈÜÒº¡¢Ê¯»Ò¼°ÑõÆø´¦Àíºó£¬¼ÙÉèÁòÔªËز»Ëðʧ£¬ÀíÂÛÉϿɵõ½
258
258
gʯ¸à£¨CaSO4?2H2O£©£®
£¨2£©ÓÃCH4Ïû³ýNOxÎÛȾµÄ»¯Ñ§·½³ÌʽΪ£º
CH4+4NO¡ú2N2+CO2+2H2O£»       CH4+2NO2¡úN2+CO2+2H2O
ÏÖÓÐ11.2L NO2¡¢NOµÄ»ìºÏÆøÌåNOx£¬½«Æ仹ԭΪN2£¬ÐèÒª4.48L µÄCH4£¬Ôò»ìºÏÆøÌåÖÐNO2¡¢NOµÄÎïÖʵÄÁ¿·Ö±ðΪ
0.3mol¡¢0.2mol
0.3mol¡¢0.2mol
£®£¨Ìå»ý¶¼ÒÑ»»ËãΪ±ê×¼×´¿ö£©
£¨3£©£¨1£©³£ÎÂÏÂÓÃÑõȱλÌúËáпZnFe2Oy¿ÉÒÔÏû³ýNOxÎÛȾ£¬Ê¹NOxת±äΪN2£¬Í¬Ê±ZnFe2Oyת±äΪZnFe2O4£®Èô2mol ZnFe2OyÓë×ãÁ¿NO2¿ÉÉú³É0.5mol N2£¬Ôòy=
3
3
£®
£¨2£©ÑõȱλÌúËáпZnFe2Oz»¯Ñ§Ê½µÄÑõ»¯ÎïÐÎʽΪaZnO?bFeO?cFe2O3£®ÒÑÖª1mol ZnFe2Oz×î¶àÄÜʹ4.0L£¨±ê¿ö£©NO1.4ת»¯ÎªN2£®ÔòÉÏÊöÑõ»¯ÎïÐÎʽµÄ»¯Ñ§Ê½¿É¾ßÌå±íʾΪ
4ZnO?2FeO?3Fe2O3
4ZnO?2FeO?3Fe2O3
£®
£¨4£©µÍγôÑõÑõ»¯ÍÑÁòÍÑÏõ¼¼Êõ¿ÉÒÔͬʱÎüÊÕÑÌÆøÖеĵªÑõ»¯ÎïºÍ¶þÑõ»¯Áò£¬·´Ó¦Ô­ÀíÊǽ«NOxÑõ»¯³ÉN2O5£¬Í¨¹ýÏ´µÓÐγÉÏõËáÑΣ¬¶þÑõ»¯ÁòÐγÉÁòËáÑΣ®ÆäÖ÷Òª·´Ó¦ÈçÏ£º
NO+O3¡úNO2+O2 ¡­¢Ù
2NO2+O3¡úN2O5+O2¡­¢Ú
N2O5+2NH3+H2O¡ú2NH4NO3 ¡­¢Û
SO2+O3+2NH3+H2O¡ú£¨NH4£©2SO4+O2¡­¢Ü
ijÈȵ糧ÑÌÆøÖÐƽ¾ùº¬NOx4.5¡ë¡¢SO2 9.0¡ë£¨Ìå»ý·ÖÊý£©£¬Ñ¹Ëõ¿ÕÆø¾­³ôÑõ·¢ÉúÆ÷±ä³É³ôÑõ¿ÕÆø£¬ÆäÖÐO3Ũ¶ÈΪ90L/m3£¬³ôÑõ¿ÕÆøÓë¼Óʪ°±ÆøºÍÑÌÆø»ìºÏ·´Ó¦£®Èô
V(³ôÑõ¿ÕÆø)V(ÑÌÆø)
Á÷Á¿±ÈΪy£¬Çëͨ¹ý¼ÆËãÁгöyÓëxµÄ¹Øϵʽ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

NO¡¢NO2µÈµªÑõ»¯ÎïÊÇ´óÆøÎÛȾÎïÖ®Ò»£®NO2ÊÇ»ð¼ýȼÁÏÖг£ÓÃÑõ»¯¼Á£®NOÊÇÈËÌåÖÐÒ»ÖÖ´«µÝÉñ¾­ÐÅÏ¢µÄ¡°ÐÅʹ·Ö×Ó¡±£®
¾«Ó¢¼Ò½ÌÍø
£¨1£©ÊµÑéÊÒ¿ÉÓÃÍ­ºÍ²»Í¬Å¨¶ÈµÄÏõËáÖÆÈ¡NOºÍNO2£®Èçͼ1ÖпÉÑ¡Óõķ¢Éú×°ÖÃÊÇ
 
£¨Ìî×Öĸ£©£®
£¨2£©ÊµÑéÊÒ³£ÓÃ65%ŨÏõËᣨÃܶÈΪ1.40g/cm3£©µÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ
 
£»ÖƱ¸NOʱ£¬ÐèÓÃŨÏõËáÅäÖÆÌå»ý±ÈŨ¶ÈΪ1£º4µÄÏ¡ÏõËᣬÐèÓö¨Á¿ÒÇÆ÷ÊÇ
 
£®
£¨3£©ÓÐѧÉúÉè¼ÆÈçͼ2×°ÖÃ×öÍ­ÓëŨ¡¢Ï¡ÏõËᷴӦʵÑ飮
a£®ÊµÑéʱ£¬ÏȽ«Ò»¶ËÈƳÉÂÝÐý×´µÄÍ­Ë¿²åÈëÏðƤÈû£¬ÔÙ½«Á½ÕëÍ·´©¹ýÏðƤÈû£¬Õëͷ¶³ö¼â¶Ë£®
b£®´ÓÒÇÆ÷C´¦×¢ÈëŨÏõËáÖ±µ½×ó²àÒºÃæ½Ó½üͭ˿϶Ëʱֹͣ¼ÓÈ룮
c£®×¢ÉäÆ÷AÖÐÔ¤ÏÈÎüÈë6mLÕôÁóË®£¬×¢ÉäÆ÷BµÄ»îÈû¼·µ½µ×£¬Åž¡¿ÕÆø£¬ÔÙ½«Á½Ö§×¢ÉäÆ÷²åÔÚÕëÍ·ÉÏ£¬Èçͼ2×°Å䣮
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙÒÇÆ÷CµÄÃû³ÆÊÇ
 
£®
¢ÚʹŨÏõËáÓëÍ­Ë¿½Ó´¥·¢Éú·´Ó¦µÄ²Ù×÷·½·¨ÊÇ
 
£»·´Ó¦Ê±ÏÖÏóΪ
 
£®
¢Û½«×¢ÉäÆ÷AÖÐÕôÁóË®×¢ÈëDÖУ¬ÔÙʹËáÒºÓëÍ­Ë¿½Ó´¥·´Ó¦£¬´Ëʱ·´Ó¦Àë×Ó·½³ÌʽÊÇ£º
 
£®
£¨4£©µªÑõ»¯ÎNOx£©ÊÇÄ¿Ç°´óÆøÎÛȾÖÎÀíµÄÄÑÌ⣮
¢ÙÑ¡ÔñÐÔ´ß»¯»¹Ô­·¨ÊÇÔÚ´ß»¯¼ÁÌõ¼þÏ£¬ÓÃNH3ʹNOxת»¯ÎªN2£®Ð´³ö·´Ó¦»¯Ñ§·½³Ìʽ£º
 
£®
¢Ú³ãÈÈ̼»¹Ô­·¨ÊÇÀûÓÃ̼ÖʹÌÌ廹ԭNOx£®Ö÷Òª»ùÓÚÏÂÁз´Ó¦£ºC+2NO¡úCO2+N2£¬2C+2NO2¡ú2CO2+N2£®Ç廪´óѧÓйØÑо¿±íÃ÷£¬650¡æ¡«850¡æʱ£¬NOxÄܹ»±»Ä¾Ì¿¡¢ÎÞÑÌú¡¢½¹Ì¿µÈ̼ÖʹÌÌ廹ԭ£¬ÔÚËùÑо¿µÄNOxŨ¶ÈÏ£¬»¹Ô­ÂÊÔÚ99%×óÓÒ£®Á½ÕßÏà±È£¬·ÖÎö³ãÈÈ̼»¹Ô­·¨µÄÓÅȱµã£ºÓŵãÊÇ
 
£»È±µãÊÇ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøµªÑõ»¯ÎïÊÇ´óÆøÎÛȾÎïÖ®Ò»£¬Ïû³ýµªÑõ»¯ÎïµÄ·½·¨ÓжàÖÖ£®
£¨1£©ÀûÓü×Íé´ß»¯»¹Ô­µªÑõ»¯ÎÒÑÖª£º
CH4£¨g£©+4NO2£¨g£©=4NO£¨g£©+CO2£¨g£©+2H2O£¨g£©¡÷H=-574kJ/mol
CH4£¨g£©+4NO£¨g£©=2N2£¨g£©+CO2£¨g£©+2H2O£¨g£©¡÷H=-1160kJ/mol
ÔòCH4½«NO2»¹Ô­ÎªN2µÄÈÈ»¯Ñ§·½³ÌʽΪ
 
£®
£¨2£©ÀûÓÃNH3´ß»¯»¹Ô­µªÑõ»¯ÎSCR¼¼Êõ£©£®¸Ã¼¼ÊõÊÇÄ¿Ç°Ó¦ÓÃ×î¹ã·ºµÄÑÌÆøµªÑõ»¯ÎïÍѳý¼¼Êõ£®·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
2NH3£¨g£©+NO£¨g£©+NO2£¨g£©
180¡æ
´ß»¯¼Á
2N2£¨g£©+3H2O£¨g£©¡÷H£¼0£¬ÎªÌá¸ßµªÑõ»¯ÎïµÄת»¯ÂʿɲÉÈ¡µÄ´ëÊ©ÊÇ
 
£¨Ð´³ö1Ìõ¼´¿É£©£®
£¨3£©ÀûÓÃClO2Ñõ»¯µªÑõ»¯ÎÆäת»¯Á÷³ÌÈçÏ£ºNO
ClO2
·´Ó¦¢ñ
NO2
Na2SO3
·´Ó¦¢ò
N2
ÒÑÖª·´Ó¦¢ñµÄ»¯Ñ§·½³ÌʽΪ2NO+ClO2+H2O=NO2+HNO3+HCl£¬Ôò·´Ó¦¢òµÄ»¯Ñ§·½³ÌʽÊÇ
 
£»ÈôÉú³É11.2L N2£¨±ê×¼×´¿ö£©£¬ÔòÏûºÄClO2
 
 g£®
£¨4£©ÀûÓÃCO´ß»¯»¹Ô­µªÑõ»¯ÎïÒ²¿ÉÒÔ´ïµ½Ïû³ýÎÛȾµÄÄ¿µÄ£®
ÒÑÖªÖÊÁ¿Ò»¶¨Ê±£¬Ôö´ó¹ÌÌå´ß»¯¼ÁµÄ±íÃæ»ý¿ÉÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ£®ÓÒͼÊÇ·´Ó¦2NO£¨g£©+2CO£¨g£©?2CO2£¨g£©+N2£¨g£©ÖÐNOµÄŨ¶ÈËæζȣ¨T£©¡¢µÈÖÊÁ¿´ß»¯¼Á±íÃæ»ý£¨S£©ºÍʱ¼ä£¨t£©µÄ±ä»¯ÇúÏߣ®¾Ý´ËÅжϸ÷´Ó¦µÄ¡÷H
 
0 £¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°ÎÞ·¨È·¶¨¡±£©£»´ß»¯¼Á±íÃæ»ýS1
 
S2£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°ÎÞ·¨È·¶¨¡±£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013-2014ѧÄêºþÄÏÊ¡»³»¯ÊиßÈýµÚÒ»´ÎÄ£Ä⿼ÊÔÀí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

µªÑõ»¯ÎïÊÇ´óÆøÎÛȾÎïÖ®Ò»£¬Ïû³ýµªÑõ»¯ÎïµÄ·½·¨ÓжàÖÖ¡£

£¨1£©ÀûÓü×Íé´ß»¯»¹Ô­µªÑõ»¯Îï¡£ÒÑÖª£º

CH4 (g)£«4NO2(g)£½4NO(g)£«CO2(g)£«2H2O(g)??? ¡÷H £½£­574 kJ/mol

CH4(g)£«4NO(g) £½ 2N2(g)£«CO2(g)£«2H2O(g)?? ¡÷H £½£­1160 kJ/mol

ÔòCH4 ½«NO2 »¹Ô­ÎªN2 µÄÈÈ»¯Ñ§·½³ÌʽΪ??????????????????????????????? ¡£???????

£¨2£©ÀûÓÃNH3´ß»¯»¹Ô­µªÑõ»¯ÎSCR¼¼Êõ)¡£¸Ã¼¼ÊõÊÇÄ¿Ç°Ó¦ÓÃ×î¹ã·ºµÄÑÌÆøµªÑõ»¯ÎïÍѳý¼¼Êõ¡£ ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2NH3(g)£«NO(g)£«NO2(g) ? 2N2(g)£«3H2O(g)¡¡¦¤H < 0

ΪÌá¸ßµªÑõ»¯ÎïµÄת»¯ÂʿɲÉÈ¡µÄ´ëÊ©ÊÇ????????????????? £¨Ð´³ö1Ìõ¼´¿É£©¡£

£¨3£©ÀûÓÃClO2 Ñõ»¯µªÑõ»¯Îï¡£Æäת»¯Á÷³ÌÈçÏ£º

NONO2N2

ÒÑÖª·´Ó¦¢ñµÄ»¯Ñ§·½³ÌʽΪ2NO+ ClO2 + H2O £½ NO2 + HNO3 + HCl£¬Ôò·´Ó¦¢òµÄ»¯Ñ§·½³ÌʽÊÇ?? ????????????? £»ÈôÉú³É11.2 L N2£¨±ê×¼×´¿ö£©£¬ÔòÏûºÄClO2 ??????? g ¡£

£¨4£©ÀûÓÃCO´ß»¯»¹Ô­µªÑõ»¯ÎïÒ²¿ÉÒÔ´ïµ½Ïû³ýÎÛȾµÄÄ¿µÄ¡£

ÒÑÖªÖÊÁ¿Ò»¶¨Ê±£¬Ôö´ó¹ÌÌå´ß»¯¼ÁµÄ±íÃæ»ý¿ÉÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ¡£ÈçͼÊÇ·´Ó¦2NO(g) + 2CO(g) 2CO2(g)+ N2(g) ÖÐNOµÄŨ¶ÈËæζÈ(T)¡¢µÈÖÊÁ¿´ß»¯¼Á±íÃæ»ý(S)ºÍʱ¼ä(t)µÄ±ä»¯ÇúÏß¡£¾Ý´ËÅжϸ÷´Ó¦µÄ¡÷H????? 0 (Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°ÎÞ·¨È·¶¨¡±)£»´ß»¯¼Á±íÃæ»ýS1????? S2 (Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°ÎÞ·¨È·¶¨¡±)¡£

 

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸