Éèf£¨x£©Îª¶¨ÒåÔÚÇø¼äIÉϵĺ¯Êý£®Èô¶ÔIÉÏÈÎÒâÁ½µãx1£¬x2£¨x1¡Ùx2£©ºÍʵÊý¦Ë¡Ê£¨0£¬1£©£¬×ÜÓÐf£¨¦Ëx1+£¨1-¦Ë£©x2£©£¼¦Ëf£¨x1£©+£¨1-¦Ë£©f£¨x2£©£¬Ôò³Æf£¨x£©ÎªIÉϵÄÑϸñÏÂ͹º¯Êý£®Èôf£¨x£©ÎªIÉϵÄÑϸñÏÂ͹º¯Êý£¬Æä³äÒªÌõ¼þΪ£º¶ÔÈÎÒâx¡ÊIÓÐf¡Î£¨x£©£¾0³ÉÁ¢£¨f¡Î£¨x£©ÊǺ¯Êýf£¨x£©µ¼º¯ÊýµÄµ¼º¯Êý£©£¬ÔòÒÔϽáÂÛÕýÈ·µÄÓÐ
¢Ù¢Ü
¢Ù¢Ü
£®
¢Ùf£¨x£©=
2x+2014
3x+7
£¬x¡Ê[0£¬2014]ÊÇÑϸñÏÂ͹º¯Êý£®
¢ÚÉèx1£¬x2¡Ê£¨0£¬
¦Ð
2
£©ÇÒx1¡Ùx2£¬ÔòÓÐtan(
x1+x2
2
)£¾
1
2
(tanx1+tanx2)

¢ÛÈôf£¨x£©ÊÇÇø¼äIÉϵÄÑϸñÏÂ͹º¯Êý£¬¶ÔÈÎÒâx0¡ÊI£¬Ôò¶¼ÓÐf£¨x£©£¾f¡ä£¨x0£©£¨x-x0£©+f£¨x0£©
¢Üf£¨x£©=
1
6
x3
+sinx£¬£¨x¡Ê£¨
¦Ð
6
£¬
¦Ð
3
£©£©ÊÇÑϸñÏÂ͹º¯Êý£®
·ÖÎö£º¸ù¾ÝÑϸñÏÂ͹º¯ÊýµÄ³äÒªÌõ¼þ£¬Çóf¡Î£¨x£©£¾0ºã³ÉÁ¢¼´¿É£®
½â´ð£º½â£º¢ÙÒòΪf£¨x£©=
2x+2014
3x+7
=
2
3
(3x+7)+2014-
14
3
3x+7
=
2
3
+
6028
9x+21
£¬ËùÒÔf'£¨x£©=-
6028¡Á9
(9x+21)2
=-
6028
(3x+7)2
£¬
ËùÒÔf¡Î£¨x£©=
2¡Á3¡Á6028
(3x+7)3
£¬µ±x¡Ê[0£¬2014]ʱ£¬f¡Î£¨x£©£¾0ºã³ÉÁ¢£¬ËùÒÔ¢ÙÕýÈ·£®
¢ÚÈôx1=
¦Ð
3
£¬x2=
¦Ð
6
£¬Ôò
1
2
(tanx1+tanx2)=
1
2
(tan
¦Ð
3
+tan
¦Ð
6
)=
1
2
(
3
3
+
3
)=
2
3
3
£¬¶ø
1
2
(tan?
x1+x2
2
=tan?
¦Ð
3
+
¦Ð
6
2
)=tan?
¦Ð
4
=1
£¬
ËùÒÔÓÐtan(
x1+x2
2
)£¾
1
2
(tanx1+tanx2)
²»³ÉÁ¢£¬ËùÒÔ¢Ú´íÎó£®
¢ÛÒòΪf£¨x£©=x2ΪÑϸñÏÂ͹º¯Êý£¬Ôòf'£¨x£©=2x£¬f¡Î£¨x£©=2£¾0ºã³ÉÁ¢£¬µ±x0=1ʱ£¬f¡ä£¨1£©=2£¬f£¨1£©=1£¬
´Ëʱ²»µÈʽµÈ¼ÛΪ£¬f£¨x£©£¾2£¨x-1£©+1=2x-1£¬µ±x=0ʱ£¬f£¨0£©=0£¾-1²»³ÉÁ¢£¬ËùÒÔ¢Û´íÎó£®
¢ÜÈôf£¨x£©=
1
6
x3
+sinx£¬Ôòf'£¨x£©=
1
2
x2+cosx
£¬f¡Î£¨x£©=x-sinx£¬µ±x¡Ê[
¦Ð
6
£¬
¦Ð
3
]£¬Éèy=x-sinx£¬Ôòy'=1-cosx¡Ý0£¬ËùÒÔº¯Êýf¡Î£¨x£©=x-sinxµ¥µ÷µÝÔö£¬
ËùÒÔf¡Î£¨
¦Ð
6
£©=
¦Ð
6
-sin
¦Ð
6
=
¦Ð
6
-
1
2
£¾0
£©£¬ËùÒÔf£¨x£©=
1
6
x3
+sinx£¬£¨x¡Ê£¨
¦Ð
6
£¬
¦Ð
3
£©£©ÊÇÑϸñÏÂ͹º¯Êý£¬ËùÒÔ¢ÜÕýÈ·£®
¹Ê´ð°¸Îª£º¢Ù¢Ü£®
µãÆÀ£º±¾ÌâÖ÷Òª¿¼²éж¨ÒåµÄÓ¦Ó㬿¼²éѧÉúµÄÔËËãÄÜÁ¦£¬×ÛºÏÐÔ½ÏÇ¿£®ÕýÈ·Àí½âж¨ÒåÊǽâ¾ö±¾ÌâµÄ¹Ø¼ü£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º

£¨2013•ÌìºÓÇøÈýÄ££©Éèf£¨x£©ÊǶ¨ÒåÔÚÇø¼ä£¨1£¬+¡Þ£©Éϵĺ¯Êý£¬Æäµ¼º¯ÊýΪf'£¨x£©£®Èç¹û´æÔÚʵÊýaºÍº¯Êýh£¨x£©£¬ÆäÖÐh£¨x£©¶ÔÈÎÒâµÄx¡Ê£¨1£¬+¡Þ£©¶¼ÓÐh£¨x£©£¾0£¬Ê¹µÃf'£¨x£©=h£¨x£©£¨x2-ax+1£©£¬Ôò³Æº¯Êýf£¨x£©¾ßÓÐÐÔÖÊP£¨a£©£®
£¨1£©É躯Êýf(x)=Inx+
b+2x+1
(x£¾1)
£¬ÆäÖÐbΪʵÊý£®
£¨i£©ÇóÖ¤£ºº¯Êýf£¨x£©¾ßÓÐÐÔÖÊP£¨b£©£»
£¨ii£©Çóº¯Êýf£¨x£©µÄµ¥µ÷Çø¼ä£®
£¨2£©ÒÑÖªº¯Êýg£¨x£©¾ßÓÐÐÔÖÊP£¨2£©£¬¸ø¶¨x1£¬x2¡Ê£¨1£¬+¡Þ£©£¬x1£¼x2£¬ÉèmΪʵÊý£¬a=mx1+£¨1-m£©x2£¬¦Â=£¨1-m£©x1+mx2£¬ÇÒa£¾1£¬¦Â£¾1£¬Èô|g£¨a£©-g£¨¦Â£©|£¼|g£¨x1£©-g£¨x2£©|£¬ÇómÈ¡Öµ·¶Î§£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º

£¨2013•Ë³ÒåÇø¶þÄ££©É趨ÒåÔÚRÉϵĺ¯Êýf£¨x£©ÊÇ×îСÕýÖÜÆÚΪ2¦ÐµÄżº¯Êý£¬f¡ä£¨x£©ÊÇf£¨x£©µÄµ¼º¯Êý£®µ±x¡Ê[0£¬¦Ð]ʱ£¬0£¼f£¨x£©£¼1£»µ±x¡Ê£¨0£¬¦Ð£©ÇÒx¡Ù
¦Ð
2
ʱ£¬(x-
¦Ð
2
)f¡ä(x)£¼0
£®Ôòº¯Êýy=f£¨x£©-cosxÔÚ[-3¦Ð£¬3¦Ð]ÉϵÄÁãµã¸öÊýΪ
6
6
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º

£¨2013•·îÏÍÇø¶þÄ££©Éèf£¨x£©ÊǶ¨ÒåÔÚRÉÏÒÔ2ΪÖÜÆڵĿº¯Êý£¬ÒÑÖªx¡Ê£¨0£¬1£©£¬f(x)=log
1
2
(1-x)
£¬Ôòº¯Êýf£¨x£©ÔÚ£¨1£¬2£©ÉϵĽâÎöʽÊÇ
y=log
1
2
(x-1)
y=log
1
2
(x-1)
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸