ÒÑÖªº¯Êý
£¬£¨x>0£©£®
£¨1£©µ±0<a<b£¬ÇÒf£¨a£©=f£¨b£©Ê±£¬Çó
µÄÖµ £»
£¨2£©ÊÇ·ñ´æÔÚʵÊýa£¬b£¨a<b£©£¬Ê¹µÃº¯Êýy=f£¨x£©µÄ¶¨ÒåÓò¡¢ÖµÓò¶¼ÊÇ[a£¬b]£¬Èô´æÔÚ£¬Çó³öa£¬bµÄÖµ£¬Èô²»´æÔÚ£¬Çë˵Ã÷ÀíÓÉ£®
£¨3£©Èô´æÔÚʵÊýa£¬b£¨a<b£©£¬Ê¹µÃº¯Êýy=f£¨x£©µÄ¶¨ÒåÓòΪ [a£¬b]ʱ£¬ÖµÓòΪ [ma£¬mb]£¬£¨m¡Ù0£©£¬ÇómµÄȡֵ·¶Î§£®
½â£º£¨1£© ¡ßx>0£¬¡à![]()
¡àf£¨x£©ÔÚ£¨0£¬1£©ÉÏΪ¼õº¯Êý£¬ÔÚ
ÉÏÊÇÔöº¯Êý£®
ÓÉ0<a<b£¬ÇÒf£¨a£©=f£¨b£©£¬¿ÉµÃ 0<a
1<bºÍ
£®
¼´
£®¡¡¡¡¡¡¡¡3·Ö
£¨2£©²»´æÔÚÂú×ãÌõ¼þµÄʵÊýa£¬b£®
Èô´æÔÚÂú×ãÌõ¼þµÄʵÊýa£¬b£¬Ê¹µÃº¯Êýy=
µÄ¶¨ÒåÓò¡¢ÖµÓò¶¼ÊÇ[a£¬b]£¬
Ôòa>0£®¶ø![]()
¢Ùµ±
ʱ£¬
ÔÚ£¨0£¬1£©ÉÏΪ¼õº¯Êý£®
¹Ê
¼´
½âµÃ a=b£®
¹Ê´Ëʱ²»´æÔÚÊʺÏÌõ¼þµÄʵÊýa£¬b£®
¢Úµ±
ʱ£¬
ÔÚ
ÉÏÊÇÔöº¯Êý£®
¹Ê
¼´
![]()
´Ëʱa£¬bÊÇ·½³Ì
µÄ¸ù£¬´Ë·½³ÌÎÞʵ¸ù£®
¹Ê´Ëʱ²»´æÔÚÊʺÏÌõ¼þµÄʵÊýa£¬b£®
¢Ûµ±
£¬
ʱ£¬ÓÉÓÚ
£¬¶ø
£¬
¹Ê´Ëʱ²»´æÔÚÊʺÏÌõ¼þµÄʵÊýa£¬b£®
×ÛÉÏ¿ÉÖª£¬²»´æÔÚÊʺÏÌõ¼þµÄʵÊýa£¬b£® ¡¡¡¡¡¡¡¡¡¡8·Ö
£¨3£©Èô´æÔÚʵÊýa£¬b£¨a<b£©£¬Ê¹µÃº¯Êýy=f£¨x£©µÄ¶¨ÒåÓòΪ[a£¬b]ʱ£¬ÖµÓòΪ[ma£¬mb]£®
Ôòa>0£¬m>0£®
µ±
ʱ£¬ÓÉÓÚf£¨x£©ÔÚ£¨0£¬1£©ÉÏÊǼõº¯Êý£¬
¹Ê
£®´ËʱµÃa=b£¬²»·ûºÏÌâÒ⣬ËùÒÔa£¬b²»´æÔÚ£®
µ±
£¬
ʱ£¬ÓÉ£¨2£©Öª0ÔÚÖµÓòÄÚ£¬ÖµÓò²»¿ÉÄÜÊÇ[ma£¬mb]£¬ËùÒÔa£¬b²»´æÔÚ£®
¹ÊÖ»ÓÐ
£®
¡ß
ÔÚ
ÉÏÊÇÔöº¯Êý£¬
¡à
¼´
ËùÒÔa¡¢bÊÇ·½³Ì
µÄÁ½¸ö¸ù£®
¼´¹ØÓÚxµÄ·½³Ì
ÓÐÁ½¸ö´óÓÚ»òµÈÓÚ1µÄÏàÒìʵ¸ù£®
ÉèÕâÁ½¸ö¸ùΪ
¡¢
£¬Ôò
+
=
£¬
¡¤
=
£®
¡à
¼´
½âµÃ
£®
¹ÊmµÄȡֵ·¶Î§ÊÇ
£® ¡¡¡¡¡¡¡¡¡¡¡14·Ö
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º2012-2013ѧÄêɽ¶«Ê¡Ì©°²ÊиßÈý12ÔÂÖʼìÎÄ¿ÆÊýѧÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÒÑÖªº¯Êýy=2sin(¦Øx+¦Õ)(¦Ø>0)ÔÚÇø¼ä[0£¬2¦Ð]µÄͼÏñÈçÏ£ºÄÇô¦Ø=£¨ £©
![]()
A£®1 B£®2
C£®1/2 D£®1/3
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º2013½ì¸ÊËàÊ¡ÌìË®Êи߶þÉÏѧÆÚÆÚÄ©¿¼ÊÔÀí¿ÆÊýѧ ÌâÐÍ£º½â´ðÌâ
ÒÑÖªº¯Êý
£¬£¨x>0£©,³£Êý
>0.
(¢ñ)ÊÔÈ·¶¨º¯Êý
µÄµ¥µ÷Çø¼ä£»
(¢ò)Èô¶ÔÓÚÈÎÒâ
£¬
£¾0ºã³ÉÁ¢£¬ÊÔÈ·¶¨ÊµÊý
µÄȡֵ·¶Î§£»
(¢ó)É躯Êý
=
+
£¬ÇóÖ¤£º
¡
£¾
£¨
,
£©
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
£¨º£ÄÏÄþÏľíÀí1£©ÒÑÖªº¯Êýy=2sin(¦Øx+¦Õ)(¦Ø>0)ÔÚÇø¼ä[0£¬2¦Ð]µÄͼÏñÈçÏ£ºÄÇô¦Ø=£¨ £©
A. 1 B. 2 C. 1/2 D. 1/3
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
£¨º£ÄÏÄþÏľíÀí1£©ÒÑÖªº¯Êýy=2sin(¦Øx+¦Õ)(¦Ø>0)ÔÚÇø¼ä[0£¬2¦Ð]µÄͼÏñÈçÏ£ºÄÇô¦Ø=£¨ £©
A. 1 B. 2 C. 1/2 D. 1/3
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com