Question

解关于x的不等式：loga(x2－x－2)＞loga(x－)＋1(a＞0，a≠1)

Answer 1

见解析

原不等式等价于
……①                                                           
1°当时，①式可化为
                                                                           
从而即
∴                                                                                             
2°当时，①式可化为
                                                                                
从而  即
∴Φ    
综上所述，当时，原不等式的解集为；当时，不等式的解集为Φ