£¨1£©¢ÙÓÃÓα꿨³ß£¨¿¨³ßµÄÓαêÓÐ20µÈ·Ö£©²âÁ¿Ò»Ö§Ç¦±ÊµÄ³¤¶È£¬²âÁ¿½á¹ûÈçͼ1ʾ£¬ÓÉ´Ë¿É֪Ǧ±ÊµÄ³¤¶ÈÊÇ
 
cm£®
¢ÚÔÚ¡°Ñо¿ÔȱäËÙÖ±ÏßÔ˶¯¡±µÄʵÑéÖУ¬Èçͼ2ʵÑéµÃµ½µÄÒ»ÌõÖ½´ø£¬Ö½´øÉÏÿÏàÁÚµÄÁ½¼ÆÊýµã¼äµÄʱ¼ä¼ä¸ô¾ùΪ0.1s£¬²âµÃAµ½BºÍBµ½CµÄ¾àÀë·Ö±ðΪ5.60cmºÍ7.82cm£¬ÔòÎïÌåµÄ¼ÓËٶȴóСΪ
 
m/s2£¬BµãµÄËٶȴóСΪ
 
m/s£®
¾«Ó¢¼Ò½ÌÍø
£¨2£©ÎªÁ˲âÁ¿Á½½Ú´®Áª¸Éµç³ØµÄµç¶¯ÊÆ£¬Ä³Í¬Ñ§Éè¼ÆÁËÈçͼ¼×ËùʾµÄʵÑéµç·£®ÆäÖУºEÊÇ´ý²âµç³Ø×飬ÄÚ×è²»ÄܺöÂÔ£»V1¡¢V2ÊÇÁ½Ö»Á¿³Ì¶¼ºÏÊʵĵçѹ±í£¬ÄÚ×è²»ÊǺܴó£¬ÇÒδ֪£»S1¡¢S2Êǵ¥µ¶µ¥ÖÀ¿ª¹Ø£»µ¼ÏßÈô¸É£®
¢ÙÇë¸ù¾Ýµç·ͼ¼×£¬ÔÚͼÒÒµÄʵÎïÖÐÁ¬Ïߣ¬½«Æ÷²ÄÁ¬³ÉʵÑéµç·£®
¢Ú¼òҪд³öʵÑé²½ÖèºÍʵÑéÖÐÐèÒª²âÁ¿µÄÎïÀíÁ¿
 
£®
¢ÛÓòâ³öµÄÎïÀíÁ¿×÷ΪÒÑÖªÁ¿£¬Ð´³ö¼ÆËã´®Áªµç³Ø×éµç¶¯ÊƵıí´ïʽ
 
£®
·ÖÎö£º£¨1£©Óα꿨³ß¶ÁÊýµÄ·½·¨ÊÇÖ÷³ß¶ÁÊý¼ÓÉÏÓαê¶ÁÊý£¬²»Ðè¹À¶Á£¬×¢ÒâÁ½ÖÖÒÇÆ÷¶ÁÊýµÄ²»Í¬£®Ö½´øʵÑéÖУ¬ÈôÖ½´øÔȱäËÙÖ±ÏßÔ˶¯£¬²âµÃÖ½´øÉϵĵã¼ä¾à£¬ÀûÓÃÔȱäËÙÖ±ÏßÔ˶¯µÄÍÆÂÛ£¬¿É¼ÆËã³ö´ò³öijµãʱֽ´øÔ˶¯µÄ˲ʱËٶȺͼÓËٶȣ®
£¨2£©¸ù¾Ýµç·ͼ½«Æ÷²ÄÁ¬³ÉʵÑéµç·£¬¸ù¾Ý±ÕºÏ»Ø·ŷķ¶¨ÂÉÁгöµÈʽÇó½â£®
½â´ð£º½â£º£¨1£©¢ÙÓαê³ßÉÏ×ܹ²ÊÇ20¸öС¸ñ£¬¹ÊÆ侫¶ÈΪ0.05mm£¬Ö÷³ß¶ÁÊýΪ9.1cm£¬Óαê³ßÉϵÚ12¸ö¿Ì¶ÈÓëÖ÷³ßÉÏijһ¿Ì¶È¶ÔÆ룬¹ÊÓαê¶ÁÊýΪ£º0.05¡Á12mm=0.60mm£¬ËùÒÔ×îÖÕ¶ÁÊýΪ£º91mm+0.60mm=91.60mm=9.160 cm£®
¢Ú¸ù¾ÝÔ˶¯Ñ§¹«Ê½¡÷x=at2µÃ£º
a=
¡÷x 
t2
=2.22m/s2£¬
ÀûÓÃÔȱäËÙÖ±ÏßÔ˶¯µÄÍÆÂ۵ãº
vB=
XAC
tAC
=0.671 m/s£®

£¨2£©¢ÙÇë¸ù¾Ýµç·ͼ¼×£¬ÔÚͼÒÒµÄʵÎïÖÐÁ¬Ïߣ¬½«Æ÷²ÄÁ¬³ÉʵÑéµç·Èçͼ£º
¾«Ó¢¼Ò½ÌÍø
¢ÚÓòâ³öµÄÎïÀíÁ¿×÷ΪÒÑÖªÁ¿£¬Ð´³ö¼ÆËã´®Áªµç³Ø×éµç¶¯ÊƵıí´ïʽ±ÕºÏS1£¬·Ö±ð¶Á³öV1ºÍV2µÄ¶ÁÊýU1 ºÍU2£»ÔÙ±ÕºÏS2£¬¶Á³öV1µÄ¶ÁÊýU1¡ä£®
¢Û¸ù¾Ý±ÕºÏ»Ø·ŷķ¶¨ÂɵÃE=U1+U2+
U1
Rv1
r£¬E=U¡ä1+
U¡ä1
Rv1
r
½âµÃ£ºE=
U1¡äU2
U1¡ä-U1


¹Ê´ð°¸Îª£º£¨1£©¢Ù9.160   ¢Ú2.22£¬0.671 
£¨2£©¢ÙÁ¬ÏßͼÈçͼʾ  
¢Ú±ÕºÏS1£¬·Ö±ð¶Á³öV1ºÍV2µÄ¶ÁÊýU1 ºÍU2£»ÔÙ±ÕºÏS2£¬¶Á³öV1µÄ¶ÁÊýU1¡ä
¢ÛE=
U1¡äU2
U1¡ä-U1
µãÆÀ£º£¨1£©½â¾ö±¾ÌâµÄ¹Ø¼üÕÆÎÕÓα꿨³ßµÄ¶ÁÊý·½·¨£¬Óα꿨³ß¶ÁÊýµÄ·½·¨ÊÇÖ÷³ß¶ÁÊý¼ÓÉÏÓαê¶ÁÊý£¬²»Ðè¹À¶Á£®ÀûÓÃÔȱäËÙÖ±ÏßÔ˶¯µÄÍÆÂÛÇó½â¼ÓËٶȺÍËٶȣ®
ҪעÒⵥλµÄ»»Ë㣮
£¨2£©±¾Ì⿼²éÁËʵÑéʵÎïͼÁ¬½ÓµÈÎÊÌ⣬ÊÇʵÑéµÄ³£¿¼ÎÊÌ⣬һ¶¨ÒªÕÆÎÕ£»ÊìÁ·ÕÆÎÕ»ù´¡ÖªÊ¶¼´¿ÉÕýÈ·½âÌ⣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ijͬѧѧ¹ýƽÅ×Ô˶¯ºó£¬ÀûÓÃƽÅ×Ô˶¯ÖªÊ¶²âÁ¿Ä³Ë®Æ½ÅçË®¿ÚµÄÁ÷Á¿Q£¨Q=Sv£¬SΪ³öË®¿ÚµÄºá½ØÃæ»ý£¬vΪ³öË®¿ÚµÄË®ËÙ£©£¬·½·¨ÈçÏ£º
£¨1£©ÏÈÓÃÓα꿨³ß²âÁ¿ÅçË®¿ÚµÄÄÚ¾¶D£®Èçͼ¼×Ëùʾ£¬A¡¢B¡¢C¡¢DËĸöͼÖУ¬²âÁ¿·½Ê½ÕýÈ·µÄÊÇ
C
C
£®
£¨2£©ÕýÈ·²âÁ¿µÃµ½µÄ½á¹ûÈçͼÒÒÖеÄÓα꿨³ßËùʾ£¬Óɴ˿ɵÃÅçË®¿ÚµÄÄÚ¾¶D=
1.044
1.044
cm£®
£¨3£©´ò¿ªË®·§£¬ÈÃË®´ÓÅçË®¿ÚˮƽÅç³ö£¬Îȶ¨ºó²âµÃÂäµØµã¾àÅçË®¿Úˮƽ¾àÀëΪx£¬ÊúÖ±¾àÀëΪy£¬ÔòÅç³öµÄË®µÄ³õËÙ¶Èv0=
x
g
2y
x
g
2y
£¨ÓÃx£¬y¡¢g±íʾ£©£®
£¨4£©¸ù¾ÝÉÏÊö²âÁ¿Öµ£¬¿ÉµÃË®¹ÜÄÚË®µÄÁ÷Á¿Q=
¦ÐD2x
4
g
2y
¦ÐD2x
4
g
2y
£¨ÓÃD¡¢x¡¢y¡¢g±íʾ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

Èçͼ¼×ËùʾÊÇijͬѧ̽¾¿Ð¡³µ¼ÓËÙ¶ÈÓëÁ¦µÄ¹ØϵµÄʵÑé×°Öã¬Ëû½«¹âµçÃŹ̶¨ÔÚˮƽ¹ìµÀÉϵÄBµã£¬Óò»Í¬ÖØÎïͨ¹ýϸÏßÀ­Í¬Ò»Ð¡³µ£¬Ã¿´ÎС³µ¶¼´ÓͬһλÖÃAÓɾ²Ö¹ÊÍ·Å£®
£¨1£©ÈôÓÃÓα꿨³ß²â³öÕÚ¹âÌõµÄ¿í¶ÈdÈçͼÒÒËùʾ£¬Ôòd=
1.140
1.140
cm£»ÊµÑéʱ½«Ð¡³µ´ÓͼʾλÖÃÓɾ²Ö¹ÊÍ·Å£¬ÓÉÊý×Ö¼ÆʱÆ÷¶Á³öÕÚ¹âÌõͨ¹ý¹âµçÃŵÄʱ¼ä¡÷t=2.0¡Á10-2s£¬ÔòС³µ¾­¹ý¹âµçÃÅʱµÄËÙ¶ÈΪ
0.57
0.57
m/s£»
£¨2£©ÊµÑéÖпɽüËÆÈÏΪϸÏ߶ÔС³µµÄÀ­Á¦ÓëÖØÎïÖØÁ¦´óСÏàµÈ£¬ÔòÖØÎïµÄÖÊÁ¿mÓëС³µµÄÖÊÁ¿M¼äÓ¦Âú×ãµÄ¹ØϵΪ
M£¾£¾m
M£¾£¾m
£»
£¨3£©²â³ö¶à×éÖØÎïµÄÖÊÁ¿mºÍ¶ÔÓ¦ÕÚ¹âÌõͨ¹ý¹âµçÃŵÄʱ¼ä¡÷t£¬²¢Ëã³öÏàӦС³µ¾­¹ý¹âµçÃÅʱµÄËÙ¶Èv£¬Í¨¹ýÃèµã×÷³öÏßÐÔͼÏó£¬Ñо¿Ð¡³µ¼ÓËÙ¶ÈÓëÁ¦µÄ¹Øϵ£¬´¦ÀíÊý¾ÝʱӦ×÷³ö
v2-m
v2-m
£¨Ñ¡Ìî¡°v-m¡±»ò¡°v2-m¡±£©Í¼Ïó£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

£¨2012?¼ÎÐ˶þÄ££©Ä³ÐËȤС×éÀûÓÃƽÅ×Ô˶¯ÖªÊ¶²âÁ¿Ä³Å©×¯Ë®Æ½ÅçË®¿ÚµÄÁ÷Á¿£¨µ¥Î»Ê±¼äÄڴӹܿÚÅç³öµÄË®µÄÌå»ý£©£¬·½·¨ÈçÏ£º
£¨1£©ÏÈÓÃÓα꿨³ß²âÁ¿ÅçË®¿ÚµÄÄÚ¾¶D£®A¡¢B¡¢C¡¢DͼÖУ¬²âÁ¿·½Ê½ÕýÈ·µÄÊÇ
C
C

£¨2£©ÈçͼΪÕýÈ·²âÁ¿µÃµ½µÄ½á¹û£¬Óɴ˿ɵÃÅçË®¿ÚµÄÄÚ¾¶D=
1.010¡Á10-2
1.010¡Á10-2
m£®
£¨3£©´ò¿ªË®·§£¬ÈÃË®´ÓÅçË®¿ÚˮƽÅç³ö£¬Îȶ¨ºó²âµÃÂäµØµã¾àÅçË®¿Úˮƽ¾àÀëΪx£¬ÊúÖ±¾àÀëΪy£¬ÔòÅç³öµÄË®µÄ³õËÙ¶Èv0=
x
g
2y
x
g
2y
£¨ÓÃx¡¢y¡¢g±íʾ£©£®
£¨4£©¸ù¾ÝÉÏÊö²âÁ¿Öµ£¬¿ÉµÃË®¹ÜÄÚË®µÄÁ÷Á¿Q=
¦ÐD2x
4
g
2y
¦ÐD2x
4
g
2y
£¨ÓÃD¡¢x¡¢y¡¢g±íʾ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

£¨2013?Ö£ÖݶþÄ££©Ä³ÐËȤС×éÀûÓÃÎïÀíѧ֪ʶ²âÁ¿Ä³Å©×¯ÅçË®¿ÚµÄÁ÷Á¿Q£¨Q=Sv£¬SΪ³öË®¿ÚµÄºá½ØÃæ»ý£¬vΪ³öË®¿ÚµÄË®Á÷Ëٶȣ©£¬·½·¨ÈçÏ£º
£¨1£©ÏÈÓÃÓα꿨³ß²âÁ¿Ô²ÐÎÅçË®¿ÚµÄÄÚ¾¶d£®ÈçͼΪÕýÈ·²âÁ¿µÃµ½µÄ½á¹û£¬Óɴ˿ɵóöË®¿ÚµÄÄÚ¾¶d=
10.10
10.10
 mm£®
£¨2£©´ò¿ªË®·§£¬ÈÃË®´ÓÅçË®¿ÚÊúÖ±ÏòÉÏÅç³ö£¬Îȶ¨ºó²âµÃË®Öù×î¸ßµã¾àÅçË®¿ÚÊúÖ±¾àÀëΪh£¬ÔòÅç³öµÄË®µÄ³õËÙ¶È
v
 
0
=
2gh
2gh
£¨ÓÃh¡¢g±íʾ£©£®
£¨3£©¸ù¾ÝÉÏÊö²âÁ¿Öµ£¬¿ÉµÃÅçË®¿ÚË®µÄÁ÷Á¿Q=
¦Ðd2
2gh
4
¦Ðd2
2gh
4
£¨ÓÃd¡¢h¡¢g±íʾ£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ΪÁ˲âÁ¿Îï¿éÓëбÃæÖ®¼äµÄ¶¯Ä¦²ÁÒòÊý£¬Ä³Í¬Ñ§Éè¼ÆÁËÒ»¸öʵÑ飺Èçͼ1Ëùʾ£¬ÔÚÒÑÖªÇã½ÇΪ¦ÈµÄбÃæÉÏ£¬¿¿½üбÃæµ×¶Ë°²ÖÃÒ»¹âµçÃÅ£¬Îï¿é´øÓÐÕÚ¹âƬ£¬ÕÚ¹âƬµÄ¿í¶ÈΪd£¬´ÓбÃæÉÏijһλÖÃÓɾ²Ö¹ÊÍ·ÅСÎï¿é£¬¼Ç¼ÊÍ·ÅʱÕÚ¹âƬµ½¹âµçÃŵľàÀëxºÍÕÚ¹âƬͨ¹ý¹âµçÃŵÄʱ¼ät£®
¾«Ó¢¼Ò½ÌÍø
£¨1£©ÈôÓÃÓα꿨³ß²âÁ¿¹âµçÃÅÕÚ¹âÌõµÄ¿í¶ÈÈçͼ2Ëùʾ£¬ÔòÕÚ¹âÌõµÄ¿í¶ÈΪ
 
cm£®
£¨2£©ÒÑÖªÖØÁ¦¼ÓËÙ¶ÈΪg£¬½áºÏÌâÖвâÁ¿µÄÎïÀíÁ¿Ð´³öÎïÌåÓëбÃæ¼ä¶¯Ä¦²ÁÒòÊý±í´ïʽ£º¦Ì©„
 
£¨ÓÃÌâÖÐËù¸øµÄ×Öĸ±íʾ£©£®
£¨3£©ÎªÁ˼õСʵÑé´øÀ´µÄżȻÎó²î£¬¿É²ÉÓöà´Î²âÁ¿µÄ·½·¨£®½«ÎïÌå´ÓбÃæÉϲ»Í¬Î»ÖÃÊÍ·Å£¬²â³ö¶à×éÎïÌåµ½¹âµçÃŵľàÀëxºÍÕÚ¹âƬͨ¹ý¹âµçÃŵÄʱ¼ät£¬Í¨¹ýͼÏó·¨À´µÃµ½ÎïÌåÓëбÃæ¼äµÄ¶¯Ä¦²ÁÒòÊý£¬ÎªÁËʹͼÏóÖ±¹ÛÒ×ÓÚ¹Û²ìÓë²âÁ¿£¨¼´Í¼ÏóΪһֱÏߣ©£¬ÄÇô×ø±êϵµÄºá×ø±êÎïÀíӦΪ£¬×Ý×ø±êÎïÀíÁ¿Ó¦Îª£®Èç¹ûÇó³öͼÏóµÄбÂÊֵΪk£¬ÔòÎïÌåÓëбÃæ¼ä¶¯Ä¦²ÁÒòÊý±í´ïʽΪ¦Ì©„
 
£¨ÓÃÌâÖÐËù¸øµÄ×Öĸ±íʾ£©£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸