Èçͼ¼×Ëùʾ£¬Õæ¿ÕÇøÓòÄÚÓÐÒ»Á£×ÓÔ´A£¬ÄÜÿ¸ô
T
2
µÄʱ¼ä¼ä¸ô¶¨Ê±µØÑØAO·½ÏòÏòÍâ·¢³öÒ»¸öÁ£×Ó£®ÐéÏßÓÒ²àΪһÓÐÀíÏë±ß½çµÄÏ໥Õý½»µÄÔÈÇ¿µç³¡ºÍÔÈÇ¿´Å³¡ÇøÓò£¬ÀëÐéÏß¾àÀëΪLµÄλÖô¦ÓÐÒ»Ó«¹âÆÁ£¬Á£×Ó´òµ½Ó«¹âÆÁÉϽ«Ê¹Ó«¹âÆÁÉϳöÏÖÒ»¸öÁÁµã£®ÐéÏߺÍÓ«¹âÆÁÏ໥ƽÐУ¬¶øAOÓëÓ«¹âÆÁÏ໥´¹Ö±£®Èç¹ûijʱ¿ÌÁ£×ÓÔ˶¯µ½ÐéÏßλÖÿªÊ¼¼Æʱ£¨¼ÇΪt=0£©£¬¼ÓÉÏÈçͼÒÒËùʾÖÜÆÚÐԱ仯µÄµç¡¢´Å³¡£¬³¡Ç¿´óС¹ØϵΪ
E0
=
v0
B
£¨ÆäÖÐ
v0
ΪÁ£×Óµ½´ïÐéÏßλÖÃʱµÄËٶȴóС£©£¬·¢ÏÖt=
3T
2
µÈʱ¿Ìµ½´ïÐéÏßλÖõÄÁ£×ÓÔÚt=2Tʱ¿Ìµ½´ïÓ«¹âÆÁÉϵÄOµã£»ÔÚt=
T
2
ʱ¿Ìµ½´ïÐéÏßλÖõÄÁ£×Ó´òµ½Ó«¹âÆÁÉϵÄPµã£¬ÇÒOPÖ®¼äµÄ¾àÀëΪ
L
2
£¬ÊÔ¸ù¾ÝÒÔÉÏÌõ¼þÈ·¶¨£¬Ó«¹âÆÁÉÏÔÚÄÄЩʱ¿Ì£¬ÔÚʲôλÖÃÓÐÁ£×Óµ½´ï£¿
ÓÉÓÚt=
3T
2
ʱ¿Ìµ½´ïÐéÏßµÄÁ£×ÓÔÚ=2Tʱ¿Ìµ½´ïÓ«¹âÆÁÉϵÄOµã£¬¶øÔÚt=
3T
2
¡«t=2TÆÚ¼äµç³¡ºÍ´Å³¡¶¼ÎªÁ㣬Á£×ÓÑØÖ±ÏßÔ˶¯µ½Oµã£¬ËµÃ÷Á£×ÓµÄÖØÁ¦²»¼Æ£¬¹Ê£º
£¨1£©t=0ʱ¿Ì½øÈëµÄÁ£×ÓÊܵ½µÄµç³¡Á¦ºÍÂåÂ××ÈÁ¦Æ½ºâ£¬¹Ê×öÔÈËÙÖ±ÏßÔ˶¯£¬ÔÚt=
T
2
ʱ¿Ìµ½´ïOµã£®
£¨2£©t=
T
2
ʱ¿Ì½øÈëµÄÁ£×ÓÖ»Êܵ糡Á¦×÷Óã¬×öÀàƽÅ×Ô˶¯£¬t=Tʱ¿Ìµ½´ïPµã£¬OP=
L
2
£®
£¨3£©t=Tʱ¿Ì½øÈëµÄÁ£×ÓÖ»ÊÜÂåÂ××ÈÁ¦×÷Óã¬ÔòµÃ
x=v0?
T
2
=L
µÃ
L
v0
=
T
2
»òv0T=2L
ÓÉy=
1
2
?
E0q
m
?(
T
2
)2
=
L
2
µÃ
m
E0q
=
T2
4L

ÓÖÓÉqv0B=m
v20
R
£¬ÁªÁ¢µÃR=
mv0
qB
=L
Á£×ÓÔڴų¡ÖÐÔ˶¯µÄÖÜÆÚΪ T0=
2¦Ðm
qB
=¦ÐT
Éè¾­¹ý
T
2
ʱ¼ä¼´
3T
2
ʱ¿ÌÁ£×ÓÔ˶¯µ½
Fµã£¬Éè´Ë¹ý³ÌÖÐÁ£×Óת¹ýµÄÔ²ÐĽÇΪ¦È£¬Ôò
¦È
2¦Ð
=
1
2
T
¦ÐT
£¬ÔòµÃ¦È=1rad
ÒÔºóÁ£×Ó²»ÊÜÁ¦×öÔÈËÙÖ±ÏßÔ˶¯µÄ´òµ½Qµã£¬ÓÉQOµã¼äµÄ¾àÀëΪ
yQO=£¨L-Lcos¦È£©+£¨L-Lsin¦È£©tan¦È=£¨L-Lcos1£©+£©+£¨L-Lsin1£©tan1£»
£¨4£©t=
3T
2
ʱ¿Ìµ½´ïÐéÏßλÖõÄÁ£×Ó×öÔÈËÙÖ±ÏßÔ˶¯ÔÚt=2Tʱ¿Ìµ½´ïÓ«¹âÆÁÉϵÄOµã£»
£¨5£©ÒÔºóÖظ´£¬¼´£ºt=2kT£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½ÐéÏßλÖõÄÁ£×Ó£¬ÔÚt=£¨2k+
1
2
£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½´ïOµã£»
t=£¨2k+
1
2
£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½ÐéÏßλÖõÄÁ£×Ó£¬ÔÚt=£¨2k+1£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½´ïPµã£»
t=£¨2k+1£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½ÐéÏßλÖõÄÁ£×Ó£¬ÔÚt=£¨2k+1£©T+
T
2
+
L-sin1
v0cos1
£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½´ïQµã£»
t=£¨2k+
3
2
£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½ÐéÏßλÖõÄÁ£×Ó£¬ÔÚt=£¨2k+2£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½´ïOµã£®
´ð£º
t=2kT£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½ÐéÏßλÖõÄÁ£×Ó£¬ÔÚt=£¨2k+
1
2
£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½´ïOµã£»
t=£¨2k+
1
2
£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½ÐéÏßλÖõÄÁ£×Ó£¬ÔÚt=£¨2k+1£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½´ïPµã£»
t=£¨2k+1£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½ÐéÏßλÖõÄÁ£×Ó£¬ÔÚt=£¨2k+1£©T+
T
2
+
L-sin1
v0cos1
£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½´ïQµã£»
t=£¨2k+
3
2
£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½ÐéÏßλÖõÄÁ£×Ó£¬ÔÚt=£¨2k+2£©T£¨k=0£¬1£¬2£¬3£¬¡­£©Ê±¿Ìµ½´ïOµã£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

Èçͼ£¬Ò»ÔÈÇ¿´Å³¡´Å¸ÐӦǿ¶ÈΪB£¬·½ÏòÏòÀÆä±ß½çÊǰ뾶ΪRµÄÔ²¡£ABΪԲµÄÒ»Ö±¾¶¡£ÔÚAµãÓÐÒ»Á£×ÓÔ´ÏòԲƽÃæÄڵĸ÷¸ö·½Ïò·¢ÉäÖÊÁ¿m¡¢µçÁ¿+qµÄÁ£×Ó£¬Á£×ÓÖØÁ¦²»¼Æ¡££¨½á¹û±£Áô2λÓÐЧÊý×Ö£©

£¨1£©Èç¹ûÓÐÒ»´øµçÁ£×ÓÒÔ´¹Ö±Óڴų¡µÄËٶȣ¬Ñذ뾶·½Ïò½øÈëÔ²ÐÎÇøÓòµÄ´Å³¡ÖС£ÊÔÖ¤Ã÷´ËÁ£×ÓÒ»¶¨Ñذ뾶·½ÏòÉä³ö´Å³¡¡£
£¨2£©Èç¹û´Å³¡µÄ±ß½çÊǵ¯ÐԱ߽磬Á£×ÓÑذ뾶·½ÏòÉäÈë´Å³¡£¬Á£×ÓµÄËٶȴóСÂú×ãʲôÌõ¼þ£¬¿ÉʹÁ£×ÓÔڴų¡ÖÐÈÆÐÐÒ»Öܻص½³ö·¢µã,²¢ÇóÀë×ÓÔ˶¯µÄʱ¼ä¡£
£¨3£©Èç¹ûR=3cm¡¢B=0.2T,ÔÚAµãµÄÁ£×ÓÔ´ÏòԲƽÃæÄڵĸ÷¸ö·½Ïò·¢ÉäËٶȾùΪ106m/s£¬±ÈºÉΪ108c/kgµÄÁ£×Ó.ÊÔ»­³öÔڴų¡ÖÐÔ˶¯Ê±¼ä×µÄÁ£×ÓµÄÔ˶¯¹ì¼£²¢Çó´ËÁ£×ÓµÄÔ˶¯µÄʱ¼ä¡£
(4)ÔÚ£¨3£©ÖУ¬Èç¹ûÁ£×ӵijõËٶȴóС¾ùΪ3¡Á105Ã×/Ãë,Çó´Å³¡ÖÐÓÐÁ£×Óµ½´ïµÄÃæ»ý.

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

ÈçͼËùʾ£¬Ïà¾àΪd¡¢°å¼äµçѹΪUµÄƽÐнðÊô°åM¡¢N¼äÓд¹Ö±Ö½ÃæÏòÀï¡¢´Å¸ÐӦǿ¶ÈΪB0µÄÔÈÇ¿´Å³¡£»ÔÚpOyÇøÓòÄÚÓд¹Ö±Ö½ÃæÏòÍâ¡¢´Å¸ÐӦǿ¶ÈΪBµÄÔÈÇ¿´Å³¡£»ÕâpOxÇøÓòΪÎÞ³¡Çø£®Ò»ÕýÀë×ÓÑØƽÐÐÓÚ½ðÊô°å¡¢´¹Ö±´Å³¡ÉäÈËÁ½°å¼ä²¢×öÔÈËÙÖ±ÏßÔ˶¯£¬´ÓH£¨0£¬a£©µã´¹Ö±yÖá½øÈëµÚIÏóÏÞ£¬¾­OpÉÏijµãÀ뿪´Å³¡£¬×îºó´¹Ö±xÖáÀ뿪µÚIÏóÏÞ£®Çó£º
£¨1£©Àë×ÓÔÚ½ðÊô°åM¡¢N¼äµÄÔ˶¯Ëٶȣ»
£¨2£©Àë×ӵĺÉÖʱÈ
q
m
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

Èçͼ£¬ÔÚÊúÖ±ÏòÉϵÄÔÈÇ¿µç³¡ÖУ¬ÓÐÒ»¸öÖÊÁ¿Îªm´øµçÁ¿ÎªqµÄСÇò£®Ð¡Çò×ÔÀëµØÃæh¸ß¶È´¦ÒÔ³õËÙ¶ÈvˮƽÅ׳öºó£¬×öÔÈËÙÖ±ÏßÔ˶¯£¬ÖØÁ¦¼ÓËÙ¶ÈΪg£®
£¨1£©ÊÔÅжÏСÇòµÄµçÐÔ²¢Çó³ö³¡Ç¿EµÄ´óС
£¨2£©ÈôÔÚ´Ë¿Õ¼äÔÙ¼ÓÒ»¸ö´¹Ö±Ö½ÃæµÄÔÈÇ¿´Å³¡£¬Ð¡ÇòÈÔÒÔÏàͬ·½Ê½Ë®Æ½Å׳ö£¬×ÔÅ׳öµ½µÚÒ»´ÎÂäµØµãPµÄˮƽλÒÆOP=x£¬ÒÑÖªx´óÓÚh£®ÊÔÅжϴŸÐӦǿ¶ÈBµÄ·½Ïò²¢Çó³öBµÄ´óС£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

ÈçͼaËùʾ£¬Óëˮƽ·½Ïò³É37¡ã½ÇµÄÖ±ÏßMNÏ·½ÓÐÓëMN´¹Ö±ÏòÉϵÄÔÈÇ¿µç³¡£¬ÏÖ½«Ò»ÖØÁ¦²»¼Æ¡¢±ÈºÉ
q
m
=106c/kgµÄÕýµçºÉÖÃÓڵ糡ÖеÄOµãÓɾ²Ö¹ÊÍ·Å£¬¾­¹ý
¦Ð
15
¡Á10-5sºó£¬µçºÉÒÔv0=1.5¡Ál04m/sµÄËÙ¶Èͨ¹ýMN½øÈëÆäÉÏ·½µÄÔÈÇ¿´Å³¡£¬´Å³¡ÓëÖ½Ãæ´¹Ö±£¬´Å¸ÐӦǿ¶ÈB°´Í¼bËùʾ¹æÂÉÖÜÆÚÐԱ仯£¨Í¼bÖдų¡ÒÔ´¹Ö±Ö½ÃæÏòÍâΪÕý£¬ÒÔµçºÉµÚÒ»´Îͨ¹ýMNʱΪt=0ʱ¿Ì£©£®Çó£º
£¨1£©ÔÈÇ¿µç³¡µÄµç³¡Ç¿¶ÈE£»
£¨2£©Í¼bÖÐt=
4¦Ð
5
¡Á10-5sʱ¿ÌµçºÉÓëµÚÒ»´Îͨ¹ýMNµÄλÖÃÏà¾à¶àÔ¶£»
£¨3£©Èç¹ûµçºÉµÚÒ»´Îͨ¹ýMNµÄλÖõ½NµãµÄ¾àÀëd=68cm£¬ÔÚNµãÉÏ·½ÇÒ´¹Ö±MN·ÅÖÃ×ã¹»´óµÄµ²°å£®ÇóµçºÉ´ÓOµã³ö·¢Ô˶¯µ½µ²°åËùÐèµÄʱ¼ä£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

Èçͼ¼×Ëùʾ£¬MNºÍPQÊÇÁ½¿é¹â»¬µ²°å£¬Á½°åƽÐзÅÖ㬰å¼ä¾àΪd=0.15m£¬A¡¢CÊÇMN°åÉÏÏà¾àl=0.2mµÄÁ½¸öС¿×£®ÖÊÁ¿Îªm=2¡Á10-12kg£¬´øµçÁ¿Îªq=+5¡Á10-8CµÄÁ£×Ó£¨¿ÉÒÔ¿´³ÉµãµçºÉ£©´ÓAµãÒÔËÙ¶Èv=3¡Á103m/sµÄËٶȴ¹Ö±ÓÚMN°åÉäÈ룬Á£×ÓÓëÁ½°åµÄÅöײΪµ¯ÐÔÅöײ£¨Á£×ÓÅöײǰºóÑØ°å·½ÏòµÄËٶȲ»±ä£¬´¹Ö±ÓÚ°åµÄËٶȴóС²»±ä£¬·½Ïò±äΪ·´Ïò£©£¬´øµçÁ£×ÓµÄÖØÁ¦²»¼Æ£®Ôò
£¨1£©ÈôÁ½°å¼äÓÐÓë°åÃæƽÐеÄÔÈÇ¿µç³¡£¬Èçͼ¼×£¬ÇÒÁ£×ÓÖ»ÓëPQ°åÅöײһ´Î¾Í´ÓCµã·É³ö£¬ÇóÔÈÇ¿µç³¡µÄµç³¡Ç¿¶ÈµÄ´óС£»
£¨2£©ÈôÁ½°å¼äÓÐÈçͼÒÒËùʾµÄÔÈÇ¿´Å³¡£¬ÒªÊ¹Á£×ÓÄÜ´ÓCµã·É³ö£¬Çó´Å¸ÐӦǿ¶ÈµÄ¿ÉÄÜÈ¡Öµ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

ÈçͼËùʾ£¬ÔÚyÖáÉÏAµãÑØƽÐÐxÖáÕý·½ÏòÒÔv0·¢ÉäÒ»¸ö´øÕýµçµÄÁ£×Ó£¬Ôڸ÷½ÏòÉϾàAµã3R´¦µÄBµãΪԲÐÄ´æÔÚÒ»¸ö°ë¾¶ÎªRµÄÔ²ÐÎÓнçµÄÔÈÇ¿´Å³¡£¬´Å³¡·½Ïò´¹Ö±Ö½ÃæÏòÍ⣬µ±Á£×Óͨ¹ý´Å³¡ºó´òµ½xÖáÉϵÄCµã£¬ÇÒËٶȷ½ÏòÓëxÖáÕýÏò³É60¡ã½ÇбÏòÏ£¬ÒÑÖª´øµçÁ£×ӵĵçÁ¿Îªq£¬ÖÊÁ¿Îªm£¬Á£×ÓµÄÖØÁ¦ºöÂÔ²»¼Æ£¬Oµãµ½AµãµÄ¾àÀëΪ2
3
R£®Çó£º
£¨1£©¸Ã´Å³¡µÄ´Å¸ÐӦǿ¶ÈBµÄ´óС
£¨2£©Èô³·µô´Å³¡£¬ÔÚ¸ÃƽÃæÄÚ¼ÓÉÏÒ»¸öÓëyÖáƽÐеÄÓнçÔÈÇ¿µç³¡£¬Á£×ÓÈÔ°´Ô­·½ÏòÈëÉ䣬µ±Á£×Ó½øÈëµç³¡ºóÒ»Ö±Ôڵ糡Á¦µÄ×÷ÓÃÏ´òµ½xÖáÉϵÄCµãÇÒËٶȷ½ÏòÈÔÓëxÖáÕýÏò³É60¡ã½ÇбÏòÏ£¬Ôò¸Ãµç³¡µÄ×ó±ß½çÓëyÖáµÄ¾àÀëΪ¶àÉÙ£¿
£¨3£©Èô³·µôµç³¡£¬ÔÚ¸ÃƽÃæÄÚ¼ÓÉÏÒ»¸öÓ루1£©ÎʴŸÐӦǿ¶È´óСÏàͬµÄ¾ØÐÎÓнçÔÈÇ¿´Å³¡£¬´Å³¡·½Ïò´¹Ö±Ö½ÃæÏòÀÁ£×ÓÈÔ°´Ô­·½ÏòÈëÉ䣬ͨ¹ý¸Ã´Å³¡ºó´òµ½xÖáÉϵÄCµãÇÒËٶȷ½ÏòÈÔÓëxÖáÕýÏò³É60¡ã½ÇбÏòÏ£¬ÔòËù¼Ó¾ØÐδų¡µÄ×îСÃæ»ýΪ¶àÉÙ£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

ͼÖÐ×ó±ßÓÐÒ»¶ÔƽÐнðÊô°å£¬Á½°åÏà¾àΪd£¬µçѹΪU£¬Á½°åÖ®¼äÓÐÔÈÇ¿´Å³¡£¬´Å¸ÐӦǿ¶È´óСΪB0£¬·½ÏòÓë½ðÊô°åÃæƽÐв¢´¹Ö±ÓÚÖ½Ã泯ÀͼÖÐÓÒ±ßÓÐÒ»°ë¾¶ÎªR¡¢Ô²ÐÄΪOµÄÔ²ÐÎÇøÓò£¬ÇøÓòÄÚÒ²´æÔÚÔÈÇ¿´Å³¡£¬´Å¸ÐӦǿ¶È´óСΪB£¬·½Ïò´¹Ö±ÓÚÖ½Ã泯ÀһÖÊÁ¿ÎªmµÄÕýÀë×ÓÑØƽÐÐÓÚ½ðÊô°åÃæ¡¢´¹Ö±Óڴų¡µÄ·½ÏòÉäÈëƽÐнðÊô°åÖ®¼ä£¬ÑØͬһ·½ÏòÉä³öƽÐнðÊô°åÖ®¼äµÄÇøÓò£¬²¢ÑØÖ±¾¶EF·½ÏòÉäÈë´Å³¡ÇøÓò£¬×îºó´ÓÔ²ÐÎÇøÓò±ß½çÉϵÄGµãÉä³ö£®ÒÑÖª»¡
FG
Ëù¶ÔÓ¦µÄÔ²ÐĽÇΪ¦È£¬²»¼ÆÖØÁ¦£®
Ç󣺣¨1£©Àë×ÓËÙ¶ÈvµÄ´óС£»
£¨2£©Àë×ӵĵçÁ¿qµÈÓÚ£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

ÈçͼËùʾ£¬Ò»¶ÔÊúÖ±·ÅÖõÄƽÐнðÊô°å³¤ÎªL£¬Á½°å¼ä¾àΪd£¬½ÓÔÚÖ±Á÷µçÔ´ÉÏ£¬Á½°å¼äµÄÔÈÇ¿µç³¡³¡Ç¿ÎªE£®ÔÚÁ½°å¼ä»¹ÓÐÓëµç³¡·½Ïò´¹Ö±µÄÔÈÇ¿´Å³¡£¬´Å¸ÐӦǿ¶ÈΪB£¬·½Ïò´¹Ö±Ö½Æ½ÃæÏòÀһ¸öÖÊÁ¿Îªm£¬µçÁ¿Îªq£¨q£¾0£©µÄÓ͵Σ¬´Ó¾àÀëƽ°åÉ϶ËΪh¸ß´¦Óɾ²Ö¹¿ªÊ¼×ÔÓÉÏÂÂ䣮²¢¾­Á½°åÉ϶˵ÄÖÐÑëµãP½øÈëÁ½°åÖ®¼äÓе糡ºÍ´Å³¡µÄ¿Õ¼ä£®ÉèÓ͵ÎÔÚPµãËùÊܵĵ糡Á¦Óë´Å³¡Á¦Ç¡ºÃƽºâ£¬ÇÒÓ͵ξ­Pµãºó²»¶ÏÏòÓÒ¼«°åƫת£¬×îºó¾­ÓÒ¼«°å϶˱ßÔµµÄDµãÀ뿪Á½°åÖ®Îʵĵ糡ºÍ´Å³¡ÇøÓò£®ÊÔÇó£º
£¨1£©hµÄ´óС£»
£¨2£©Ó͵ÎÔÚDµãµÄËٶȴóС£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸