ÈçͼËùʾ£¬ÔÚÊúÖ±Æ½ÃæÄڹ̶¨µÄÔ²ÐξøÔµ¹ìµÀµÄÔ²ÐÄÔÚOµã¡¢°ë¾¶Îªr£¬Äڱڹ⻬£¬A¡¢BÁ½µã·Ö±ðÊÇÔ²»¡µÄ×îµÍµãºÍ×î¸ßµã¡£¸ÃÇø¼ä´æÔÚ·½ÏòˮƽÏòÓÒµÄÔÈÇ¿µç³¡£¬Ò»ÖÊÁ¿Îªm¡¢´ø¸ºµçµÄСÇòÔÚ¹ìµÀÄÚ²à×öÍêÕûµÄÔ²ÖÜÔ˶¯(µçºÉÁ¿²»±ä)£¬¾­CµãʱËÙ¶È×î´ó£¬O¡¢CÁ¬ÏßÓëÊúÖ±·½ÏòµÄ¼Ð½Ç¦È=60¡ã£¬ÖØÁ¦¼ÓËÙ¶ÈΪg¡£

(1)ÇóСÇòËùÊܵ½µÄµç³¡Á¦´óС£»

(2)СÇòÔÚAµãËÙ¶Èv0¶à´óʱ£¬Ð¡Çò¾­Bµãʱ¶Ô¹ìµÀµÄѹÁ¦×îС£¿


(1)ÒÑÖª´øµçСÇòÔڹ⻬µÄÊúÖ±Ô²¹ìµÀÄÚ×öÍêÕûµÄÔ²ÖÜÔ˶¯£¬¾­CµãʱËÙ¶È×î´ó£¬Òò´Ë£¬CµãÊÇÊúÖ±ÃæÄÚÔ²ÖÜÔ˶¯µÄÎïÀí¡°×îµÍµã¡±£¬Ò²¾ÍÊÇСÇòÔÚCµãÊÜÁ¦Çé¿öÂú×ãºÏÍâÁ¦ÍêÈ«³äµ±ÏòÐÄÁ¦£¬tan¦È=                                    (3·Ö)

Òò´Ë£¬µç³¡Á¦F=mgtan60¡ã

¼´F=mg                                                                                                                      (2·Ö)

(2)СÇòÔÚ¹ìµÀ×î¸ßµãBʱµÄÊÜÁ¦Çé¿öÈçͼËùʾ£¬

ÔÚBµãʱ¹ìµÀ¶ÔСÇòµÄѹÁ¦×îСµÈÓÚÁã¡£°ë¾¶·½ÏòµÄºÏÍâÁ¦ÎªÖØÁ¦mg£¬ÔÚBµã£¬¸ù¾ÝÔ²ÖÜÔ˶¯µÄÌõ¼þ¿ÉµÃ£¬

mg=m                                                                                                                      (3·Ö)

СÇò´ÓAµ½B¹ý³ÌÖУ¬Ö»Óе糡Á¦ºÍÖØÁ¦×öÁ˹¦£¬ÓÖÖªA¡¢BÁ½µãÔÚͬһµÈÊÆÃæÉÏ£¬¸Ã¹ý³Ìµç³¡Á¦×ö¹¦ÎªÁ㣬¸ù¾Ý¶¯Äܶ¨Àí¿ÉµÃ£¬

-mg¡¤2r=                                                                                                     (2·Ö)

ÁªÁ¢ÒÔÉÏÁ½Ê½¿ÉµÃv0=                                                                                         (2·Ö)

´ð°¸£º(1)mg  (2)


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º


ÈçͼËùʾ£¬ÓÐÈý¸öµç×裬ÒÑÖªR1¡ÃR2¡ÃR3£½1¡Ã3¡Ã6£¬Ôòµç·¹¤×÷ʱ£¬µçѹU1¡ÃU2Ϊ

A£®1¡Ã6¡¡  B£®1¡Ã9¡¡¡¡C£®1¡Ã3¡¡  D£®1¡Ã2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º


ÈçͼËùʾ£¬ÔÚͬһƽ̨ÉϵÄOµãˮƽÅ׳öµÄÈý¸öÎïÌ壬·Ö±ðÂäµ½a¡¢b¡¢cÈýµã£¬ÔòÈý¸öÎïÌåÔ˶¯µÄ³õËÙ¶Èva¡¢vb¡¢vcµÄ¹ØÏµºÍÈý¸öÎïÌåÔ˶¯µÄʱ¼äta¡¢tb¡¢tcµÄ¹ØÏµÊÇ(¡¡¡¡)

A. va>vb>vc¡¡ta>tb>tc     B. va<vb<vc   ta£½tb£½tc                                                                        

C. va<vb<vc¡¡ta>tb>tc     D. va>vb>vc¡¡ta<tb<tc

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º


Ì«¿ÕÉî´¦ÓÐÒ»¾ùÔÈ´ø¸ºµçµÄÐÇÇòP£¬ÓÐÒ»Ò²´ø¸ºµçµÄ¼«Ð¡ÐÇÌåQÑØÈçͼËùʾµÄ·¾¶ABCÂÓ¹ýÐÇÇò£¬BµãÊÇÁ½ÕßµÄ×î½üµã¡£ºöÂÔÆäËûÌìÌåµÄÓ°Ï죬Ô˶¯¹ý³ÌÖÐÍòÓÐÒýÁ¦Ê¼ÖÕ´óÓÚ¾²µçÁ¦¡£Ôò

A£®¼«Ð¡ÐÇÌåQÔÚAµãµÄ¶¯ÄܱÈBµã´ó

B£¬¼«Ð¡ÐÇÌåQÔÚAµãµÄµçÊÆÄܱÈBµã´ó

C£®¼«Ð¡ÐÇÌåQÔÚAµãËùÊܵĵ糡Á¦±ÈBµã´ó

D£®ÐÇÇòP²úÉúµÄµç³¡ÔÚAµãµÄµçÊÆ±ÈBµã¸ß

 


²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º


Ò»ÎïÌå¾²Ö¹ÔÚ´Ö²ÚË®Æ½ÃæÉÏ£¬ÔÚˮƽÏòÓÒµÄÀ­Á¦×÷ÓÃÏ¿ªÊ¼ÏòÓÒÔ˶¯¡£ÔÚÔ˶¯¹ý³ÌÖУ¬ÎïÌåµÄ¶¯ÄÜEkÓëÎ»ÒÆxµÄ¹ØÏµÍ¼ÏóÈçͼËùʾ£¬ÆäÖÐ0-x1¹ý³ÌµÄͼÏßÊǹýÔ­µãµÄÖ±Ïߣ¬x1-x2¹ý³ÌµÄͼÏßΪƽÐÐÓÚºá×ø±êÖáµÄÖ±Ïß¡£ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£º

A. ÔÚ0-x1¹ý³ÌÖУ¬ÎïÌåµÄÀ­Á¦²»¶ÏÔö´ó

B. ÔÚx1-x2¹ý³ÌÖУ¬À­Á¦×ö¹¦ÎªÁã

C. ÔÚ0-x2¹ý³ÌÖУ¬ÎïÌåµÄ»úеÄܲ»¶ÏÔö´ó

D. ÔÚ0-x2¹ý³ÌÖУ¬ÎïÌå¿Ë·þĦ²ÁÁ¦×ö¹¦µÄ¹¦ÂÊÏÈÔö´óºó±£³Ö²»±ä

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º


ÖÊÁ¿ÎªmµÄÎïÌå·ÅÔÚÇã½ÇΪ¦ÁµÄ¹â»¬Ð±ÃæÉÏ£¬ËæÐ±ÃæÌåÒ»ÆðÑØË®Æ½·½ÏòÔ˶¯£¬ÒªÊ¹ÎïÌåÏà¶ÔÓÚÐ±Ãæ±£³Ö¾²Ö¹£¬Ð±ÃæÌåµÄÔ˶¯Çé¿öÒÔ¼°ÎïÌå¶ÔÐ±ÃæÑ¹Á¦FµÄ´óСÊÇ £¨      £©

A.Ð±ÃæÌåÒÔijһ¼ÓËÙ¶ÈÏòÓÒ¼ÓËÙÔ˶¯£¬FСÓÚmg

B£®Ð±ÃæÌåÒÔijһ¼ÓËÙ¶ÈÏòÓÒ¼ÓËÙÔ˶¯£¬F²»Ð¡ÓÚmg

C.Ð±ÃæÌåÒÔijһ¼ÓËÙ¶ÈÏò×ó¼ÓËÙÔ˶¯£¬F´óÓÚmg

D£®Ð±ÃæÌåÒÔijһ¼ÓËÙ¶ÈÏò×ó¼ÓËÙÔ˶¯£¬F²»´óÓÚmg

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º


½«µØÃæÉϾ²Ö¹µÄ»õÎïÊúÖ±ÏòÉϵõÆð£¬»õÎïÓɵØÃæÔ˶¯ÖÁ×î¸ßµãµÄ¹ý³ÌÖУ¬Í¼ÏñÈçͼËùʾ¡£ÒÔÏÂÅжÏÕýÈ·µÄÊÇ£¨    ¡¡£©

A£®Ç°3sÄÚ»õÎï´¦ÓÚ³¬ÖØ×´Ì¬

B£®×îºó2sÄÚ»õÎïÖ»ÊÜÖØÁ¦×÷ÓÃ

C£®Ç°3sÄÚÓë×îºó2sÄÚ»õÎïµÄƽ¾ùËÙ¶ÈÏàͬ

D£®µÚ3sÄ©ÖÁµÚ5sÄ©µÄ¹ý³ÌÖУ¬»õÎïµÄ»úеÄÜÊØºã

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º


Ò»¶¨Á¿µÄÀíÏëÆøÌåÔÚijһ¹ý³ÌÖУ¬´ÓÍâ½çÎüÊÕÈÈÁ¿2.5¡Á104J£¬ÆøÌå¶ÔÍâ½ç×ö¹¦1.0¡Á104J£¬Ôò¸ÃÀíÏëÆøÌåµÄ£¨ÌîÑ¡ÏîǰµÄ×Öĸ£©£¨¡¡¡¡£©

¡¡  A£®Î¶ȽµµÍ£¬ÃܶÈÔö´ó                   B£® ζȽµµÍ£¬ÃܶȼõС

¡¡  C£®Î¶ÈÉý¸ß£¬ÃܶÈÔö´ó                   D£® ζÈÉý¸ß£¬ÃܶȼõС

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º


R1ºÍR2·Ö±ð±êÓС°2¦¸¡¢1.0A¡±ºÍ¡°4¦¸¡¢0.5A¡±£¬½«ËüÃÇ´®Áªºó½ÓÈëµç·ÖУ¬ÈçͼËùʾ£¬Ôò´Ëµç·ÖÐÔÊÐíÏûºÄµÄ×î´ó¹¦ÂÊΪ£¨¡¡¡¡£©

¡¡

A£®

6.0 W

B£®

5.0 W

C£®

3.0 W

D£®

1.5 W

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸