Question

2£®ÈçͼËùʾ£¬ÖÊÁ¿Îª5¡Á10^-8kg£¬µçÁ¿Îª-2¡Á10^-12CµÄ´øµçÁ£×ÓÒÔ2m/sËٶȴÓˮƽ·ÅÖõÄƽÐнðÊô°åA¡¢BÖÐÑëÑØˮƽ·½Ïò·ÉÈë°å¼ä£¬ÈçͼËùʾ£®ÒÑÖª°å³¤L=10cm£¬¼ä¾àd=2cm£®
£¨1£©Èô²»¿¼ÂÇ´øµçÁ£×ÓµÄÖØÁ¦£¬µ±U_ABΪ1000Vʱ£¬ÇóÁ£×Ó¸ÕÀ뿪ƫתµç³¡Ê±ËÙ¶ÈVµÄ´óСºÍËٶȵÄƫת·½Ïò£¨ÓÃÆ«½Ç¦ÕµÄÕýÇÐÖµ±íʾ£©£¿
£¨2£©Èô¿¼ÂÇ´øµçÁ£×ÓµÄÖØÁ¦£¬µ±U_ABΪ1600Vʱ£¬ÇóÁ£×Ó¸ÕÀ뿪ƫתµç³¡Ê±µÄƫתλÒÆ£¿£¨g=10N/kg£©

Answer 1

·ÖÎö £¨1£©²»¿¼ÂÇÖØÁ¦£¬µç³¡Á¦ÏòÉÏ£¬×öÀàËÆƽÅ×Ô˶¯£¬¸ù¾ÝÀàËÆƽÅ×Ô˶¯µÄ·ÖÔ˶¯¹«Ê½ÁÐʽÇó½â£»
£¨2£©ÏÈÊÜÁ¦·ÖÎö£¬¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÇó½â¼ÓËٶȣ¬È»ºóÔËÓÃÕý½»·Ö½â·¢Çó½â£®

½â´ð ½â£º£¨1£©Á£×Ó×öÀàËÆƽÅ×Ô˶¯£¬µç³¡Á¦ÏòÉÏ£¬¹ÊÏòÉÏƫת£»
ˮƽ·½Ïò£ºL=v₀t
½âµÃ£ºt=$\frac{L}{{v}_{0}}=\frac{0.1m}{2m/s}=0.05s$
ÊúÖ±·½Ïò£º${v}_{y}=at=\frac{q{U}_{AB}}{md}t=\frac{2¡Á1{0}^{-12}¡Á1000}{5¡Á1{0}^{-8}¡Á0.02}¡Á0.05m/s$=0.1m/s
¹ÊºÏËٶȣº$v=\sqrt{{v}_{0}^{2}+{v}_{y}^{2}}=\sqrt{{2}^{2}+{0.1}^{2}}m/s¡Ö2m/s$
ÓëÊúÖ±·½Ïò¼Ð½ÇµÄÕýÇÐֵΪ£ºtan¦Á=$\frac{{v}_{y}}{{v}_{x}}=\frac{0.1}{2}=0.05$£¬¹Ê¦Á¡Ö5¡ã£»
£¨2£©¿¼ÂÇÁ£×ÓµÄÖØÁ¦£¬µç³¡Á¦ÎªF=qE=$\frac{q{U}_{AB}}{md}$=$\frac{2¡Á1{0}^{-12}¡Á1600}{5¡Á1{0}^{-8}¡Á0.02}$=3.2N£¬ÖØÁ¦ÎªG=mg=5¡Á10^-7N£»
ÓÉÓÚF£¾£¾G£¬¹Ê¿ÉÒÔ²»¿¼ÂÇÖØÁ¦£»
²àÒÆÁ¿Îª£ºy=$\frac{1}{2}a{t}^{2}$=$\frac{1}{2}\frac{F}{m}{t}^{2}$=$\frac{1}{2}¡Á\frac{3.2}{5¡Á1{0}^{-8}}¡Á0.0{5}^{2}$m=8¡Á10⁴m
´ð£º£¨1£©Èô²»¿¼ÂÇ´øµçÁ£×ÓµÄÖØÁ¦£¬µ±U_ABΪ1000Vʱ£¬Á£×Ó¸ÕÀ뿪ƫתµç³¡Ê±ËÙ¶ÈVµÄ´óСΪ0.1m/s£¬ËٶȵÄƫת½Ç¶ÈΪ5¡ã£»
£¨2£©Èô¿¼ÂÇ´øµçÁ£×ÓµÄÖØÁ¦£¬µ±U_ABΪ1600Vʱ£¬Á£×Ó¸ÕÀ뿪ƫתµç³¡Ê±µÄƫתλÒÆΪ8¡Á10⁴m£®

µãÆÀ ±¾Ì⿼²éÖØÁ¦Óëµç³¡Á¦´óСµÄ¹Øϵ£¬ºÎʱ×öÖ±ÏßÔ˶¯£¬ºÎʱ×öÇúÏßÔ˶¯£¬¼°ÈçºÎ´¦ÀíÀàƽÅ×Ô˶¯·½·¨£®Í»³öÅ£¶ÙµÚ¶þ¶¨ÂÉÓëÔ˶¯Ñ§¹«Ê½µÄÖØÒªÐÔ£®