Question

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(1)СÎï¿éÓëбÃæ¼äµÄ¶¯Ä¦²ÁÒòÊý¦Ì₂;

(2)ҪʹÎï¿éÔÚµØÃæÉϵÄÂäµãP¾àÕÏ°­ÎïQ×îÔ¶,ˮƽÍÆÁ¦FΪ¶à´ó;

(3)СÎï¿éÔÚµØÃæÉϵÄÂäµãP¾àÕÏ°­ÎïQµÄ×îÔ¶¾àÀë¡£

Answer 1

¡¾½âÎö¡¿(1)¶ÔmÓÉƽºâÌõ¼þµÃ:

mgsin¦È-¦Ì₂mgcos¦È=0¡¡                                     (2·Ö)

½âµÃ:¦Ì₂=tan¦È¡¡                                           (1·Ö)

(2)¶ÔmÉèÆä×î´ó¼ÓËÙ¶ÈΪa_m,ÓÉÅ£¶ÙµÚ¶þ¶¨ÂɵÃ:

ˮƽ·½Ïò:Nsin¦È+¦Ì₂Ncos¦È=ma_m                                                             (2·Ö)

ÊúÖ±·½Ïò:Ncos¦È-¦Ì₂Nsin¦È-mg=0¡¡                           (2·Ö)

½âµÃ:a_m=¡¡                                      (1·Ö)

¶ÔM¡¢mÕûÌåÓÉÅ£¶ÙµÚ¶þ¶¨ÂɵÃ:

F-¦Ì₁(M+m)g=(M+m)a_m                                                                                (2·Ö)

½âµÃ:F=¦Ì₁(M+m)g+(M+m)¡¡                        (1·Ö)

(3)¶ÔM¡¢mÕûÌåÓɶ¯Äܶ¨ÀíµÃ:

Fd-¦Ì₁(M+m)gd=(M+m)v²¡¡                                   (3·Ö)

½âµÃ:v=2¡¡                                    (1·Ö)

¶ÔmÓÉƽÅ×Ô˶¯¹æÂɵÃ:

ˮƽ·½Ïò:x_P+=vt¡¡                                      (2·Ö)

ÊúÖ±·½Ïò:h=gt²¡¡                                         (2·Ö)

½âµÃ:x_P=2-¡¡                              (1·Ö)

´ð°¸:(1)tan¦È

(2)¦Ì₁(M+m)g+(M+m)

(3)2-