·ÖÎö £¨1£©Á£×ÓÔڵ糡ÖÐ×öÔȼÓËÙÖ±ÏßÔ˶¯£¬Óɶ¯Äܶ¨Àí¿ÉÇóµÃÁ£×ÓµÄËÙ¶È£»ÔÙÓÉÔ˶¯µÄºÏ³ÉºÍ·Ö½â¿ÉÇóµÃÔ˶¯Ê±¼ä£»
£¨2£©´øµçÀë×ÓÔÚÆ½ÐаåM¡¢NÖ®¼ä×öÀàÆ½Å×Ô˶¯£¬¸ù¾ÝÔ˶¯µÄºÏ³ÉºÍ·Ö½â¿ÉÃ÷È·¹ì¼£µÄ±í´ïʽ£¬Ôò¿ÉÃ÷È·¹ì¼£ÊÇ·ñÖØºÏ£»
£¨3£©µ±MN¼äµÄ´Å¸ÐӦǿ¶È´óСΪBʱ£¬Àë×Ó×öÔ²ÖÜÔ˶¯£¬¸ù¾ÝÔ²ÖÜÔ˶¯µÄ֪ʶºÍ¼¸ºÎ¹ØÏµ¿ÉÇóµÃ´Å¸ÐӦǿ¶ÈµÄ×î´óÖµ£®
½â´ð ½â£º£¨1£©´øµçÀë×ÓÔÚÆ½Ðаåa¡¢bÖ®¼äÔ˶¯Ê±£¬Óɶ¯Äܶ¨ÀíµÃ£ºqU0=$\frac{1}{2}$mv2-0£¬
½âµÃ£ºv=$\sqrt{\frac{2q{U}_{0}}{m}}$£¬¼´£ºv=$\sqrt{2k{U}_{0}}$ ¡¢Ù
´øµçÀë×ÓÔÚÆ½Ðаåa¡¢bÖ®¼äµÄ¼ÓËÙ¶ÈΪ£º
a1=$\frac{q{U}_{0}}{dm}$£¬¼´£ºa1=$\frac{k{U}_{0}}{d}$£®
ËùÒÔ´øµçÀë×ÓÔÚÆ½Ðаåa¡¢bÖ®¼äµÄÔ˶¯Ê±¼äΪ£º
t1=$\frac{v}{{a}_{1}}$$\frac{d\sqrt{2k{U}_{0}}}{k{U}_{0}}$£»
´øµçÀë×ÓÔÚÆ½ÐаåM¡¢NÖ®¼äµÄÔ˶¯Ê±¼äΪ£º
t2=$\frac{L}{v}$=$\frac{L}{\sqrt{2k{U}_{0}}}$£»
ËùÒÔ´øµçÀë×Ó´Óa°åµ½Ì½²âÆ÷µÄ·ÉÐÐʱ¼äΪ£º
t=t1+t2=$\frac{2d+L}{\sqrt{2k{U}_{0}}}$£®
£¨2£©´øµçÀë×ÓÔÚÆ½ÐаåM¡¢NÖ®¼äË®Æ½Î»ÒÆÎªxʱ£¬ÔÚÊúÖ±·½ÏòÎ»ÒÆÎªy£¬
ˮƽ·½ÏòÂú×㣺x=vt£¬
ÊúÖ±·½ÏòÂú×㣺y=$\frac{1}{2}$a2t2£¬
¼ÓËÙ¶Èa2=$\frac{k{U}_{1}}{L}$£¬
ÁªÁ¢½âµÃ£ºy=$\frac{{U}_{1}{x}^{2}}{4L{U}_{0}}$ ¡¢Ú
¢ÚʽÊÇÕýÀë×ӵĹ켣·½³Ì£¬ÓëÕýÀë×ÓµÄÖÊÁ¿ºÍµçºÉÁ¿¾ùÎÞ¹ØÏµ£¬ËùÒÔ²»Í¬ÕýÀë×ӵĹ켣ÊÇÖØºÏµÄ£®
£¨3£©µ±M¡¢N¼ä´Å¸ÐӦǿ¶È´óСΪBʱ£¬Àë×Ó×öÔ²ÖÜÔ˶¯£¬Âú×㣺Bvq=$\frac{m{v}^{2}}{R}$¡¢Û
ÁªÁ¢¢Ù¢ÛÁ½Ê½½âµÃ£º´øµçÀë×ӵĹìµÀ°ë¾¶Îª£ºR=$\sqrt{\frac{2{U}_{0}m}{{B}^{2}q}}$¡¢Ü
ÉÏʽ±íÃ÷£ºÔÚÀë×ÓÖÊÁ¿Ò»¶¨µÄÇé¿öÏ£¬Àë×ӵĵçºÉÁ¿Ô½´ó£¬Ôڴų¡ÖÐ×öÔ²ÖÜÔ˶¯µÄ°ë¾¶Ô½Ð¡£¬Ò²¾ÍÔ½²»ÈÝÒ×´©¹ý·½ÐÎÇø´ÓÓÒ²à·É³ö£®
ËùÒÔ£¬ÒªÊ¹ËùÓеÄÒ»¼ÛºÍ¶þ¼ÛÕýÀë×Ó¾ùÄÜͨ¹ý·½ÐÎÇø´ÓÓÒ²à·É³ö£¬Ö»Òª¶þ¼ÛÕýÀë×ÓÄÜ´Ó·½ÐÎÇø·É³ö¼´¿É£®
µ±¶þ¼ÛÕýÀë×Ó¸ÕºÃÄÜ´Ó·½ÐÎÇøÓò·É³öʱµÄ´Å¸ÐӦǿ¶ÈΪÂú×ãÌâÄ¿Ìõ¼þµÄ´Å¸ÐӦǿ¶ÈµÄ×î´óÖµ
Éèµ±Àë×Ó¸ÕºÃͨ¹ý·½ÐÎÇø´ÓÓÒ²à·É³öʱµÄ¹ìµÀ°ë¾¶ÎªR£¬
Óɼ¸ºÎ¹ØÏµµÃ£¬R2=L2+£¨R-$\frac{L}{2}$£©2£¬
½âµÃ£ºR=$\frac{5L}{4}$¡¢Ý
½«¶þ¼ÛÕýÀë×ӵĵçÁ¿2e´úÈë¢ßʽµÃ£ºR=$\sqrt{\frac{{U}_{0}m}{{B}^{2}e}}$¡¢Þ
ÁªÁ¢¢à¢á¿É½âµÃ£ºB=$\frac{4}{5L}$$\sqrt{\frac{{U}_{0}m}{e}}$£¬´ËÖµ¼´ÎªËùÇóµÄ´Å¸ÐӦǿ¶ÈµÄ×î´óÖµBm£®
´ð£º£¨1£©Àë×Ó´Óa°åµ½Ì½²âÆ÷µÄ·ÉÐÐʱ¼ät=$\frac{2d+L}{\sqrt{2k{U}_{0}}}$£»
£¨2£©ÈôÔÚM¡¢N¼äÖ»¼ÓÉÏÆ«×ªµçѹU1£¬ÕýÀë×ӵĹ켣·½³Ì£¬ÓëÕýÀë×ÓµÄÖÊÁ¿ºÍµçºÉÁ¿¾ùÎÞ¹ØÏµ£¬ËùÒÔ²»Í¬ÕýÀë×ӵĹ켣ÊÇÖØºÏµÄ£»
£¨3£©ÒªÊ¹ËùÓÐÕýÀë×Ó¾ùÄÜͨ¹ý·½ÐÎÇøÓò´ÓÓÒ²à·É³ö£¬Ëù¼Ó´Å³¡µÄ´Å¸ÐӦǿ¶ÈµÄ×î´óÖµÊÇ$\frac{4}{5L}$$\sqrt{\frac{{U}_{0}m}{e}}$£®
µãÆÀ ±¾Ì⿼²éÁ˵çºÉµÄ¼ÓËÙÓëµçºÉµÄƫת£¬¹Ø¼ü½«µçºÉµÄƫת½øÐзֽ⣬֪µÀÔÚˮƽ·½ÏòºÍÊúÖ±·½ÏòÉϵÄÔ˶¯¹æÂÉ£¬¹Ø¼üÒª°Ñ¶¯Äܶ¨Àí¡¢ÀàÆ½Å×Ô˶¯¹æÂÉ¡¢Å£¶ÙÔ˶¯¶¨Âɼ°ÆäÏà¹ØÖªÊ¶½áºÏ½â´ð£®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | OµãµÄ³¡Ç¿·½ÏòˮƽÏòÓÒ | |
| B£® | ÔÚ¶ÌÖáMNÉÏ£¬OµãµÄµçÊÆ×î¸ß | |
| C£® | ½«Ò»ÕýµÄÊÔ̽µçºÉÓÉMµãÒÆ¶¯µ½Oµã£¬µç³¡Á¦×ö¸º¹¦ | |
| D£® | ½«Ò»¸ºµÄÊÔ̽µçºÉÓÉOµãÒÆ¶¯µ½Nµã£¬ÊÔ̽µçºÉµÄµçÊÆÄܱä´ó |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ÎïÌå¾²Ö¹ÔÚˮƽ×ÀÃæÉÏ£¬ÎïÌå¶Ô×ÀÃæµÄѹÁ¦¾ÍÊÇÎïÌåÊܵ½µÄÖØÁ¦ | |
| B£® | ÐÎ×´¹æÔòµÄÎïÌåµÄÖØÐÄÒ»¶¨ÔÚÆä¼¸ºÎÖÐÐÄÉÏ | |
| C£® | ÖØÐÄÒ»¶¨ÔÚÎïÌåµÄ¼¸ºÎÖÐÐÄ£¬ÓëÎïÌåÄÚ²¿µÄÖÊÁ¿·Ö²¼ÎÞ¹Ø | |
| D£® | ÓÃÒ»Öñ¸Í²¦¶¯Ë®ÖеÄľͷ£¬Ä¾Í·Êܵ½Öñ¸ÍÍÆÁ¦£¬ÊÇÓÉÓÚÖñ¸Í·¢ÉúÐÎ±ä¶ø²úÉúµÄ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | MµãµÄ³¡Ç¿½ÏN´ó | |
| B£® | MµãµçÊÆ½ÏNµÍ | |
| C£® | ÕýµçºÉ´ÓMµãÒÆÖÁNµãʱ£¬ÆäµçÊÆÄܼõÉÙ | |
| D£® | Òª±È½ÏM¡¢NÄÄÒ»µãµçÊÆ¸ß£¬ÓëÁãµçÊÆµÄÑ¡ÔñÓÐ¹Ø |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | µ¼Ìå°ôÖеçÁ÷Ϊ$\frac{E}{{R}_{2}+r{+R}_{1}}$ | B£® | Çᵯ»ÉµÄ³¤¶ÈÔö¼Ó$\frac{BLE}{k£¨r{+R}_{1}£©}$ | ||
| C£® | Çᵯ»ÉµÄ³¤¶È¼õÉÙ$\frac{BLE}{k£¨r{+R}_{1}£©}$ | D£® | µçÈÝÆ÷´øµçÁ¿Îª$\frac{E}{r{+R}_{1}}$CR |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | EA£¼EC | B£® | EB£¾EA | C£® | ¦ÕA£¾ϕC | D£® | ϕB£¾¦ÕA |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com