·ÖÎö £¨1£©¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÇó½ðÊô¿éÔȼÓËÙÔ˶¯µÄ¼ÓËÙ¶È£»
£¨2£©½ðÊô¿éÀ뿪ƽ̨×öƽÅ×Ô˶¯£¬¸ù¾ÝÊúÖ±¸ß¶ÈÇó³öʱ¼ä¼°ÊúÖ±·ÖËÙ¶È£¬ÔÙ¸ù¾Ý¼¸ºÎ¹ØÏµÇó³öˮƽ·ÖËÙ¶È£»
£¨3£©Çó³ö³·È¥FºóÔȼõËÙÔ˶¯µÄ¼ÓËÙ¶È£¬¶ÔǰºóÁ½¸ö¹ý³ÌÔËÓÃËÙ¶ÈÎ»ÒÆ¹«Ê½ÁÐʽ¼´¿ÉÇó³öÀÁ¦F³·È¥ºóÔÚÆ½Ì¨ÉÏ»¬ÐоàÀ룻
½â´ð ½â£º£¨1£©ÉèÆ½Ì¨¶Ô½ðÊô¿éµÄÖ§³ÖÁ¦Îª${F}_{N}^{\;}$£¬½ðÊô¿é¶Ôƽ̨µÄ¶¯Ä¦²ÁÒòÊýΪ¦Ì£¬ËùÒÔÓУº
$Fcos¦È-f=m{a}_{1}^{\;}$
$mg=Fsin¦È+{F}_{N}^{\;}$
$f=¦Ì{F}_{N}^{\;}$
½âµÃ£º${a}_{1}^{\;}=6m/{s}_{\;}^{2}$
£¨2£©¸ù¾ÝƽÅ×Ô˶¯µÄ·ÖÎö¿ÉµÃÊúÖ±·½ÏòÓУº$h=\frac{1}{2}g{t}_{\;}^{2}$
µÃ£º$t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2¡Á3.2}{10}}=0.8s$
${v}_{y}^{\;}=gt=10¡Á0.8=8m/s$
$tan37¡ã=\frac{{v}_{x}^{\;}}{{v}_{y}^{\;}}$=$\frac{{v}_{x}^{\;}}{8}$
½âµÃ£º${v}_{x}^{\;}=6m/s$
£¨3£©Éè³·È¥Fºó£¬Ô˶¯µÄ¼ÓËÙ¶ÈΪ${a}_{2}^{\;}$£¬
$¦Ìmg=m{a}_{2}^{\;}$£¬
¼´£º${a}_{2}^{\;}=¦Ìg$
½âµÃ£º${a}_{2}^{\;}=6m/{s}_{\;}^{2}$
ÉèÔÚÆ½Ì¨ÉÏ×î´óËÙ¶ÈΪv£¬
ÔȼÓËÙÖ±ÏßÔ˶¯¹ý³ÌÎ»ÒÆÎª${x}_{1}^{\;}$£¬ÓУº${x}_{1}^{\;}=\frac{{v}_{\;}^{2}}{2{a}_{1}^{\;}}$
³·È¥FºóÔȼõËÙÖ±ÏßÔ˶¯µÄÎ»ÒÆÎª${x}_{2}^{\;}$£¬ÓУº${x}_{2}^{\;}=\frac{{v}_{x}^{2}-{v}_{\;}^{2}}{-2{a}_{2}^{\;}}$
${x}_{1}^{\;}+{x}_{2}^{\;}=11.25$m
½âµÃ£º${x}_{2}^{\;}=4.5m$
´ð£º£¨1£©½ðÊô¿é×öÔȼÓËÙÖ±ÏßÔ˶¯µÄ¼ÓËÙ¶È´óС${a}_{1}^{\;}$Ϊ$6m/{s}_{\;}^{2}$£»
£¨2£©½ðÊô¿é´Óƽ̨ÉϷɳöµÄËÙ¶È´óС${v}_{x}^{\;}$Ϊ6m/s£»
£¨3£©ÇóÀÁ¦F³·È¥ºóÔÚÆ½Ì¨ÉÏ»¬ÐоàÀë${x}_{2}^{\;}$Ϊ4.5m
µãÆÀ ±¾Ì⿼²é¶à¹ý³ÌÎÊÌ⣬¹Ø¼üÊÇÇå³þ¸÷¸ö¹ý³ÌµÄÔ˶¯Çé¿öºÍÊÜÁ¦Çé¿ö£¬ÖªµÀǰºó¹ý³ÌµÄÏνӣ¬ÔËÓÃÅ£¶ÙÔ˶¯¶¨ÂɺÍÔ˶¯Ñ§¹«Ê½Çó½â£®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | ²¼ÀÊÔ˶¯ÊÇÖ¸Ðü¸¡ÔÚÒºÌåÖеĹÌÌåС¿ÅÁ£µÄÎÞ¹æÔòÈÈÔ˶¯ | |
| B£® | Ç峿ºÉÒ¶ÉϾ§Ó¨ÌÞ͸µÄ¶Öé³ÉÇòÐΣ¬ÊÇË®µÄ±íÃæÕÅÁ¦×÷ÓõĽá¹û | |
| C£® | Ò»¶¨ÖÊÁ¿µÄÀíÏëÆøÌå·¢ÉúµÈα仯ʱ£¬ÆäÄÚÄÜÒ»¶¨²»±ä | |
| D£® | ÏÄÌì´óÆøÑ¹Ç¿Òª±È¶¬ÌìµÄµÍ£¬ÁùÔÂÓëʮһÔÂÏà±È£¬µ¥Î»Ãæ»ýÉÏײ»÷µØÃæµÄ¿ÕÆø·Ö×Ó¸öÊýÒª¶à | |
| E£® | ¸ÉʪÅÝʪ¶È¼ÆµÄʪÅÝÏÔʾµÄζȵÍÓÚ¸ÉÅÝÏÔʾµÄζȣ¬ÕâÊÇÓÉÓÚʪÅÝÍâÉ´²¼ÖеÄË®Õô·¢ÎüÈȵĽá¹û |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | ¼×ÒÒÈÔÈ»Ïà¶Ô¾²Ö¹£¬Ò»ÆðÔȼõËÙÔ˶¯Ö±ÖÁÍ£Ö¹ | |
| B£® | ÔÚ¼×Í£Ö¹Ô˶¯Ç°£¬µØÃæ¶ÔÒÒµÄĦ²ÁÁ¦´óСʼÖÕ²»±ä | |
| C£® | ÔÚ¼×Í£Ö¹Ô˶¯Ç°£¬ÒҵļÓËÙ´óС¶¼ÊÇ4.5m/s2 | |
| D£® | ÔÚÒÒÍ£Ö¹Ô˶¯Ç°£¬¼×µÄ¼ÓËÙ¶È´óСʼÖÕΪ1m/s2 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | $\frac{v_0^2}{2¦Ìg}$ | B£® | v0 t | C£® | v0t-$\frac{1}{2}$¦Ìgt2 | D£® | $\frac{v_0^2}{¦Ìg}$ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | ¼×ͼÖУ¬ÎÞÂÙF1µÄ´óСÈçºÎ£¬Ö»ÒªF1×÷ÓÃʱ¼ä×ã¹»³¤£¬ÔòÎï¿éºÍľ°å¾Í¿É·ÖÀë | |
| B£® | ÒÒͼÖУ¬Ö»ÓÐF2µÄ´óС´óÓÚijһֵʱ£¬²Å¿ÉÄÜʹÎï¿éºÍľ°å·ÖÀë | |
| C£® | ʹÎï¿éºÍľ°å·ÖÀëµÄ×îС×÷ÓÃÁ¦F1£¾F2 | |
| D£® | ʹÎï¿éºÍľ°å·ÖÀëµÄ×îС×÷ÓÃÁ¦F1£¼F2 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | »¬¿éÒ»Ö±×öÔȱäËÙÖ±ÏßÔ˶¯ | |
| B£® | t=1sʱ£¬»¬¿éËٶȼõΪÁ㣬Ȼºó¾²Ö¹ÔÚÐ±ÃæÉÏ | |
| C£® | t=2sʱ£¬»¬¿éÇ¡ºÃÓֻص½³ö·¢µã | |
| D£® | t=3sʱ£¬»¬¿éµÄËÙ¶ÈΪ4m/s |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | ½ðÊô°ôÏòÓÒ×öÔȼõËÙÖ±ÏßÔ˶¯ | |
| B£® | ½ðÊô°ôÔÚx=1 m´¦µÄËÙ¶È´óСΪ0.5m/s | |
| C£® | ½ðÊô°ô´Óx=0Ô˶¯µ½x=1m¹ý³ÌÖУ¬ÍâÁ¦FËù×öµÄ¹¦Îª-0.175 J | |
| D£® | ½ðÊô°ô´Óx=0Ô˶¯µ½x=2m¹ý³ÌÖУ¬Á÷¹ý½ðÊô°ôµÄµçÁ¿Îª2C |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com