4£®Ä³Í¬Ñ§ÔÚ¡°Ì½¾¿Ð¡³µËÙ¶ÈËæÊ±¼ä±ä»¯µÄ¹æÂÉ¡±µÄʵÑéÖУ¬ËùÓý»Á÷µçµÄÖÜÆÚΪT=0.02s£®´òµã¼ÆÊ±Æ÷¼Ç¼Á˱»Ð¡³µÍ϶¯µÄÖ½´øµÄÔ˶¯Çé¿ö£¬ÔÚÖ½´øÉÏÈ·¶¨³öA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¹²7¸ö¼ÆÊýµã£®ÆäÏàÁÚµã¼äµÄ¾àÀ루¿ÉÒÀ´ÎÓÃ×Öĸx1¡¢x2¡¢x3¡¢x4¡¢x5¡¢x6±íʾ£©ÈçͼËùʾ£¬Ã¿Á½¸öÏàÁڵļÆÊýµãÖ®¼ä»¹ÓÐ4¸ö´òÓ¡µãδ»­³ö£®

£¨1£©ÊÔ¸ù¾ÝÖ½´øÉϸ÷¸ö¼ÆÊýµã¼äµÄ¾àÀ룬¼ÆËã³ö´òÏÂBµãС³µµÄ˲ʱËÙ¶È£¬vB=0.38£¨ÒªÇó±£Áô2λÓÐЧÊý×Ö£©
£¨2£©Çëд³ö¼ÆËãС³µ¼ÓËٶȵıí´ïʽ£º$a=\frac{£¨{x}_{4}^{\;}+{x}_{5}^{\;}+{x}_{6}^{\;}£©-£¨{x}_{1}^{\;}+{x}_{2}^{\;}+{x}_{3}^{\;}£©}{9{T}_{\;}^{2}}$£¨ÓÃ×Öĸx1¡¢x2¡¢x3¡¢x4¡¢x5¡¢x6ºÍT±íʾ£©£®±íʾ³öС³µ¼ÓËÙ¶ÈΪ1.19m/s2£¨±£ÁôСÊýµãºóÃæ¶þλÊý×Ö£©£®

·ÖÎö £¨1£©¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯ÖÐʱ¼äÖеãµÄËٶȵÈÓڸùý³ÌÖÐµÄÆ½¾ùËÙ¶È£¬¿ÉÒÔÇó³ö´òÖ½´øÉÏB¡¢FµãʱС³µµÄ˲ʱËÙ¶È´óС£®
£¨2£©¸ù¾ÝÖð²î·¨Çó½â¼ÓËÙ¶È£®

½â´ð ½â£º£¨1£©Ã¿Á½¸öÏàÁÚ¼ÆÊýµãÖ®¼ä»¹ÓÐËĸöµãδ»­³ö£¬ËùÒÔÏàÁڵļÆÊýµã¼äµÄʱ¼ä¼ä¸ôT=0.1s£®
¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯ÖÐʱ¼äÖеãµÄËٶȵÈÓڸùý³ÌÖÐµÄÆ½¾ùËÙ¶È£¬
vB=$\frac{{x}_{AC}^{\;}}{2T}$=$\frac{3.18cm+4.36cm}{2¡Á0.1s}=38cm/s$=0.38m/s£¬
£¨2£©¸ù¾ÝÖð²î·¨Çó¼ÓËÙ¶È
${x}_{4}^{\;}-{x}_{1}^{\;}=3{a}_{1}^{\;}{T}_{\;}^{2}$¢Ù
${x}_{5}^{\;}-{x}_{2}^{\;}=3{a}_{2}^{\;}{T}_{\;}^{2}$¢Ú
${x}_{6}^{\;}-{x}_{3}^{\;}=3{a}_{3}^{\;}{T}_{\;}^{2}$¢Û
$a=\frac{{a}_{1}^{\;}+{a}_{2}^{\;}+{a}_{3}^{\;}}{3}$¢Ü
ÁªÁ¢µÃ$a=\frac{£¨{x}_{4}^{\;}+{x}_{5}^{\;}+{x}_{6}^{\;}£©-£¨{x}_{1}^{\;}+{x}_{2}^{\;}+{x}_{3}^{\;}£©}{9{T}_{\;}^{2}}$
´úÈëÊý¾ÝµÃ£º$a=\frac{£¨6.74cm+7.92cm+9.12cm£©-£¨3.18cm+4.36cm+5.55cm£©}{£¨3¡Á0.1s£©_{\;}^{2}}$=119$cm/{s}_{\;}^{2}$=$1.19m/{s}_{\;}^{2}$
¹Ê´ð°¸Îª£º£¨1£©0.38   £¨2£©$a=\frac{£¨{x}_{4}^{\;}+{x}_{5}^{\;}+{x}_{6}^{\;}£©-£¨{x}_{1}^{\;}+{x}_{2}^{\;}+{x}_{3}^{\;}£©}{9{T}_{\;}^{2}}$            1.19

µãÆÀ ÒªÌá¸ßÓ¦ÓÃÔȱäËÙÖ±ÏߵĹæÂÉÒÔ¼°ÍÆÂÛ½â´ðʵÑéÎÊÌâµÄÄÜÁ¦£¬ÔÚÆ½Ê±Á·Ï°ÖÐÒª¼ÓÇ¿»ù´¡ÖªÊ¶µÄÀí½âÓëÓ¦Óã®
ҪעÒⵥλµÄ»»ËãºÍÓÐЧÊý×ֵı£Áô£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

20£®ÈçͼËùʾ£¬´øµçÖʵãP¾²Ö¹ÓÚÁ½Æ½ÐнðÊô°å¼ä£¬²»¿¼ÂǵçÁ÷±íºÍµçѹ±í¶Ôµç·µÄÓ°Ï죬µ±»¬¶¯±ä×èÆ÷R3µÄ»¬Æ¬Ïòb¶ËÒÆ¶¯Ê±£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®µçѹ±í¶ÁÊýÔö´óB£®µçÁ÷±í¶ÁÊýÔö´ó
C£®ÖʵãP½«ÏòÏÂÔ˶¯D£®R2ÏûºÄµÄ¹¦ÂÊÔö´ó

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

15£®ÈçͼËùʾΪA¡¢BÁ½ÖʵãÔÚͬһֱÏßÉÏÔ˶¯µÄÎ»ÒÆ-ʱ¼ä£¨x-t£©Í¼Ïó£®AÖʵãµÄͼÏóΪֱÏߣ¬BÖʵãµÄͼÏóΪ¹ýÔ­µãµÄÅ×ÎïÏߣ¬Á½Í¼Ïó½»µãC¡¢D×ø±êÈçͼ£®ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®A¡¢BÏàÓöÁ½´Î
B£®t1¡«t2ʱ¼ä¶ÎÄÚBÖʵãµÄƽ¾ùËÙ¶ÈÓëAÖʵãÔÈËÙÔ˶¯µÄËÙ¶ÈÏàµÈ
C£®Á½ÎïÌåËÙ¶ÈÏàµÈµÄʱ¿ÌÒ»¶¨ÔÚt1¡«t2ʱ¼ä¶ÎÄÚµÄÖмäʱ¿Ì
D£®AÔÚBÇ°ÃæÇÒÀëB×îԶʱ£¬BµÄÎ»ÒÆÎª$\frac{{x}_{1}+{x}_{2}}{2}$

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

12£®ÈçͼËùʾ£¬ÓÐÒ»°ë¾¶ÎªRµÄ°ëÇòÐΰ¼²ÛP£¬·ÅÔڹ⻬µÄˮƽµØÃæÉÏ£¬Ò»Ãæ½ô¿¿Ôڹ⻬µÄǽ±ÚÉÏ£¬ÔÚ²Û¿ÚÉÏÓÐÒ»ÖÊÁ¿ÎªmµÄСÇò£¬Óɾ²Ö¹ÊÍ·Å£¬Ñع⻬µÄÇòÃæ»¬Ï£¬¾­×îµÍµãB£¬ÓÖÑØÇòÃæÉÏÉýµ½×î¸ßµãC£¬¾­ÀúµÄʱ¼äΪt£¬B¡¢CÁ½µã¸ß¶È²îΪ0.6R£®Ð¡Çòµ½´ïCµãµÄËÙ¶È$\frac{2}{5}\sqrt{2gR}$£»ÔÚÕâ¶Îʱ¼ä tÀÊúֱǽ¶Ô°¼²ÛµÄ³åÁ¿$m\sqrt{2gR}$£¬·½ÏòˮƽÏòÓÒ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

19£®ÈçͼËùʾ£¬a¡¢b¡¢cÊDZ±¶·ÎÀÐǵ¼º½ÏµÍ³ÖеÄ3¿ÅÎÀÐÇ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®b¡¢cµÄÏßËÙ¶È´óСÏàµÈ£¬ÇÒСÓÚaµÄÏßËÙ¶È
B£®b¡¢cµÄÏòÐļÓËÙ¶È´óСÏàµÈ£¬ÇÒ´óÓÚaµÄÏòÐļÓËÙ¶È
C£®c¼ÓËÙ¿É×·ÉÏͬһ¹ìµÀÉϵÄb£¬b¼õËٿɵȺòͬһ¹ìµÀÉϵÄc
D£®aÎÀÐÇÓÉÓÚijÖÖÔ­Òò£¬¹ìµÀ°ë¾¶»ºÂý¼õС£¬ÆäÏßËٶȲ»±ä

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

9£®¹ØÓÚÆ½¾ùËÙ¶È£¬ÏÂÁÐ˵·¨ÖдíÎóµÄÊÇ£¨¡¡¡¡£©
A£®ÓÉÓÚÔȱäËÙÖ±ÏßÔ˶¯µÄËÙ¶ÈËæÊ±¼äÊǾùÔȸıäµÄ£¬Òò¶øËüÔÚʱ¼ätÄ򵀮½¾ùËٶȾ͵ÈÓÚÕâ¶Îʱ¼ätÄڵijõËٶȺÍÄ©ËÙ¶ÈµÄÆ½¾ùÖµ£¬¼´$\overline{v}$=$\frac{v+{v}_{0}}{2}$
B£®¶ÔÓÚÈκÎÖ±ÏßÔ˶¯¶¼¿ÉÓù«Ê½$\overline{v}$=$\frac{v+{v}_{0}}{2}$À´Ç󯽾ùËÙ¶È
C£®¶ÔÓÚ¼ÓËÙ¶È·¢Éú±ä»¯µÄÖ±ÏßÔ˶¯£¬ÈÔÈ»¿ÉÓÃ$\overline{v}$=$\frac{x}{t}$À´Ç󯽾ùËÙ¶È
D£®¶ÔÓÚÇúÏßÔ˶¯£¬Ò²¿ÉÓÃ$\overline{v}$=$\frac{x}{t}$À´Ç󯽾ùËÙ¶È

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

16£®Ä³Í¬Ñ§ÔÚ̽¾¿Ð¡³µËÙ¶ÈËæÊ±¼ä±ä»¯µÄ¹æÂɵÄʵÑéÖУ¬Óôòµã¼ÆÊ±Æ÷¼Ç¼Á˱»Ð¡³µÍ϶¯µÄÖ½´øµÄÔ˶¯Çé¿ö£¬ÔÚÖ½´øÉÏÈ·¶¨³ö0¡¢1¡¢2¡¢3¡¢4¡¢5¡¢6¹²7¸ö²âÁ¿µã£®ÆäÏàÁÚµã¼äµÄ¾àÀëÈçͼËùʾ£¬Ã¿Á½¸öÏàÁڵIJâÁ¿µãÖ®¼äµÄʱ¼ä¼ä¸ôΪ0.10s£¬ÊÔÍê³ÉÏÂÃæÎÊÌ⣮
£¨1£©½«ÏÂÊö²½ÖèµÄ´úºÅÌîÔÚºáÏßÉÏBACD
A£®½«´©ºÃµÄÖ½´ø¹Ì¶¨ÔÚС³µºóÃæ£¬Ë©ÉÏϸÉþ£¬Ï¸Éþ¿ç¹ý¶¨»¬ÂÖ£¬¹ÒÉϺÏÊʵĹ³Âë
B£®°Ñ´òµã¼ÆÊ±Æ÷¹Ì¶¨ÔÚľ°åµÄûÓл¬ÂÖµÄÒ»¶Ë£¬´©ºÃÖ½´ø£¬²¢Á¬ºÃµç·
C£®Ê¹Ð¡³µÍ£ÔÚ¿¿½ü´òµã¼ÆÊ±Æ÷´¦£¬½ÓͨµçÔ´£¬·Å¿ªÐ¡³µ£¬ÈÃС³µÔ˶¯
D£®¶Ï¿ªµçÔ´£¬È¡³öÖ½´ø
£¨2£©¸ù¾ÝÖ½´øÉϸ÷¸ö²âÁ¿µã¼äµÄ¾àÀ룬ijͬѧÒѽ«1¡¢2¡¢3¡¢5µã¶ÔÓ¦µÄʱ¿ÌµÄ˲ʱËٶȽøÐмÆËã²¢ÌîÈë±íÖУ¬ÇëÄ㽫4µã¶ÔÓ¦µÄʱ¿ÌµÄ˲ʱËÙ¶ÈÌîÈë±íÖУ¬4µã¶ÔÓ¦µÄ˲ʱËÙ¶ÈΪ0.314m/s£®£¨ÒªÇó±£ÁôÈýλÓÐЧÊý×Ö£©
˲ʱËÙ¶È/m•s-1v1v2v3v4v5
ÊýÖµ0.1650.2140.2630.363
£¨3£©ÓÉÖ½´øÇó³öС³µµÄ¼ÓËÙ¶Èa=0.496m/s2£®£¨±£ÁôÈýλÓÐЧÊý×Ö£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

13£®ÈçͼËùʾ£¬Æ½°åµçÈÝÆ÷´øÓеÈÁ¿ÒìÖÖµçºÉ£¬Óë¾²µç¼ÆÏàÁ¬£¬¾²µç¼Æ½ðÊôÍâ¿ÇºÍµçÈÝÆ÷ϼ«°å¶¼½ÓµØ£¬ÔÚÁ½¼«°å¼äÓÐÒ»¸ö´øµçСÇò¸ÕºÃ¾²Ö¹ÓÚPµã£®Èô±£³Öϼ«°å²»¶¯£¬½«Éϼ¶°åÏòÏÂÒÆ¶¯Ò»Ð¡¶Î¾àÀëÖÁͼÖÐÐéÏßλÖã¬Ôò£¨¡¡¡¡£©
A£®Ð¡ÇòÒ»¶¨´ø¸ºµçB£®¾²µç¼ÆÖ¸ÕëµÄÆ«½Ç½«¼õС
C£®Ð¡ÇòÈÔÄܾ²Ö¹ÓÚPµãD£®Ð¡ÇòÔÚPµãµÄµçÊÆÄܽ«¼õС

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

14£®ÈçͼËùʾÊÇÎÒ¹úÃñÓý»Á÷µçµÄµçѹͼÏ󣮸ù¾ÝͼÏó¿ÉÖª£¬½»Á÷µçµÄƵÂÊÊÇ50Hz£» Óý»Á÷µçѹ±í²âÁ¿µçѹ£¬²â³öµÄµçѹֵÊÇ220V£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸