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Answer 1

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${p}_{1}^{\;}={p}_{0}^{\;}-¦Ñg£¨{h}_{1}^{\;}-{h}_{2}^{\;}£©=60cmHg$£¬${V}_{1}^{\;}={V}_{0}^{\;}+{h}_{0}^{\;}S=100c{m}_{\;}^{3}$£¬${T}_{1}^{\;}=300K$
ĩ״̬£º${p}_{2}^{\;}={p}_{0}^{\;}=76cmHg$£¬${V}_{2}^{\;}={V}_{1}^{\;}+\frac{1}{2}£¨{h}_{1}^{\;}-{h}_{2}^{\;}£©S=104c{m}_{\;}^{3}$
ÓÉÀíÏëÆøÌå״̬·½³ÌÓÐ$\frac{{p}_{1}^{\;}{V}_{1}^{\;}}{{T}_{1}^{\;}}=\frac{{p}_{2}^{\;}{V}_{2}^{\;}}{{T}_{2}^{\;}}$
´úÈëÊý¾Ý½âµÃ${T}_{2}^{\;}=395.2K$
${t}_{2}^{\;}=122.2¡æ$
¢Ú¶ÔÓÚ·â±ÕÆøÌ壬ĩ״̬${p}_{3}^{\;}={p}_{0}^{\;}+¦Ñg{h}_{3}^{\;}=100cmHg$£¬${V}_{3}^{\;}={V}_{1}^{\;}+£¨{h}_{3}^{\;}-{h}_{2}^{\;}£©S=111c{m}_{\;}^{3}$
ÓÉÀíÏëÆøÌå״̬·½³ÌÓÐ$\frac{{p}_{1}^{\;}{V}_{1}^{\;}}{{T}_{1}^{\;}}=\frac{{P}_{3}^{\;}{V}_{3}^{\;}}{{T}_{3}^{\;}}$
´úÈëÊý¾Ý½âµÃ${T}_{3}^{\;}=555K$
${t}_{3}^{\;}=282¡æ$
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