10£®Èçͼ¼×Ëùʾ£¬Á½¿é×ã¹»´óµÄƽÐнðÊô°åˮƽ·ÅÖ㬼«°å¼ä¼ÓÓпռä·Ö²¼¾ùÔÈ¡¢´óÐ¡ËæÊ±¼äÖÜÆÚÐԱ仯¡¢·½ÏòÊúÖ±Ïòϵĵ糡£¬±ä»¯¹æÂÉÈçͼÒÒËùʾ£¬ÔÚt=0ʱ¿Ì´Ó¸º¼«°åÓɾ²Ö¹ÊÍ·ÅÒ»¸öÖÊÁ¿Îªm¡¢´øµçÁ¿Îªq£¨q£¼0£©µÄÖʵ㣮ÒÑÖªµç³¡Ç¿¶ÈE0=$\frac{mg}{q}$£¬Í¬Ê±t0ҲΪÒÑÖªÁ¿£®
£¨1£©ÈôÖʵãÇ¡ºÃÔÚt=3t0ʱ¿Ìµ½´ïÕý¼«°å£¬ÊÔÇóÁ½¼«°åÖ®¼äµÄ¾àÀëd
£¨2£©ÔÚµÚ£¨1£©ÎʵÄÌõ¼þÏ£¬ÔÚ¼«°å¼äÔÙ¼ÓÉϿռä·Ö²¼¾ùÔÈ¡¢´óÐ¡ËæÊ±¼äÖÜÆÚÐԱ仯¡¢·½Ïò´¹Ö±Ö½ÃæÏòÍâµÄ´Å³¡£¬±ä»¯¹æÂÉÈçͼ±ûËùʾ£¬ÒÑÖª´Å¸ÐӦǿ¶ÈB0=$\frac{2¦Ðm}{q{t}_{0}}$£®ÊÔÇó£º
¢Ù´øµçÖʵ㾭¹ý¶à³¤Ê±¼äµ½´ïÕý¼«°å
¢Ú´øµçÖʵãÔÚ¼«°å¼ä×öÔ²ÖÜÔ˶¯µÄ×î´ó°ë¾¶
¢Û»­³öÖʵãÔÚ¼«°å¼äÔ˶¯µÄ¹ì¼£Í¼£¨²»ÐèҪд¼ÆËã¹ý³Ì£©

·ÖÎö £¨1£©ÖʵãÔÚ0¡«t0ʱ¼äÄÚ×öÔȼÓËÙÖ±ÏßÔ˶¯£¬ÔÚt0¡«2t0ʱ¼äÄÚ£¬ÊÜÁ¦Æ½ºâ£¬×öÔÈËÙÖ±ÏßÔ˶¯£¬ÔÚ2t0¡«3t0ʱ¼äÄÚ£¬ÔÙ×ö¼ÓËÙ¶ÈΪgµÄÔȼÓËÙÖ±ÏßÔ˶¯£¬×÷³öËÙ¶Èʱ¼äͼÏߣ¬½áºÏͼÏßΧ³ÉµÄÃæ»ýÇó³öÁ½¼«°å¼äµÄ¾àÀ룮
£¨2£©´øµçÖʵãÔÚt0¡«2t0ʱ¼äºÍ3t0¡«4t0ʱ¼äÄÚ£¬ËùÊÜÖØÁ¦ºÍµç³¡Á¦Æ½ºâ£¬ÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦×÷Óã¬×öÔÈËÙÔ²ÖÜÔ˶¯£¬ÆäËüʱ¼ä×öÔȼÓËÙÔ˶¯£¬½áºÏÖÜÆÚ¹«Ê½Çó³öÔ˶¯µÄʱ¼ä£¬¸ù¾ÝÔ˶¯Ñ§¹«Ê½Çó³öÔȼÓËÙÔ˶¯µÄʱ¼ä£®
×î´ó°ë¾¶Êܵ½Á½°åÖ®¼äµÄ¾àÀëµÄÓ°Ï죬Ê×ÏÈ¶ÔÆäÔ˶¯¹ì¼£½øÐзÖÎö£¬½áºÏ°å¼ä¾àÀ룬¿É·ÖÎö³öÁ£×ÓÄÜ×ö¼¸¸öÍêÕûµÄÔ²ÖÜÔ˶¯£¬´Ó¶øµÃÖª×öÔ²ÖÜÔ˶¯µÄ×î´ó°ë¾¶£®

½â´ð ½â£º£¨1£©ÖʵãÔÚ0¡«t0ʱ¼äÄÚ£¬a=$\frac{{F}_{ºÏ}}{m}$=$\frac{2q{E}_{0}-mg}{m}=g$£¬×ö³õËÙ¶ÈΪ0µÄÔȼÓËÙÖ±ÏßÔ˶¯
ÔÚt0¡«2t0ʱ¼äÄÚ£¬ÊÜÁ¦Æ½ºâ£¬×öÔÈËÙÖ±ÏßÔ˶¯£¬ÔÚ2t0¡«3t0ʱ¼äÄÚ£¬ÔÙ×ö¼ÓËÙ¶ÈΪgµÄÔȼÓËÙÖ±ÏßÔ˶¯£¬v-tͼÏóÈçͼ£®
ÓУºd=6¡Á$\frac{1}{2}a{{t}_{0}}^{2}=3g{{t}_{0}}^{2}$£®
£¨2£©¢Ù´øµçÖʵãÔÚt0¡«2t0ʱ¼äºÍ3t0¡«4t0ʱ¼äÄÚ£¬ËùÊÜÖØÁ¦ºÍµç³¡Á¦Æ½ºâ£¬ÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦×÷Óã¬×öÔÈËÙÔ²ÖÜÔ˶¯£¬ÆäËüʱ¼ä×öÔȼÓËÙÔ˶¯£¬´øµçÖʵã×öÔÈËÙÔ²ÖÜÔ˶¯Ê±ÓУº$qv{B}_{0}=m\frac{{v}^{2}}{R}=mR\frac{4{¦Ð}^{2}}{{T}^{2}}$
ËùÒÔÓУºT=$\frac{2¦Ðm}{q{B}_{0}}={t}_{0}$£®
´øµçÖʵã×öÔȼÓËÙÖ±ÏßÔ˶¯Ê±ÓУº
d=$\frac{1}{2}a{t}^{2}=\frac{1}{2}g{t}^{2}$µÃ£¬t=$\sqrt{\frac{2d}{g}}=\sqrt{6}{t}_{0}$
ÓÉÓÚ3t0$£¾\sqrt{6}{t}_{0}£¾2{t}_{0}$£¬ËùÒÔÖʵãÔÚ¼«°å¼ä½«Íê³É0-t0ʱ¼äÄÚÔȼÓËÙÔ˶¯£¬t0-2t0ʱ¼äÄÚÔÈËÙÔ²ÖÜÔ˶¯£¬2t0-3t0ʱ¼äÄÚÔȼÓËÙÔ˶¯£¬3t0-4t0ʱ¼äÄÚÔ²ÖÜÔ˶¯£¬
$2{t}_{0}-\sqrt{6}{t}_{0}$ʱ¼äÄÚÔȼÓËÙÔ˶¯Ö±µ½Õý¼«°å£¬ÖʵãÔ˶¯×Üʱ¼äΪ${t}_{×Ü}=t+2T=\sqrt{6}{T}_{0}+2{t}_{0}$=$£¨2+\sqrt{6}£©{t}_{0}$£®
¢Ú´øµçÖʵã×öÔÈËÙÔ²ÖÜÔ˶¯Ê±ÓУºR=$\frac{mv}{q{B}_{0}}=\frac{v{t}_{0}}{2¦Ð}$£®
¿É¼ûÖʵãËÙ¶ÈÔ½´ó£¬Ô²¹ìµÀµÄ°ë¾¶Ò²Ô½´ó£¬¼´Öʵ㾭Àú0¡«t0ʱ¼äºÍ2t0¡«3t0Á½¶Îʱ¼ä¼ÓËÙºóÔ²¹ìµÀ°ë¾¶×î´ó£®
ÖʵãÔȼÓËÙÔ˶¯Ê±£¬v=at=2gt0£¬
ËùÒÔÔ²¹ìµÀ×î´ó°ë¾¶ÎªR=$\frac{v{t}_{0}}{2¦Ð}=\frac{2g{{t}_{0}}^{2}}{2¦Ð}=\frac{g{{t}_{0}}^{2}}{¦Ð}$£®
ͬʱ£ºR+$\frac{1}{2}a£¨2{t}_{0}£©^{2}=g{{t}_{0}}^{2}£¨2+\frac{1}{¦Ð}£©£¼d$£¬ÖʵãûÓе½´ïÕý¼«°å£®
¢ÛÈçͼ                                      

´ð£º£¨1£©ÇóÁ½¼«°åÖ®¼äµÄ¾àÀëΪ$3g{{t}_{0}}^{2}$£»
£¨2£©¢Ù´øµçÖʵ㾭¹ý$£¨2+\sqrt{6}£©{t}_{0}$ʱ¼äµ½´ïÕý¼«°å£»
¢Ú´øµçÖʵãÔÚ¼«°å¼ä×öÔ²ÖÜÔ˶¯µÄ×î´ó°ë¾¶Îª$\frac{g{{t}_{0}}^{2}}{¦Ð}$£»
¢ÛÈçͼËùʾ£®

µãÆÀ ´øµãÁ£×ÓÔÚ¸´ºÏ³¡ÖеÄÔ˶¯±¾ÖÊÊÇÁ¦Ñ§ÎÊÌâ
1¡¢´øµçÁ£×ÓÔڵ糡¡¢´Å³¡ºÍÖØÁ¦³¡µÈ¹²´æµÄ¸´ºÏ³¡ÖеÄÔ˶¯£¬ÆäÊÜÁ¦Çé¿öºÍÔ˶¯Í¼¾°¶¼±È½Ï¸´ÔÓ£¬µ«Æä±¾ÖÊÊÇÁ¦Ñ§ÎÊÌ⣬Ӧ°´Á¦Ñ§µÄ»ù±¾Ë¼Â·£¬ÔËÓÃÁ¦Ñ§µÄ»ù±¾¹æÂÉÑо¿ºÍ½â¾ö´ËÀàÎÊÌ⣮
2¡¢·ÖÎö´øµçÁ£×ÓÔÚ¸´ºÏ³¡ÖеÄÊÜÁ¦Ê±£¬Òª×¢Òâ¸÷Á¦µÄÌØµã£¬Èç´øµçÁ£×ÓÎÞÂÛÔ˶¯Óë·ñ£¬ÔÚÖØÁ¦³¡ÖÐËùÊÜÖØÁ¦¼°ÔÚÔÈÇ¿µç³¡ÖÐËùÊܵĵ糡Á¦¾ùΪºãÁ¦£¬¶ø´øµçÁ£×ÓÔڴų¡ÖÐÖ»ÓÐÔ˶¯ £¨ÇÒËٶȲ»Óë´Å³¡Æ½ÐУ©Ê±²Å»áÊܵ½ÂåÂØ×ÈÁ¦£¬Á¦µÄ´óÐ¡ËæËÙ¶È´óС¶ø±ä£¬·½ÏòʼÖÕÓëËÙ¶È´¹Ö±£¬¹ÊÂåÂØ×ÈÁ¦¶ÔÔ˶¯µçºÉÖ»¸Ä±äÁ£×ÓÔ˶¯µÄ·½Ïò£¬²»¸Ä±ä´óС£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

20£®ÔÚij½ÚÈÕÇìµäÉÏ£¬ÎªÁË´ïµ½ËùÐèÒªµÄµÆ¹âЧ¹û£¬ÐèÒªÍê³ÉÏÂÁй¤×÷£®ÈçͼËùʾ£¬Óɺ졢»ÆÁ½ÖÖµ¥É«¹â×é³ÉµÄ¹âÊøa£¬ÒÔÈëÉä½Çi´ÓƽÐв£Á§°åÉϱíÃæOµãÈëÉ䣮ÒÑ֪ƽÐв£Á§°åºñ¶ÈΪd£¬ºì¹âºÍ»Æ¹âµÄÕÛÉäÂÊ·Ö±ðΪn1ºÍn2£¬Õæ¿ÕÖеĹâËÙΪc£®ÊÔÇóºì¹âºÍ»Æ¹â´ÓϱíÃæÉä³öµÄʱ¼ä²î£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

1£®2011Äê11ÔÂ3ÈÕ£¬ÔÚ¾àµØÃæÔ¼343ǧÃ׵ĽüÔ²¹ìµÀÉϵȴýµÄ¡°Ì칬һºÅ¡±ÓëǰÀ´Ïà»áµÄ¡°ÉñÖ۰˺š±³É¹¦¶Ô½Ó£®ÔÚ´Ë֮ǰ£¬¡°ÉñÖ۰˺š±Í¨¹ý5´Î±ä¹ì4´Î¡°É²³µ¡±£¬´Ó³õʼ¹ìµÀ×ªÒÆµ½¾àµØ330ǧÃ׵ĽüÔ²¹ìµÀ£¬²¢ÔھࡰÌ칬һºÅ¡±ºóÏ·½52ǧÃ×´¦£¬Óë¡°Ì칬һºÅ¡±½¨Á¢Í¨ÐÅÁ´Â·ºó£¬¾­¹ý×îºóÒ»´Î±ä¹ìµ½Óë¡°Ì칬һºÅ¡±Í¬Ò»¹ìµÀÏà¾à30Ã×Ô¶´¦µÄÍ£²´µã£®¹ØÓڴ˴ζԽӣ¬ÒÔÏÂ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®¡°Ì칬һºÅ¡±ÔڵȴýÆÚ¼ä£¬Ïà¶ÔµØÇòÊǾ²Ö¹µÄ
B£®¡°ÉñÖ۰˺š±ÔÚ½øÐÐ×îºóÒ»´Î±ä¹ìʱӦÊ×ÏȼÓËÙ
C£®¡°ÉñÖ۰˺š±ÔÚ½øÐÐ×îºóÒ»´Î±ä¹ìʱӦÊ×ÏȼõËÙ
D£®¡°ÉñÖ۰˺š±×îºóÒ»´Î±ä¹ìÍê³ÉºóµÄËÙ¶È´óÓÚ±ä¹ìǰµÄËÙ¶È

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

18£®ÈçͼËùʾ£¬d´¦¹Ì¶¨ÓиºµãµçºÉQ£¬Ò»¸ö´øµçÖʵãÖ»Ôڵ糡Á¦×÷ÓÃÏÂÔ˶¯£¬ÉäÈë´ËÇøÓòʱµÄ¹ì¼£ÎªÍ¼ÖÐÇúÏßabc£¬a¡¢b¡¢c¡¢dÇ¡ºÃÊÇÒ»Õý·½ÐεÄËĸö¶¥µã£¬ÔòÓУ¨¡¡¡¡£©
A£®a¡¢b¡¢cÈýµã´¦µçÊÆ¸ßµÍ¹ØÏµÊǦÕa=¦Õc£¾¦Õb
B£®ÖʵãÓÉaµ½c£¬µçÊÆÄÜÏÈÔö¼Óºó¼õС£¬ÔÚbµã¶¯ÄÜ×îС
C£®ÖʵãÔÚa¡¢b¡¢cÈýµã´¦µÄ¼ÓËÙ¶È´óС֮±ÈΪ2£º1£º2
D£®Èô½«d´¦µÄµãµçºÉ¸ÄΪ+Q£¬¸Ã´øµçÖʵãµÄ¹ì¼£ÈÔ¿ÉÄÜΪÇúÏßabc

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

5£®ÈçͼËùʾ£¬ÔÚM¡¢NÁ½µã¹Ì¶¨µÈÁ¿µÄÒìÖÖµçºÉ£¬OµãÊÇMNÁ¬ÏßÉϵÄÖе㣬a¡¢bÁ½µãÔÚÁ¬ÏßÉϲ¢¹ØÓÚOµã¶Ô³Æ£¬c¡¢dÊÇÖд¹ÏßÉϹØÓÚOµã¶Ô³ÆµÄÁ½µã£¬Ôò£¨¡¡¡¡£©
A£®a¡¢b¡¢c¡¢dËĵ㳡ǿ·½ÏòÏàͬ£¬²¢ÇÒÓУºEa=Eb£¾Ec=Ed
B£®a¡¢bÁ½µãµçÊÆÏàµÈÇÒ´óÓÚc¡¢dÁ½µãµÄµçÊÆ
C£®½«Ò»´øÕýµçµÄÁ£×Ó´ÓcµãÑØcadÕÛÏßÒÆ¶¯µ½dµã£¬µç³¡Á¦×öÕý¹¦
D£®½«Ò»´øÕýµçµÄÁ£×Ó£¨²»¼ÆÁ£×ÓÖØÁ¦£©ÓÉaµãÊÍ·Å£¬Á£×ÓÒ»¶¨ÑØÖ±ÏßÔ˶¯µ½b£¬ÇÒÁ£×Ó¶¯ÄÜÓëÁ£×ÓÔ˶¯Ê±¼äµÄƽ·½³ÉÕý±È

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

15£®¹ØÓÚÆû³µµÄÔ˶¯£¬ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®Óë°¼ÐÎÂ·ÃæÏà±È£¬Æû³µ¹ý͹ÐÎÂ·ÃæÊ±¸üÈÝÒ×±¬Ì¥
B£®ÒԶ¹¦ÂÊÔ˶¯µÄÆû³µ£¬³µËÙÔ½¿ì£¬Ç£ÒýÁ¦Ô½´ó
C£®ÇóÆû³µ´Ó³É¶¼Ô˶¯µ½Ã¼É½µÄʱ¼äʱ£¬¿É½«Æû³µÊÓΪÖʵã
D£®Æû³µÀ­×ÅÍϳµÔÚÆ½Ö±Â·ÃæÉϼÓËÙǰ½øÊ±£¬Ëü¶ÔÍϳµµÄÀ­Á¦´óÓÚÍϳµ¶ÔËüµÄÀ­Á¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

2£®Ä³Ñ§Ï°Ð¡×éÀûÓ÷ü°²·¨²â¶¨Ä³¸ù2BǦ±ÊоµÄµç×裨×èÖµÔ¼5¦¸£©£¬ÊµÑéÔ­ÀíÈçͼ1Ëùʾ£®ÆäÖУ¬ÐéÏß¿òÄÚΪÓÃÁéÃôµçÁ÷¼ÆG¸Ä×°µÄµçѹ±íV£¬AΪµçÁ÷±í£¬EΪµç³Ø×飨µç¶¯ÊÆÔ¼Îª3V£¬ÄÚ×èºÜС£©£¬SΪ¿ª¹Ø£¬RΪ»¬¶¯±ä×èÆ÷£®

£¨1£©ÒÑÖªÁéÃôµçÁ÷¼ÆGµÄÂúÆ«µçÁ÷Ig=300¦ÌA£¬ÄÚ×èrg=500¦¸£¬ÈôҪʹ¸Ä×°ºóµÄµçѹ±íÂúÆ«µçѹΪ3V£¬Ó¦´®ÁªÒ»Ö»9.5k¦¸µÄ¶¨Öµµç×èR0£®
£¨2£©ÊµÑéÊÒÌṩÈçÏÂÆ÷²Ä£º
µçÁ÷±íA1£¨Á¿³Ì0.6A£¬ÄÚ×èԼΪ1.0¦¸£©
µçÁ÷±íA2£¨Á¿³Ì3A£¬ÄÚ×èԼΪ0.1¦¸£©
»¬¶¯±ä×èÆ÷R1£¨×î´ó×èÖµ10¦¸£¬¶î¶¨µçÁ÷2A£©
»¬¶¯±ä×èÆ÷R2£¨×î´ó×èÖµ2k¦¸£¬¶î¶¨µçÁ÷0.5A£©
Ϊ˳ÀûÍê³ÉʵÑ飬µçÁ÷±íӦѡÓÃ${A}_{1}^{\;}$£¬»¬¶¯±ä×èÆ÷Ó¦ Ñ¡ÓÃ${R}_{1}^{\;}$£®
£¨3£©Ä³´ÎʵÑéÊý¾ÝÈç±íËùʾ£®
²âÁ¿´ÎÊý123456
¸Ä×°±íVµÄ¶ÁÊýU/V0.801.101.401.702.002.30
µçÁ÷±íAµÄ¶ÁÊýI/A0.170.240.300.370.430.50
Çë¸ù¾ÝÒÔÉÏÊý¾ÝÔÚͼ2×ø±êϵÖлæ³öU-IͼÏ󣬸ù¾ÝͼÏó¿ÉµÃ2BǦ±ÊоµÄµç×èR=4.60¦¸£¨½á¹û±£ÁôÁ½Î»Ð¡Êý£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

19£®ÈçͼËùʾ£¬Ò»ÀºÇò´ÓÀëµØH¸ß´¦µÄÀº°åÉÏAµãÒÔ³õËÙ¶ÈV0ˮƽµ¯³ö£¬¸ÕºÃÔÚÀëµØh¸ß´¦±»ÌøÆðµÄͬѧ½Óס£¬²»¼Æ¿ÕÆø×èÁ¦£®ÔòÀºÇòÔÚ¿ÕÖзÉÐе썡¡¡¡£©
A£®Ê±¼äΪ$\sqrt{\frac{2H}{g}}$B£®Ê±¼äΪ$\sqrt{\frac{2h}{g}}$
C£®Ë®Æ½Î»ÒÆÎªv0$\sqrt{\frac{2£¨H-h£©}{g}}$D£®Ë®Æ½Î»ÒÆÎªv0$\sqrt{\frac{2£¨H+h£©}{g}}$

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

11£®£¨1£©AͬѧÔÚ×öÑéÖ¤»úеÄÜÊØºã¶¨ÂÉʵÑéʱ£¬×÷ÁËÒ»µã¸Ä½ø£¬½«Ô­×°Öã¨Èçͼ¼×£©ÖеĴòµã¼ÆÊ±Æ÷·ÅµÍ£¬ÈçͼÒÒËùʾ£¬¼ÆÊ±Æ÷ÓÉ·½×ùÖ§¼ÜÌ¨ÃæÖ§³Å£¬Ìú¼ÐÆð¹Ì¶¨×÷Óã®ÏȽ«Ö½´øÑ¹ÔÚºá¸ËÉÏ£¬×öµ½´Ó¾²Ö¹¿ªÊ¼ÊÍ·ÅÖ½´ø£®

³ý±£Ö¤Ö½´ø´Ó¾²Ö¹ÊÍ·ÅÍ⣬¸ÃͬѧµÄ¸Ä¶¯½ÏÔ­×°ÖÃÔÚ¼õÉÙÎó²î·½ÃæµÄÓŵãÓб£Ö¤¼ÆÊ±Æ÷²»Çãб»ò±£Ö¤ÉÏ¡¢ÏÂÏÞλ¿×ÔÚͬһÊúÖ±ÏßÉÏ£®
£¨2£©BͬѧÈÔÓü××°ÖûñµÃÒ»ÌõÖ½´ø£¨Èçͼ±û£©£®³öÏÖÕâÑùµÄÔ­Òò¿ÉÄÜÊÇ·ÅÖ½´øÊ±ÊÖÓж¶¶¯£¨Ìî¡°ÏÈ·ÅÖ½´øÔÙͨµç¡±»ò¡°·ÅÖ½´øÊ±ÊÖÓж¶¶¯¡±£©£®ÓÚÊǸÃͬѧ¾Í°ÑÖ½´øµÄ¿ªÊ¼Ò»Ð¡¶Î˺µô£¬ÓûÓÃʣϵÄÖ½´ø¼ÌÐøÊµÑ飬ÎÊÕâÑùµÄÖ½´ø£¬ÄÜ·ñÑéÖ¤»úеÄÜÊØºã¶¨ÂÉ£¿ÄÜ£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©£®

£¨3£©AͬѧÓÃͼÒÒ×°ÖûñµÃÒ»ÌõÖ½´ø£¨Èçͼ¶¡£©£¬²¢ÒÔÆðµãΪ¼ÇÊýµãO£¬ºó¸ôÒ»¶Î¾àÀ룬ȡÁ¬ÐøµãΪ¼ÇÊýµã1¡¢2¡¢3¡¢4¡¢5£¬ÈçͼËùʾ£®ÔÚËûËù¼Ç¼µÄÊý¾ÝÖУ¬¼ÇÊýµã0ÖÁ¼ÇÊýµã2¡¢3µÄ¾àÀë·Ö±ðΪh2=18.12cm£¬h3=22.0cm£®ÕâÁ½¸öÊý¾ÝÖУ¬²»·ûºÏÓÐЧÊý×ÖÒªÇóµÄÊÇh3£®
ÓÉͼ¶¡¿É¶Á³ö£¬¼ÇÊýµã0ÖÁ¼ÇÊýµã4µÄ¾àÀëh4=26.30cm£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸