·ÖÎö £¨1£©µÚÒ»ÃëÄÚÁ£×Ó×öÀàËÆÆ½Å×Ô˶¯£¬¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂɺÍÔ˶¯Ñ§¹«Ê½ÁÐʽÇó½â£»
£¨2£©¸ù¾ÝÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦ÁÐʽÇó½â¹ìµÀ°ë¾¶£¬ÓÉÔ²ÖÜÔ˶¯¹«Ê½ÇóµÃÖÜÆÚ£»
£¨3£©ÏÈÇó³ö5sÄ©µÄλÖÃ×ø±êºÍËÙ¶È´óСºÍ·½Ïò£¬ÔÙÇó³öµÚ6sÄڵĹìµÀ°ë¾¶£¬»³ö¹ì¼££¬×îºóÇóÀëxÖá×îÔ¶¾àÀë
½â´ð ½â£º£¨1£©ÔÚ0¡«1sÄÚ£¬½ðÊôСÇòÔڵ糡Á¦×÷ÓÃÏ£¬ÔÚxÖá·½ÏòÉÏ×öÔÈËÙÔ˶¯vx=v0
y·½Ïò×öÔȼÓËÙÔ˶¯${v}_{y}^{\;}=\frac{q{E}_{0}^{\;}}{m}{t}_{1}^{\;}$=$\frac{0.2¡Á0.1}{10¡Á1{0}_{\;}^{-3}}¡Á1m/s=2m/s$
1sÄ©Á£×ÓµÄËÙ¶È${v}_{1}^{\;}=\sqrt{{v}_{x}^{2}+{v}_{y}^{2}}=2\sqrt{2}m/s$
£¨2£©Éèv1ÓëxÖáÕý·½ÏòµÄ¼Ð½ÇΪ¦Á£¬Ôò$tan¦Á=\frac{{v}_{y}^{\;}}{{v}_{x}^{\;}}$=$\frac{2}{2}=1$
µÃ ¦Á=45¡ã£®
ÔÚ1¡«2sÄÚ£¬Á£×ÓÔڴų¡ÖÐ×öÔ²ÖÜÔ˶¯£¬ÓÉÅ£¶ÙµÚ¶þ¶¨ÂÉ
$q{v}_{1}^{\;}{B}_{0}^{\;}=m\frac{{v}_{1}^{2}}{{R}_{1}^{\;}}$
µÃ${R}_{1}^{\;}=\frac{m{v}_{1}^{\;}}{q{B}_{0}^{\;}}=\frac{10¡Á1{0}_{\;}^{-3}¡Á2\sqrt{2}}{0.1¡Á0.1¦Ð}=\frac{2\sqrt{2}}{¦Ð}m$
Á£×Ó×öÔ²ÖÜÔ˶¯µÄÖÜÆÚ£º$T=\frac{2¦Ðm}{q{B}_{0}^{\;}}=\frac{2¦Ð¡Á10¡Á1{0}_{\;}^{-3}}{0.1¡Á0.1¦Ð}$=2s
£¨3£©»³öÁ£×ÓÔ˶¯µÄ¹ì¼£ÈçͼËùʾ£¬![]()
µÚ1sÄÚµÄÎ»ÒÆ${x}_{1}^{\;}=\frac{1}{2}a{t}_{1}^{2}=\frac{1}{2}\frac{q{E}_{0}^{\;}}{m}{t}_{1}^{2}$=$\frac{1}{2}¡Á\frac{0.1¡Á0.2}{10¡Á1{0}_{\;}^{-3}}¡Á{1}_{\;}^{2}=1m$
СÇòÔÚ6sÄÚÔ˶¯µ½ÀëXÖáµÄ×î´ó¾àÀë${S}_{X}^{\;}=2{R}_{1}^{\;}=\frac{4\sqrt{2}}{¦Ð}m$
Ô˶¯µ½ÀëYÖáµÄ×î´ó¾àÀë${S}_{Y}^{\;}=3{x}_{1}^{\;}+R=3+\frac{2\sqrt{2}}{¦Ð}m$
´ð£º£¨1£©t=1sÄ©£¬½ðÊôСÇòËٶȵĴóС$2\sqrt{2}m/s$£»
£¨2£©1s¡«2sÄÚ£¬½ðÊôСÇòÔڴų¡ÖÐ×öÔ²ÖÜÔ˶¯µÄÖÜÆÚTΪ2sºÍ°ë¾¶RΪ$\frac{2\sqrt{2}}{¦Ð}m$£»
£¨3£©6sÄÚ½ðÊôСÇòÔ˶¯ÀëXÖá¡¢YÖáµÄ×î´ó¾àÀë${S}_{X}^{\;}$Ϊ$\frac{4\sqrt{2}}{¦Ð}m$ºÍ${S}_{Y}^{\;}$Ϊ£¨$3+\frac{2\sqrt{2}}{¦Ð}$£©m
µãÆÀ ±¾ÌâÖÐÁ£×ÓÆæÊýÃëÄÚ×öÀàËÆÆ½Å×Ô˶¯£¬Å¼ÊýÃëÄÚ×öÔÈËÙÔ²ÖÜÔ˶¯£¬¹Ø¼üÊÇ»³öÔ˶¯¹ì¼£²¢¸ù¾ÝƽÅ×Ô˶¯¹æÂɺÍÔÈËÙÔ²ÖÜÔ˶¯¹æÂÉÁÐʽ·ÖÎö£®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | Õñ·ùΪ20cm | |
| B£® | ´«²¥·½ÏòÑØxÖḺÏò | |
| C£® | ´«²¥ËÙ¶ÈΪ10m/s | |
| D£® | PµãµÚÒ»´Î»Øµ½Æ½ºâλÖõÄʱ¿ÌΪ0.1s |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | ´øµçÁ£×ÓµÄ±ÈºÉ | B£® | ´øµçÁ£×ӵijõËÙ¶È | ||
| C£® | ´øµçÁ£×ÓÔڴų¡ÖÐÔ˶¯µÄ°ë¾¶ | D£® | ´øµçÁ£×ÓÔڴų¡ÖÐÔ˶¯µÄÖÜÆÚ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | 0¡«10sÄÚ¿Õ½µ±øºÍÉ¡ÕûÌåËùÊÜÖØÁ¦´óÓÚ¿ÕÆø×èÁ¦£¬10¡«15ÕûÌåËùÊÜÖØÁ¦Ð¡ÓÚ¿ÕÆø×èÁ¦ | |
| B£® | 0¡«10sÄÚ×ö¼ÓËÙ¶ÈÖð½¥¼õСµÄ¼ÓËÙÔ˶¯¶¯£¬10¡«15sÄÚ×ö¼ÓËٶȼõСµÄ¼õËÙÔ˶¯ | |
| C£® | µÚ10sÄ©´ò¿ª½µÂäÉ¡£¬ÒÔºó×öÔȼõËÙÔ˶¯ÖÁµÚ15sÄ© | |
| D£® | 10sÄ©¡«15sÄ©¼ÓËÙ¶È·½ÏòÊúÖ±ÏòÉÏ£¬¼ÓËٶȵĴóСÔÚÖð½¥¼õС |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | $\frac{{T}_{1}}{{T}_{2}}$=$\frac{{m}_{B}}{{m}_{A}}$ | B£® | $\frac{{T}_{1}}{{T}_{2}}$=$\frac{{F}_{1}}{{F}_{2}}$ | ||
| C£® | $\frac{{T}_{1}}{{T}_{2}}$=$\frac{{m}_{A}{F}_{1}}{{m}_{B}{F}_{2}}$ | D£® | $\frac{{T}_{1}}{{T}_{2}}$=$\frac{{m}_{B}{F}_{1}}{{m}_{A}{F}_{2}}$ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | ¸ÃÔÈÇ¿µç³¡µÄµç³¡Ç¿¶ÈΪ$\frac{2mg}{q}$ | |
| B£® | Îï¿é´ÓAµãÔ˶¯µ½CµãµÄ¹ý³ÌÖУ¬Îï¿éºÍµ¯»É¹¹³ÉµÄϵͳ»úеÄÜÊØºã | |
| C£® | Îï¿é´ÓAµãÔ˶¯µ½CµãµÄ¹ý³ÌÖеçÊÆÄܵļõÉÙÁ¿Îªmg£¨H+h£© | |
| D£® | Îï¿é´ÓBµãÔ˶¯µ½CµãµÄ¹ý³ÌÖÐÎï¿éµÄ»úеÄܺ͵çÊÆÄÜÖ®ºÍ±£³Ö²»±ä |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com