·ÖÎö £¨1£©ÓÉÁ£×ÓÔڵ糡ÖÐ×öÀàÆ½Å×Ô˶¯µÄˮƽ¡¢ÊúÖ±Î»ÒÆÁªÁ¢ÇóµÃµç³¡Ç¿¶È£¬ÓÉÁ£×ÓÔڴų¡ÖÐ×öÔ²ÖÜÔ˶¯¼¸ºÎ¹ØÏµµÃµ½°ë¾¶£¬½ø¶øÇóµÃ´Å¸ÐӦǿ¶È£»
£¨2£©Í¨¹ýÀàÆ½Å×Ô˶¯µÄˮƽ¡¢ÊúÖ±Î»ÒÆÇóµÃÆäÔ˶¯Ê±¼ä£¬ÔÙÓɼ¸ºÎ¹ØÏµÇóµÃÔ²ÖÜÔ˶¯µÄÖÐÐĽǣ¬½ø¶ø¸ù¾ÝÔ˶¯ÖÜÆÚÇóµÃÔ˶¯Ê±¼ä£¬Ôڵ糡¡¢´Å³¡ÖеÄÔ˶¯Ê±¼äµþ¼Ó¼´¿ÉµÃÁ£×ÓµÄÔ˶¯Ê±¼ä£»
£¨3£©¸ù¾ÝÀàÆ½Å×Ô˶¯¹æÂÉ£¬ÓÉÊúÖ±Î»ÒÆÇóµÃË®Æ½Î»ÒÆ£¬ÔÙÓÉÔ²ÖÜÔ˶¯µÄ¶Ô³ÆÐÔ£¬Í¨¹ý°ë¾¶ÇóµÃÔÚxÖáÉϵÄÏÒ³¤£¬½ø¶øÇóµÃÁ£×ÓÀ뿪´Å³¡µÄλÖ㬼´µÚ¶þ´Îͨ¹ýxÖáµÄλÖã®
½â´ð
½â£º£¨1£©Á£×ÓÔڵ糡ÖÐÖ»Êܵ糡Á¦×÷Óã¬×öƽÅ×Ô˶¯£¬ËùÒÔ£¬ÓУº
$\left\{\begin{array}{l}{2l={v}_{0}t}\\{l=\frac{1}{2}¡Á\frac{qE}{m}¡Á{t}^{2}}\end{array}\right.$£¬
ËùÒÔÓУº$E=\frac{2ml}{q{t}^{2}}=\frac{2ml{{v}_{0}}^{2}}{4{l}^{2}q}$=$\frac{m{{v}_{0}}^{2}}{2ql}$£»
ÇÒÓÉÆ½Å×Ô˶¯µÄ¹æÂÉ¿ÉÖª£¬Á£×ÓÔڵ糡ÖÐÔ˶¯µÄʱ¼äΪ£º$t=\frac{2l}{{v}_{0}}$£¬½øÈë´Å³¡Ê±£¬ËÙ¶ÈvµÄˮƽ·ÖÁ¿Îª£ºvx=v0£¬ÊúÖ±·ÖÁ¿Îª£º${v}_{y}=\frac{qE}{m}¡Á\frac{2l}{{v}_{0}}={v}_{0}$£¬
½âµÃ£º$v=\sqrt{2}{v}_{0}$£»
Á£×ÓÔڴų¡ÖÐÖ»ÊÜÂåÂ××ÈÁ¦£¬ÔÚÂåÂ××ÈÁ¦µÄ×÷ÓÃÏÂ×÷Ô²ÖÜÔ˶¯£¬ËùÒÔ£¬Á£×ÓÔ˶¯¹ì¼£ÈçͼËùʾ£¬
Ôò£¬Á£×Ó×öÔ²ÖÜÔ˶¯µÄ°ë¾¶Îª£º$R=\sqrt{2}l$£¬
ËùÒÔ£¬ÓÉÂåÂ××ÈÁ¦×÷ÏòÐÄÁ¦¿ÉµÃ£º$Bvq=\frac{m{v}^{2}}{R}$£¬
½âµÃ£º$B=\frac{mv}{qR}=\frac{m{v}_{0}}{ql}$£»
£¨2£©ÓÉ£¨1£©¿ÉÖª£¬Á£×ÓÔڵ糡ÖеÄÔ˶¯Ê±¼äΪ$\frac{2l}{{v}_{0}}$£»
Á£×ÓÔڴų¡ÖÐת¹ýµÄÖÐÐĽÇΪ270¡ã£¬Ô²ÖÜÔ˶¯µÄÖÜÆÚΪ£º$T=\frac{2¦ÐR}{v}=\frac{2¦Ðl}{{v}_{0}}$£¬
ËùÒÔ£¬Á£×ÓÔڴų¡ÖеÄÔ˶¯Ê±¼äΪ£º$\frac{270¡ã}{360¡ã}T=\frac{3¦Ðl}{2{v}_{0}}$£»
ËùÒÔ£¬Á£×Ó´ÓAÔ˶¯µ½O¾ÀúµÄʱ¼äΪ$\frac{2l}{{v}_{0}}+\frac{3¦Ðl}{2{v}_{0}}=\frac{£¨4+3¦Ð£©l}{2{v}_{0}}$£»
£¨3£©Á£×ÓÔڵ糡ÖÐÖ»Êܵ糡Á¦×÷Óã¬×öƽÅ×Ô˶¯£¬ËùÒÔ£¬ÓÐ$\left\{\begin{array}{l}{{x}_{1}={v}_{0}{t}_{1}}\\{y=\frac{1}{2}¡Á\frac{qE}{m}¡Á{{t}_{1}}^{2}=\frac{{{v}_{0}}^{2}}{4l}{{t}_{1}}^{2}}\end{array}\right.$£¬ËùÒÔ£¬${x}_{1}=2\sqrt{yl}$£¬
ËùÒÔ£¬Á£×ÓÔÚ${x}_{1}=2\sqrt{yl}$´¦ÒÔËÙ¶Èv¡ä½øÈë´Å³¡£¬v¡äµÄˮƽ·ÖÁ¿Îªv0£¬ÊúÖ±·ÖÁ¿Îª$\sqrt{2¡Á\frac{qE}{m}¡Áy}=\sqrt{\frac{y}{l}}{v}_{0}$£»
ËùÒÔ£¬$v¡ä=\sqrt{\frac{y}{l}+1}{v}_{0}$£¬ËùÒÔ£¬Á£×ÓÔ˶¯¹ì¼£Èçͼ£¬
£¬
ËùÒÔÓУ¬$sin¦È=\frac{\sqrt{\frac{y}{l}}{v}_{0}}{\sqrt{\frac{y}{l}+1}{v}_{0}}=\sqrt{\frac{y}{y+l}}$
Á£×ÓÓÉÂåÂ××ÈÁ¦×öÏòÐÄÁ¦£¬ËùÒÔ£¬$R¡ä=\frac{mv¡ä}{Bq}=\sqrt{\frac{y}{l}+1}l$£¬
ÓÉÔ²ÖÜÔ˶¯µÄ¶Ô³ÆÐÔ¿ÉÖª£¬Á£×ÓÔڴų¡ÖÐÔ˶¯ÔÚxÖáÉϽصõÄÏÒ³¤Îª$2R¡äsin¦È=2\sqrt{\frac{y}{l}+1}l¡Á\sqrt{\frac{y}{y+l}}=2\sqrt{yl}$£»
ÒòΪÏÒ³¤µÈÓÚÈëÉäµãµÄ×ø±ê£¬ËùÒÔ£¬Á£×ÓÒ»¶¨ÖØOµãÀ뿪´Å³¡£¬ËùÒÔ£¬Á£×ÓµÚ¶þ´Îͨ¹ýxÖáʱµÄºá×ø±êΪx=0£®
´ð£º£¨1£©ÔÈÇ¿µç³¡µÄ³¡Ç¿EµÄ´óСΪ$\frac{m{{v}_{0}}^{2}}{2ql}$£¬ÔÈÇ¿´Å³¡µÄ´Å¸ÐӦǿ¶ÈBµÄ´óСΪ$\frac{m{v}_{0}}{ql}$£»
£¨2£©Á£×Ó´ÓAÔ˶¯µ½O¾ÀúµÄʱ¼äΪ$\frac{£¨4+3¦Ð£©l}{2{v}_{0}}$£»
£¨3£©ÈôÈøÃÁ£×Ó´ÓyÉÏy£¾0µÄÈÎÒâλÖÃP´¦ÑØÕýx·½Ïò·¢É䣨·¢ÉäËÙ¶Èv0²»±ä£©£¬ÔòËüµÚ¶þ´Îͨ¹ýxÖáʱµÄºá×ø±êΪ0£®
µãÆÀ Çó½âÁ£×ÓÔڴų¡ÖеÄÔ˶¯ÎÊÌ⣬һ°ãÒªÏÈÇó³öÁ£×Ó½øÈë´Å³¡µÄËÙ¶È´óС¼°·½Ïò£¬È»ºóÔÙ¸ù¾ÝÔ²ÖÜÔ˶¯µÄ¶Ô³ÆÐÔÇóµÃÈëÉäµãºÍ³öÉäµãµÄ¹ØÏµ£»Èô±ß½ç²»ÔÙÒ»ÌõÖ±ÏßÉÏ£¬ÔòÖ»ÄÜÀûÓÃÔ²»¡µÄÌØÐÔ£¬¶Ô³ÆÐÔÖÊÓ¦ÓõÄʱºòÐÎÊÆ²¢²»Ò»Ö£®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | 6m/s | B£® | 6.5m/s | C£® | 7m/s | D£® | 7.5m/s |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ¿ªÊ¼Á½¸Ë×ö±ä¼ÓËÙÔ˶¯£¬Îȶ¨Ê±£¬Á½¸ËÒÔÏàͬµÄ¼ÓËÙ¶È×öÔȱäËÙÖ±ÏßÔ˶¯ | |
| B£® | ¿ªÊ¼Á½¸Ë×öÔȼÓËÙÔ˶¯£¬Îȶ¨Ê±£¬Á½¸ËÏàͬµÄËÙ¶È×öÔÈËÙÖ±ÏßÔ˶¯ | |
| C£® | ¿ªÊ¼Á½¸Ë×öÔȼÓËÙÔ˶¯£¬Îȶ¨Ê±£¬Á½¸ËÒԺ㶨µÄËٶȲî×öÔÈËÙÖ±ÏßÔ˶¯ | |
| D£® | ¿ªÊ¼Á½¸Ë×ö±ä¼ÓËÙÔ˶¯£¬Îȶ¨Ê±£¬Á½¸ËÒԺ㶨µÄËٶȲî×öÔÈËÙÖ±ÏßÔ˶¯ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | Èý¸öÁ£×ÓµÄËÙ¶È´óС¹ØÏµ¿ÉÄÜÊÇv1=v2£¾v3 | |
| B£® | Èý¸öÁ£×ÓµÄËÙ¶È´óС¹ØÏµ¿ÉÄÜÊÇv1£¼v2£¼v3 | |
| C£® | Á£×ӵıȺÉ$\frac{q}{m}=\frac{v_3}{BL}$ | |
| D£® | Á£×ӵıȺÉ$\frac{q}{m}=\frac{¦Ð}{{2B{t_1}}}$ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ¶¯Á¿´óСһ¶¨ÏàµÈ | B£® | ¶¯ÄÜÒ»¶¨ÏàµÈ | ||
| C£® | ÖÊÁ¿Ò»¶¨ÏàµÈ | D£® | ËÙ¶È´óСһ¶¨ÏàµÈ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | ¹âµ¼ÏËάÓÉÄÚоºÍÍâÌ×Á½²ã×é³É£¬ÄÚоµÄÕÛÉäÂʱÈÍâÌ׵Ĵ󣬹⴫²¥Ê±ÔÚÄÚоÓëÍâÌ׵ĽçÃæÉÏ·¢ÉúÈ«·´Éä | |
| B£® | ÔÚË«·ì¸ÉÉæÊµÑéÖУ¬Èç¹û°ÑµÆÅÝÓëË«·ì¼äµÄµ¥·ìÏòË«·ìÒÆ½ü£¬ÏàÁÚÁ½ÁÁÌõÎÆÖÐÐĵľàÀ뽫±äС | |
| C£® | ÓÃÁ½Ö§Ç¦±Ê¼Ð³ÉÒ»ÌõÏÁ·ì£¬½«ÑÛ¾¦½ôÌù×ÅÏÁ·ì²¢Ê¹ÏÁ·ìÓëÈÕ¹âµÆ¹ÜƽÐУ¬»á¹Û²ìÃ÷°µÏàͬµÄ²ÊÉ«ÌõÎÆ£¬ÕâÊǹâµÄÆ«ÕñÏÖÏó | |
| D£® | µç´Å²¨Óöµ½ÕϰÎïÒª·¢Éú·´É䣬À×´ï¾ÍÊÇÀûÓõç´Å²¨µÄÕâ¸öÌØÐÔ¹¤×÷µÄ | |
| E£® | »ð¼ýÒÔ0.5±¶µÄ¹âËÙ´Ó¹Û²ìÕßµÄÉí±ßÂÓ¹ý£¬¹Û²ìÕß²âµÃ»ð¼ýµÄ³¤¶È±ä¶ÌÁË |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com