6.设f0(x)=sinx.f1(x)=f0′(x).f2(x)=f1′(x).-.fn+1(x)=fn′(x).n∈N.则f2005(x)=( ) A.sinx B.-sinx C.cosx D.-cosx 查看更多

 

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设f0(x)=sinx,f1(x)=f0(x),f2(x)=f1(x),…,fn1(x)=fn’(x),n∈N,则f2005(x)=

  A、sinx         B、-sinx        C、cosx      D、-cosx

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f0(x)=sinxf1(x)=f0′(x),f2(x)=f1′(x),…,fn+1(x)=fn′(x),n∈N,则f2006(x)=(   )

   A.sinx            B.-sinx          C.cosx            D.-cosx

 

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f0(x) = sinxf1(x)=f0′(x),f2(x)=f1′(x),…,fn1(x) = fn′(x),n∈N,则

f2005(x)=                                                                                                     

A.sinx            B.-sinx         C.cosx         D.-cosx

 

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f0(x)=sinxf1(x)=f0′(x),f2(x)=f1′(x),…,fn+1(x)=fn′(x),n∈N,则f2006(x)=(  )
  
A.sinx B.-sinxC.cosx D.-cosx

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f0(x) = sinxf1(x)=f0′(x),f2(x)=f1′(x),…,fn+1(x) = fn′(x),n∈N,则
f2005(x)=                                                         
A.sinx B.-sinx C.cosxD.-cosx

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