Question

2£®A¡«DÊÇÎÒÃÇÒÑѧϰµÄ³£¼ûÎïÖÊ£¬ÆäÖÐAÊǺìÉ«¹ÌÌ壬DÊÇÓÃÓÚ²£Á§¡¢ÔìÖ½¡¢·ÄÖ¯¡¢Ï´µÓ¼ÁµÈÉú²úµÄÔ­ÁÏ£¬ÒÑÖªA¡¢B¡¢C¡¢D²»ÊÇËáºÍ¼î£¬ËüÃÇÓëÏ¡H₂SO₄¡¢Ca£¨OH£©₂Ö®¼äµÄÏ໥¹ØϵÈçͼËùʾ£¨¡°¡ú¡±±íʾÎïÖʼäµÄת»¯¹Øϵ£¬¡°-¡±±íʾÎïÖʼä¿ÉÒÔÏ໥·´Ó¦£©£¬Çë»Ø´ðÎÊÌ⣺

£¨1£©³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£ºBFe£¬CCO2£®
£¨2£©H₂SO₄ÓëCa£¨OH£©₂·´Ó¦µÄ»ù±¾ÀàÐÍÊÇ£º¸´·Ö½â·´Ó¦£®
£¨3£©Ð´³öÏÂÁз´±àºÅ¶ÔÓ¦µÄ»¯Ñ§·½³Ìʽ£º¢Ú2NaOH+CO₂=Na₂CO₃+H₂O£¬
£¨4£©Èô¢ÙÊÇÒ»¸öÖû»·´Ó¦£¬Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ3C+2Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$4Fe+3CO₂¡ü£®

Answer 1

·ÖÎö ¸ù¾ÝA¡«DÊÇÎÒÃÇÒѾ­Ñ§¹ýµÄËÄÖÖ³£¼ûÎïÖÊ£¬AÊǺìÉ«¹ÌÌ壬A»áÓëÁòËá·´Ó¦£¬ËùÒÔAÊÇÑõ»¯Ìú£¬DÓÃÓÚ²£Á§¡¢ÔìÖ½¡¢·ÄÖ¯¡¢Ï´µÓ¼ÁµÄÉú²ú£¬D»áÓëÇâÑõ»¯¸Æ·´Ó¦£¬ËùÒÔDÊÇ̼ËáÄÆ£¬A¡¢B¡¢C¡¢D²»ÊÇËáºÍ¼î£¬Aת»¯³ÉµÄB»áÓëÁòËá·´Ó¦£¬ËùÒÔBÊÇÌú£¬C»áÓëÇâÑõ»¯¸Æ·´Ó¦£¬C»áת»¯³É̼ËáÄÆ£¬ËùÒÔC¿ÉÒÔÊǶþÑõ»¯Ì¼£¬È»ºó½«ÍƳöµÄÎïÖʽøÐÐÑéÖ¤¼´¿É£®

½â´ð ½â£ºA¡«DÊÇÎÒÃÇÒѾ­Ñ§¹ýµÄËÄÖÖ³£¼ûÎïÖÊ£¬AÊǺìÉ«¹ÌÌ壬A»áÓëÁòËá·´Ó¦£¬ËùÒÔAÊÇÑõ»¯Ìú£¬DÓÃÓÚ²£Á§¡¢ÔìÖ½¡¢·ÄÖ¯¡¢Ï´µÓ¼ÁµÄÉú²ú£¬D»áÓëÇâÑõ»¯¸Æ·´Ó¦£¬ËùÒÔDÊÇ̼ËáÄÆ£¬A¡¢B¡¢C¡¢D²»ÊÇËáºÍ¼î£¬Aת»¯³ÉµÄB»áÓëÁòËá·´Ó¦£¬ËùÒÔBÊÇÌú£¬C»áÓëÇâÑõ»¯¸Æ·´Ó¦£¬C»áת»¯³É̼ËáÄÆ£¬ËùÒÔC¿ÉÒÔÊǶþÑõ»¯Ì¼£¬¾­¹ýÑéÖ¤£¬ÍƵ¼ÕýÈ·£»
£¨1£©Í¨¹ýÍƵ¼¿ÉÖª£¬BÊÇFe£¬CÊÇCO₂£»¹ÊÌFe£»CO₂£»
£¨2£©H₂SO₄ÓëCa£¨OH£©₂·´Ó¦Éú³ÉÁòËá±µ³ÁµíºÍË®£¬ÊôÓÚ¸´·Ö½â·´Ó¦£¬¹ÊÌ¸´·Ö½â£»
£¨3£©·´Ó¦¢ÚÊǶþÑõ»¯Ì¼ºÍÇâÑõ»¯ÄÆ·´Ó¦Éú³É̼ËáÄƺÍË®£¬»¯Ñ§·½³ÌʽΪ£º2NaOH+CO₂=Na₂CO₃+H₂O£»¹ÊÌ2NaOH+CO₂=Na₂CO₃+H₂O£»
£¨4£©Èô¢ÙÊÇÒ»¸öÖû»·´Ó¦£¬·´Ó¦ÊÇÑõ»¯ÌúºÍ̼ÔÚ¸ßεÄÌõ¼þÏ·´Ó¦Éú³ÉÌúºÍ¶þÑõ»¯Ì¼£¬»¯Ñ§·½³ÌʽÊÇ£º3C+2Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$4Fe+3CO₂¡ü£®¹ÊÌ3C+2Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$4Fe+3CO₂¡ü£®

µãÆÀ ÔÚ½â´ËÀàÌâʱ£¬Ê×ÏȽ«ÌâÖÐÓÐÌØÕ÷µÄÎïÖÊÍƳö£¬È»ºó½áºÏÍƳöµÄÎïÖʺÍÌâÖеÄת»¯¹ØϵÍƵ¼Ê£ÓàµÄÎïÖÊ£¬×îºó½«ÍƳöµÄ¸÷ÖÖÎïÖÊ´úÈëת»¯¹ØϵÖнøÐÐÑéÖ¤¼´¿É£®