Question

10．已知$\left\{\begin{array}{l}{x=1}\\{y=3}\end{array}\right.$，$\left\{\begin{array}{l}{x=0}\\{y=-2}\end{array}\right.$都是方程ax-y=b的解，则a=5，b=2．

Answer 1

分析 把$\left\{\begin{array}{l}{x=1}\\{y=3}\end{array}\right.$，$\left\{\begin{array}{l}{x=0}\\{y=-2}\end{array}\right.$代入方程ax-y=b，组成二元一次方程组，即可解答．

解答 解：把$\left\{\begin{array}{l}{x=1}\\{y=3}\end{array}\right.$，$\left\{\begin{array}{l}{x=0}\\{y=-2}\end{array}\right.$代入方程ax-y=b，得，
$\left\{\begin{array}{l}{a-3=b}\\{0+2=b}\end{array}\right.$
解得：$\left\{\begin{array}{l}{a=5}\\{b=2}\end{array}\right.$，
故答案为：5，2．

点评 本题考查了二元一次方程的解，解决本题的关键是明确二元一次方程的解．