ÈçÏÂͼËùʾµÄ×°ÖÃÖУ¬AÊÇÂÈÆø·¢Éú×°Öã¬C¡¢D ΪÆøÌå¾»»¯×°Öã¨CÖÐ×°Óб¥ºÍʳÑÎË®£»D ÖÐ×°ÓÐŨÁòËᣩ£¬E ÊÇÓ²Öʲ£Á§¹Ü×°ÓÐϸÌúË¿Íø£¬FΪ¸ÉÔïµÄ¿Õ¹ã¿ÚÆ¿£¬ÉÕ±­G ÖÐ×°ÓÐÇâÑõ»¯ÄÆÈÜÒº¡£

ÊԻشð£º
£¨1£©ÊµÑéÊÒÖÆÂÈÆøµÄ»¯Ñ§·½³Ìʽ£º_______________________________£»
£¨2£©C×°ÖõÄ×÷ÓÃÊÇ________________£»D ×°ÖõÄ×÷ÓÃÊÇ__________________£»
EÖз¢Éú»¯Ñ§·´Ó¦µÄ·½³ÌʽΪ£º_____________________________¡£
£¨3£©ÉÕ±­G ÖÐ×°ÓÐÇâÑõ»¯ÄÆÈÜÒºµÄ×÷ÓÃÊÇ___________________£»·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º_______________________________________¡£
£¨1£©MnO2 + 4 HCl(Ũ) = MnCl2 + Cl2¡ü+ 2 H2O
£¨2£©³ýÈ¥ÂÈÆøÖлìÓеÄÂÈ»¯Çâ    ¸ÉÔïÂÈÆø
2 Fe + 3 Cl2 =" 2" FeCl3
£¨3£©ÎüÊÕ¶àÓàµÄÂÈÆø
Cl2 + 2 NaOH =" NaCl" + NaClO + H2O
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

£¨12·Ö£©Ä³Ð£»¯Ñ§Ð¡×éѧÉúÀûÓá°·ÏÌúмÓëË®·´Ó¦¡±µÄ²úÎﻹԭÑõ»¯Í­£¬²¢ÖÆÈ¡FeCl3¡¤6H2O¾§Ìå¡££¨Í¼Öмг֡¢¼ÓÈȼ°Î²Æø´¦Àí×°ÖþùÒÑÂÔÈ¥£©

¢Ù½«5%Na2CO3ÈÜÒº¼ÓÈ뵽ʢÓÐÒ»¶¨Á¿·ÏÌúмµÄÉÕ±­ÖУ¬¼ÓÈÈÊý·ÖÖÓ£¬ÓÃÇãÎö·¨³ýÈ¥Na2CO3ÈÜÒº£¬È»ºó½«·ÏÌúмÓÃÕôÁóˮϴµÓ2¡«3±é£¬ÓÃÂËÖ½Îü¸ÉË®·Ö¡£
¢Ú½«Ï´µÓ¸ÉÔïºóµÄ·ÏÌúмºÍʯÃÞÈÞ»ìºÏÖÃÓÚÆøÃÜÐÔÁ¼ºÃµÄÉÏÊö×°ÖÃBÖС£
¢ÛÏȵãȼX´¦µÄ¾Æ¾«µÆ£¬´ýÊÔ¹ÜCÖгöÏÖ´óÁ¿Ë®Îíʱ£¬µãȼY´¦µÄ¾Æ¾«ÅçµÆ¡£
¢Ü¾­¹ý±ØÒªµÄʵÑé²Ù×÷ºó£¬µãȼZ´¦µÄ¾Æ¾«µÆ¡£
¢ÝÍ£Ö¹·´Ó¦£¬´ýB¹ÜÀäÈ´ºó£¬È¡ÆäÖеĹÌÌ壬¼ÓÈë¹ýÁ¿Ï¡ÑÎËá³ä·Ö·´Ó¦£¬¹ýÂË¡£
¢ÞÀûÓÃÉÏÊöÂËÒºÖÆÈ¡FeCl3¡¤6H2O¾§Ì壬Éè¼ÆÁ÷³ÌÈçÏ£º

»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊµÑé²½Öè¢ÙµÄÄ¿µÄÊÇ                                            ¡£
£¨2£©²½Öè¢ÛX´¦ÊÇÖ¸       £¨ÓÃͼÖеÄA¡¢B¡¢C¡­¡­±íʾ£©£¬´ýÊÔ¹ÜCÖгöÏÖ´óÁ¿Ë®Îíʱ£¬µãȼY´¦µÄ¾Æ¾«ÅçµÆµÄÄ¿µÄÊÇ£º                                 ¡£
£¨3£©²½Öè¢Ü±ØÒªµÄʵÑé²Ù×÷ÊÇÖ¸£º                                     ¡£
£¨4£©²½Öè¢Þ´ÓFeCl3ÈÜÒºÖеõ½FeCl3¡¤6H2O¾§ÌåµÄÖ÷Òª²Ù×÷°üÀ¨£º
                                                                    ¡£
£¨5£©Õâ¸öÁ÷³ÌÖÐÐè±£³ÖÑÎËá¹ýÁ¿£¬Ö÷ÒªÔ­ÒòÊÇ£º
                                                                      ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

°×ÔÆʯµÄÖ÷Òª³É·ÖΪCaCO3¡¤MgCO3£¬»¹º¬ÓÐÉÙÁ¿Fe¡¢SiµÄ»¯ºÏÎʵÑéÊÒÒÔ°×ÔÆʯΪԭÁÏÖƱ¸Mg(OH)2¼°CaCO3¡£²½ÖèÈçÏ£º

ʵÑé¹ý³ÌÖÐÐèÒªµÄÊý¾Ý¼ûÏÂ±í£º
 
ÇâÑõ»¯Î↑ʼ³ÁµíʱµÄpH
ÇâÑõ»¯Îï³ÁµíÍêȫʱµÄpH
Fe3+
1.9
3.2
Fe2+
7.0
9.0
Mg2+
9.5
11.0
 
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÈÜÒºAÖк¬ÓÐCa2+¡¢Mg2+¡¢Fe2+¡¢Fe3+£¬ÔòÊÔ¼Á¢Ù¿ÉÑ¡Ôñ_________£¨Ìî×Öĸ£¬ÏÂͬ£©£»ÊÔ¼Á¢Ú¿ÉÑ¡Ôñ_________£»ÊÔ¼Á¢Û¿ÉÑ¡Ôñ_________¡£
A£®KMnO4B£®Cl2C£®MgOD£®CaO
£¨2£©ÈôÒªÀûÓ÷´Ó¦¹ý³ÌÖÐÉú³ÉµÄCO2£¬´ÓÈÜÒºDÖÐÖÆÈ¡CaCO3£¬ÐèÒªÏÈͨÈëµÄÒ»ÖÖÆøÌåÊÇ_______£¬È»ºóͨÈëCO2¡£Í¨ÈëCO2ÆøÌåӦѡÔñµÄ×î¼Ñ×°ÖÃΪ_______£¨Ìî×Öĸ£©¡£

£¨3£©¸ù¾Ý±íÖÐÌṩµÄÊý¾ÝÅжϣ¬Fe(OH)3¡¢Fe(OH)2ºÍMg(OH)2µÄÈܶȻý³£ÊýÓÉСµ½´óµÄÅÅÁÐ˳ÐòΪ________________________________¡£
£¨4£©½«ÖÆÈ¡µÄMg(OH)2ìÑÉյõ½MgO£¬È»ºóÔÚ»¹Ô­Â¯£¨Õæ¿Õ£©ÖУ¬1200¡æÌõ¼þÏ£¬ÓùèÌú£¨Ìú²»²ÎÓë·´Ó¦£©»¹Ô­Éú³ÉþÕôÆø¡£ÔÚ»¹Ô­¹ý³ÌÖз´Ó¦Î¶ȶÔÉú³É½ðÊôþµÄÓ°ÏìÈçÏÂͼ£º

ìÑÉÕMg(OH)2ËùÐèÒªµÄÒÇÆ÷³ýÈý½Ç¼Ü¡¢¾Æ¾«µÆÍ⣬»¹±ØÐëÑ¡Ôñ___________¡£MgOÓë¹èÌú·¢ÉúµÄ·´Ó¦´ïµ½Æ½ºâºó£¬Æ½ºâ³£Êý±í´ïʽΪ_______________________¡£ÓÉͼ¿ÉÖª£¬»¹Ô­·´Ó¦µÄ¡÷H ____0£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

(16·Ö)ÒÒËᶡõ¥£¨CH3COOCH2CH­2CH2CH3£©ÊǾßÓйûÏãζµÄÏ㾫£¬¾­õ¥»¯·´Ó¦¿É½øÐÐÒÒËᶡõ¥µÄºÏ³É¡£ÓйØÎïÖʵÄÎïÀíÐÔÖʼûÏÂ±í¡£ºÏ³É¹ý³ÌÈçÏ£ºµÚÒ»²½£º½«¶¡´¼ºÍ¹ýÁ¿µÄÒÒËá»ìºÏ¼ÓÈÈ·¢Éúõ¥»¯·´Ó¦£»µÚ¶þ²½£ºÏ´µÓÌá´¿£»µÚÈý²½£ºÕôÁóÌá´¿¡£


(1)ÉÏÊöÊǺϳɺÍÌá´¿ÒÒËᶡõ¥µÄÓйØ×°ÖÃͼ£¬Çëд³öºÏ³ÉºÍÌá´¿ÒÒËᶡõ¥µÄ²Ù×÷˳Ðò(Ìî×Öĸ)C¡úF¡ú   ¡ú   ¡ú   ¡ú     ¡£
(2)C×°ÖÃÖгýÁË×°ÓÐ1-¶¡´¼ºÍ¹ýÁ¿µÄÒÒËáÍ⣬»¹ÐèÒª¼ÓÈë___________¡¢___________¡£
ÒÒËá¹ýÁ¿µÄÔ­ÒòÊÇ__________________¡£×°ÖÃCÖÐÀäÄý¹ÜµÄ×÷ÓÃÊÇ£º            £»
(3)²½ÖèF£ºõ¥»¯·´Ó¦Íê³Éºó£¬ÏòжϵÄÉÕÆ¿ÖмÓÈë25mLË®µÄ×÷ÓÃÊÇ_____ ___  _   ¡£A×°ÖÃÖÐNa2CO3ÈÜÒºµÄ×÷ÓÃÊÇ_______                          ¡£
(4)²½ÖèEµÄ²Ù×÷ÒªÁìÊÇ£º¢ÙÓÃÒ»Ö»ÊÖµÄÊÖÕÆѹס·ÖҺ©¶·µÄÈû×Ó²¢ÎÕס·ÖҺ©¶·£»
¢ÚÁíÒ»Ö»ÊÖÎÕס»îÈû²¿·Ö£»¢Û                       ¡£
£¨5£©×°ÖÃAµÄ·ÖҺ©¶·ÖÐÒºÌå·ÖΪÁ½²ã£¬ÒÒËᶡõ¥Ó¦ÔÚ    £¨ÌîÉÏ¡¢Ï£©²ã¡£
£¨6£©µÚÒ»²½õ¥»¯·´Ó¦¹ý³ÌÖпÉÄܵõ½µÄÓлú¸±²úÎïÓÐ______(д³öÁ½ÖÖÎïÖʵĽṹ¼òʽ)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

ÒÒËᶡõ¥£º£¨CH3COOCH2CH­2CH2CH3£©ÊÇÒ»ÖÖ³£ÓõÄÏ㾫£¬¾­õ¥»¯·´Ó¦¿É½øÐÐÒÒËᶡõ¥µÄºÏ³É¡£ÓйØÎïÖʵÄÎïÀíÐÔÖÊÏÂ±í¡£   

µÚÒ»²½£º½«¹ýÁ¿µÄ¶¡´¼ºÍÒÒËá»ìºÏ¼ÓÈÈ·¢Éúõ¥»¯·´Ó¦£»
µÚ¶þ²½£ºË®Ï´Ìá´¿£»
µÚÈý²½£ºÕôÁóÌá´¿¡£

(1)ÉÏÊöÊǺϳɺÍÌá´¿ÒÒËᶡõ¥µÄÓйØ×°ÖÃͼ£¬Çëд³öºÏ³ÉºÍÌá´¿ÒÒËᶡõ¥µÄ²Ù×÷˳Ðò(Ìî×Öĸ)C¡úF¡ú    ¡ú    ¡ú    ¡ú     ¡£
(2)C×°ÖÃÖгýÁË×°ÓÐÒÒËáºÍ¹ýÁ¿µÄ1-¶¡´¼Í⣬»¹ÐèÒª¼ÓÈë_________¡¢_____ ___ ¡£
(3)×°ÖÃCÖÐÀäÄý¹ÜµÄ×÷ÓÃÊÇ£º                                             £»ÀäÄýˮӦ´Ó___________£¨Ìî¡°c¡±»ò¡°d¡±£©½øÈëÀäÄý¹Ü
(4)²½ÖèFõ¥»¯·´Ó¦Íê³Éºó£¬ÏòжϵÄÉÕÆ¿ÖмÓÈë25mLË®µÄ×÷ÓÃÊÇ_____ _ _    __¡£
(5)×°ÖÃAµÄ·ÖҺ©¶·ÖÐÒºÌå·ÖΪÁ½²ã£¬ÒÒËᶡõ¥Ó¦ÔÚ    £¨ÌîÉÏ¡¢Ï£©²ã£»B×°ÖÃÕôÁóʱ£¬½ÓÊÕÒÒËᶡõ¥Ç°£¨Î¶È<126.3¡æ£©×¶ÐÎÆ¿Öеõ½µÄÎïÖÊÊÇ       ¡¢       ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

(14·Ö)ʵÑéÌ⣺ij°à¼¶µÄ̽¾¿Ð¡×éÑо¿Ñõ»¯Í­ÄÜ·ñÔÚÂÈËá¼ØµÄÊÜÈÈ·Ö½âÖÐÆðµ½´ß»¯¼ÁµÄ×÷Óã¬Éè¼ÆÁËÈçÏÂʵÑ飺
£¨Ò»£©  ÖƱ¸Ñõ»¯Í­
£¨1£©³ÆÈ¡5.0g CuSO4¡¤5H2O¾§Ì壬ÑÐϸºóÈܽ⣺´Ë²½ÖèÐèÒªµÄÒÇÆ÷ÓУߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߡ£
£¨2£©ÏòÊ¢ÓÐÁòËáÍ­ÈÜÒºµÄÉÕ±­ÖеμÓNaOHÈÜÒº£¬Ö±µ½²»ÔÙ²úÉú³ÁµíΪֹ¡£´Ë²½ÊµÑéÏÖÏ󣺣ߣߣߣߣߣߣߣߣߣߣߣߣ»Àë×Ó·½³ÌʽΪ£º£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£
£¨3£©A£®°Ñ²½Ö裨2£©ÖеÄÈÜÒººÍ³ÁµíתÒƵ½Õô·¢ÃóÄÚ£¬ÉÔ΢¼ÓÈÈÖÁ·ÐÌÚ£¬½Á°è£¬Ö±µ½³ÁµíÈ«²¿±äΪºÚÉ«¹ÌÌ壬ֹͣ¼ÓÈÈ£¬ÔÙ¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔï¡¢ÔÙתÒƵ½Ñв§ÖÐÑÐϸ±¸Óá£
B£®°Ñ²½Ö裨2£©ÖеÄÈÜÒººÍ³ÁµíתÒƵ½¹ýÂËÆ÷ÖйýÂË£¬Ï´µÓ£¬½«ÉÏÊö³ÁµíÔÚÕô·¢ÃóÖнøÐÐÕô·¢£¬ÖÁÈ«²¿±äΪºÚÉ«¹ÌÌåΪֹ¡£ÔÙתÒƵ½Ñв§ÖÐÑÐϸ±¸Óá£
ÄãÈÏΪÄÇÒ»¸ö²½Öè¸üºÃ£¬ËµÃ÷ÀíÓÉ£º£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£
£¨¶þ£©  Ö¤Ã÷Ñõ»¯Í­Æð´ß»¯¼Á×÷ÓÃ
Éè¼Æ¶Ô±ÈʵÑé¢ÙÈÎÈ¡Á½·ÝÂÈËá¼Ø£¬·Ö±ð·ÅÈëÁ½Ö§ÊԹܣ¬ÔÚÆäÖÐÒ»·ÝÖмÓÈë¾­¾«È·³ÆÁ¿µÄngÑõ»¯Í­·ÛÄ©£»¢Ú½«Á½·ÝÂÈËá¼ØͬʱÔÚÏàͬÌõ¼þÏÂÕýÈ·¼ÓÈÈ£¬½«·Å³öµÄÆøÌåͨÈëË®ÖУ»¢ÛÍ£Ö¹¼ÓÈÈ£¬ÀäÈ´£¬½«Ô­ÏÈ»ìÓÐÑõ»¯Í­µÄ·´Ó¦ºó»ìºÏÎï¼ÓË®Èܽ⣬СÐĹýÂË£¬µÃµ½Â˳öÎϴµÓ²¢¸ÉÔ¢Ü¹Û²ìÂ˳öÎïµÄÑÕÉ«ºÍ״̬£»¢Ý½«Â˳öÎïºÍÌ¿·Û»ìºÍ£¬ÔÚÃܱÕÈÝÆ÷ÖиßμÓÈÈ£¬½«·´Ó¦²úÉúµÄÆøÌåͨÈë³ÎÇåµÄʯ»ÒË®ÖУ¬²¢¹Û²ìÊÔÑéÏÖÏó¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ñõ»¯Í­×÷´ß»¯¼ÁµÄÀíÂÛÒÀ¾ÝÊÇ£º£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£
£¨2£©ÒÔÉÏʵÑé²½Ö裬ÓÐÒ»²½²»¹»ÑÏÃÜ£¬ÇëÖ¸³öÊÇÄÇÒ»²½£º£ß£ß£ß£ß£ß£ß£¨Ìî²½ÖèÐòºÅ£©£»¸Ã²½ÖèÓ¦¸Ã×öºÎ¸Ä½ø£¿£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£
£¨3£©Òª´ïµ½ÊµÑéÄ¿µÄ£¬»¹Ó¦¸ÃÔÙÔö¼ÓÒ»¸öʵÑé²½Ö裬Õâ¸öʵÑé²½ÖèÊǣߣߣߣߣߣߡ£
£¨4£©ÈôÓÃÁíÒ»Ì×ʵÑé×°ÖúͲÙ×÷Ìæ»»µÚ¢Ý²½ÊµÑ飬Ҳ¿ÉÒÔ´ïµ½ÕâÒ»²½µÄʵÑéÄ¿µÄ£¬Çë´ÓͼÖÐËù¸øµÄÒÇÆ÷×÷³öºÏÀíÑ¡Ôñ£¬½«ËüÃÇÁ¬½Ó³ÉÒ»¸ö·ûºÏÉè¼ÆÕßÒªÇóµÄÊÔÑé×°Öá£
Õâ¸öʵÑé×°Öð´ÕÕÆøÁ÷´Ó×óµ½ÓÒµÄÁ¬½Ó˳ÐòÊǣߣ߽ӣߣ߽ӣߣ߽ӣߣ߽ӣߣ߽ӣߣߡ£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

ÓÐÈçÏÂͼËùʾÁù×éÖÆȡƯ°×·ÛµÄ×°Öã¬ÇëÒÀ¾ÝÌâÒâ»Ø´ðÎÊÌâ¡£

£¨1£©ÓÐÏÂÁм¸ÏîÓÅȱµã£ºa.²»ÈÝÒ׿ØÖÆ·´Ó¦ËÙÂÊ£»b.ÈÝÒ׿ØÖÆ·´Ó¦ËÙÂÊ£»c.Óи±·´Ó¦·¢Éú£»d.¿É·ÀÖ¹¸±·´Ó¦·¢Éú£»e.ÎÛȾ»·¾³£»f.¿É·ÀÖ¹ÎÛȾ»·¾³¡£Çë¶ÔÉÏͼËùʾµÄ¼×¡¢ÒÒ¡¢±ûÈýÌ××°ÖõÄÓÅȱµã×÷³öÆÀÎö£¬Ñ¡Ôñ·ûºÏÌâÄ¿ÒªÇóµÄÑ¡ÏîÌîÔÚÏÂÁпոñÄÚ¡£
 
Óŵã
ȱµã
¢Ù¼××°ÖÃ
 
 
¢ÚÒÒ×°ÖÃ
 
 
¢Û±û×°ÖÃ
 
 
£¨2£©ÉÏͼËùʾװÖÃÖУ¬¼×ÓÉA¡¢BÁ½²¿·Ö×é³É£»ÒÒÓÉC¡¢D¡¢EÈý²¿·Ö×é³É£»±ûÓÉF¡¢GÁ½²¿·Ö×é³É¡£Çë´ÓͼA¡«G¸÷²¿·Ö×°ÖÃÖÐÑ¡È¡ºÏÀíµÄ×é³É²¿·Ö£¬×é×°³ÉÒ»Ì×½ÏÍêÉƵÄʵÑé×°Öã¬×°ÖõÄÁ¬½Ó˳Ðò£¨°´ÆøÁ÷´Ó×óµ½Óҵķ½Ïò£©ÊÇ__________¡£
£¨3£©ÊµÑéÖÐÈôÓÃ100 mL 12 mol¡¤L-1µÄŨÑÎËáÓë×ãÁ¿µÄMnO2·´Ó¦£¬×îÖÕÉú³ÉCa£¨ClO£©2µÄÎïÖʵÄÁ¿×ÜÊÇ__________£¨Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©0.15 mol£¬ÆäÔ­ÒòÊÇ£¨¼Ù¶¨¸÷²½·´Ó¦¾ùÎÞ·´Ó¦ÎïËðºÄ£¬ÇÒÓÃÎÞ¸±·´Ó¦·¢Éú£©________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÖÓÃ5mol¡¤L-1µÄÇâÑõ»¯ÄÆÈÜÒºÅäÖÆ1mol¡¤L-1µÄÇâÑõ»¯ÄÆÈÜÒº£¬ÔòËùÈ¡Ô­ÇâÑõ»¯ÄÆÈÜÒºÓëÕôÁóË®µÄÌå»ý±ÈԼΪ
A£®1:5B£®1£º4C£®3£º1D£®1£º1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂͼÖÐa¡¢b±íʾÏàÓ¦ÒÇÆ÷ÖмÓÈëµÄÊÔ¼Á£¬¿ÉÓÃÏÂͼװÖÃÖÆÈ¡¡¢ÊÕ¼¯µÄÆøÌåÊÇ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸