X¡¢Y¡¢ZÈýÖÖÖ÷×åÔªËØµÄµ¥ÖÊÔÚ³£ÎÂ϶¼Êdz£¼ûµÄÎÞÉ«ÆøÌ壬ÔÚÊʵ±Ìõ¼þÏÂÈýÕßÖ®¼ä¿ÉÒÔÁ½Á½·¢Éú·´Ó¦Éú³É·Ö±ðÊÇË«ºË¡¢ÈýºËºÍËĺ˵ļס¢ÒÒ¡¢±ûÈýÖÖ·Ö×Ó£¬ÇÒÒÒ¡¢±û·Ö×ÓÖк¬ÓÐXÔªËØµÄÔ×Ó¸öÊý±ÈΪ2¡Ã3¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÔªËØXµÄÃû³ÆÊÇ________¡£
(2)Èô¼×ÓëYµ¥ÖÊÔÚ³£ÎÂÏ»ìºÏ¾ÍÓÐÃ÷ÏÔÏÖÏó£¬Ôò¼×µÄ»¯Ñ§Ê½Îª________¡£±ûÔÚÒ»¶¨Ìõ¼þÏÂת»¯Îª¼×ºÍÒҵķ´Ó¦·½³ÌʽΪ_______________________________________¡£
(3)¢Ù»¯ºÏÎï¶¡º¬X¡¢Y¡¢ZÈýÖÖÔªËØ£¬0.1 mol·L£1¶¡ÈÜÒºµÄpHΪ1£¬½«¶¡Óë±û°´ÎïÖʵÄÁ¿Ö®±ÈΪ1¡Ã1»ìºÏºóËùµÃÎïÖÊÎìµÄ¾§Ìå½á¹¹Öк¬ÓеĻ¯Ñ§¼üΪ________(Ñ¡ÌîÐòºÅ)¡£
a£®Ö»º¬¹²¼Û¼ü b£®Ö»º¬Àë×Ó¼ü
c£®¼Èº¬Àë×Ó¼ü£¬ÓÖº¬¹²¼Û¼ü
¢Ú³£ÎÂÏ£¬ÎìµÄË®ÈÜÒºµÄpH________7(Ìî¡°£¼¡±¡°£½¡±»ò¡°£¾¡±)£¬ÆäÔÒòÊÇ________________________________________________________________________
(ÓÃÀë×Ó·½³Ìʽ±íʾ)¡£
½âÎö¡¡ÎÞÉ«µ¥ÖÊÆøÌåΪH2¡¢N2ºÍO2£¬ÈýÕßÁ½Á½·´Ó¦¿ÉÉú³ÉNO¡¢H2O¡¢NH3µÈ·Ö×Ó£¬ÓÉÒÒ±û·Ö×ÓÖÐXµÄÔ×Ó¸öÊý±ÈΪ2¡Ã3ÍÆÖªXΪH£¬Óɼ×ÓëYµ¥ÖÊÔÚ³£ÎÂÏ»ìºÏÓÐÃ÷ÏÔÏÖÏóÍÆÖªYΪO£¬ZΪN¡£¶¡ÎªHNO3£¬ÎìΪNH4NO3£¬ÔÚNH4NO3¾§ÌåÖмȺ¬Àë×Ó¼ü£¬ÓÖº¬¹²¼Û¼ü£¬NH4NO3Ë®½âÏÔËáÐÔ¡£
´ð°¸¡¡(1)Çâ¡¡(2)NO¡¡4NH3£«5O2
4NO£«6H2O¡¡
(3)¢Ùc¡¡¢Ú£¼¡¡NH
£«H2O
NH3·H2O£«H£«
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
°×޼«´¼Êô¶þ±½ÒÒÏ©Àà¶à·Ó»¯ºÏÎ¾ßÓп¹Ñõ»¯¡¢¿¹°©ºÍÔ¤·ÀÐÄѪ¹Ü¼²²¡µÄ×÷Óá£Ä³¿ÎÌâ×éÌá³öÁËÈçϺϳÉ·Ïߣº
![]()
![]()
¸ù¾ÝÒÔÉÏÐÅÏ¢»Ø´ðÏÂÁÐÎÊÌ⣺
(1)°×޼«´¼µÄ·Ö×ÓʽÊÇ____________¡£
(2)C¡úDµÄ·´Ó¦ÀàÐÍÊÇ____________£»E¡úFµÄ·´Ó¦ÀàÐÍÊÇ____________¡£
(3)»¯ºÏÎï A ²»Óë FeCl3 ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦£¬ÄÜÓë NaHCO3·´Ó¦·Å³ö CO2£¬ÍƲâÆäºË´Å¹²ÕñÇâÆ×(1H£NMR)ÖÐÏÔʾÓÐ________ÖÖ²»Í¬»¯Ñ§»·¾³µÄÇâÔ×Ó£¬Æä¸öÊý±ÈΪ________¡£
(4)д³öA¡úB ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º______________________________________¡£
(5)д³ö»¯ºÏÎï D¡¢E µÄ½á¹¹¼òʽ£ºD________________________________________£¬
E__________________¡£
(6)»¯ºÏÎï
ÓжàÖÖͬ·ÖÒì¹¹Ì壬д³ö·ûºÏÏÂÁÐÌõ¼þµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º
________________________________________________________________________¡£
¢ÙÄÜ·¢ÉúÒø¾µ·´Ó¦£»¢Úº¬±½»·ÇÒ±½»·ÉÏÖ»ÓÐÁ½ÖÖ²»Í¬»¯Ñ§»·¾³µÄÇâÔ×Ó¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(1)BF3ÓëÒ»¶¨Á¿Ë®ÐγÉ(H2O)2·BF3¾§ÌåQ£¬QÔÚÒ»¶¨Ìõ¼þÏ¿Éת»¯ÎªR£º
![]()
¢Ù¾§ÌåQÖи÷ÖÖ΢Á£¼äµÄ×÷ÓÃÁ¦²»Éæ¼°________(ÌîÐòºÅ)¡£
a£®Àë×Ó¼ü¡¡b£®¹²¼Û¼ü¡¡c£®Åäλ¼ü¡¡d£®½ðÊô¼ü¡¡e£®Çâ¼ü¡¡f£®·¶µÂ»ªÁ¦
¢ÚRÖÐÑôÀë×ӵĿռ乹ÐÍΪ____________£¬ÒõÀë×ÓµÄÖÐÐÄÔ×Ó¹ìµÀ²ÉÓÃ________ÔÓ»¯¡£
(2)ÒÑÖª±½·Ó(
)¾ßÓÐÈõËáÐÔ£¬ÆäKa£½1.1¡Á10£10£»Ë®ÑîËáµÚÒ»¼¶µçÀëÐγɵÄÀë×Ó
ÄÜÐγɷÖ×ÓÄÚÇâ¼ü¡£¾Ý´ËÅжϣ¬ÏàͬζÈϵçÀëÆ½ºâ³£ÊýKa2(Ë®ÑîËá)________Ka(±½·Ó)(Ìî¡°£¾¡±»ò¡°£¼¡±)£¬ÆäÔÒòÊÇ_____________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¶þïÌú·Ö×Ó[Fe(C5H5)2]ÊÇÒ»ÖÖ½ðÊôÓлúÅäºÏÎÊÇȼÁÏÓ͵ÄÌí¼Ó¼Á£¬ÓÃÒÔÌá¸ßȼÉÕµÄЧÂʺÍÈ¥ÑÌ£¬¿É×÷Ϊµ¼µ¯ºÍÎÀÐǵÄÍ¿Áϵȡ£ËüµÄ½á¹¹ÈçÓÒͼËùʾ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A£®¶þïÌúÖÐFe2£«Óë»·Îì¶þÏ©Àë×Ó(C5H
)Ö®¼äΪÀë×Ó¼ü
B£®FeÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊǵÚËÄÖÜÆÚ¢øA
C£®Fe2£«µÄµç×ÓÅŲ¼Ê½Îª1s22s22p63s23p63d6
D£®»·Îì¶þÏ©(
)ÖеÄ̼Ô×ÓÓÐspÔÓ»¯¡¢sp2ÔÓ»¯¡¢sp3ÔÓ»¯
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÔÂÇòº¬ÓÐH¡¢He¡¢N¡¢Na¡¢Mg¡¢SiµÈÔªËØ£¬ÊÇÈËÀàδÀ´µÄ×ÊÔ´±¦¿â¡£
(1)3HeÊǸßЧºËÄÜÔÁÏ£¬ÆäÔ×ÓºËÄÚÖÐ×ÓÊýΪ________¡£
(2)NaµÄÔ×ӽṹʾÒâͼΪ________£¬NaÔÚÑõÆøÖÐÍêȫȼÉÕËùµÃ²úÎïµÄµç×ÓʽΪ________¡£
(3)MgClÔÚ¹¤ÒµÉÏÓ¦Óù㷺£¬¿ÉÓÉMgOÖÆ±¸¡£
¢ÙMgOµÄÈÛµã±ÈBaOµÄÈÛµã________(Ìî¡°¸ß¡±»ò¡°µÍ¡±)¡£
¢ÚÔÂÇòÉÏij¿óʯ¾´¦ÀíµÃµ½µÄMgOÖк¬ÓÐÉÙÁ¿SiO2£¬³ýÈ¥SiO2µÄÀë×Ó·½³ÌʽΪ__________________________£»SiO2µÄ¾§ÌåÀàÐÍΪ________¡£
¢ÛMgOÓëÌ¿·ÛºÍÂÈÆøÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦¿ÉÖÆ±¸MgCl2¡£ÈôÎ²Æø¿ÉÓÃ×ãÁ¿NaOHÈÜÒºÍêÈ«ÎüÊÕ£¬ÔòÉú³ÉµÄÑÎΪ________________(д»¯Ñ§Ê½)¡£
(4)ÔÂÈÀÖк¬ÓзḻµÄ3He£¬´ÓÔÂÈÀÖÐÌáÁ¶1 kg 3He£¬Í¬Ê±¿ÉµÃ6000 kg H2ºÍ700 kg N2£¬ÈôÒÔËùµÃH2ºÍN2ΪÔÁϾһϵÁз´Ó¦×î¶à¿ÉÉú²ú̼ËáÇâï§________kg¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
X¡¢Y¡¢Z¾ùΪ¶ÌÖÜÆÚÔªËØ£¬X¡¢Y´¦ÓÚͬһÖÜÆÚ£¬X¡¢ZµÄ×îµÍ¼ÛÀë×Ó·Ö±ðΪX2£ºÍZ££¬Y£«ºÍZ£¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®Ô×Ó×îÍâ²ãµç×ÓÊý£ºX>Y>Z
B£®µ¥Öʷе㣺X>Y>Z
C£®Àë×Ó°ë¾¶£ºX2£>Y£«>Z£
D£®Ô×ÓÐòÊý£ºX>Y>Z
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
230ThºÍ232ThÊÇîʵÄÁ½ÖÖÍ¬Î»ËØ£¬232Th¿ÉÒÔת»¯³É233U¡£ÏÂÁÐÓйØThµÄ˵·¨ÕýÈ·µÄÊÇ
A. Th ÔªËØµÄÖÊÁ¿ÊýÊÇ232 B. Th ÔªËØµÄÏà¶ÔÔ×ÓÖÊÁ¿ÊÇ231
C. 232Th ת»»³É233UÊÇ»¯Ñ§±ä»¯ D. 230ThºÍ232ThµÄ»¯Ñ§ÐÔÖÊÏàͬ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÒÑÖª
£¨1£©H2O(g) == H2O(l) ¦¤H1£½-Q1 kJ¡¤mol-1
£¨2£©CH3OH(g) == CH3OH(l) ¡÷H2£½-Q2 kJ¡¤mol-1
£¨3£©2CH3OH(g) +3O2(g) == 2CO2(g)£«4H2O(g) ¡÷H3£½-Q3 kJ¡¤mol-1
£¨Q1¡¢Q2¡¢Q3¾ù´óÓÚ0£©ÈôҪʹ32gҺ̬¼×´¼ÍêȫȼÉÕ£¬×îºó»Ö¸´µ½ÊÒΣ¬·Å³öµÄÈÈÁ¿Îª£¨µ¥Î»£ºkJ£© £¨ £©
A£®Q1+Q2+Q3 B£® 0.5 Q3-Q2+2Q1 C£® 0.5 Q3+ Q2-2Q1 D£® 0.5£¨Q1+Q2+Q3£©
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com