£¨7·Ö£©ÔªËØÖÜÆÚ±íÊÇѧϰÎïÖʽṹºÍÐÔÖʵÄÖØÒª¹¤¾ß£¬ÏÂÃæÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬±íÖÐËùÁÐ×ÖĸA¡¢D¡¢E¡¢G¡¢Q¡¢M¡¢R¡¢T·Ö±ð´ú±íijһ»¯Ñ§ÔªËØ¡£ÇëÓÃËù¸øÔªËػشðÏÂÁÐÎÊÌâ¡£

A

 

 

 

 

 

 

D

E

 

 

 

G

 

 

Q

 

M

R

 

 

 

 

 

 

 

 

T

 

 

 

 

 

 

 

 

 

 

£¨1£©Ä³ÔªËØÔ­×ӵĺËÍâµç×Ó²ãÊýÊÇ×îÍâ²ãµç×ÓÊýµÄ3±¶£¬¸ÃÔªËصÄÔ­×ӽṹʾÒâͼΪ               ¡£

£¨2£©Ä³Ð©ÔªËصÄÔ­×Ó¿ÉÐγÉÓëAr¾ßÓÐÏàͬµç×Ó²ã½á¹¹µÄ¼òµ¥Àë×Ó£¬ÕâЩÀë×ӵİ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£¨ÌîÀë×Ó·ûºÅ£©                                ¡£

£¨3£©M¡¢DÁ½ÖÖÔªËØÐγɵĻ¯ºÏÎﺬÓеĻ¯Ñ§¼üÀàÐÍÊÇ            £¬Æä·Ö×ÓÊÇ£¨Ìî¡°¼«ÐÔ¡±»ò¡°·Ç¼«ÐÔ¡±£©       ·Ö×Ó£»

A·Ö±ðÓëD¡¢E¡¢RÐγɵķÖ×ÓÖУ¬·Ö×Ó¼ä´æÔÚÇâ¼üµÄÊÇ£¨Ìî·Ö×Óʽ£©           ¡£

AÓëDÐγɷÖ×ӵĿռä½á¹¹¿ÉÄÜÊÇ£¨ÌîÐòºÅ£©             ¡££¨2·Ö£©

 

¡¾´ð°¸¡¿

(ÿ¿Õ1·Ö,¹²6·Ö)£¨1£© Na      £¨2£© S2- >Cl-

£¨3£©¼«ÐÔ¹²¼Û¼ü£¬ ·Ç¼«ÐÔ·Ö×Ó    NH3    c  d (ÉÙÑ¡¡¢´íÑ¡¾ù²»¸ø·Ö£¬2·Ö)

¡¾½âÎö¡¿£¨1£©¸ù¾ÝÔªËØÔÚÖÜÆÚ±íÖеÄλÖÿÉÖª£¬ÔªËØÈ«²¿Î»ÓÚÇ°ËÄÖÜÆÚ£¬ËùÒÔºËÍâµç×Ó²ãÊýÊÇ×îÍâ²ãµç×ÓÊýµÄ3±¶µÄÔªËØÊÇÄÆÔªËØ¡£

£¨2£©ArµÄÔ­×ÓÐòÊýΪ18£¬ËùÒÔ¼òµ¥Àë×Ó·Ö±ðÊÇS2-¡¢Cl-¡£ºËÍâµç×ÓÅŲ¼ÏàͬµÄÀë×Ó£¬ÆäÀë×Ӱ뾶ËæÔ­×ÓÐòÊýµÄÔö´ó¶ø¼õС£¬ËùÒÔÀë×Ӱ뾶ÊÇS2- >Cl-¡£

£¨3£©M¡¢DÁ½ÖÖÔªËØ·Ö±ðÊÇSºÍC£¬ÐγɵĻ¯ºÏÎïÊÇCS2£¬º¬ÓеĻ¯Ñ§¼üÊǼ«ÐÔ¼ü£¬ÓÉÓÚÊÇÖ±ÏßÐͽṹ£¬ËùÒÔÊôÓڷǼ«ÐÔ·Ö×Ó¡£A·Ö±ðÓëD¡¢E¡¢RÐγɵķÖ×Ó·Ö±ðÊÇCH4¡¢NH3¡¢HCl£¬ÆäÖк¬ÓÐÇâ¼üµÄÊÇ°±Æø¡£HºÍCÐγɵķÖ×Ó¿ÉÒÔÊǼ×Íé»ò±½µÈ£¬ËùÒÔ´ð°¸Ñ¡cd¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔªËØÖÜÆÚ±íÊÇѧϰÎïÖʽṹÓëÐÔÖʵÄÖØÒª¹¤¾ß£®Ï±íÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬±íÖÐËùÁÐ×ÖĸA¡¢B¡¢D¡¢E¡¢G¡¢H¡¢Q¡¢M¡¢R·Ö±ð´ú±íijһ»¯Ñ§ÔªËØ£®ÇëÓÃËù¸øÔªËػشðÏÂÁÐÎÊÌ⣮
A
M B D
G H Q R
E
£¨1£©QÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃ
µÚÈýÖÜÆÚ¢öA×å
µÚÈýÖÜÆÚ¢öA×å
£¬EÔªËØÔ­×ӽṹʾÒâͼΪ

£¨2£©E¡¢Q¡¢RÈýÖÖÔªËصÄÔ­×Ó¿ÉÐγÉÓëAr¾ßÓÐÏàͬµç×Ó²ã½á¹¹µÄ¼òµ¥Àë×Ó£¬ÕâЩÀë×ӵİ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£¨ÌîÀë×Ó·ûºÅ£©
S2-£¾Cl-£¾K+
S2-£¾Cl-£¾K+
£®
£¨3£©M¡¢DÁ½ÔªËØÐγɵĻ¯ºÏÎïÖк¬ÓеĻ¯Ñ§¼üÀàÐÍÊÇ
¹²¼Û¼ü
¹²¼Û¼ü
£¬ÆäMD2·Ö×ӵĽṹʽ£º
O=C=O
O=C=O
£®
£¨4£©ÓñíÖÐËù¸øÔªËØ×é³É·´Ó¦ÎÓû¯Ñ§·½³Ìʽ˵Ã÷ÔªËØQºÍR·Ç½ðÊôÐÔµÄÇ¿Èõ£º
H2S+C12=2HC1+S
H2S+C12=2HC1+S
£»ÔªËØG¡¢HµÄ½ðÊôÐÔÇ¿Èõ£º
2Na+2H2O=2NaOH+H2¡ü
2Na+2H2O=2NaOH+H2¡ü
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔªËØÖÜÆÚ±íÊÇѧϰÎïÖʽṹºÍÐÔÖʵÄÖØÒª¹¤¾ß£¬ÏÂͼÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬±íÖÐËùÁÐ×ÖĸA¡¢D¡¢F¡¢G¡¢Q¡¢M¡¢R¡¢N¡¢T·Ö±ð´ú±íijÖÖ»¯Ñ§ÔªËØ£®ÇëÒÀ¾ÝÕâ9ÖÖÔªËػشðÏÂÁÐÎÊÌ⣮

£¨1£©±íÖÐTµÄÔªËØ·ûºÅΪ
Fe
Fe
£¬½ðÊôÐÔ×îÇ¿µÄÔªËØÊÇ
K
K
£¨ÌîÔªËØ·ûºÅ£©£®
£¨2£©ÔªËصķǽðÊôÐÔ£ºM
£¼
£¼
R£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©£®
£¨3£©RµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄ»¯Ñ§Ê½ÊÇ
HClO4
HClO4
£®
£¨4£©F¡¢GÁ½ÔªËØÐγɵĵ­»ÆÉ«¹ÌÌåÎïÖʵĵç×ÓʽΪ
£¬¸ÃÎïÖʺ¬ÓеĻ¯Ñ§¼üµÄÀàÐÍÊÇ
Àë×Ó¼ü¡¢·Ç¼«ÐÔ¹²¼Û¼ü
Àë×Ó¼ü¡¢·Ç¼«ÐÔ¹²¼Û¼ü
£®
£¨5£©±íÖÐijЩԪËصÄÔ­×Ó¿ÉÐγÉÓëAr¾ßÓÐÏàͬµç×Ó²ã½á¹¹µÄ¼òµ¥Àë×Ó£¬ÕâЩÀë×ӵİ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ
S2-£¾Cl-£¾K+
S2-£¾Cl-£¾K+
£¨ÌîÀë×Ó·ûºÅ£©£®
£¨6£©±íÖÐijԪËØÔ­×ӵĺËÍâµç×Ó²ãÊýÊÇ×îÍâ²ãµç×ÓÊýµÄ3±¶£¬¸ÃÔªËصÄÔ­×ӽṹʾÒâͼΪ
£®
£¨7£©AÓëDÐγɷÖ×ӵĿռä½á¹¹¿ÉÄÜÊÇ£¨ÌîÐòºÅ£©
cd
cd
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨10·Ö£©ÔªËØÖÜÆÚ±íÊÇѧϰÎïÖʽṹÓëÐÔÖʵÄÖØÒª¹¤¾ß¡£Ï±íÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬±íÖÐËùÁÐ×ÖĸA¡¢B¡¢D¡¢E¡¢G¡¢H¡¢Q¡¢M¡¢R·Ö±ð´ú±íijһ»¯Ñ§ÔªËØ¡£ÇëÓÃËù¸øÔªËػشðÏÂÁÐÎÊÌâ¡£

(1)QÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖà       £¬EÔªËØÔ­×ӽṹʾÒâͼΪ_____     

(2)E¡¢Q¡¢RÈýÖÖÔªËصÄÔ­×Ó¿ÉÐγÉÓëAr¾ßÓÐÏàͬµç×Ó²ã½á¹¹µÄ¼òµ¥Àë×Ó£¬ÕâЩÀë×ӵİ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£¨ÌîÀë×Ó·ûºÅ£©_________________________________¡£

(3)M¡¢DÁ½ÔªËØÐγɵĻ¯ºÏÎïÖк¬ÓеĻ¯Ñ§¼üÀàÐÍÊÇ                 £¬ÆäMD2·Ö×ӵĽṹʽ£º                  ¡£

(4) ÓñíÖÐËù¸øÔªËØ×é³É·´Ó¦ÎÓû¯Ñ§·½³Ìʽ˵Ã÷ÔªËØQºÍR·Ç½ðÊôÐÔµÄÇ¿Èõ£º

                        £»ÔªËØG¡¢HµÄ½ðÊôÐÔÇ¿Èõ£º                    

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄêÉϺ£ÊÐÕ¢±±Çø¸ßÈýÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

ÔªËØÖÜÆÚ±íÊÇѧϰÎïÖʽṹºÍÐÔÖʵÄÖØÒª¹¤¾ß£¬ÔªËØÖÜÆÚÂÉ·´Ó³ÁËÔªËØÐÔÖʵÄÖÜÆÚÐԱ仯¹æÂÉ¡£

£¨1£©ÔªËØAµÄÔ­×Ó×îÍâ²ãµç×ÓÅŲ¼Ê½Îªnsnnpn£¬¸ÃÔ­×Ó×îÍâ²ã¹²ÓР      ÖÖ²»Í¬Ô˶¯×´Ì¬µÄµç×Ó£¬¸ÃÔ­×ÓºËÍâ¹²ÓР      ÖÖÄÜÁ¿²»Í¬µÄµç×Ó¡£ÔªËØAÓëÇâÔªËØÐγɵķÖ×Ó£¬Æä¿Õ¼ä½á¹¹¿ÉÄÜÊÇ£¨ÌîÐòºÅ£©                 ¡£

£¨2£©ÏÂÁб仯¹æÂÉÖÐÕýÈ·µÄÊÇ       ¡£

         A£®½ðÊôK¡¢Na¡¢MgµÄÈ۷еãÓɵ͵½¸ß

B£®C1-¡¢Br-¡¢I-µÄʧµç×ÓÄÜÁ¦ÓÉÈõµ½Ç¿

       C£®H+¡¢Li+¡¢H-µÄ°ë¾¶ÓÉ´óµ½Ð¡

       D£®H3PO4¡¢HClO4¡¢H2SO4µÄËáÐÔÓÉÈõµ½Ç¿

£¨3£©µÚ¶þÖÜÆÚÔªËØÖУ¬³ýBe¡¢B¡¢NeÈýÖÖÔªËØÍ⣬ÆäËûÔªËصÄÇ⻯Îï·ÐµãÈçϱíËùʾ£¬ÆäÖÐAµÄµç×ÓʽΪ        £¬EµÄ»¯Ñ§Ê½Îª       ¡£

Ç⻯Îï

A

B

HF

D

E

·Ðµã/¡æ

1317

100

19.5

33

164

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ì½­ËÕÊ¡¸ßÒ»µÚ¶þѧÆÚÆÚÄ©¸´Ï°»¯Ñ§ÊÔ¾í1 ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£©ÔªËØÖÜÆÚ±íÊÇѧϰÎïÖʽṹÓëÐÔÖʵÄÖØÒª¹¤¾ß¡£Ï±íÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬±íÖÐËùÁÐ×ÖĸA¡¢B¡¢D¡¢E¡¢G¡¢H¡¢Q¡¢M¡¢R·Ö±ð´ú±íijһ»¯Ñ§ÔªËØ¡£ÇëÓÃËù¸øÔªËػشðÏÂÁÐÎÊÌâ¡£

(1)QÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖà        £¬EÔªËØÔ­×ӽṹʾÒâͼΪ_____     

(2)E¡¢Q¡¢RÈýÖÖÔªËصÄÔ­×Ó¿ÉÐγÉÓëAr¾ßÓÐÏàͬµç×Ó²ã½á¹¹µÄ¼òµ¥Àë×Ó£¬ÕâЩÀë×ӵİ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£¨ÌîÀë×Ó·ûºÅ£©_________________________________¡£

(3)M¡¢DÁ½ÔªËØÐγɵĻ¯ºÏÎïÖк¬ÓеĻ¯Ñ§¼üÀàÐÍÊÇ                  £¬ÆäMD2·Ö×ӵĽṹʽ£º                   ¡£

(4) ÓñíÖÐËù¸øÔªËØ×é³É·´Ó¦ÎÓû¯Ñ§·½³Ìʽ˵Ã÷ÔªËØQºÍR·Ç½ðÊôÐÔµÄÇ¿Èõ£º

                         £»ÔªËØG¡¢HµÄ½ðÊôÐÔÇ¿Èõ£º                    

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸