Éú»îÖÐÓöµ½µÄijЩÎÊÌ⣬³£³£Éæ¼°µ½»¯Ñ§ÖªÊ¶£¬ÏÂÁи÷ÏîÐðÊöÕýÈ·µÄÊÇ

A£®¡°¼ÓµâÑΡ±¡¢¡°¸ß¸ÆÅ£ÄÌ¡±¡¢¡°¸»ÎøÓªÑøÆ·¡±µÈʳÓÃÆ·Öеĵ⡢¸Æ¡¢ÎøÊÇÖ¸µ¥ÖÊ

B£®ÂÁºÏ½ðµÄ´óÁ¿Ê¹Óù鹦ÓÚÈËÃÇÄÜÓý¹Ì¿µÈ»¹Ô­¼Á´ÓÑõ»¯ÂÁÖлñÈ¡ÂÁµ¥ÖÊ

C£®Ò½ÁÆÉϽøÐÐθ²¿ÔìӰǰ£¬»¼Õß·þÓõġ°±µ²Í¡±ÊÇBaCO3µÈ²»ÈÜÓÚË®µÄÎïÖÊ

D£®¡°Ëá¿ÉÒÔ³ýÐ⡱¡¢¡°ÈȵĴ¿¼îÈÜҺȥÓÍÎÛ¡±£¬¶¼·¢ÉúÁË»¯Ñ§±ä»¯

D

¡¾½âÎö¡¿

ÊÔÌâ·ÖÎö£ºA£®¡°¼ÓµâÑΡ±¡¢¡°¸ß¸ÆÅ£ÄÌ¡±¡¢¡°¸»ÎøÓªÑøÆ·¡±µÈʳÓÃÆ·Öеĵ⡢¸Æ¡¢ÎøÊÇÖ¸ÔªËØ£¬´íÎó£»B£®ÂÁºÏ½ðµÄ´óÁ¿Ê¹Óù鹦ÓÚÈËÃÇÓõç½â·¨µç½âÈÛÈÚµÄÑõ»¯ÂÁÖлñÈ¡ÂÁµ¥ÖÊ£¬´íÎó£»C£®Ò½ÁÆÉϽøÐÐθ²¿ÔìӰǰ£¬»¼Õß·þÓõġ°±µ²Í¡±ÊÇBaSO4µÈ²»ÈÜÓÚˮҲ²»ÄÜÈÜÓÚËáµÄÎïÖÊ£¬ÈôʹÓÃBaCO3£¬ÓÉÓÚÆäÄܹ»ÈÜÓÚËáµ¼ÖÂÖØ½ðÊôÖж¾£¬´íÎó£»D£®¡°Ëá¿ÉÒÔ³ýÐ⡱¡¢¡°ÈȵĴ¿¼îÈÜҺȥÓÍÎÛ¡±£¬¶¼²úÉúÁËеÄÎïÖÊ£¬·¢ÉúµÄÊÇ»¯Ñ§±ä»¯£¬ÕýÈ·¡£

¿¼µã£º¿¼²é»¯Ñ§ÖªÊ¶ÔÚÉú»îÖеÄÓ¦ÓõÄ֪ʶ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014-2015¸ÊËàÊ¡ÌìË®ÊиßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

£¨±¾Ð¡Ìâ14·Ö£ºÃ¿¿Õ2·Ö£©ÏÂͼÊÇʵÑéÊÒÖÆ±¸ÂÈÆø²¢½øÐÐһϵÁÐÏà¹ØÊµÑéµÄ×°Ö㨼гÖÉ豸ÒÑÂÔ£©¡£

£¨1£©ÖƱ¸ÂÈÆøÑ¡ÓõÄҩƷΪ£ºÆ¯·Û¾«¹ÌÌåºÍŨÑÎËᣬÏà¹ØµÄ»¯Ñ§·´Ó¦·½³ÌʽΪ£º__ __¡£

£¨2£©×°ÖÃBÖб¥ºÍʳÑÎË®µÄ×÷ÓÃÊÇ_________________________________£»Í¬Ê±×°ÖÃBÒàÊǰ²È«Æ¿£¬¼à²âʵÑé½øÐÐʱCÖÐÊÇ·ñ·¢Éú¶ÂÈû£¬Çëд³ö·¢Éú¶ÂÈûʱBÖеÄÏÖÏó__________¡£

£¨3£©×°ÖÃCµÄʵÑéÄ¿µÄÊÇÑéÖ¤ÂÈÆøÊÇ·ñ¾ßÓÐÆ¯°×ÐÔ£¬Îª´ËCÖТñ¡¢¢ò¡¢¢óÒÀ´Î·ÅÈë___¡£

A

B

C

D

¢ñ

¸ÉÔïµÄÓÐÉ«²¼Ìõ

¸ÉÔïµÄÓÐÉ«²¼Ìõ

ʪÈóµÄÓÐÉ«²¼Ìõ

ʪÈóµÄÓÐÉ«²¼Ìõ

¢ò

¼îʯ»Ò

¹è½º

ŨÁòËá

ÎÞË®ÂÈ»¯¸Æ

¢ó

ʪÈóµÄÓÐÉ«²¼Ìõ

ʪÈóµÄÓÐÉ«²¼Ìõ

¸ÉÔïµÄÓÐÉ«²¼Ìõ

¸ÉÔïµÄÓÐÉ«²¼Ìõ

£¨4£©Éè¼Æ×°ÖÃD¡¢EµÄÄ¿µÄÊÇ ¡£´ò¿ª»îÈû£¬½«×°ÖÃDÖÐÉÙÁ¿ÈÜÒº¼ÓÈë×°ÖÃEÖУ¬Õñµ´¡£¹Û²ìµ½µÄÏÖÏóÊÇ_______________________________¡£

£¨5£©Ä³Í¬Ñ§½¨Ò齫װÖÃFÖеÄÒ©Æ·¸ÄÓÃ×ãÁ¿µÄNaHSO3ÈÜÒºÎüÊÕÓàÂÈ£¬ÀÏʦÈÏΪ²»Í×£¬ÓÃ×Ü·´Ó¦µÄÀë×Ó·½³Ìʽ½âÊÍÔ­Òò_____________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014-2015ѧÄêºþÄÏÊ¡ÔÀÑôÊиßÈý½ÌѧÖÊÁ¿¼ì²â»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁÐÓйØËµ·¨ºÍ½áÂÛ¶¼ÕýÈ·µÄÊÇ

A£®ÒÑÖªCu2O + 2H+=Cu2+ + Cu + H2O£¬ÇâÆø»¹Ô­Ñõ»¯Í­ºóËùµÃºìÉ«¹ÌÌåÄÜÍêÈ«ÈÜÓÚÏ¡ÏõËᣬ˵Ã÷ºìÉ«¹ÌÌåÊÇÍ­

B£®ÓÃÕôÁóË®¡¢·Ó̪¡¢BaCl2ÈÜÒººÍÒÑ֪Ũ¶ÈÑÎËá±ê×¼ÈÜÒº×÷ÊÔ¼Á£¬¿É²â¶¨NaOH¹ÌÌå(ÔÓÖʽöΪNa2CO3)µÄ´¿¶È

C£®½«SO2ÆøÌåͨÈëäåË®ÖУ¬äåË®ÑÕÉ«Öð½¥ÍÊÈ¥£¬ËµÃ÷SO2¾ßÓÐÆ¯°×ÐÔ

D£®ÒÑÖªKsp(Ag2CrO4)=9.0¡Á10-12, Ksp(AgCl)=1.8¡Á10-10£¬ËµÃ÷Ag2CrO4µÄÈܽâ¶ÈСÓÚAgCl

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014-2015ѧÄêºþÄÏÊ¡¸ßÈýÉÏѧÆÚ12ÔÂÁª¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁÐͼʾÓë¶ÔÓ¦µÄÐðÊöÏà·ûµÄÊÇ

A£®ÓÉͼ1ËùʾÇúÏß¿ÉÖª£¬»¯Ñ§´ß»¯±Èø´ß»¯µÄЧ¹ûºÃ

B£®ÔÚH2SÈÜÒºµ¼µçÐÔʵÑéÖУ¬ÓÉͼ2ËùʾÇúÏß¿ÉÈ·¶¨Í¨ÈëµÄÆøÌåXΪCl2

C£®ÔÚÆäËüÌõ¼þ²»±äʱ£¬2SO2(g)+ O2(g)2SO3(g)ת»¯¹ØÏµ£¨Í¼3£©ÖУ¬×Ý×ø±ê±íʾO2µÄת»¯ÂÊ

D£®Í¼4ÊÇÓÃ0.l000 mol¡¤L£­1µÄÑÎËáµÎ¶¨20.00 mL 0.l000mol¡¤L£­1 Na2CO3ÈÜÒºµÄÇúÏߣ¬´Óa¡úbµã·´Ó¦µÄÀë×Ó·½³ÌʽΪ£ºHCO3£­£«H£« = CO2¡ü£«H2O

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014-2015ѧÄêºþÄÏÊ¡¸ßÈýÉÏѧÆÚ12ÔÂÁª¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁÐÓйØÊµÑéÕýÈ·µÄ

A£®Í¼1£ºÏ¡ÊÍŨÁòËá

B£®Í¼2£ºÊµÑéÊÒÖÆ±¸°±Æø

C£®Í¼3£ºÊµÑéÊÒÖÆ±¸ÒÒËáÒÒõ¥

D£®Í¼4£º¼ìÑéŨÁòËáÓëÕáÌÇ·´Ó¦²úÉúµÄ¶þÑõ»¯Áò

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014-2015ѧÄêºÓ±±Ê¡¸ßÈýÉÏѧÆÚµÚ¶þ´ÎÁª¿¼Àí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨15·Ö£©¶þÑõ»¯Ì¼ÊÇÒýÆð¡°ÎÂÊÒЧӦ¡±µÄÖ÷ÒªÎïÖÊ£¬½ÚÄܼõÅÅ£¬¸ßЧÀûÓÃÄÜÔ´£¬Äܹ»¼õÉÙ¶þÑõ»¯Ì¼µÄÅÅ·Å¡£

£¨1£©ÔÚÒ»¶¨Î¶ÈϵÄ2L¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬Í¨Èë2 molCO2ºÍ3mol H2£¬·¢ÉúµÄ·´Ó¦Îª£ºCO2(g)£«3H2(g) ? CH3OH(g)£«H2O(g)£¬¡÷H£½£­a kJ¡¤mol£­1£¨a£¾0£©£¬ ²âµÃCO2(g)ºÍCH3OH(g)µÄŨ¶ÈËæÊ±¼ä±ä»¯ÈçͼËùʾ¡£

¢ÙÄÜ˵Ã÷¸Ã·´Ó¦ÒÑ´ïÆ½ºâ״̬µÄÊÇ________¡££¨Ñ¡Ìî±àºÅ£©

A£®CO2µÄÌå»ý·ÖÊýÔÚ»ìºÏÆøÌåÖб£³Ö²»±ä

B£®»ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»ËæÊ±¼äµÄ±ä»¯¶ø±ä»¯

C£®µ¥Î»Ê±¼äÄÚÿÏûºÄ1.2mol H2£¬Í¬Ê±Éú³É0.4molH2O

D£®¸ÃÌåϵÖÐH2OÓëCH3OHµÄÎïÖʵÄÁ¿Å¨¶ÈÖ®±ÈΪ1:1£¬ÇÒ±£³Ö²»±ä

¢Ú¼ÆËã¸ÃζÈÏ´˷´Ó¦µÄƽºâ³£ÊýK£½_________¡££¨±£ÁôÁ½Î»ÓÐЧÊý×Ö£©¡£Èô¸Ä±äÌõ¼þ £¨ÌîÑ¡Ï£¬¿ÉʹK£½1¡£

A£®Ôö´óѹǿ

B£®Ôö´ó·´Ó¦ÎïŨ¶È

C£®½µµÍζÈ

D£®Éý¸ßζÈ

E£®¼ÓÈë´ß»¯¼Á

£¨2£©Ä³¼×´¼È¼ÁÏµç³ØÔ­ÀíÈçͼ1Ëùʾ¡£

¢ÙMÇø·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½Îª_______________________________¡£

¢ÚÓÃÉÏÊöµç³Ø×öµçÔ´£¬ÓÃͼ2×°Öõç½â±¥ºÍʳÑÎË®£¨µç¼«¾ùΪ¶èÐԵ缫£©£¬Ôò¸Ãµç½âµÄ×Ü·´Ó¦Àë×Ó·½³ÌʽΪ£º ¡£¼ÙÉèÈÜÒºÌå»ýΪ300mL£¬µ±ÈÜÒºµÄpHÖµ±äΪ13ʱ£¨ÔÚ³£ÎÂϲⶨ£©£¬ÀíÂÛÉÏÏûºÄ¼×´¼µÄÖÊÁ¿Îª______________£¨ºöÂÔÈÜÒºÌå»ý±ä»¯£©¡£

£¨3£©ÓÐÒ»ÖÖÓÃCO2Éú²ú¼×´¼È¼Áϵķ½·¨£º

ÒÑÖª£º¢ÙCO2(g)£«3H2(g) CH3OH(g)£«H2O(g) ¡÷H£½£­a kJ¡¤mol£­1£»

¢ÚCH3OH(g)£½CH3OH(l) ¡÷H£½£­b kJ¡¤mol£­1£»

¢Û2H2(g)£«O2(g)£½2H2O(g) ¡÷H£½£­c kJ¡¤mol£­1£»

¢ÜH2O(g)£½H2O(l) ¡÷H£½£­d kJ¡¤mol£­1£¬

Ôò±íʾCH3OH£¨l£©È¼ÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ£º_____________________________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014-2015ѧÄêºÓ±±Ê¡¸ßÈýÉÏѧÆÚµÚ¶þ´ÎÁª¿¼Àí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÈçͼËùʾÊÇ298 Kʱ£¬N2ÓëH2·´Ó¦¹ý³ÌÖÐÄÜÁ¿±ä»¯µÄÇúÏßͼ ,ÏÂÁÐÐðÊö´íÎóµÄÊÇ

A£®¼ÓÈë´ß»¯¼Á£¬²»Äܸıä¸Ã»¯Ñ§·´Ó¦µÄ·´Ó¦ÈÈ

B£®bÇúÏßÊǼÓÈë´ß»¯¼ÁʱµÄÄÜÁ¿±ä»¯ÇúÏß

C£®¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£ºN2(g)£«3H2(g) 2NH3(g)£¬¦¤H£½£­92 kJ/mol

D£®ÔÚζȡ¢Ìå»ýÒ»¶¨µÄÌõ¼þÏ£¬Í¨Èë1 mol N2ºÍ3 molH2·´Ó¦ºó·Å³öµÄÈÈÁ¿Îª92kJ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014-2015ѧÄê¸ÊËàÊ¡ÌìË®ÊиßÈýÒ»ÂÖ¸´Ï°»ù´¡ÖªÊ¶¼ì²â»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

£¨12·Ö£©ÒÒÈ©ÔÚ´ß»¯¼Á´æÔÚµÄÌõ¼þÏ£¬¿ÉÒÔ±»¿ÕÆøÑõ»¯³ÉÒÒËá¡£ÒÀ¾Ý´ËÔ­ÀíÉè¼ÆÊµÑéÖÆµÃ²¢ÔÚÊÔ¹ÜCÖÐÊÕ¼¯µ½ÉÙÁ¿ÒÒËáÈÜÒº£¨ÈçͼËùʾ£ºÊÔ¹ÜAÖÐ×°ÓÐ40£¥µÄÒÒȩˮÈÜÒº¡¢Ñõ»¯Í­·ÛÄ©£»ÊÔ¹ÜCÖÐ×°ÓÐÊÊÁ¿ÕôÁóË®£»ÉÕ±­BÖÐ×°ÓÐijҺÌ壩¡£ÒÑÖªÔÚ60¡æ¡«80¡æÊ±ÓÃË«Á¬´òÆøÇò¹ÄÈë¿ÕÆø¼´¿É·¢ÉúÒÒÈ©µÄÑõ»¯·´Ó¦£¬Á¬Ðø¹ÄÈëÊ®¼¸´Î·´Ó¦»ù±¾ÍêÈ«¡£ÓйØÎïÖʵķеã¼ûÏÂ±í£º

ÎïÖÊ

ÒÒÈ©

ÒÒËá

¸ÊÓÍ

ÒÒ¶þ´¼

Ë®

·Ðµã

20.8¡æ

117.9¡æ

290¡æ

197.2¡æ

100¡æ

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÊÔ¹ÜAÄÚÔÚ60¡æ¡«80¡æÊ±·¢ÉúµÄÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£¨×¢Ã÷·´Ó¦Ìõ¼þ£©________________£»

£¨2£©ÈçͼËùʾÔÚʵÑéµÄ²»Í¬½×¶Î£¬ÐèÒªµ÷ÕûζȼÆÔÚÊÔ¹ÜAÄÚµÄλÖá£ÔÚʵÑ鿪ʼʱζȼÆË®ÒøÇòµÄλÖÃÓ¦ÔÚ___________£¬Ä¿µÄÊÇ_____________________________£»µ±ÊÔ¹ÜAÄÚµÄÖ÷Òª·´Ó¦Íê³Éºó£¬Ó¦½øÐÐÕôÁó²Ù×÷£¬Î¶ȼÆË®ÒøÇòµÄλÖÃÓ¦ÔÚ___________________¡£

£¨3£©ÉÕ±­BÄÚÊ¢×°µÄÒºÌå¿ÉÒÔÊÇ____________£¨Ð´³öÒ»ÖÖ¼´¿É£©¡£

£¨4£©ÈôÏë¼ìÑéÊÔ¹ÜCÖÐÊÇ·ñº¬ÓвúÎïÒÒËᣬÔÚÏÂÁÐËùÌṩµÄÒ©Æ·»òÓÃÆ·ÖУ¬¿ÉÒÔʹÓõÄÊÇ____________¡££¨Ìî×Öĸ£©

a£®pHÊÔÖ½ b£®Ì¼ËáÇâÄÆ·ÛÄ©

c£®ºìɫʯÈïÊÔÖ½ d£®Òø°±ÈÜÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014-2015¼ªÁÖÊ¡ËÉÔ­ÊиßÒ»ÉÏѧÆÚÆÚÖл¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨15·Ö£©ÒÔÏÂÊÇÓйØÎïÖÊÏ໥ת»¯µÄ¹ØÏµÍ¼£¬ÆäÖÐAË׳ÆÌúºì£¬¼×ΪǿËᣬÒÒΪ»¹Ô­ÐÔÆøÌ壬±ûΪǿ¼îÈÜÒº£¬GΪºìºÖÉ«³Áµí£¬IµÄÑÕÉ«³ÊdzÂÌÉ«¡£

£¨1£©ÈôFÊÇÓÉNa£«ºÍSO42-×é³ÉµÄÈÜÒº£¬Ôò¼×µÄ»¯Ñ§Ê½ÊÇ _____________£¬ÁоÙAÎïÖʵÄÒ»ÖÖÓÃ;______________________________________________________________¡£

£¨2£©ÈôDÊÇÄÜʹ³ÎÇåʯ»ÒË®±ä»ë×ÇµÄÆøÌ壬ÔòÒҵĻ¯Ñ§Ê½Îª________£¬¶¡ÊôÓÚµ¥ÖÊ¡¢Ëá¡¢¼îÖеÄ________£»ÔÚIÈÜÒºÖмÓÈëÇâÑõ»¯ÄÆÈÜÒº£¬¿ÉÒԹ۲쵽µÄÏÖÏóÊÇ______________________________£¬

¶ÔÓ¦µÄÀë×Ó·½³ÌʽºÍ»¯Ñ§·½³ÌʽÒÀ´ÎÊÇ______________________£¬___________________¡£

£¨3£©Ð´³öG¡úA£«CµÄ»¯Ñ§·½³Ìʽ£º ___________________________________¡£

£¨4£©Ð´³öEºÍC·´Ó¦µÄ·½³Ìʽ²¢Óõ¥ÏßÇÅ·¨±êÃ÷µç×ÓµÄ×ªÒÆ·½ÏòºÍÊýÄ¿£º__________¡£

£¨5£©ÈôAÖлìÓÐÔÓÖÊAl2O3£¬³ýÈ¥ÔÓÖʵķ½·¨ÊǼÓÈë¹ýÁ¿µÄ________£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________¡£

£¨6£©ÓÉEºÍA×é³ÉµÄ»ìºÏÎïÓëÏ¡H2SO4×÷Ó㬹ÌÌåÇ¡ºÃÈܽ⣬ËùµÃÈÜÒºÖв»º¬Fe3£«£¬ÇÒÉú³ÉµÄFe2£«ÓëH2µÄÎïÖʵÄÁ¿Ö®±ÈΪ4¡Ã1¡£Ôò·´Ó¦ÎïÖÐA¡¢E¡¢H2SO4µÄÎïÖʵÄÁ¿Ö®±ÈΪ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸