Ã÷·¯Ê¯ÊÇÖÆÈ¡¼Ø·ÊºÍÇâÑõ»¯ÂÁµÄÖØÒªÔ­ÁÏ£¬Ã÷·¯Ê¯µÄ×é³ÉºÍÃ÷·¯ÏàËÆ£¬´ËÍ⻹º¬ÓÐÑõ»¯ÂÁºÍÉÙÁ¿Ñõ»¯ÌúÔÓÖÊ¡£¾ßÌåʵÑé²½ÖèÈçÏÂͼËùʾ£º

¸ù¾ÝÉÏÊöͼʾ£¬Íê³ÉÏÂÁÐÌî¿Õ£º
£¨1£©Ã÷·¯Ê¯±ºÉÕºóÓÃÏ¡°±Ë®½þ³ö¡£ÅäÖÆ500mLÏ¡°±Ë®£¨Ã¿Éýº¬ÓÐ39.20g°±£©ÐèҪȡŨ°±Ë®£¨Ã¿Éýº¬ÓÐ251.28g°±£©__________mL£¬Óùæ¸ñΪ_______mLÁ¿Í²Á¿È¡¡£
£¨2£©°±Ë®½þ³öºóµÃµ½¹ÌÌå»ìºÏÌåϵ£¬¹ýÂË£¬ÂËÒºÖгýK£«¡¢SO42£­Í⣬»¹ÓдóÁ¿µÄNH4£«¡£¼ìÑéNH4£«µÄ·½·¨ÊÇ______________________________________________¡£
£¨3£©Ð´³ö³ÁµíÎïÖÐËùÓÐÎïÖʵĻ¯Ñ§Ê½________________________________________¡£
£¨4£©ÂËÒºIµÄ³É·ÖÊÇË®ºÍ______________¡£
£¨5£©Îª²â¶¨»ìºÏ·ÊÁÏK2SO4¡¢(NH4)2SO4Öмصĺ¬Á¿£¬ÇëÍêÉÆÏÂÁв½Ö裺
¢Ù³ÆÈ¡¼Øµª·ÊÊÔÑù²¢ÈÜÓÚË®£¬¼ÓÈë×ãÁ¿______ÈÜÒº£¬²úÉú°×É«³Áµí¡£
¢Ú___________¡¢__________¡¢_________(ÒÀ´ÎÌîдʵÑé²Ù×÷Ãû³Æ)¡£
¢ÛÀäÈ´¡¢³ÆÖØ¡£
£¨6£©ÈôÊÔÑùΪmg£¬³ÁµíµÄÎïÖʵÄÁ¿Îªnmol£¬ÔòÊÔÑùÖÐK2SO4µÄÎïÖʵÄÁ¿Îª£º___________mol£¨Óú¬ÓÐm¡¢nµÄ´úÊýʽ±íʾ£©¡£

£¨1£©78 £»100
£¨2£©È¡ÂËÒºÉÙÐí£¬¼ÓÈëNaOH£¬¼ÓÈÈ£¬Éú³ÉµÄÆøÌåÄÜʹÈóʪµÄºìɫʯÈïÊÔÖ½±äÀ¶£¨ºÏÀí¼´¸ø·Ö£©
£¨3£©Al(OH)3£»Al2O3£»Fe2O3
£¨4£©K2SO4£»(NH4)2SO4
£¨5£©BaCl2£»¹ýÂË£»Ï´µÓ£»¸ÉÔï
£¨6£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨2011?ÔæׯģÄ⣩Ã÷·¯Ê¯ÊÇÖÆÈ¡¼Ø·ÊºÍÇâÑõ»¯ÂÁµÄÖØÒªÔ­ÁÏ£¬Ã÷·¯Ê¯µÄ×é³ÉºÍÃ÷·¯ÏàËÆ£¬´ËÍ⻹º¬ÓÐÑõ»¯ÂÁºÍÉÙÁ¿µÄÑõ»¯ÌúÔÓÖÊ£®¾ßÌåʵÑéÁ÷³ÌÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©²Ù×÷1ËùÓõ½µÄ²£Á§ÒÇÆ÷µÄÃû³ÆÊÇ
©¶·¡¢ÉÕ±­¡¢²£Á§°ô
©¶·¡¢ÉÕ±­¡¢²£Á§°ô
£®
£¨2£©ÓÉÈÜÒº3ÖÆÈ¡ÇâÑõ»¯ÂÁµÄÀë×Ó·½³ÌʽΪ
AlO2-+CO2+H2O=Al£¨OH£©3+HCO3-
AlO2-+CO2+H2O=Al£¨OH£©3+HCO3-
£®
£¨3£©Ã÷·¯Ê¯±ºÉÕʱ²úÉúSO2ÆøÌ壬ÇëÄãд³öÄÜÑéÖ¤SO2ÆøÌå¾ßÓл¹Ô­ÐÔÇÒʵÑéÏÖÏóÃ÷ÏԵĻ¯Ñ§·½³Ìʽ
SO2+Cl2+2H2O=H2SO4+2HCl
SO2+Cl2+2H2O=H2SO4+2HCl
£®
£¨4£©ÇëÄãд³öÑéÖ¤ÈÜÒº1ÖÐÓÐNH4+µÄʵÑé¹ý³Ì
È¡ÉÙÁ¿ÈÜÒº1ÓÚÊÔ¹ÜÖУ¬¼ÓÈëŨÇâÑõ»¯ÄÆÈÜÒº¼ÓÈÈ£¬ÓÐÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶µÄÆøÌåÉú³É£¬Ö¤Ã÷ÈÜÒº1Öк¬ÓÐNH4+
È¡ÉÙÁ¿ÈÜÒº1ÓÚÊÔ¹ÜÖУ¬¼ÓÈëŨÇâÑõ»¯ÄÆÈÜÒº¼ÓÈÈ£¬ÓÐÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶µÄÆøÌåÉú³É£¬Ö¤Ã÷ÈÜÒº1Öк¬ÓÐNH4+
£®
£¨5£©ÊµÑéÊÒÓÃFe2O3ÓëCO·´Ó¦À´ÖÆÈ¡µ¥ÖÊFe£®

¢ÙÇëÄã°´ÆøÁ÷ÓÉ×óµ½ÓÒ·½ÏòÁ¬½ÓÏÂÁи÷×°Öã¬Ë³ÐòΪ£ºA¡ú
E¡úB¡úC¡úD
E¡úB¡úC¡úD
£®
¢Ú¼ìÑé×°ÖÃAÆøÃÜÐԵķ½·¨ÊÇ
¹Ø±Õa¡¢bÁ½´¦»îÈû£¬½«µ¼Æø¹Ü²åÈëË®²ÛÖУ¬Î¢ÈÈ£¬µ¼Æø¹Ü¿ÚÓÐÆøÅݲúÉú£¬Í£Ö¹Î¢ÈÈ£¬Ò»¶Îʱ¼äºó£¬µ¼¹ÜÖÐÐγÉÒ»¶ÎË®Öù£¬ËµÃ÷ÆøÃÜÐÔÁ¼ºÃ
¹Ø±Õa¡¢bÁ½´¦»îÈû£¬½«µ¼Æø¹Ü²åÈëË®²ÛÖУ¬Î¢ÈÈ£¬µ¼Æø¹Ü¿ÚÓÐÆøÅݲúÉú£¬Í£Ö¹Î¢ÈÈ£¬Ò»¶Îʱ¼äºó£¬µ¼¹ÜÖÐÐγÉÒ»¶ÎË®Öù£¬ËµÃ÷ÆøÃÜÐÔÁ¼ºÃ
£®
¢ÛÔÚµãȼB´¦µÄ¾Æ¾«µÆÇ°£¬Ó¦½øÐеIJÙ×÷ÊÇ
¼ìÑéCOÆøÌå´¿¶È
¼ìÑéCOÆøÌå´¿¶È
£®
¢Ü×°ÖÃCµÄ×÷ÓÃÊÇ
³ýÈ¥COÆøÌå»ìÓеĶþÑõ»¯Ì¼£¬ÀûÓÃCOµãȼ
³ýÈ¥COÆøÌå»ìÓеĶþÑõ»¯Ì¼£¬ÀûÓÃCOµãȼ
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

¢ñ£ºÃ÷·¯Ê¯ÊÇÖÆÈ¡¼Ø·ÊºÍÇâÑõ»¯ÂÁµÄÖØÒªÔ­ÁÏ£¬Ã÷·¯Ê¯µÄ×é³ÉºÍÃ÷·¯ÏàËÆ£¬´ËÍ⻹º¬ÓÐÑõ»¯ ÂÁºÍÉÙÁ¿Ñõ»¯ÌúÔÓÖÊ£®¾ßÌåʵÑé²½ÖèÈçͼһËùʾ£º

¸ù¾Ýͼһʾ£¬Íê³ÉÏÂÁÐÌî¿Õ£º
£¨1£©Ã÷·¯Ê¯±ºÉÕºóÓÃÏ¡°±Ë®½þ³ö£®ÅäÖÆ500mLÏ¡°±Ë®£¨Ã¿Éýº¬ÓÐ39.20g°±£©ÐèҪȡŨ°±Ë®£¨Ã¿ Éýº¬ÓÐ250.28g°±£©
78
78
mL£¬Óùæ¸ñΪ
100
100
mLÁ¿Í²Á¿È¡£®
£¨2£©°±Ë®½þ³öºóµÃµ½¹ÌÒº»ìºÏÌåϵ£¬¹ýÂË£¬ÂËÒºÖгýK+¡¢SO42-Í⣬»¹ÓдóÁ¿µÄNH4+£®¼ìÑéNH4+µÄ·½·¨ÊÇ
È¡ÂËÒºÉÙÐí£¬¼ÓÈëNaOH£¬¼ÓÈÈ£¬Éú³ÉµÄÆøÌåÄÜʹÈóʪµÄºìɫʯÈïÊÔÖ½±äÀ¶
È¡ÂËÒºÉÙÐí£¬¼ÓÈëNaOH£¬¼ÓÈÈ£¬Éú³ÉµÄÆøÌåÄÜʹÈóʪµÄºìɫʯÈïÊÔÖ½±äÀ¶
£®
£¨3£©Ð´³ö³ÁµíÎïÖÐËùÓÐÎïÖʵĻ¯Ñ§Ê½
Al£¨OH£©3¡¢Al2O3¡¢Fe2O3
Al£¨OH£©3¡¢Al2O3¡¢Fe2O3
£®
£¨4£©ÂËÒºIµÄ³É·ÖÊÇË®ºÍ
K2SO4¡¢£¨NH4£©2SO4
K2SO4¡¢£¨NH4£©2SO4
£®
£¨5£©Îª²â¶¨»ìºÏ·ÊÁÏK2SO4¡¢£¨NH4£©2SO4Öмصĺ¬Á¿£¬ÍêÉÆÏÂÁв½Ö裺
¢Ù³ÆÈ¡¼Øµª·ÊÊÔÑù²¢ÈÜÓÚË®£¬¼ÓÈë×ãÁ¿
BaCl2»òBa£¨NO3£©2
BaCl2»òBa£¨NO3£©2
ÈÜÒº£¬²úÉú°×É«³Áµí£®
¢Ú
¹ýÂË
¹ýÂË
¡¢
Ï´µÓ
Ï´µÓ
¡¢
¸ÉÔï
¸ÉÔï
£¨ÒÀ´ÎÌîдʵÑé²Ù×÷Ãû³Æ£©£®
¢ÛÀäÈ´¡¢³ÆÖØ£®
£¨6£©ÈôÊÔÑùΪmg£¬³ÁµíµÄÎïÖʵÄÁ¿Îªnmol£¬ÔòÊÔÑùÖÐK2SO4µÄÎïÖʵÄÁ¿Îª£º
(m-132n)
42
(m-132n)
42
mol£¨Óú¬m¡¢nµÄ´úÊýʽ±íʾ£©£®
¢ò£ºÄ³ÎÞɫ͸Ã÷ÈÜÒº¿ÉÄܺ¬ÓÐÏÂÁÐÀë×Ó£ºK+¡¢Al3+¡¢Fe3+¡¢Ba2+¡¢NO3-¡¢SO42-¡¢HCO3-¡¢Cl-µÈ£¬È¡¸ÃÈÜÒº½øÐÐÈçÏÂʵÑ飺
¢ÙÓÃÀ¶É«Ê¯ÈïÊÔÖ½¼ì²â¸ÃÈÜÒº£¬ÊÔÖ½ÏÔºìÉ«£»
¢ÚÈ¡ÈÜÒºÉÙÐí£¬¼ÓÈëͭƬºÍÏ¡ÁòËá¹²ÈÈ£¬²úÉúÎÞÉ«ÆøÌ壬¸ÃÆøÌåÓöµ½¿ÕÆøÁ¢¼´±äΪºì×Ø  É«£»
¢ÛÈ¡ÈÜÒºÉÙÐí£¬¼ÓÈ백ˮÓа×É«³ÁµíÉú³É£¬¼ÌÐø¼ÓÈë¹ýÁ¿°±Ë®£¬³Áµí²»Ïûʧ£»
¢ÜÈ¡ÈÜÒºÉÙÐí£¬µÎÈëÂÈ»¯±µÈÜÒº²úÉú°×É«³Áµí£»
¢ÝȡʵÑ頢ܺóµÄ³ÎÇåÈÜÒº£¬µÎÈëÏõËáÒøÈÜÒº²úÉú°×É«³Áµí£¬ÔÙ¼ÓÈë¹ýÁ¿µÄÏ¡ÏõËᣬ³Áµí²»Ïûʧ£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨ l £©ÔÚʵÑé ¢ÙÖУ¬Í¼¶þËùʾµÄ²Ù×÷ÖÐÕýÈ·µÄÊÇ
BD
BD
£¨Ìî´úºÅ£©
£¨2£©¸ù¾ÝÉÏÊöʵÑéÅжÏÔ­ÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÊÇ
Al3+¡¢NO3-¡¢SO42-
Al3+¡¢NO3-¡¢SO42-
£¬¿Ï¶¨²»´æÔÚµÄÀë×ÓÊÇ
Fe3+¡¢Ba2+¡¢HCO3-
Fe3+¡¢Ba2+¡¢HCO3-
£®
£¨3£©Ð´³öÓë¢Ú¢ÛÁ½¸öʵÑéÓйصÄÀë×Ó·½³Ìʽ£º
¢Ú
3Cu+8H++2NO3-¨T3Cu2++2NO¡ü+4H2O
3Cu+8H++2NO3-¨T3Cu2++2NO¡ü+4H2O
£»
¢Û
Al3++3NH3?H2O¨TAl£¨OH£©3¡ý+3NH4+
Al3++3NH3?H2O¨TAl£¨OH£©3¡ý+3NH4+
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ã÷·¯Ê¯ÊÇÖÆÈ¡¼Ø·ÊºÍÇâÑõ»¯ÂÁµÄÖØÒªÔ­ÁÏ£¬Ã÷·¯Ê¯µÄ×é³ÉºÍÃ÷·¯ÏàËÆ£¬´ËÍ⻹º¬ÓÐÑõ»¯ÂÁºÍÉÙÁ¿Ñõ»¯ÌúÔÓÖÊ£®¾ßÌåʵÑé²½ÖèÈçͼËùʾ£º
¾«Ó¢¼Ò½ÌÍø
¸ù¾ÝÉÏÊöͼʾ£¬Íê³ÉÏÂÁÐÌì¿Õ£º
£¨1£©Ã÷·¯Ê¯±ºÉÕºóÓÃÏ¡°±Ë®½þ³ö£®ÅäÖÆ500mLÏ¡°±Ë®£¨Ã¿Éýº¬ÓÐ39.20g°±£©ÐèҪȡŨ°±Ë®£¨Ã¿Éýº¬ÓÐ250.28g°±£©
 
mL£¬Óùæ¸ñΪ
 
mLÁ¿Í²Á¿È¡£®
£¨2£©°±Ë®½þ³öºóµÃµ½¹ÌÒº»ìºÏÌåϵ£¬¹ýÂË£¬ÂËÒºÖгýK+¡¢SO42-Í⣬»¹ÓдóÁ¿µÄNH4+£®¼ìÑéNH4+µÄ·½·¨ÊÇ
 
£®
£¨3£©Ð´³ö³ÁµíÎïÖÐËùÓÐÎïÖʵĻ¯Ñ§Ê½
 
£®
£¨4£©ÂËÒºIµÄ³É·ÖÊÇË®ºÍ
 
£®
£¨5£©Îª²â¶¨»ìºÏ·ÊÁÏK2SO4¡¢£¨NH4£©2SO4Öмصĺ¬Á¿£¬ÍêÉÆÏÂÁв½Ö裺
¢Ù³ÆÈ¡¼Øµª·ÊÊÔÑù²¢ÈÜÓÚË®£¬¼ÓÈë×ãÁ¿
 
ÈÜÒº£¬²úÉú°×É«³Áµí£®
¢Ú
 
¡¢
 
¡¢
 
£¨ÒÀ´ÎÌîдʵÑé²Ù×÷Ãû³Æ£©£®
¢ÛÀäÈ´¡¢³ÆÖØ£®
£¨6£©ÈôÊÔÑùΪmg£¬³ÁµíµÄÎïÖʵÄÁ¿Îªnmol£¬ÔòÊÔÑùÖÐK2SO4µÄÎïÖʵÄÁ¿Îª£º
 
mol£¨Óú¬m¡¢nµÄ´úÊýʽ±íʾ£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ã÷·¯Ê¯ÊÇÖÆÈ¡¼Ø·ÊºÍÇâÑõ»¯ÂÁµÄÖØÒªÔ­ÁÏ£¬Ã÷·¯Ê¯µÄ×é³ÉºÍÃ÷·¯ÏàËÆ£¬´ËÍ⻹º¬ÓÐÑõ»¯ÂÁºÍÉÙÁ¿Ñõ»¯ÌúÔÓÖÊ¡£¾ßÌåʵÑé²½ÖèÈçÏÂͼËùʾ£º

¸ù¾ÝÉÏÊöͼʾ£¬Íê³ÉÏÂÁÐÌî¿Õ£º

£¨1£©Ã÷·¯Ê¯±ºÉÕºóÓÃÏ¡°±Ë®½þ³ö¡£ÅäÖÆ500mLÏ¡°±Ë®£¨Ã¿Éýº¬ÓÐ39.20g°±£©ÐèҪȡŨ°±Ë®£¨Ã¿Éýº¬ÓÐ251.28g°±£©__________mL£¬Óùæ¸ñΪ_______mLÁ¿Í²Á¿È¡¡£

£¨2£©°±Ë®½þ³öºóµÃµ½¹ÌÌå»ìºÏÌåϵ£¬¹ýÂË£¬ÂËÒºÖгýK£«¡¢SO42£­Í⣬»¹ÓдóÁ¿µÄNH4£«¡£¼ìÑéNH4£«µÄ·½·¨ÊÇ______________________________________________¡£

£¨3£©Ð´³ö³ÁµíÎïÖÐËùÓÐÎïÖʵĻ¯Ñ§Ê½________________________________________¡£

£¨4£©ÂËÒºIµÄ³É·ÖÊÇË®ºÍ______________¡£

£¨5£©Îª²â¶¨»ìºÏ·ÊÁÏK2SO4¡¢(NH4)2SO4Öмصĺ¬Á¿£¬ÇëÍêÉÆÏÂÁв½Ö裺

        ¢Ù³ÆÈ¡¼Øµª·ÊÊÔÑù²¢ÈÜÓÚË®£¬¼ÓÈë×ãÁ¿______ÈÜÒº£¬²úÉú°×É«³Áµí¡£

        ¢Ú___________¡¢__________¡¢_________(ÒÀ´ÎÌîдʵÑé²Ù×÷Ãû³Æ)¡£

        ¢ÛÀäÈ´¡¢³ÆÖØ¡£

£¨6£©ÈôÊÔÑùΪmg£¬³ÁµíµÄÎïÖʵÄÁ¿Îªnmol£¬ÔòÊÔÑùÖÐK2SO4µÄÎïÖʵÄÁ¿Îª£º___________mol£¨Óú¬ÓÐm¡¢nµÄ´úÊýʽ±íʾ£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013-2014ѧÄ긣½¨Ê¡ÕÄÖÝÊÐÆßУ¸ßÈýµÚ¶þ´ÎÁª¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

Ã÷·¯Ê¯ÊÇÖÆÈ¡¼Ø·ÊºÍÇâÑõ»¯ÂÁµÄÖØÒªÔ­ÁÏ£¬Ã÷·¯Ê¯µÄ×é³ÉºÍÃ÷·¯[KAl(SO4)2?12H2O]ÏàËÆ£¬´ËÍ⻹º¬ÓÐÑõ»¯ÂÁºÍÉÙÁ¿Ñõ»¯ÌúÔÓÖÊ¡£¾ßÌåʵÑé²½ÖèÈçÏÂͼËùʾ£º

¸ù¾ÝÉÏÊöͼʾ£¬Íê³ÉÏÂÁÐÌî¿Õ£º

£¨1£©Ã÷·¯Ê¯±ºÉÕºóÓÃÏ¡°±Ë®½þ³ö¡£ÅäÖÆ500mlÏ¡°±Ë®£¨Ã¿Éýº¬ÓÐ39.00g°±£©ÐèҪȡŨ°±Ë®£¨Ã¿Éýº¬ÓÐ250g°±£©__________ml£¬Óùæ¸ñΪ_______mlÁ¿Í²Á¿È¡¡£

£¨2£©°±Ë®½þ³öºóµÃµ½¹ÌÌå»ìºÏÌåϵ£¬¹ýÂË£¬ÂËÒºÖгýK£«¡¢SO42£­Í⣬»¹ÓдóÁ¿µÄNH4£«¡£¼ìÑéNH4£«µÄ·½·¨ÊÇ_______________________________________________________¡£

£¨3£©Ð´³ö³ÁµíÎïÖÐËùÓÐÎïÖʵĻ¯Ñ§Ê½________________________________________¡£

£¨4£©ÂËÒºµÄ³É·ÖÊÇË®ºÍ______________¡£

£¨5£©Îª²â¶¨»ìºÏ·ÊÁÏK2SO4¡¢(NH4)2SO4Öмصĺ¬Á¿£¬ÇëÍêÉÆÏÂÁв½Ö裺

¢Ù³ÆÈ¡¼Øµª·ÊÊÔÑù²¢ÈÜÓÚË®£¬¼ÓÈë×ãÁ¿______ÈÜÒº£¬²úÉú°×É«³Áµí¡£¢Ú_______¡¢______¡¢¸ÉÔï(ÌîʵÑé²Ù×÷Ãû³Æ)¡£¢ÛÀäÈ´¡¢³ÆÖØ¡£

£¨6£©ÈôÊÔÑùΪmg£¬³ÁµíµÄÎïÖʵÄÁ¿Îªn mol£¬ÔòÊÔÑùÖÐK2SO4µÄÎïÖʵÄÁ¿Îª£º______£¨Óú¬ÓÐm¡¢nµÄ´úÊýʽ±íʾ£©¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸