¹¤ÒµÉÏÒ±Á¶±ùÍ­(mCu2O¡¤nFeS)¿ÉµÃµ½´ÖÍ­£¬ÔÙÒÔ´ÖͭΪԭÁÏÖƱ¸ÁòËáÍ­¾§Ì壮

Íê³ÉÏÂÁÐÌî¿Õ£º

1£®ÆøÌåAÖеĴóÆøÎÛȾÎï¿ÉÑ¡ÓÃÏÂÁÐÊÔ¼ÁÖеÄ________(ÌîÐòºÅ)ÎüÊÕ£®

a£®Å¨H2SO4

b£®Å¨HNO3

c£®NaOHÈÜÒº

d£®°±Ë®

2£®ÓÃÏ¡H2SO4½þÅÝÈÛÔüB£¬È¡ÉÙÁ¿ËùµÃÈÜÒº£¬µÎ¼Ó________(ÌîÎïÖÊÃû³Æ)ÈÜÒººó³ÊºìÉ«£¬ËµÃ÷ÈÜÒºÖдæÔÚFe3+£¬¼ìÑéÈÜÒºÖл¹´æÔÚFe2+µÄ·½·¨ÊÇ________(×¢Ã÷ÊÔ¼Á¡¢ÏÖÏó)£®ÊµÑéÊÒ¿ÉÓÃÈçÏÂͼµÄ×°ÖÃÍê³ÉÅÝÍ­Ò±Á¶´ÖÍ­µÄ·´

Ó¦£®

3£®ÅÝÍ­Ò±Á¶´ÖÍ­µÄ»¯Ñ§·½³ÌʽÊÇ________£®

4£®×°ÖÃÖÐþ´øµÄ×÷ÓÃÊÇ________£®ÅÝÍ­ºÍÂÁ·Û»ìºÏÎï±íÃ渲¸ÇÉÙÁ¿°×É«

¹ÌÌåa£¬aÊÇ________(ÌîÃû³Æ)£®É³×ÓÄÜ·ñ»»³ÉË®£¿________(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)£®

5£®Óõζ¨·¨²â¶¨CuSO4¡¤5H2OµÄº¬Á¿£®È¡a gÊÔÑùÅä³É100 mLÈÜÒº£¬

È¡20.00 mLÓÃc mol/LµÎ¶¨¼Á(H2Y2£­£¬µÎ¶¨¼Á²»ÓëÔÓÖÊ·´Ó¦)µÎ¶¨ÖÁÖյ㣬ÏûºÄµÎ¶¨¼Áb mLµÎ¶¨·´Ó¦£ºCu2+£«H2Y2£­CuY2£­£«2H+£®ÔòCuSO4¡¤5H2OÖÊÁ¿·ÖÊýµÄ±í´ïʽÊÇ________£®

6£®ÏÂÁвÙ×÷»áµ¼ÖÂCuSO4¡¤5H2Oº¬Á¿µÄ²â¶¨½á¹ûÆ«¸ßµÄÊÇ________£®

a£®µÎ¶¨ÁÙ½üÖÕµãʱ£¬ÓÃÏ´Æ¿ÖеÄÕôÁóˮϴÏµζ¨¹Ü¼â×ì¿ÚµÄ°ëµÎ±ê×¼ÒºÖÁ׶ÐÎÆ¿ÖÐ

b£®µÎ¶¨¹ÜÓÃÕôÁóˮϴµÓºó£¬Ö±½Ó×¢Èë´ý²âÒº£¬È¡20.00 mL½øÐеζ¨

c£®µÎ¶¨Ç°£¬µÎ¶¨¹Ü¼â¶ËÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ

´ð°¸£º
½âÎö£º

¡¡¡¡1£®c¡¡d(2·Ö)

¡¡¡¡2£®ÁòÇ軯¼Ø(1·Ö)¡¡ÁíÈ¡ÉÙÁ¿ÈÜÒº£¬µÎ¼Ó¼¸µÎ¸ßÃÌËá¼ØµÄËáÐÔÈÜÒº£¬×ÏÉ«ÍÊÈ¥£¬ËµÃ÷ÈÜÒºÖдæÔÚFe2+(2·Ö)

¡¡¡¡3£®3Cu2O£«2Al6Cu£«Al2O3(1·Ö)

¡¡¡¡4£®È¼Éշųö´óÁ¿µÄÈÈ£¬´´Ôì¸ßλ·¾³(»òÒýȼ¼Á)(1·Ö)¡¡ÂÈËá¼Ø(1·Ö)¡¡²»ÄÜ(1·Ö)

¡¡¡¡5£®5bc/4a(2·Ö)

¡¡¡¡6£®c(1·Ö)


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

¹¤ÒµÉÏÒ±Á¶±ùÍ­£¨mCu2O?nFeS£©¿ÉµÃµ½´ÖÍ­£¬ÔÙÒÔ´ÖͭΪԭÁÏÖƱ¸ÁòËáÍ­¾§Ì壮

Íê³ÉÏÂÁÐÌî¿Õ£º
£¨1£©ÆøÌåAÖеĴóÆøÎÛȾÎï¿ÉÑ¡ÓÃÏÂÁÐÊÔ¼ÁÖеÄ
cd
cd
£¨ÌîÐòºÅ£©ÎüÊÕ£®
a£®Å¨H2SO4        b£®Å¨HNO3
c£®NaOHÈÜÒº      d£®°±Ë®
£¨2£©ÓÃÏ¡H2SO4½þÅÝÈÛÔüB£¬È¡ÉÙÁ¿ËùµÃÈÜÒº£¬µÎ¼Ó
ÁòÇ軯¼Ø
ÁòÇ軯¼Ø
£¨ÌîÎïÖÊÃû³Æ£©ÈÜÒººó³ÊºìÉ«£¬ËµÃ÷ÈÜÒºÖдæÔÚFe3+£¬¼ìÑéÈÜÒºÖл¹´æÔÚFe2+µÄ·½·¨ÊÇ
ÁíÈ¡ÉÙÁ¿ÈÜÒº£¬µÎ¼Ó¼¸µÎ¸ßÃÌËá¼ØµÄËáÐÔÈÜÒº£¬×ÏÉ«ÍÊÈ¥£¬ËµÃ÷ÈÜÒºÖдæÔÚFe2+
ÁíÈ¡ÉÙÁ¿ÈÜÒº£¬µÎ¼Ó¼¸µÎ¸ßÃÌËá¼ØµÄËáÐÔÈÜÒº£¬×ÏÉ«ÍÊÈ¥£¬ËµÃ÷ÈÜÒºÖдæÔÚFe2+
£¨×¢Ã÷ÊÔ¼Á¡¢ÏÖÏ󣩣®ÊµÑéÊÒ¿ÉÓÃÈçͼµÄ×°ÖÃÍê³ÉÅÝÍ­Ò±Á¶´ÖÍ­µÄ·´Ó¦£®
£¨3£©ÅÝÍ­Ò±Á¶´ÖÍ­µÄ»¯Ñ§·½³ÌʽÊÇ
3Cu2O+2Al
 ¸ßΠ
.
 
6Cu+Al2O3
3Cu2O+2Al
 ¸ßΠ
.
 
6Cu+Al2O3
£®
£¨4£©×°ÖÃÖÐþ´øµÄ×÷ÓÃÊÇ
ȼÉշųö´óÁ¿µÄÈÈ£¬´´Ôì¸ßλ·¾³£¨»òÒýȼ¼Á£©
ȼÉշųö´óÁ¿µÄÈÈ£¬´´Ôì¸ßλ·¾³£¨»òÒýȼ¼Á£©
£®ÅÝÍ­ºÍÂÁ·Û»ìºÏÎï±íÃ渲¸ÇÉÙÁ¿°×É«¹ÌÌåa£¬aÊÇ
ÂÈËá¼Ø
ÂÈËá¼Ø
£¨ÌîÃû³Æ£©£®É³×ÓÄÜ·ñ»»³ÉË®£¿
²»ÄÜ
²»ÄÜ
£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©£®
£¨5£©Óõζ¨·¨²â¶¨CuSO4?5H2OµÄº¬Á¿£®È¡a gÊÔÑùÅä³É100mLÈÜÒº£¬È¡20.00mLÓÃc mol/L £¨H2Y2-£¬µÎ¶¨¼Á²»ÓëÔÓÖÊ·´Ó¦£©µÎ¶¨ÖÁÖյ㣬ÏûºÄµÎ¶¨¼ÁbmLµÎ¶¨·´Ó¦£ºCu2++H2Y2-?
µÎ¶¨¼Á
?CuY2-+2H+£®ÔòCuSO4?5H2OÖÊÁ¿·ÖÊýµÄ±í´ïʽÊÇ
5bc
4a
5bc
4a
£®
£¨6£©ÏÂÁвÙ×÷»áµ¼ÖÂCuSO4?5H2Oº¬Á¿µÄ²â¶¨½á¹ûÆ«¸ßµÄÊÇ
c
c
£®
a£®µÎ¶¨ÁÙ½üÖÕµãʱ£¬ÓÃÏ´Æ¿ÖеÄÕôÁóˮϴÏµζ¨¹Ü¼â×ì¿ÚµÄ°ëµÎ±ê×¼ÒºÖÁ׶ÐÎÆ¿ÖÐ
b£®µÎ¶¨¹ÜÓÃÕôÁóˮϴµÓºó£¬Ö±½Ó×¢Èë´ý²âÒº£¬È¡20.00mL½øÐеζ¨
c£®µÎ¶¨Ç°£¬µÎ¶¨¹Ü¼â¶ËÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢¹¤ÒµÉÏÒ±Á¶ÂÁ³£Óý¹Ì¿»¹Ô­Ñõ»¯ÂÁB¡¢CO2¡¢N02»òSO2¶¼»áµ¼ÖÂËáÓêµÄÐγÉC¡¢¹âµ¼ÏËά¡¢¾ÛÒÒÏ©¡¢ÓÍÖ¬¶¼ÊǸ߷Ö×Ó»¯ºÏÎïD¡¢¿Éͨ¹ý¼ÓË®ÎüÊÕºóÔÙÓðë͸ĤÉøÎöµÄ·½·¨·ÖÀëPM2.5΢Á£Óë¿ÉÈÜÐÔÎü¸½Îï

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÉϺ£ÊÐÑîÆÖÇø¸ßÈýÉÏѧÆÚѧҵÖÊÁ¿µ÷Ñл¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

¹¤ÒµÉÏÒ±Á¶±ùÍ­£¨mCu2O¡¤nFeS£©¿ÉµÃµ½´ÖÍ­£¬ÔÙÒÔ´ÖͭΪԭÁÏÖƱ¸ÁòËáÍ­¾§Ìå¡£

Íê³ÉÏÂÁÐÌî¿Õ£º

£¨1£©ÆøÌåAÖеĴóÆøÎÛȾÎï¿ÉÑ¡ÓÃÏÂÁÐÊÔ¼ÁÖеĠ       £¨ÌîÐòºÅ£©ÎüÊÕ¡£

a. ŨH2SO4        b. ŨHNO3       c. NaOHÈÜÒº      d. °±Ë®

£¨2£©ÓÃÏ¡H2SO4 ½þÅÝÈÛÔüB£¬È¡ÉÙÁ¿ËùµÃÈÜÒº£¬µÎ¼Ó     £¨ÌîÎïÖÊÃû³Æ£©ÈÜÒººó³ÊºìÉ«£¬ËµÃ÷ÈÜÒºÖдæÔÚFe3+£¬¼ìÑéÈÜÒºÖл¹´æÔÚFe2+µÄ·½·¨ÊÇ    £¨×¢Ã÷ÊÔ¼Á¡¢ÏÖÏ󣩡£

 

 
ʵÑéÊÒ¿ÉÓÃͼµÄ×°ÖÃÍê³ÉÅÝÍ­Ò±Á¶´ÖÍ­µÄ·´Ó¦¡£

£¨3£©ÅÝÍ­Ò±Á¶´ÖÍ­µÄ»¯Ñ§·½³ÌʽÊÇ                             ¡£

£¨4£©×°ÖÃÖÐþ´øµÄ×÷ÓÃÊÇ     ¡£ÅÝÍ­ºÍÂÁ·Û»ìºÏÎï±íÃ渲¸ÇÉÙÁ¿°×É«¹ÌÌåa£¬

aÊÇ   (ÌîÃû³Æ)¡£É³×ÓÄÜ·ñ»»³ÉË®£¿   (Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)¡£

£¨5£©Óõζ¨·¨²â¶¨CuSO4¡¤5H2OµÄº¬Á¿¡£È¡a gÊÔÑùÅä³É100 mLÈÜÒº£¬È¡20.00mLÓÃc mol /L µÎ¶¨¼Á(H2Y2¨C£¬µÎ¶¨¼Á²»ÓëÔÓÖÊ·´Ó¦)µÎ¶¨ÖÁÖյ㣬ÏûºÄµÎ¶¨¼ÁbmL£¬µÎ¶¨·´Ó¦£ºCu2+ + H2Y2¨C£½CuY2¨C+ 2H+¡£ÔòCuSO4¡¤5H2OÖÊÁ¿·ÖÊýµÄ±í´ïʽÊÇ        ¡£

£¨6£©ÏÂÁвÙ×÷»áµ¼ÖÂCuSO4¡¤5H2Oº¬Á¿µÄ²â¶¨½á¹ûÆ«¸ßµÄÊÇ_____________¡£

a£®µÎ¶¨ÁÙ½üÖÕµãʱ£¬ÓÃÏ´Æ¿ÖеÄÕôÁóˮϴÏµζ¨¹Ü¼â×ì¿ÚµÄ°ëµÎ±ê×¼ÒºÖÁ׶ÐÎÆ¿ÖÐ

b£®µÎ¶¨¹ÜÓÃÕôÁóˮϴµÓºó£¬Ö±½Ó×¢Èë´ý²âÒº£¬È¡20.00mL½øÐеζ¨

c£®µÎ¶¨Ç°£¬µÎ¶¨¹Ü¼â¶ËÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

¹¤ÒµÉÏÒ±Á¶±ùÍ­£¨mCu2O?nFeS£©¿ÉµÃµ½´ÖÍ­£¬ÔÙÒÔ´ÖͭΪԭÁÏÖƱ¸ÁòËáÍ­¾§Ì壮

Íê³ÉÏÂÁÐÌî¿Õ£º
£¨1£©ÆøÌåAÖеĴóÆøÎÛȾÎï¿ÉÑ¡ÓÃÏÂÁÐÊÔ¼ÁÖеÄ______£¨ÌîÐòºÅ£©ÎüÊÕ£®
a£®Å¨H2SO4¡¡¡¡¡¡¡¡b£®Å¨HNO3
c£®NaOHÈÜÒº¡¡¡¡¡¡d£®°±Ë®
£¨2£©ÓÃÏ¡H2SO4½þÅÝÈÛÔüB£¬È¡ÉÙÁ¿ËùµÃÈÜÒº£¬µÎ¼Ó______£¨ÌîÎïÖÊÃû³Æ£©ÈÜÒººó³ÊºìÉ«£¬ËµÃ÷ÈÜÒºÖдæÔÚFe3+£¬¼ìÑéÈÜÒºÖл¹´æÔÚFe2+µÄ·½·¨ÊÇ______£¨×¢Ã÷ÊÔ¼Á¡¢ÏÖÏ󣩣®ÊµÑéÊÒ¿ÉÓÃÈçͼµÄ×°ÖÃÍê³ÉÅÝÍ­Ò±Á¶´ÖÍ­µÄ·´Ó¦£®
£¨3£©ÅÝÍ­Ò±Á¶´ÖÍ­µÄ»¯Ñ§·½³ÌʽÊÇ______£®
£¨4£©×°ÖÃÖÐþ´øµÄ×÷ÓÃÊÇ______£®ÅÝÍ­ºÍÂÁ·Û»ìºÏÎï±íÃ渲¸ÇÉÙÁ¿°×É«¹ÌÌåa£¬aÊÇ______£¨ÌîÃû³Æ£©£®É³×ÓÄÜ·ñ»»³ÉË®£¿______£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©£®
£¨5£©Óõζ¨·¨²â¶¨CuSO4?5H2OµÄº¬Á¿£®È¡a gÊÔÑùÅä³É100mLÈÜÒº£¬È¡20.00mLÓÃc mol/L £¨H2Y2-£¬µÎ¶¨¼Á²»ÓëÔÓÖÊ·´Ó¦£©µÎ¶¨ÖÁÖյ㣬ÏûºÄµÎ¶¨¼ÁbmLµÎ¶¨·´Ó¦£ºCu2++H2Y2-?Êýѧ¹«Ê½?CuY2-+2H+£®ÔòCuSO4?5H2OÖÊÁ¿·ÖÊýµÄ±í´ïʽÊÇ______£®
£¨6£©ÏÂÁвÙ×÷»áµ¼ÖÂCuSO4?5H2Oº¬Á¿µÄ²â¶¨½á¹ûÆ«¸ßµÄÊÇ______£®
a£®µÎ¶¨ÁÙ½üÖÕµãʱ£¬ÓÃÏ´Æ¿ÖеÄÕôÁóˮϴÏµζ¨¹Ü¼â×ì¿ÚµÄ°ëµÎ±ê×¼ÒºÖÁ׶ÐÎÆ¿ÖÐ
b£®µÎ¶¨¹ÜÓÃÕôÁóˮϴµÓºó£¬Ö±½Ó×¢Èë´ý²âÒº£¬È¡20.00mL½øÐеζ¨
c£®µÎ¶¨Ç°£¬µÎ¶¨¹Ü¼â¶ËÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸