I£®ÒÒÏ©ÊÇʯÓÍÁѽâÆøµÄÖ÷Òª³É·Ö£¬ËüµÄ²úÁ¿Í¨³£ÓÃÀ´ºâÁ¿Ò»¸ö¹ú¼ÒµÄʯÓÍ»¯¹¤Ë®Æ½¡£Çë»Ø´ðÏÂÁÐÎÊÌâ¡£
(1)ÒÒÏ©µÄ½á¹¹¼òʽΪ____________¡£
(2)ÏÂÁÐÎïÖÊÖУ¬²»¿ÉÒÔͨ¹ýÒÒÏ©¼Ó³É·´Ó¦µÃµ½µÄÊÇ______(ÌîÐòºÅ)¡£

A£®CH3CH3 B£®CH3CHCl2
C£®CH3CH2OH D£®CH3CH2Br
(3)ÒÑÖª 2CH3CHO£«O2 2CH3COOH¡£ÈôÒÔÒÒϩΪÖ÷ÒªÔ­ÁϺϳÉÒÒËᣬÆäºÏ³É·ÏßÈçÏÂͼËùʾ¡£

·´Ó¦¢ÚµÄ»¯Ñ§·½³ÌʽΪ____________________________________¡£
¹¤ÒµÉÏÒÔÒÒϩΪԭÁÏ¿ÉÒÔÉú²úÒ»ÖÖÖØÒªµÄºÏ³ÉÓлú¸ß·Ö×Ó»¯ºÏÎÆä·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________________________________£¬·´Ó¦ÀàÐÍÊÇ__________________¡£
II£®ÔÚʵÑéÊÒ¿ÉÒÔÓÃÈçÏÂͼËùʾµÄ×°ÖÃÖÆÈ¡ÒÒËáÒÒõ¥£¬Çë»Ø´ðÏÂÁÐÎÊÌâ¡£

(1)ÒÒ´¼¡¢ÒÒËá·Ö×ÓÖйÙÄÜÍŵÄÃû³Æ·Ö±ðÊÇ_________¡¢_________¡£
(2)ÊÔ¹ÜaÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
_____________________________________________£¬
·´Ó¦ÀàÐÍÊÇ______________¡£
£¨3£©Å¨H2SO4µÄ×÷ÓÃÊÇ£º__________________________¡£
·´Ó¦¿ªÊ¼Ç°£¬ÊÔ¹ÜbÖÐÊ¢·ÅµÄÈÜÒºÊÇ____________¡£
¸ÃÈÜÒºµÄ×÷ÓÃÊÇ                                
___________________________________________________________________________________¡£

I. £¨1£©H2C£½CH2                 (2)B
(3)2CH3CH2OH£«O2 2CH3CHO£«2H2O
    ¼Ó¾Û·´Ó¦
II.  (1)ôÇ»ù¡¢ôÈ»ù
(2)CH3COOH£«C2H5OH CH3COOC2H5£«H2O     ¡¡õ¥»¯·´Ó¦
£¨3£©´ß»¯¼Á¡¢ÎüË®¼Á
(4)±¥ºÍ̼ËáÄÆÈÜÒº
ÎüÊÕÒÒ´¼¡¢ÖкÍÒÒËᣬ±ãÓÚÎÅõ¥µÄÆøζ£»½µµÍõ¥µÄÈܽâ¶È£¬ÀûÓÚ·Ö²ãÎö³ö¡¡£¨3·Ö£©

½âÎöÊÔÌâ·ÖÎö£ºI£®(1)ÒÒÏ©µÄ½á¹¹¼òʽΪH2C£½CH2¡£(2)A¡¢ÒÒÏ©ºÍÇâÆø¼Ó³ÉÉú³ÉCH3CH3£¬C¡¢ÒÒÏ©ºÍË®¼Ó³ÉÉú³ÉCH3CH2OH£¬  D¡¢ÒÒÏ©Óëä廯Çâ¼Ó³ÉÉú³ÉCH3CH2Br£¬Ñ¡B£»£¨3£©ÓÉÌâ¸øÁ÷³Ìͼ֪£¬·´Ó¦¢ÚΪÒÒ´¼´ß»¯Ñõ»¯Éú³ÉÒÒÈ©£¬»¯Ñ§·½³ÌʽΪ2CH3CH2OH£«O22CH3CHO£«2H2O¡£ ¹¤ÒµÉÏÒÔÒÒϩΪԭÁÏ¿ÉÒÔÉú²úÒ»ÖÖÖØÒªµÄºÏ³ÉÓлú¸ß·Ö×Ó»¯ºÏÎÆä·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
£¬·´Ó¦ÀàÐÍÊǼӾ۷´Ó¦¡£II£®(1)ÒÒ´¼¡¢ÒÒËá·Ö×ÓÖйÙÄÜÍŵÄÃû
³Æ·Ö±ðÊÇôÇ»ù¡¢ôÈ»ù£»(2)ÊÔ¹ÜaÖÐÒÒËáÓëÒÒ´¼·¢Éúõ¥»¯·´Ó¦Éú³ÉÒÒËáÒÒõ¥£¬»¯Ñ§·½³ÌʽΪCH3COOH£«C2H5OHCH3COOC2H5£«H2O£¬·´Ó¦ÀàÐÍÊÇõ¥»¯·´Ó¦¡££¨3£©Å¨H2SO4µÄ×÷ÓÃÊÇ£º´ß»¯¼Á¡¢ÎüË®¼Á£»£¨4£©·´Ó¦¿ªÊ¼Ç°£¬ÊÔ¹ÜbÖÐÊ¢·ÅµÄÈÜÒºÊDZ¥ºÍ̼ËáÄÆÈÜÒº£»¸ÃÈÜÒºµÄ×÷ÓÃÊÇÎüÊÕÒÒ´¼¡¢ÖкÍÒÒËᣬ±ãÓÚÎÅõ¥µÄÆøζ£»½µµÍõ¥µÄÈܽâ¶È£¬ÀûÓÚ·Ö²ãÎö³ö¡£
¿¼µã£º¿¼²éÒÒÏ©µÄ½á¹¹ÓëÐÔÖÊ¡¢ÒÒËáÒÒõ¥µÄÖƱ¸¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ 

A£®µí·ÛºÍÏËάËØ»¥ÎªÍ¬·ÖÒì¹¹Ì壬»¯Ñ§Ê½¾ùΪ(C6H10O5)n
B£®ÓÍÖ¬ÔÚËáÐÔÌõ¼þϵÄË®½â·´Ó¦½ÐÔí»¯·´Ó¦
C£®¼¦µ°ÇåÈÜÒºÖмÓÈë´×ËáǦÈÜÒº»á±äÐÔ
D£®µí·Û¡¢ÏËάËØ¡¢µ°°×ÖʺÍÓÍÖ¬¾ùÊôÓÚÌìÈ»¸ß·Ö×Ó»¯ºÏÎï

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

£¨14·Ö£©ÒÒËáÒÒõ¥ÊÇÖØÒªµÄÓлúºÏ³ÉÖмäÌ壬¹ã·ºÓ¦ÓÃÓÚ»¯Ñ§¹¤Òµ£®ÊµÑéÊÒÀûÓÃÏÂͼA×°ÖÃÖƱ¸ÒÒËáÒÒõ¥£®

£¨1£©ÈôʵÑéÖÐÓÃÒÒËáºÍº¬18OµÄÒÒ´¼×÷Ó㬸÷´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ£º      
Óë½Ì²Ä²ÉÓõÄʵÑé×°Öò»Í¬£¬´Ë×°ÖÃÖвÉÓÃÁËÇòÐθÉÔï¹Ü£¬Æä×÷ÓÃÊÇ       £®
£¨2£©ÎªÁËÖ¤Ã÷ŨÁòËáÔڸ÷´Ó¦ÖÐÆðµ½ÁË´ß»¯¼ÁºÍÎüË®¼ÁµÄ×÷Óã¬Ä³Í¬Ñ§ÀûÓÃÉÏͼËùʾװÖýøÐÐÁËÒÔÏÂ4¸öʵÑ飮ʵÑ鿪ʼÏÈÓþƾ«µÆ΢ÈÈ3min£¬ÔÙ¼ÓÈÈʹ֮΢΢·ÐÌÚ3min£®ÊµÑé½áÊøºó³ä·ÖÕñµ´Ð¡ÊԹܢòÔÙ²âÓлú²ãµÄºñ¶È£¬ÊµÑé¼Ç¼ÈçÏ£º

ʵÑé±àºÅ
ÊԹܢñÖÐÊÔ¼Á
ÊԹܢòÖÐÊÔ¼Á
Óлú²ãµÄºñ¶È/cm
A
2mLÒÒ´¼¡¢1mLÒÒËá¡¢
1mL18mol?L-1 Å¨ÁòËá
±¥ºÍNa2CO3ÈÜÒº
3.0
B
2mLÒÒ´¼¡¢1mLÒÒËá
0.1
C
2mLÒÒ´¼¡¢1mLÒÒËá¡¢
3mL 2mol?L-1H2SO4
0.6
D
2mLÒÒ´¼¡¢1mLÒÒËá¡¢ÑÎËá
0.6
¢ÙʵÑéDµÄÄ¿µÄÊÇÓëʵÑéCÏà¶ÔÕÕ£¬Ö¤Ã÷H+¶Ôõ¥»¯·´Ó¦¾ßÓд߻¯×÷Óã®ÊµÑéDÖÐÓ¦¼ÓÈëÑÎËáµÄÌå»ýºÍŨ¶È·Ö±ðÊÇ    mLºÍ     mol?L-1£®
¢Ú·ÖÎöʵÑé    £¨ÌîʵÑé±àºÅ£©µÄÊý¾Ý£¬¿ÉÒÔÍƲâ³öŨH2SO4µÄÎüË®ÐÔÌá¸ßÁËÒÒËáÒÒõ¥µÄ²úÂÊ£®
£¨3£©ÈôÏÖÓÐÒÒËá90g£¬ÒÒ´¼138g·¢Éúõ¥»¯·´Ó¦µÃµ½88gÒÒËáÒÒõ¥£¬ÊÔ¼ÆËã¸Ã·´Ó¦µÄ²úÂÊΪ         £®
£¨4£©ÏÖÄâ·ÖÀ뺬ÒÒËá¡¢ÒÒ´¼ºÍË®µÄÒÒËáÒÒõ¥´Ö²úÆ·£¬ÈçͼÊÇ·ÖÀë²Ù×÷²½ÖèÁ÷³Ìͼ£®Í¼ÖУ¨ £©ÄÚΪÊʵ±µÄÊÔ¼Á£¬¡¾ ¡¿ÄÚΪÊʵ±µÄ·ÖÀë·½·¨£®

¢ÙÊÔ¼ÁaÊÇ         £»·ÖÀë·½·¨¢ÚÊÇ         £¬·ÖÀë·½·¨¢ÛÊÇ      £®·ÖÀë·½·¨¢ÙÊÇ·ÖÒº£¬ÔÚ¾ßÌå²Ù×÷ÖÐÓ¦³ä·ÖÕñµ´£¬È»ºó¾²Ö㬴ý·Ö²ãºó       £¨Ìî±êºÅ£©£¬
A£®Ö±½Ó½«ÒÒËáÒÒõ¥´Ó·ÖҺ©¶·ÉÏ¿Úµ¹³ö  
B£®Ö±½Ó½«ÒÒËáÒÒõ¥´Ó·ÖҺ©¶·Ï¿ڷųö
C£®ÏȽ«Ë®²ã´Ó·ÖҺ©¶·µÄÏ¿ڷųö£¬ÔÙ½«ÒÒËáÒÒõ¥´ÓÏ¿ڷųö
D£®ÏȽ«Ë®²ã´Ó·ÖҺ©¶·µÄÏ¿ڷųö£¬ÔÙ½«ÒÒËáÒÒõ¥´ÓÉϿڷųö
¢ÚÔڵõ½µÄAÖмÓÈëÎÞˮ̼ËáÄÆ·ÛÄ©£¬Õñµ´£¬Ä¿µÄÊÇ                    £®
£¨5£©Îª³ä·ÖÀûÓ÷´Ó¦Î¼×¡¢ÒÒÁ½Î»Í¬Ñ§·Ö±ðÉè¼ÆÁËÉÏÃæͼÖмס¢ÒÒÁ½¸ö×°Öã¨ÒÒͬѧ´ý·´Ó¦Íê±ÏÀäÈ´ºó£¬ÔÙÓñ¥ºÍ̼ËáÄÆÈÜÒºÌáÈ¡ÉÕÆ¿ÖеIJúÎ£®ÄãÈÏΪ×îºÏÀíµÄÊÇ         

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

£¨5·Ö£©ÒÑ֪±´úÌþ£¨R-X£©ÔÚ¼îÐÔÌõ¼þÏ¿ÉË®½âµÃµ½´¼£¨R-OH£©£¬È磺CH3CH2-X+H2O CH3CH2-OH+HR£¬ÏÖÓÐÈçÏÂת»¯¹Øϵ:
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©·´Ó¦1µÄÊÔ¼ÁÓëÌõ¼þΪ __________£¬XµÄ½á¹¹¼òʽΪ______£¬YµÄ½á¹¹¼òʽΪ______£»
£¨2£©Ð´³ö·´Ó¦3µÄ·½³Ìʽ___________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

£¨15·Ö£©Ä³»¯Ñ§Ð¡×éÒÔ±½¼×ËáΪԭÁÏ£¬ÖÆÈ¡±½¼×Ëá¼×õ¥£¬ÒÑÖªÓйØÎïÖʵķеãÈç±í£º

ÎïÖÊ
¼×´¼
±½¼×Ëá
±½¼×Ëá¼×õ¥
·Ðµã/¡æ
64.7
249
199.6
¢ñ.ºÏ³É±½¼×Ëá¼×õ¥´Ö²úÆ·
ÔÚÔ²µ×ÉÕÆ¿ÖмÓÈë12.2 g±½¼×ËáºÍ20 mL¼×´¼(ÃܶÈԼΪ0.79 g¡¤cm-3)£¬ÔÙСÐļÓÈë3mLŨÁòËᣬ»ìÔȺó£¬Í¶È뼸¿éËé´ÉƬ£¬Ð¡ÐļÓÈÈʹ·´Ó¦ÍêÈ«£¬µÃ±½¼×Ëá¼×õ¥´Ö²úÆ·¡£
¢ÅŨÁòËáµÄ×÷ÓÃÊÇ________________________________________        _________£»
Èô·´Ó¦²úÎïË®·Ö×ÓÖÐÓÐͬλËØ18O£¬Ð´³öÄܱíʾ·´Ó¦Ç°ºó18OλÖõĻ¯Ñ§·½³Ìʽ
___________________________________________________¡£
¢Æ¼×ºÍÒÒÁ½Î»Í¬Ñ§·Ö±ðÉè¼ÆÁËÈçͼËùʾµÄÁ½Ì×ʵÑéÊҺϳɱ½¼×Ëá¼× õ¥µÄ×°Öà (¼Ð³ÖÒÇÆ÷ºÍ¼ÓÈÈÒÇÆ÷¾ùÒÑÂÔÈ¥)¡£

¸ù¾ÝÓлúÎïµÄ·Ðµã£¬×îºÃ²ÉÓÃ______(Ìî¡°¼×¡±»ò¡°ÒÒ¡±)×°Öá£
ÀíÓÉÊÇ______________________________________________¡£
¢ÇÈôÒªÌá¸ß±½¼×Ëá¼×õ¥µÄ²úÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©_      
______                                 _¡££¨ÈÎдһÌõ£©
¢ò.´Ö²úÆ·µÄ¾«ÖÆ
¢È±½¼×Ëá¼×õ¥´Ö²úÆ·ÖÐÍùÍùº¬ÓÐÉÙÁ¿¼×´¼¡¢±½¼×ËáºÍË®µÈ£¬ÏÖÄâÓÃÏÂÁÐÁ÷³Ìͼ½øÐо«ÖÆ£¬ÇëÔÚÁ÷³ÌͼÖз½À¨ºÅÄÚÌîÈë²Ù×÷·½·¨µÄÃû³Æ¡£

¢Éͨ¹ý¼ÆË㣬±½¼×Ëá¼×õ¥µÄ²úÂÊΪ__________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

°´ÒªÇóÍê³ÉÏÂÁÐÎÊÌ⣺
¢ÅijÓлúÎïµÄ¼üÏßʽÊÇ£¬Çëд³öËüÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ   £º
¢ÆDDTÈËÀàºÏ³ÉµÄµÚÒ»ÖÖÓлúÂÈÅ©Ò©£¬Æä·Ö×ӽṹÇò¹÷Ä£ÐÍÈçͼËùʾ¡£Çë·ÖÎö¸ÃÎïÖʵĺ˴Ź²Õñ1HÆ×ͼÖÐÓР              ¸öÎüÊÕ·å¡£

¢ÇFºÍG£¨£© ÊÇÈÕ³£Éú»îÖг£ÓõÄÁ½Öֺϳɸ߷Ö×Ó²ÄÁÏ£¬¿ÉÓÉijÌþ¾­ÏÂÁз´Ó¦µÃµ½¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙFµÄ½á¹¹¼òʽΪ                   ¡£
¢ÚCÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆΪ      £¬Óà      ÒÇ£¬¿ÉÒԲⶨDÖÐËùº¬¹ÙÄÜÍÅ¡£
¢ÛA¡úBµÄ»¯Ñ§·½³ÌʽΪ                ¡£
¢ÜÒÑÖª2RCH(OH)COOH2H2O  +
Çë²Î¿¼ÌâÄ¿ÖеĺϳÉ;¾¶£¬ÈôºÏ³É£¬ÆðʼԭÁϵÄijÌþµÄ½á¹¹¼òʽΪ    £¬×îÉÙÓà      ²½·´Ó¦£¬¿ÉÒԺϳɲúÎï¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

Ò»ÖÖÓлúÎïµÄ½á¹¹¼òʽΪ£º

ÊԻشðÏÂÁÐÎÊÌ⣺
(1)¸Ã»¯ºÏÎïµÄÖÖÀàÊÇ________¡£
A£®Ï©Ìþ      B£®õ¥            C£®ÓÍÖ¬      D£®¸ß·Ö×Ó»¯ºÏÎï
(2)¸Ã»¯ºÏÎïµÄÃܶÈ________¡£
A£®±ÈË®´ó  B£®±ÈˮС
(3)¸Ã»¯ºÏÎï³£ÎÂϵÄ״̬Ϊ________¡£
A£®ÒºÌå¡¡¡¡B£®¹ÌÌå¡¡¡¡C£®ÆøÌå
(4)Óë¸ÃÎïÖÊÄÜ·´Ó¦µÄÓÐ________¡£
A£®NaOHÈÜÒº   B£®µâË®
C£®ÒÒ´¼¡¡¡¡¡¡     D£®ÒÒËá¡¡¡¡¡¡            E£®H2
д³ö¸ÃÓлúÎïÓëÑ¡³öµÄ»¯ºÏÎï·´Ó¦µÄ»¯Ñ§·½³Ìʽ(ÈÎдһ¸ö)£º________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ͨ¹ýÁ¸Ê³·¢½Í¿É»ñµÃijº¬ÑõÓлú»¯ºÏÎïX,ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª46,ÆäÖÐ̼µÄÖÊÁ¿·ÖÊýΪ52.2%,ÇâµÄÖÊÁ¿·ÖÊýΪ13.0%¡£
(1)XµÄ·Ö×ÓʽÊÇ¡¡¡¡¡¡¡¡¡£ 
(2)XÓë½ðÊôÄÆ·´Ó¦·Å³öÇâÆø,·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ¡¡¡¡¡¡¡¡¡£ 
(3)XÓë¿ÕÆøÖеÄÑõÆøÔÚÍ­»òÒø´ß»¯Ï·´Ó¦Éú³ÉY,YµÄ½á¹¹¼òʽÊÇ¡¡¡¡¡¡¡¡¡£ 
(4)XÓëËáÐÔ¸ßÃÌËá¼ØÈÜÒº·´Ó¦¿ÉÉú³ÉZ¡£ÔÚ¼ÓÈȺÍŨÁòËá×÷ÓÃÏÂ,XÓëZ·´Ó¦¿ÉÉú³ÉÒ»ÖÖÓÐÏãζµÄÎïÖÊW,Èô184 g XºÍ120 g Z·´Ó¦ÄÜÉú³É106 g W,¼ÆËã¸Ã·´Ó¦µÄ²úÂÊ(ÒªÇóд³ö¼ÆËã¹ý³Ì)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÈçͼÊÇA·Ö×ÓµÄÇò¹÷Ä£ÐͺÍB·Ö×ӵıÈÀýÄ£ÐÍ£¬»Ø´ðÏÂÁÐÎÊÌ⣺

(1)AºÍBµÄ¹ØϵÊÇ_____¡£
(2)д³öA·Ö×ÓÔÚ´ß»¯¼Á´æÔÚÌõ¼þϼÓÈȺÍÑõÆø·´Ó¦µÄ»¯Ñ§·½³Ìʽ___________¡£
(3)д³öB·Ö×ӺͽðÊôÄÆ·´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________________¡£
(4)BÔÚ¼ÓÈÈÌõ¼þÏÂÄܹ»ºÍHBr·¢Éú·´Ó¦Éú³ÉäåÒÒÍ飬¸Ã·´Ó¦ÀàÐÍÊÇ____________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸