| A. | $\left.\begin{array}{l}{3}\\{2}\end{array}\right.$He+$\left.\begin{array}{l}{2}\\{1}\end{array}\right.$H→$\left.\begin{array}{l}{4}\\{2}\end{array}\right.$He+$\left.\begin{array}{l}{1}\\{1}\end{array}\right.$H是聚变反应 | |
| B. | $\left.\begin{array}{l}{238}\\{92}\end{array}\right.$U→$\left.\begin{array}{l}{234}\\{90}\end{array}\right.$Th+$\left.\begin{array}{l}{4}\\{2}\end{array}\right.$He是人工核转变 | |
| C. | $\left.\begin{array}{l}{24}\\{11}\end{array}\right.$Na→$\left.\begin{array}{l}{24}\\{12}\end{array}\right.$Mg+$\left.\begin{array}{l}{0}\\{-1}\end{array}\right.$e是衰变反应 | |
| D. | 元素的半衰期会受到其所处环境的影响 | |
| E. | $\left.\begin{array}{l}{235}\\{92}\end{array}\right.$U+$\left.\begin{array}{l}{1}\\{0}\end{array}\right.$n→$\left.\begin{array}{l}{92}\\{36}\end{array}\right.$Kr+$\left.\begin{array}{l}{141}\\{56}\end{array}\right.$Ba+3$\left.\begin{array}{l}{1}\\{0}\end{array}\right.$n是裂变反应 |
分析 α衰变生成氦原子核,自发进行;β衰变生成电子,自发进行;聚变是质量轻的核结合成质量大的核.裂变是质量较大的核分裂成较轻的几个核
解答 解:A、$\left.\begin{array}{l}{3}\\{2}\end{array}\right.$He+$\left.\begin{array}{l}{2}\\{1}\end{array}\right.$H→$\left.\begin{array}{l}{4}\\{2}\end{array}\right.$He+$\left.\begin{array}{l}{1}\\{1}\end{array}\right.$H是聚变反应.故A正确.
B、$\left.\begin{array}{l}{238}\\{92}\end{array}\right.$U→$\left.\begin{array}{l}{234}\\{90}\end{array}\right.$Th+$\left.\begin{array}{l}{4}\\{2}\end{array}\right.$He是α衰变.故B错误.
C、$\left.\begin{array}{l}{24}\\{11}\end{array}\right.$Na→$\left.\begin{array}{l}{24}\\{12}\end{array}\right.$Mg+$\left.\begin{array}{l}{0}\\{-1}\end{array}\right.$e是β衰变.故C正确.
D、元素的半衰期不会受到其所处环境的影响.故D错误.
E、$\left.\begin{array}{l}{235}\\{92}\end{array}\right.$U+$\left.\begin{array}{l}{1}\\{0}\end{array}\right.$n→$\left.\begin{array}{l}{92}\\{36}\end{array}\right.$Kr+$\left.\begin{array}{l}{141}\\{56}\end{array}\right.$Ba+3$\left.\begin{array}{l}{1}\\{0}\end{array}\right.$n是裂变反应,故E正确;
故选:ACE.
点评 本题难度不大,考查了核反应方程的种类,在学习中需要记住一些特殊的方程式.
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