Question

5£®ÈçͼËùʾµÄƽÃæÖ±½Ç×ø±êϵÄÚ£¬´æÔڴŸÐӦǿ¶ÈΪBµÄÔ²ÐÎÔÈÇ¿´Å³¡ÇøÓò£¬´Å³¡·½Ïò´¹Ö±Ö½ÃæÏòÀԲÐÄ×ø±êΪa£¨10£¬0£©£¬´Å³¡Ô²°ë¾¶r=10cm£®ÓÐÒ»ÖÊÁ¿m=6.4¡Á10^-27kg£¬´øµçºÉÁ¿Îªq=3.2¡Á10^-19CµÄÁ£×Ó£¬ÒÔ³õËÙ¶Èv₀=1¡Á10⁷m/sÑØxÖáÕý·½ÏòÓÉOµãÉäÈ룬ǡÄÜ´Óbµã·É³ö£¬ÒÑÖªbµãµÄ×ø±êΪ£¨10£¬10£©£¬Á£×ÓÖØÁ¦²»¼Æ£¬ÊÔÇó
£¨1£©Á£×Ó´øºÎÖÖµçºÉ£»£¨²»ÒªÇóÅжϹý³Ì£©
£¨2£©´Å³¡´Å¸ÐӦǿ¶ÈBµÄ´óС£»
£¨3£©ÔÚÆäËüÌõ¼þ²»±äµÄÇé¿öÏ£¬ÈçҪʹÁ£×ӷɳö´Å³¡Ê±Ëٶȷ½Ïò¸Ä±ä60¡ã£¬Á£×ÓËÙ¶ÈÓ¦±äΪ¶àÉÙ£¿´ËʱÁ£×ӷɳö´Å³¡ÇøÓòʱµÄ×ø±êÊÇʲô£¿£¨½á¹û¿É±£Áô¸ùºÅ£©

Answer 1

·ÖÎö £¨1£©¸ù¾Ý×óÊÖ¶¨ÔòÅжÏÁ£×ӵĵçÐÔ
£¨2£©»­³öÔ˶¯¹ì¼££¬¸ù¾Ý¼¸ºÎ¹ØϵÇó³ö°ë¾¶£¬¸ù¾ÝÂåÂ××ÈÌṩÏòÐÄÁ¦¼´¿ÉÇó³ö´Å³¡µÄ´Å¸ÐӦǿ¶È£»
£¨3£©ÔÚÆäËüÌõ¼þ²»±äµÄÇé¿öÏ£¬ÈçҪʹÁ£×ӷɳö´Å³¡Ê±Ëٶȷ½Ïò¸Ä±ä60¡ã£¬»­³öÁ£×ÓÔ˶¯¹ì¼££¬¸ù¾Ý¼¸ºÎ¹Ø»úÇó³ö°ë¾¶£¬Óɰ뾶¹«Ê½Çó³öËٶȣ¬ÔÙÓɼ¸ºÎ¹ØϵÇó³ö×ø±ê£»

½â´ð ½â£º£¨1£©¸ù¾Ý×óÊÖ¶¨Ôò£¬ÖªÁ£×Ó´øÕýµç
£¨2£©»­³öÁ£×ÓµÄÔ˶¯¹ì¼££¬ÈçͼËùʾ

¸ù¾Ý¼¸ºÎ¹Øϵ£¬Á£×ÓÔڴų¡ÖÐ×öÔÈËÙÔ²ÖÜÔ˶¯µÄ°ë¾¶${R}_{1}^{\;}=r=10cm=0.1m$
¸ù¾ÝÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦£¬ÓÐ$q{v}_{0}^{\;}B=m\frac{{v}_{0}^{2}}{{R}_{1}^{\;}}$
µÃ$B=\frac{m{v}_{0}^{\;}}{q{R}_{1}^{\;}}=\frac{6.4¡Á1{0}_{\;}^{-27}¡Á1¡Á1{0}_{\;}^{7}}{3.2¡Á1{0}_{\;}^{-19}¡Á0.1}=2T$
£¨3£©»­³öÁ£×ÓÔ˶¯µÄ¹ì¼£ÈçͼËùʾ

ÉèÁ£×ÓÔڴų¡ÖеĹìµÀ°ë¾¶Îª${R}_{2}^{\;}$£¬¸ù¾Ý¼¸ºÎ¹Øϵ£¬ÓУº
$tan30¡ã=\frac{r}{{R}_{2}^{\;}}$£¬µÃ${R}_{2}^{\;}=10\sqrt{3}cm$
¸ù¾Ý°ë¾¶¹«Ê½${R}_{2}^{\;}=\frac{m{v}_{2}^{\;}}{qB}$£¬µÃ${v}_{2}^{\;}=\frac{qB{R}_{2}^{\;}}{m}=\frac{3.2¡Á1{0}_{\;}^{-19}¡Á2¡Á0.1\sqrt{3}}{6.4¡Á1{0}_{\;}^{-27}}$=$\sqrt{3}¡Á1{0}_{\;}^{7}m/s$
´ËʱÁ£×ӷɳö´Å³¡Ê±µÄºá×ø±ê£º$x={R}_{2}^{\;}+{R}_{2}^{\;}cos60¡ã=15\sqrt{3}cm$
×Ý×ø±ê$y={R}_{2}^{\;}sin60¡ã=10\sqrt{3}¡Á\frac{\sqrt{3}}{2}=15cm$
´ð£º£¨1£©Á£×Ó´øÕýµçºÉ£»
£¨2£©´Å³¡´Å¸ÐӦǿ¶ÈBµÄ´óС2T£»
£¨3£©ÔÚÆäËüÌõ¼þ²»±äµÄÇé¿öÏ£¬ÈçҪʹÁ£×ӷɳö´Å³¡Ê±Ëٶȷ½Ïò¸Ä±ä60¡ã£¬Á£×ÓËÙ¶ÈÓ¦±äΪ$\sqrt{3}¡Á1{0}_{\;}^{7}m/s$£¿´ËʱÁ£×ӷɳö´Å³¡ÇøÓòʱµÄ×ø±êÊÇ£¨15$\sqrt{3}cm$£¬15cm£©

µãÆÀ ¿¼²éÁ£×ÓÔÚÂåÂ××ÈÁ¦×÷ÓÃÏ£¬×öÔÈËÙÔ²ÖÜÔ˶¯£¬ÕÆÎÕÅ£¶ÙµÚ¶þ¶¨ÂɵÄÓ¦Óã¬Àí½â¼¸ºÎ¹ØϵÓëÔ˶¯°ë¾¶ÁªÏµ£®