Question

12£®Ä³¿ÎÍâÐËȤС×éÔÚ¡°Ì½¾¿Ð¡³µËÙ¶ÈËæʱ¼ä±ä»¯¹æÂÉ¡±µÄʵÑéÖУ¬µÃµ½Èçͼ6ËùʾµÄÖ½´ø£®ÊµÑéÖÐËùÓý»Á÷µçµÄƵÂÊΪ50Hz£¬Ö½´øÇ°ÃæµÄ¼¸¸öµã½ÏÄ£ºý£¬Òò´Ë´ÓAµã¿ªÊ¼Ã¿5¸öµãÈ¡Ò»¸ö¼ÆÊýµã£¬ÆäÖÐB¡¢C¡¢D¡¢EµãµÄ¶ÔÓ¦ËٶȷֱðΪv_B=0.25m/s£¬v_C=0.33m/s£¬v_D=0.40m/s£¬v_E=0.48m/sÓÉ´ËÍƵÃFµãµÄËÙ¶Èv_F=0.56m/s£®Ð¡³µ´ÓBÔ˶¯µ½CµÄ¼ÓËÙ¶Èa₁=0.80m/s²£¬´ÓCÔ˶¯µ½DµÄ¼ÓËÙ¶Èa₂=0.70m/s²£¬´ÓDÔ˶¯µ½EµÄ¼ÓËÙ¶Èa₃=0.80m/s²£®

Answer 1

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BµãµÄ¶ÔÓ¦ËÙ¶Èv_B=$\frac{{x}_{AC}^{\;}}{{t}_{AC}^{\;}}$=$\frac{6.45cm-1.40cm}{2¡Á0.1s}=25cm/s$=0.25m/s
ͬÀí£¬CµãµÄ¶ÔÓ¦ËÙ¶Èv_C=$\frac{{x}_{BD}^{\;}}{{t}_{BD}^{\;}}$=$\frac{10.10cm-3.55cm}{2¡Á0.1s}$¡Ö33cm/s¡Ö0.33m/s£»
${v}_{D}^{\;}=\frac{{x}_{CE}^{\;}}{2T}=\frac{14.50cm-6.45cm}{2¡Á0.1s}=40cm/s=0.40m/s$
${v}_{E}^{\;}=\frac{{x}_{DF}^{\;}}{2T}=\frac{19.65cm-10.10cm}{2¡Á0.1s}=48cm/s$=0.48m/s
ÏàµÈʱ¼äµÄËٶȱ仯Á¿0.08m/s
ÓÉ´Ë¿ÉÍƵÃFµãµÄËÙ¶ÈΪ0.56m/s
Bµ½CµÄ¼ÓËÙ¶È${a}_{1}^{\;}=\frac{¡÷v}{¡÷t}=\frac{0.33-0.25}{0.1}m/{s}_{\;}^{2}=0.80m/{s}_{\;}^{2}$
´ÓCµ½DµÄ¼ÓËÙ¶È${a}_{2}^{\;}=\frac{¡÷v}{¡÷t}=\frac{0.40-0.33}{0.1}m/{s}_{\;}^{2}=0.70m/{s}_{\;}^{2}$
´ÓDµ½EµÄ¼ÓËÙ¶È${a}_{3}^{\;}=\frac{¡÷v}{¡÷t}=\frac{0.48-0.40}{0.1}m/{s}_{\;}^{2}=0.80m/{s}_{\;}^{2}$
¹Ê´ð°¸Îª£º0.25      0.33      0.40       0.48        0.80         0.70        0.80

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