14£®Ä³Ð£¼×¡¢ÒÒÁ½¸öÐËȤС×é¶ÔʵÑéÊÒһƿ³¨¿Ú·ÅÖõÄÇâÑõ»¯ÄƹÌÌå½øÐÐ̽¾¿£º
̽¾¿Ò»£ºÇâÑõ»¯ÄƹÌÌåÊÇ·ñ±äÖÊ
ÐËȤС×éͬѧȡÉÙÁ¿ÇâÑõ»¯ÄƹÌÌåÑùÆ·ÓÚÊÔ¹ÜÖУ¬¼ÓÊÊÁ¿Ë®ÈÜÒº£¬µÎ¼ÓÏ¡ÑÎËᣬ²úÉú´óÁ¿ÆøÅÝ£®»Ø´ðÏÂÁÐÎÊÌ⣺£¨1£©ÇâÑõ»¯ÄƵÄË×ÃûÊÇ»ð¼î£»
£¨2£©¸ù¾ÝÒÔÉÏʵÑéÏÖÏó¿ÉÅжϸÃÑùÆ·ÓбäÖÊ£¨Ìî¡°ÓС±»ò¡°Ã»ÓС±£®
£¨3£©ÇâÑõ»¯ÄÆÔÚ¿ÕÆøÖбäÖʵÄÔ­Òò£ºCO2+2NaOH=Na2CO3+H2O£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£®
̽¾¿¶þ£ºÇâÑõ»¯ÄƹÌÌå±äÖʳ̶È
¡¾²éÔÄ×ÊÁÏ¡¿
¢Ù¼îʯ»ÒÊÇNaOHºÍCaOµÄ¹ÌÌå»ìºÏÎÄÜÎüÊÕË®ºÍ¶þÑõ»¯Ì¼
¢Ú±ê×¼×´¿öÏ£¬¶þÑõ»¯Ì¼µÄÃܶÈp=1.977g/L
¢Û̼ËáÄÆÈÜÒºÓëÇ⻯¸ÆÈÜÒºÄÜ·¢Éú·´Ó¦£ºNa2CO3+CaCl2=CaCO3¡ý+2NaCl
¡¾Éè¼ÆÊµÑé¡¿
¼×¡¢ÒÒÁ½ÐËȤС×éͬѧ·Ö±ð³ÆÈ¡2gÇâÑõ»¯ÄÆÑùÆ·Óë×ãÁ¿Ï¡ÑÎËá·´Ó¦£¬Í¨¹ý²â¶¨²úÉú¶þÑõ»¯Ì¼µÄÁ¿½øÐмÆË㣮¼×С×éͬѧÉè¼ÆÁËÈçͼËùʾµÄ·½°¸Ò»²â¶¨¶þÑõ»¯Ì¼µÄÖÊÁ¿£®£¨×¢£º²»¿¼ÂÇÏ¡ÑÎËáÖÐHClÆøÌåµÄ»Ó·¢£©

¡¾½»Á÷ÌÖÂÛ¡¿
£¨1£©ÒÒС×éͬѧÈÏΪ·½°¸Ò»µÄC×°ÖÃÆø¹ÜË®ÃæÉÏÓ¦¸²¸ÇÒ»²ãÖ²ÎïÓÍ£¬ÆäÔ­ÒòÊÇ·ÀÖ¹¶þÑõ»¯Ì¼ÈÜÓÚË®£¨»ò¶þÑõ»¯Ì¼ÓëË®·´Ó¦£©Ôì³É²âµÃCO2Ìå»ýƫС£®
£¨2£©¼×С×éͬѧÈÏΪ·½°¸¶þµÄ×°ÖÃÖдæÔÚȱÏÝ£¬»á¶ÔʵÑé½á¹û²úÉúÓ°Ï죮ÇëÄãÖ¸³ö²úÉúÓ°ÏìµÄÔ­Òò£ºD×°ÖòúÉú¶þÑõ»¯Ì¼´ø³öµÄË®ÕôÆø±»E×°Öõļîʯ»ÒÎüÊÕ£¨Ð´Ò»µã£©£®
¡¾ÍØÕ¹Ì½¾¿¡¿
¾­¹ý½»Á÷ÌÖÂÛ£¬¼×ÒÒ¡¢Á½Ð¡×éͬѧ¹²Í¬Éè¼ÆÁËÈçͼËùʾµÄʵÑé·½°¸À´²â¶¨¹ÌÌåÑùÆ·ÖÐÇâÑõ»¯ÄƵÄÖÊÁ¿·ÖÊý£º

£¨3£©¡°²Ù×÷¢ñ¡±µÄÃû³ÆÊǹýÂË£»
£¨4£©Èç¹û³ÁµíNûÓо­¹ýÏ´µÓ£¬¾ÍÖ±½Óºæ¸É³ÆÁ¿£¬Ôòµ¼Ö²âµÃµÄÑùÆ·ÖÐÇâÑõ»¯ÄƵÄÖÊÁ¿·ÖÊýƫС£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©£®

·ÖÎö ̽¾¿Ò»£¨1£©ÇâÑõ»¯ÄƵÄË×ÃûÊÇ»ð¼î»òÉÕ¼î»ò¿ÁÐÔÄÆ£»
£¨2£©¸ù¾ÝʵÑéµÄÏÖÏó·ÖÎö£»
£¨3£©ÇâÑõ»¯ÄÆÓë¶þÑõ»¯Ì¼·´Ó¦Éú³É̼ËáÄÆ¶ø±äÖÊ£»
̽¾¿¶þ£¨1£©Ö²ÎïÓÍ¿ÉÒÔ·ÀÖ¹¶þÑõ»¯Ì¼ÈÜÓÚË®
£¨2£©¸ù¾Ý¼îʯ»ÒµÄÐÔÖÊ·ÖÎö£»
£¨3£©¹ýÂË¿ÉÒÔ½«¹ÌÌåºÍÒºÌå·Ö¿ª£»
£¨4£©³ÁµíNûÓо­¹ýÏ´µÓ£¬»á´øÓÐÂËÒº£®

½â´ð ½â£ºÌ½¾¿Ò»£¨1£©ÇâÑõ»¯ÄƵÄË×ÃûÊÇ»ð¼î»òÉÕ¼î»ò¿ÁÐÔÄÆ£»
£¨2£©ÓÉÓÚÇâÑõ»¯ÄÆÓëÑÎËᷴӦûÓÐÃ÷ÏÔµÄÏÖÏó£¬ÊµÑéÖеμÓÏ¡ÑÎËᣬ²úÉú´óÁ¿ÆøÅݲúÉú£¬ËµÃ÷Ò»¶¨ÊÇÇâÑõ»¯ÄÆÓë¶þÑõ»¯Ì¼·´Ó¦Éú³ÉÁË̼ËáÄÆ£¬
£¨3£©ÇâÑõ»¯ÄÆÓë¶þÑõ»¯Ì¼·´Ó¦Éú³É̼ËáÄÆºÍË®£¬·´Ó¦·½³ÌʽΪCO2+2NaOH=Na2CO3+H2O£»
̽¾¿¶þ£¨1£©Ö²ÎïÓÍ¿ÉÒÔ·ÀÖ¹¶þÑõ»¯Ì¼ÈÜÓÚË®Ôì³É²âµÃCO2Ìå»ýƫС
£¨2£©¼îʯ»Ò¿ÉÒÔÎüÊÕ¶þÑõ»¯Ì¼ºÍË®£¬D×°ÖòúÉú¶þÑõ»¯Ì¼´ø³öµÄË®ÕôÆø±»E×°Öõļîʯ»ÒÎüÊÕ£»Í¬Ê±E×°Öõļîʯ»ÒÒ²»áÎüÊÕ¿ÕÆøÖеĶþÑõ»¯Ì¼ºÍË®£»
£¨3£©¡°²Ù×÷¢ñ¡±½«¹ÌÌåºÍÒºÌå·Ö¿ª£¬ËùÒÔӦΪ¹ýÂË£»
£¨4£©³ÁµíNûÓо­¹ýÏ´µÓ£¬»á´øÓÐÂËÒº£¬¾ÍÖ±½Óºæ¸É³ÆÁ¿£¬»áÔì³É̼Ëá¸ÆµÄÖÊÁ¿Ôö¼Ó£¬ËùÒÔ¼ÆËã³öµÄ̼ËáÄÆÖÊÁ¿Ôö¼Ó£¬ËùÒÔµ¼Ö²âµÃµÄÑùÆ·ÖÐÇâÑõ»¯ÄƵÄÖÊÁ¿·ÖÊýƫС£®
¹Ê´ð°¸Îª£ºÌ½¾¿Ò»£¨1£©»ð¼î£¨ÉÕ¼î»ò¿ÁÐÔÄÆ£©£»
£¨2£©ÓУ»£¨3£©CO2+2NaOH=Na2CO3+H2O£»
̽¾¿¶þ£¨1£©·ÀÖ¹¶þÑõ»¯Ì¼ÈÜÓÚË®£¨»ò¶þÑõ»¯Ì¼ÓëË®·´Ó¦£©Ôì³É²âµÃCO2Ìå»ýƫС£»
£¨2£©D×°ÖòúÉú¶þÑõ»¯Ì¼´ø³öµÄË®ÕôÆø±»E×°Öõļîʯ»ÒÎüÊÕ
£¨»òE×°Öõļîʯ»ÒÓë¿ÕÆøÏàͨ£¬ÎüÊÕÁË¿ÕÆøÖеĶþÑõ»¯Ì¼»òË®ÕôÆø£©
£¨3£©¹ýÂË£»
£¨4£©Æ«Ð¡£®

µãÆÀ ÊìÁ·ÕÆÎÕÇâÑõ»¯ÄÆ¡¢Ì¼ËáÄÆµÄ»¯Ñ§ÐÔÖÊ£¬ÖªµÀÇâÑõ»¯ÄƵıäÖʵÄÔ­Òò²¢Äܹ»Ñ¡ÔñºÏÊʵķ½·¨½øÐмìÑ飬Á˽ⷽ³Ìʽ¼ÆËãµÄ·½·¨£¬²¢ÄܾÝÎïÖʵÄÐÔÖÊÕýÈ··ÖÎö½â´ðÏà¹ØÎÊÌ⣬Ҫ½áºÏËùѧ֪ʶϸÐÄ·ÖÎö½â´ð£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

4£®ÌúË¿ÔÚÑõÆøÖÐȼÉÕÏÖÏó£ºÌúÔÚÑõÆøÖй»¾çÁÒµØÈ¼ÉÕ£¬»ðÐÇËÄÉ䣬·Å³ö´óÁ¿µÄÈÈ£¬Éú³ÉºÚÉ«¹ÌÌ壮
ÌúË¿ÔÚÑõÆøÖÐȼÉÕ¼¯ÆøÆ¿ÄÚ·ÅË®µÄ×÷ÓÃÊÇ£º·ÀÖ¹¸ßÎÂÈÛÈÚÎヲÂäʱըÁѼ¯ÆøÆ¿
ÁòÔÚÑõÆøÖÐȼÉÕ¼¯ÆøÆ¿ÄÚ·ÅË®µÄ×÷ÓÃÊÇ£ºÎüÊÕ¶þÑõ»¯Áò£¬·ÀÖ¹¶þÑõ»¯ÁòÎÛȾ¿ÕÆø£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

5£®ÔÚÑõÆøµÄÖÆÈ¡ºÍÐÔÖÊʵÑéÖУ¬Ä³Í¬Ñ§È¡Ò»¶ÎÉ´´°ÍøÉϵÄϸÌúË¿£¬ÔÚ×Ô¼ºÊÕ¼¯µ½µÄÑõÆøÖÐ×öÌúË¿ÔÚÑõÆøÖÐȼÉÕµÄʵÑ飬½á¹ûûÓй۲쵽¡°»ðÐÇËÄÉ䡱µÄÏÖÏó£®ÏÂÁв»¿ÉÄÜÊÇÔì³É´ËʵÑéʧ°ÜµÄÔ­ÒòµÄÊÇ£¨¡¡¡¡£©
A£®ÊÕ¼¯µ½µÄÑõÆøÁ¿Ì«ÉÙ»ò´¿¶ÈÌ«µÍB£®ÌúË¿ÉúÐâ»ò¿ÉÄÜÓÐÓÍÆá
C£®¼¯ÆøÆ¿µ×ûÓÐÆÌÒ»±¡²ãϸɳD£®ÌúË¿±»ÈƳÉÂÝÐý×´

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

2£®½ðÊôÔÚÉú²ú¡¢Éú»îÖÐÓй㷺µÄÓÃ;£®
ÏÂÁнðÊôÖÆÆ·ÖУ¬·Ö±ðÀûÓÃÁ˽ðÊôµÄµ¼ÈÈÐÔ¡¢µ¼µçÐÔºÍÑÓÕ¹ÐÔ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

9£®×öÌúË¿ÔÚÑõÆøÖÐȼÉÕʵÑéʱҪÔÚÆ¿µ××°ÉÙÁ¿Ë®£¬Ä¿µÄÊÇ·ÀÖ¹Éú³ÉÎïÊÜÈÈÈÛ»¯ºó½¦ÂäÏÂÀ´Õ¨ÁÑÆ¿¶ø×öÁòÔÚÑõÆøÖÐȼÉÕʱƿµ××°Ë®µÄÄ¿µÄ³ýÁËÎüÈÈ£¬¸üÖ÷ÒªµÄÔ­ÒòÊÇÊÕ¶þÑõ»¯Áò£¬·ÀÖ¹ÎÛȾ¿ÕÆø£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

19£®¸øÊÔ¹ÜÀïµÄ¹ÌÌåÎïÖʼÓÈÈ£¬²»ÕýÈ·µÄ²Ù×÷ÊÇ£¨¡¡¡¡£©
A£®Ê¹ÓÃÌú¼Ð½«ÊԹ̶ܹ¨ÔÚÌú¼Ų̈ÉÏB£®½«Ðè¼ÓÈȲ¿·Ö·ÅÔھƾ«µÆÍâÑæ
C£®ÊԹܿÚÂÔÏòÏÂÇãбD£®Ìú¼ÐÓ¦¼ÐÔÚÊԹܵÄ$\frac{1}{3}$´¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

6£®¶ÔÓйØÊµÑéÏÖÏóµÄÃèÊöÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ºìÁ×ÔÚ¿ÕÆøÖв»ÄÜȼÉÕ
B£®Ä¾Ì¿ÔÚÑõÆøÖÐȼÉÕ·¢³ö°×¹â
C£®¾Æ¾«µÆµÄÍâÑæÎ¶È×î¸ß
D£®ÌúË¿ÔÚÑõÆøÖÐȼÉÕ£¬Éú³ÉÁËËÄÑõ»¯ÈýÌú

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

3£®´Ó·Ö×Ó£¬Ô­×ӽǶȷÖÎö²¢½âÊÍÏÂÁÐÎÊÌ⣮
¢ÙÒ»µÎË®ÖдóÔ¼º¬ÓÐ6.7¡Á1021¸öË®·Ö×Ó£º·Ö×ÓµÄÌå»ýºÜС£»
¢ÚÌÇ·ÅÔÚÈÈË®ÖбÈÀäË®ÖÐÈܽâ¸ü¿ì£ºÎ¶ÈÉý¸ß£¬·Ö×ÓµÄÔ˶¯Ëٶȼӿ죻
¢Û½«50mLµÄË®Óë50mLµÄ¾Æ¾«»ìºÏ£¬ËùµÃÈÜÒºÌå»ýСÓÚ100mL·Ö×Ó¼äÓмä¸ô£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

2£®Ä³Ô­×ÓµÄÖÊÁ¿Îªa kg£¬¶øÒ»¸ö̼12Ô­×ÓµÄÖÊÁ¿Îªb kg£¬Ôò¸ÃÔ­×ÓµÄÏà¶ÔÔ­×ÓÖÊÁ¿Îª£¨¡¡¡¡£©
A£®$\frac{12a}{b}$B£®$\frac{ab}{12}$C£®$\frac{12b}{a}$D£®$\frac{12}{ab}$

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸