¡¾ÌâÄ¿¡¿ÏÖÓÐ8ÖÖÔªËصÄÐÔÖÊ¡¢Êý¾ÝÈçϱíËùÁУ¬ËüÃÇÊôÓÚµÚ¶þ»òµÚÈýÖÜÆÚ¡£

¢Ù

¢Ú

¢Û

¢Ü

¢Ý

¢Þ

¢ß

¢à

Ô­×Ӱ뾶(10£­10m)

0.74

1.60

1.86

1.10

0.99

1.52

0.75

1.43

×î¸ß»ò×îµÍ»¯ºÏ¼Û

£«2

£«1

£«5

£«7

£«1

£«5

£«3

£­2

£­3

£­1

£­3

»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©¢ÞµÄµ¥ÖÊÔÚ¿ÕÆøÖмÓÈÈ£¬Éú³ÉÎïµÄµç×ÓʽΪ_______________¡£

£¨2£©ÔÚ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖУ¬ËáÐÔ×îÇ¿µÄ»¯ºÏÎïµÄ·Ö×ÓʽÊÇ___________¡£

£¨3£©±È½Ï¢ÙºÍ¢ßµÄÇ⻯ÎïµÄÎȶ¨ÐÔ£¨Óû¯Ñ§Ê½±íʾ£©_______________________________¡£

£¨4£©Ð´³öʵÑéÊÒÖƱ¸¢ÝµÄµ¥ÖʵÄÀë×Ó·½³Ìʽ£º________________________________¡£

£¨5£©Ð´³ö¢àµÄµ¥Öʸú¢ÛµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º___________________________¡£

¡¾´ð°¸¡¿ HClO4 H2O>NH3 MnO2+4H++2Cl¡ªMn2++Cl2¡ü+2H2O 2Al+2OH£­+2H2O=2AlO2£­+3H2¡ü

¡¾½âÎö¡¿

¢ÙûÓÐ×î¸ß¼Û¡¢Ö»ÓÐ×îµÍ¼Û-2£¬¿ÉÍÆÖª¢ÙΪO£»¢Û¢Þ¶¼ÓÐ×î¸ß¼Û+1£¬´¦ÓÚ¢ñA×壬ÇÒ¢ÛµÄÔ­×Ӱ뾶½Ï´ó£¬¢ÞµÄÔ­×Ӱ뾶²»ÊÇ×îС£¬¹Ê¢ÞΪLi¡¢¢ÛΪNa£»¢ÚÓÐ×î¸ß¼Û+2£¬´¦ÓÚ¢òA×壬ԭ×Ӱ뾶´óÓÚLi£¬¹Ê¢ÚΪMg£»¢Ü¢ß¶¼ÓÐ×î¸ß¼Û+5¡¢×îµÍ¼Û-3£¬´¦ÓÚ¢õA×壬ÇҢܵÄÔ­×Ӱ뾶½Ï´ó£¬¹Ê¢ÜΪP¡¢¢ßΪN£»¢ÝÓÐ×î¸ß¼Û+7¡¢×îµÍ¼Û-1£¬Ôò¢ÝΪCl£»¢àÖ»ÓÐ×î¸ß¼Û+3£¬´¦ÓÚ¢óA×壬ԭ×Ӱ뾶´óÓÚP£¬¹Ê¢àΪAl£¬¾Ý´Ë½â´ð£»

¢ÙûÓÐ×î¸ß¼Û¡¢Ö»ÓÐ×îµÍ¼Û-2£¬¿ÉÍÆÖª¢ÙΪO£»¢Û¢Þ¶¼ÓÐ×î¸ß¼Û+1£¬´¦ÓÚ¢ñA×壬ÇÒ¢ÛµÄÔ­×Ӱ뾶½Ï´ó£¬¢ÞµÄÔ­×Ӱ뾶²»ÊÇ×îС£¬¹Ê¢ÞΪLi¡¢¢ÛΪNa£»¢ÚÓÐ×î¸ß¼Û+2£¬´¦ÓÚ¢òA×壬ԭ×Ӱ뾶´óÓÚLi£¬¹Ê¢ÚΪMg£»¢Ü¢ß¶¼ÓÐ×î¸ß¼Û+5¡¢×îµÍ¼Û-3£¬´¦ÓÚ¢õA×壬ÇҢܵÄÔ­×Ӱ뾶½Ï´ó£¬¹Ê¢ÜΪP¡¢¢ßΪN£»¢ÝÓÐ×î¸ß¼Û+7¡¢×îµÍ¼Û-1£¬Ôò¢ÝΪCl£»¢àÖ»ÓÐ×î¸ß¼Û+3£¬´¦ÓÚ¢óA×壬ԭ×Ӱ뾶´óÓÚP£¬¹Ê¢àΪAl£»

(1)¢ÞΪLiÔªËØ£¬µ¥ÖÊLiÔÚ¿ÕÆøÖмÓÈÈÖ»ÄÜÉú³ÉLi2O£¬ÊÇÀë×Ó»¯ºÏÎÆäµç×ÓʽΪ£»

(2)ÔªËصķǽðÊôÐÔԽǿ£¬Æä×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄËáÐÔԽǿ£¬ÔÚ¢Ù~~¢àÖÐÑõÔªËØÎÞ×î¸ßÕý¼Û£¬ÆäÓàÔªËØÖÐÂÈÔªËطǽðÊôÐÔ×îÇ¿£¬Ôò×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖУ¬ËáÐÔ×îÇ¿µÄ»¯ºÏÎïµÄ·Ö×ÓʽÊÇHClO4£»

(3)¢ÙΪOÔªËØ£¬¢ßΪNÔªËØ£¬·Ç½ðÊôÐÔO´óÓÚN£¬ÔòÇ⻯ÎïµÄÎȶ¨ÐÔH2O>NH3£»

(4)¢ÝΪÂÈÔªËØ£¬ÊµÑéÊÒÀûÓÃMnO2ºÍŨÑÎËá»ìºÏ¼ÓÈÈÖÆÂÈÆø£¬·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪMnO2+4H++2Cl¡ªMn2++Cl2¡ü+2H2O£»

(5)¢àΪAl£¬¢ÛΪNa£¬AlÈÜÓÚNaOHÈÜÒºÉú³ÉNaAlO2ºÍH2£¬·¢ÉúµÄ·´Ó¦µÄÀë×Ó·½³ÌʽΪ2Al+2OH£­+2H2O=2AlO2£­+3H2¡ü¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐÎïÖÊÖк¬ÓеÄÔÓÖÊ£¨À¨ºÅÄÚΪÔÓÖÊ£©£¬¿ÉÒÔÓüÓÈȵķ½·¨³ýÈ¥µÄÊÇ£¨ £©

A.CaCO3£¨CaO£©B.Cu£¨CuO£©

C.Na2CO3£¨NaHCO3£©D.NaHCO3£¨Na2CO3£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÓеÈÌå»ý¡¢µÈpHµÄBa(OH)2¡¢NaOHºÍNH3¡¤H2OÈýÖÖ¼îÈÜÒº£¬µÎ¼ÓµÈŨ¶ÈµÄÑÎËὫËüÃÇÇ¡ºÃÖкͣ¬ÓÃÈ¥ËáµÄÌå»ý·Ö±ðΪV1¡¢V2¡¢V3£¬ÔòÈýÕߵĴóС¹ØϵÕýÈ·µÄÊÇ

A.V3>V2>V1B.V3=V2=V1¡¡C.V1=V2>V3¡¡¡¡D.V3>V2=V1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿£¨1£©ÏÂͼÊÇÇâÑõȼÁϵç³Ø¹¹ÔìʾÒâͼ¡£

д³öÇâÑõȼÁϵç³ØµÄµç¼«·´Ó¦Ê½£º

¸º¼«£º______________________________£¬Õý¼«£º__________________________________¡£

£¨2£©Æû³µµÄÆô¶¯µçÔ´³£ÓÃǦÐîµç³Ø¡£Æä½á¹¹ÈçͼËùʾ£¬·ÅµçʱµÄµç³Ø·´Ó¦ÈçÏ£ºPbO2+Pb+2H2SO4=2PbSO4+2H2O¡£Ð´³öÕý¼«µÄµç¼«·´Ó¦Ê½£º_____________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¡°¾ÆÊdzµÄÏ㡱£¬ÊÇÒòΪ¾ÆÔÚ´¢´æ¹ý³ÌÖÐÉú³ÉÁËÓÐÏãζµÄÒÒËáÒÒõ¥¡£ÔÚʵÑéÊÒÎÒÃÇ¿ÉÒÔÓÃÈçͼËùʾµÄ×°ÖÃÀ´ÖÆÈ¡ÒÒËáÒÒõ¥¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ð´³öÊÔ¹ÜaÖз¢ÉúµÄ»¯Ñ§·½³Ìʽ£º_____________________________________£»

£¨2£©ÊÔ¹ÜbÖеĵ¼¹ÜÒªÔÚÒºÃæµÄÉÔÉÏ·½£¬²»ÄܲåÈëÒºÃæÒÔÏ£¬ÆäÄ¿µÄÊÇ ________________£»

£¨3£©Å¨ÁòËáµÄ×÷ÓÃΪ___________________________________________________£»

£¨4£©ÊÔ¹ÜbÖÐËùÊ¢µÄÈÜҺΪ________________£¬ÆäÖ÷Òª×÷ÓÃÊÇ _________________________¡£

£¨5£©·ÖÀëÒÒËáÒÒõ¥¡¢ÒÒ´¼¡¢ÒÒËáµÄ»ìºÏÎ¿É°´ÏÂÁв½Öè½øÐУº

¢ÙÊÔ¼Á1×îºÃÑ¡ÓÃ_________________£¬

¢Ú²Ù×÷1ÊÇ________________£¬ËùÓõÄÖ÷ÒªÒÇÆ÷Ãû³ÆÊÇ_______________£»

¢Û²Ù×÷2ÊÇ_____________£¬ÊÔ¼Á2×îºÃÑ¡ÓÃ_______________£¬²Ù×÷3ÊÇ__________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÓëÇâÆøÍêÈ«¼Ó³Éºó£¬²»¿ÉÄÜÉú³É2£¬2£¬3-Èý¼×»ùÎìÍéµÄÌþÊÇ

A. (CH3)3 C¡ªCH=CH2B. CH2=C(CH2CH3)C (CH3)3

C. HC¡ÔCCH(CH3)C(CH3)3D. (CH3)3CC(CH3)=CHCH3

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©

A.ÔªËØÖÜÆÚ±íÖÐÓÐ7¸öÖ÷×壬7¸ö¸±×壬¹²14¸ö×ÝÐÐ

B.µªÔªËØλÓÚµÚ¶þÖÜÆÚµÚÈýÖ÷×å

C.½ðÊôÐÔ×îÇ¿µÄÔªËØÊÇLi

D.·Ç½ðÊôÐÔ×îÇ¿µÄÔªËØÊÇF

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿£¨1£©¼ÙÉèÔªËØÖÜÆÚ±í¿ÉÒÔ·¢Õ¹µ½µÚ°ËÖÜÆÚ£¬¶øÇÒµç×ÓÈÔ°´ÕÕ¹¹ÔìÔ­ÀíÌîÈëÄܼ¶£¬µÚ°ËÖÜÆÚӦΪ_____ÖÖÔªËØ¡£

£¨2£©ÒÑÖªN-N¡¢N=NºÍN¡ÔN¼üÄÜÖ®±ÈΪ1.00:2.17:4.90,¶øC-C¡¢C=C¡¢C¡ÔC¼üÄÜÖ®±ÈΪ1.00:1.77:2.34.ÈçºÎÓÃÕâЩÊý¾ÝÀí½âµª·Ö×Ó²»ÈÝÒ×·¢Éú¼Ó³É·´Ó¦¶øÒÒȲÈÝÒ×·¢Éú¼Ó³É·´Ó¦?___

£¨3£©ÏÂͼÊÇÁ½ÖÖ¾ßÓÐÏàͬ·Ö×ÓʽµÄÓлúÎ¡ªÁÚôÇ»ù±½¼×ËáºÍ¶ÔôÇ»ù±½¼×ËáµÄ½á¹¹¼òʽ¡£ÒÑÖªËüµÄ·ÐµãÏà²îºÜ´ó£¬ÆäÖжÔôÇ»ù±½¼×Ëá·Ðµã½Ï¸ß£¬ÈçºÎ´ÓÇâ¼üµÄ½Ç¶ÈÀ´½âÊÍ£¿_______

ÁÚôÇ»ù±½¼×Ëá ¶ÔôÇ»ù±½¼×Ëá

£¨4£©Àë×Ó¾§ÌåÈçʳÑΣ¬ºÜ´à£¬¾­²»Æ𴸻÷£»Ô­×Ó¾§ÌåÈçʯӢ£¬Í¬ÑùºÜ´à£¬Ò²¾­²»Æ𴸻÷¡£È»¶øʳÑκÍʯӢµÄĦÊÏÓ²¶ÈÈ´Ïà²î¼«´ó£¬Ó¦ÈçºÎ½âÊÍ£¿____________________________________

£¨5£©ÈçͼÒÀ´ÎÊǽðÊôÄÆ¡¢½ðÊôп¡¢µâ¡¢½ð¸Õʯ¾§°ûµÄʾÒâͼ£¬

i£ºÉÏͼµÄµâ¾§ÌåÖеâ·Ö×ÓµÄÅÅÁÐÓÐ____ÖÖ²»Í¬È¡Ïò£¬¾§°ûƽ¾ùº¬_______¸öÔ­×Ó¡£

ii£º½ðÊôп¾§°û²ÎÊýÒÀ´ÎΪ£ºa=266.49 pm£¬b=266.49 pm£¬c=494.68 pm£¬¦Á=90¡ã,¦Â=90¡ã£¬¦Ã=120¡ã£¬Ôò¸Ã¾§°ûµÄµ×Ãæ»ýΪ ___________cm2.¡££¨Ö»ÁÐʽ²»¼ÆË㣩¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÓйØÎïÖʵÄת»¯¹ØϵÈçͼËùʾ£¨²¿·ÖÉú³ÉÎïºÍ·´Ó¦Ìõ¼þÒÑÂÔÈ¥£©¡£D¡¢F¡¢G¡¢H¾ùΪ³£¼ûÆøÌ壬ÆäÖÐDÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£¬G³Ê»ÆÂÌÉ«£¬HÔÚ¿ÕÆøÖк¬Á¿×î¸ß£»CµÄĦ¶ûÖÊÁ¿Îª32g¡¤mol£­1£»EΪÄÑÈÜÐԼ

£¨1£©CµÄ»¯Ñ§Ê½Îª_________£»

£¨2£©AµÄµç×ÓʽΪ_________£»

£¨3£©Ð´³ö·´Ó¦¢ÙµÄÀë×Ó·½³Ìʽ_______________£»

£¨4£©Ð´³ö·´Ó¦¢ÚµÄ»¯Ñ§·½³Ìʽ________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸