Question

¡¾ÌâÄ¿¡¿¢ñ.NOx¡¢CO¡¢SO2µÈ´óÆøÎÛȾÆøÌåµÄ´¦ÀíºÍÀûÓÃÊÇÊÀ½ç¸÷¹úÑо¿µÄÈȵãÎÊÌâ¡£

£¨1£©ÒÑÖª£º

a.

b.2NO£¨g£©£«O2£¨g£©2NO2£¨g£© ¦¤H1

2SO2£¨g£©£«O2£¨g£©2SO3£¨g£© ¦¤H2=£­196.6 kJ¡¤mol-1

¢Ù¦¤H1 =___kJ¡¤mol-1¡£

¢Úд³öNO2ÆøÌåÓëSO2ÆøÌå·´Ó¦Éú³ÉSO3ÆøÌåºÍNOÆøÌåµÄÈÈ»¯Ñ§·½³Ìʽ____¡£

£¨2£©ÃºÌ¿È¼ÉÕ¹ý³ÌÖвúÉúµÄCOÓÖ»áÓëCaSO4·¢Éú»¯Ñ§·´Ó¦£¬½µµÍÁËÍÑÁòЧÂÊ¡£·¢ÉúµÄÁ½¸öÏà¹Ø·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÈçÏ£º

·´Ó¦¢ñ£ºCaSO4£¨s£©£«CO£¨g£©CaO£¨s£©£«SO2£¨g£©£«CO2£¨g£© ¦¤H1£½+218.4 kJ¡¤mol-1

·´Ó¦¢ò£ºCaSO4£¨s£©£«4CO£¨g£©CaS£¨s£©£«4CO2£¨g£© ¦¤H2£½-175.6 kJ¡¤mol-1

£¨×ÊÁÏ£º¢Ù·´Ó¦¢ñºÍ·´Ó¦¢òͬʱ·¢Éú£¬¢Ú·´Ó¦¢ñµÄËÙÂÊ´óÓÚ·´Ó¦¢òµÄËÙÂÊ£©

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢ÙÏÂÁз´Ó¦¹ý³ÌÄÜÁ¿±ä»¯Ê¾ÒâͼÕýÈ·µÄÊÇ____¡£

¢ò.¿ÉÄæ·´Ó¦mA(g)£«nB(g)pC(g)£«gD(g)µÄv¡ªtͼÏñÈçͼ¼×Ëùʾ£¬ÈôÆäËûÌõ¼þ²»±ä£¬Ö»ÔÚ·´Ó¦Ç°¼ÓÈëºÏÊʵĴ߻¯¼Á£¬Æäv£­tͼÏñÈçÒÒËùʾ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ___¡£

¢Ùa1£½a2 ¢Úa1£¼a2 ¢Ûb1£½b2 ¢Üb1£¼b2 ¢Ýt1£¾t2 ¢Þt1£½t2 ¢ßÁ½Í¼ÖÐÒõÓ°²¿·ÖÃæ»ýÏàµÈ ¢àͼ¢òÖÐÒõÓ°²¿·ÖÃæ»ý¸ü´ó

¢ó.ÔÚ0.5LµÄÃܱÕÈÝÆ÷ÖУ¬Ò»¶¨Á¿µÄµªÆøºÍÇâÆø½øÐÐÈçÏ»¯Ñ§·´Ó¦£ºN2(g)+3H2(g)2NH3(g) ¦¤H£¼0£¬Æ仯ѧƽºâ³£ÊýKÓëζÈTµÄ¹ØϵÈç±í£º

T/¡æ	200	300	400
K	K1	K2	0.5

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢ÙÊԱȽÏK1¡¢K2µÄ´óС£¬K1____K2(Ì£¾¡±¡°=¡°»ò¡±£¼¡±)¡£

¢Ú400¡æʱ£¬·´Ó¦2NH3(g)N2(g)+3H2(g)µÄƽºâ³£ÊýKΪ____¡£µ±²âµÃNH3¡¢N2¡¢H2µÄŨ¶È·Ö±ðΪ3molL1¡¢2molL1¡¢1molL1ʱ£¬Ôò¸Ã·´Ó¦µÄvÕý(N2)___vÄæ(N2)(Ì£¾¡±¡°=¡°»ò¡±£¼¡±)¡£

Answer 1

¡¾´ð°¸¡¿£­113 NO2£¨g£©£«SO2£¨g£©SO3£¨g£©£«NO£¨g£© ¦¤H=£­41.8kJ¡¤mol-1 C ¢Ú¢Ü¢Ý¢ß £¾ 2 £¾

¡¾½âÎö¡¿

£¨1£©¢Ù·´Ó¦ÈȵÈÓÚ·´Ó¦ÎïÖмüÄÜÖ®ºÍÓëÉú³ÉÎïÖмüÄÜÖ®ºÍµÄ²îÖµ£¬Ôò¦¤H1ͨ¹ýͼÖÐËùʾ¿ÉÖªÓ¦¸ÃÊÇ£¨2¡Á630+498£­2¡Á935.5£©kJ¡¤mol-1£½-113 kJ¡¤mol-1£»

¢ÚÒÑÖª£º2NO£¨g£©£«O2£¨g£©2NO2£¨g£© ¦¤H1£½-113 kJ¡¤mol-1

2SO2£¨g£©£«O2£¨g£©2SO3£¨g£© ¦¤H2=£­196.6 kJ¡¤mol-1

¸ù¾Ý¸Ç˹¶¨ÂɺóÕß¼õȥǰÕß¼´µÃµ½NO2£¨g£©£«SO2£¨g£©SO3£¨g£©£«NO£¨g£©¦¤H=£­83.6kJ¡¤mol-1£¬ËùÒÔÈÈ»¯Ñ§·½³ÌʽΪNO2£¨g£©£«SO2£¨g£©SO3£¨g£©£«NO£¨g£© ¦¤H=£­41.8kJ¡¤mol-1£»

£¨2£©¢ñ.¸ù¾Ý»î»¯ÄÜԽС»¯Ñ§·´Ó¦ËÙÂÊÔ½µÍµÄÌص㣬ÒòΪ·´Ó¦¢ñµÄËÙÂÊ´óÓÚ·´Ó¦¢òµÄËÙÂÊ£¬Í¬Ê±·´Ó¦¢ñΪÎüÈÈ·´Ó¦£¬·´Ó¦¢òΪ·ÅÈÈ·´Ó¦£¬ËùÒÔÑ¡C£»

¢ò. ÒòΪ¼ÓÁË´ß»¯¼Á£¬»¯Ñ§·´Ó¦ËÙÂʿ죬ËùÒÔ¢ÚÕýÈ·£»¼ÓÁË´ß»¯¼Áºó£¬Æ½ºâʱ»¯Ñ§·´Ó¦ËÙÂÊÒ²¼Ó¿ì£¬ËùÒÔ¢ÜÕýÈ·£»ÒòΪ¼ÓÁË´ß»¯¼Á£¬»¯Ñ§·´Ó¦ËÙÂʼӿ죬ʱ¼ä±ä¶Ì£¬ËùÒÔ¢ÝÕýÈ·£»¢ß´ß»¯¼ÁÖ»¸Ä±äËÙÂÊû¸Ä±äƽºâ£¬ËùÒÔËÙÂÊÓëʱ¼äµÄ³Ë»ý²»±ä£¬ËùÒÔÒõÓ°Ãæ»ýÏàµÈ£¬ËùÒÔ¢ßÕýÈ·£»

¢ó.¢ÙÉý¸ßζȺó£¬Æ½ºâÏòÄæÏòÒƶ¯£¬»¯Ñ§Æ½ºâ³£Êý±äС£¬ËùÒÔK1£¾K2£»

¢Ú400¡æʱ£¬·´Ó¦2NH3(g)N2(g)+3H2(g)µÄƽºâ³£ÊýKΪÕý·´Ó¦µÄ»¯Ñ§Æ½ºâ³£ÊýµÄµ¹Êý£¬ËùÒÔΪ=2£»¼ÆËã´Ëʱ³£ÊýµÃ£¼2£¬ËùÒÔƽºâÏòÕýÏòÒƶ¯£¬ËùÒÔvÕý(N2)£¾vÄæ(N2)¡£