ÓÐÒ»¹ÌÌå»ìºÏÎ¿ÉÄÜÓÉNaI¡¢KCl¡¢Na2CO3¡¢Na2SO4¡¢CaCl2¡¢Cu(NO3)2ÖеÄÒ»ÖÖ»ò¼¸ÖÖ×é³É£¬ÎªÁ˼ìÑéËùº¬µÄÎïÖÊ£¬×öÁËÒÔÏÂʵÑ飺
¢ÙÈ¡ÉÙÐí¹ÌÌåÈÜÓÚË®£¬µÃµ½ÎÞɫ͸Ã÷ÈÜÒº£»
¢ÚÍù´ËÈÜÒºÖеμÓÂÈ»¯±µÈÜÒº£¬Óа×É«³ÁµíÉú³É£»
¢Û¹ýÂË£¬Íù³ÁµíÖмÓÈë×ãÁ¿µÄÏ¡ÏõËᣬ·¢ÏÖ³ÁµíûÓÐÈ«²¿ÈܽâÇÒÓÐÎÞÉ«ÎÞζµÄÆøÌåÉú³É¡£
¢ÜÍùÂËÒºÖмÓÈë×ãÁ¿µÄÐÂÖƵÄÂÈË®£¬ÔÙ¼ÓÈëÉÙÐíÆûÓÍ£¬Õñµ´£¬¾²Öã¬ÉϲãÒºÌå³Ê×ϺìÉ«¡£
£¨1£©ÊÔÅжϣº¹ÌÌå»ìºÏÎïÖп϶¨º¬ÓР                 £¬Ò»¶¨Ã»ÓР                       £¬¿ÉÄܺ¬ÓÐ________________¡£
£¨2£©¶Ô¿ÉÄܺ¬ÓеÄÎïÖÊ£¬ÈçºÎ½øÐÐʵÑéÒÔ½øÒ»²½¼ìÑé¡£                                     ¡£
£¨3£©ÊµÑé¢ÜÖз¢ÉúµÄ»¯Ñ§·´Ó¦ÊôÓÚ         ·´Ó¦£¨Ìî·´Ó¦ÀàÐÍ£©£¬Ö÷ҪʵÑé²Ù×÷Ãû³Æ½Ð          ¡£

£¨1£©¿Ï¶¨º¬ÓÐNa2CO3¡¢Na2SO4¡¢NaI£¬Ò»¶¨Ã»ÓÐCu(NO3)2¡¢CaCl2£¬¿ÉÄܺ¬ÓÐKCl
£¨2£©×öÑæÉ«·´Ó¦£¬Èô͸¹ýÀ¶É«îܲ£Á§ÓÐ×ÏÉ«»ðÑ棬Ôòº¬KCl£»·´Ö®£¬ÔòûÓС£
£¨3£©Öû»·´Ó¦»òÑõ»¯»¹Ô­·´Ó¦       ÝÍÈ¡
£¨10·Ö¡£µÚ1¡¢2СÌâÿ¿Õ2·Ö£¬µÚ3СÌâÿ¿Õ1·Ö£©

½âÎöÊÔÌâ·ÖÎö£ºÈ¡ÉÙÐí¹ÌÌåÈÜÓÚË®£¬µÃµ½ÎÞɫ͸Ã÷ÈÜÒº£¬ËµÃ÷Ò»¶¨²»´æÔÚÍ­Àë×Ó£¬¼´Ã»ÓÐÏõËáÍ­¡£Íù´ËÈÜÒºÖеμÓÂÈ»¯±µÈÜÒº£¬Óа×É«³ÁµíÉú³É£¬¸Ã°×É«³ÁµíÖ»ÄÜÊÇÁòËá±µ£¬ËùÒÔÒ»¶¨º¬ÓÐÁòËáÄÆ£¬ÔòÒ»¶¨Ã»ÓÐÂÈ»¯¸Æ¡£¹ýÂË£¬Íù³ÁµíÖмÓÈë×ãÁ¿µÄÏ¡ÏõËᣬ·¢ÏÖ³ÁµíûÓÐÈ«²¿ÈܽâÇÒÓÐÎÞÉ«ÎÞζµÄÆøÌåÉú³É£¬Õâ˵Ã÷°×É«³ÁµíÖл¹º¬ÓÐ̼Ëá±µ£¬Ì¼Ëá±µÈÜÓÚÏõËáÖÐÉú³ÉCO2ÆøÌå¡£ÍùÂËÒºÖмÓÈë×ãÁ¿µÄÐÂÖƵÄÂÈË®£¬ÔÙ¼ÓÈëÉÙÐíÆûÓÍ£¬Õñµ´£¬¾²Öã¬ÉϲãÒºÌå³Ê×ϺìÉ«£¬Õâ˵Ã÷·´Ó¦ÖÐÓе¥ÖʵâÉú³É£¬Òò´ËÒ»¶¨»¹º¬Óе⻯ÄÆ£¬¶øÂÈ»¯¼Ø²»ÄÜÈ·¶¨ÊÇ·ñº¬ÓС£
£¨1£©ÊÔÅжϣº¹ÌÌå»ìºÏÎïÖп϶¨º¬ÓÐNa2CO3¡¢Na2SO4¡¢NaI£¬Ò»¶¨Ã»ÓÐCu(NO3)2¡¢CaCl2£¬¿ÉÄܺ¬ÓÐKCl¡£
£¨2£©ÒªÑéÖ¤ÊÇ·ñº¬ÓÐÂÈ»¯¼Ø£¬Ôò¿ÉÒÔͨ¹ýÑæÉ«·´Ó¦À´Íê³É¡£¼´×öÑæÉ«·´Ó¦£¬Èô͸¹ýÀ¶É«îܲ£Á§ÓÐ×ÏÉ«»ðÑ棬Ôòº¬KCl£»·´Ö®£¬ÔòûÓС£
£¨3£©ÂÈÆø¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬Äưѵ⻯ÄÆÑõ»¯Éú³Éµ¥Öʵ⣬ͬʱ»¹ÓÐÂÈ»¯ÄÆÉú³É£¬¸Ã·´Ó¦ÊôÓÚÖû»·´Ó¦»òÑõ»¯»¹Ô­·´Ó¦£»µ¥ÖʵâÒ×ÈÜÔÚÓлúÈܼÁÖУ¬Òò´Ë¸ÃʵÑé²Ù×÷ÊÇÝÍÈ¡¡£
¿¼µã£º¿¼²éÀë×Ó¹²´æºÍÀë×Ó¼ìÑéµÄÓйØʵÑéÉè¼Æ¡¢ÝÍÈ¡²Ù×÷ÒÔ¼°·´Ó¦ÀàÐ͵ÄÅжÏ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

°´ÒªÇóд³öÏÂÁз½³Ìʽ£º
£¨1£©ÉÙÁ¿ÄÆͶÈëFeCl3ÈÜÒºÖз´Ó¦µÄ×ÜÀë×Ó·½³Ìʽ                                  £»
£¨2£©¹ýÑõ»¯ÄÆͶÈëÁòËáÍ­ÈÜÒºÖÐ×ÜÀë×Ó·½³Ìʽ                                      £»
£¨3£©Ì¼ËáÇâ±µÓë×ãÁ¿ÇâÑõ»¯ÄÆ·´Ó¦µÄÀë×Ó»¯Ñ§·½³Ìʽ                                £»
£¨4£©´×ËáÓë̼ËáÇâÄÆ·´Ó¦µÄÀë×Ó·½³Ìʽ_____________________________________________£»
£¨5£©Ñõ»¯ÄÆÓë×ãÁ¿ÁòËáÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ_______________________________________£»
£¨6£©ÏòNaHSO4ÈÜÒºµÎÈëÇâÑõ»¯±µÈÜÒºÖÁÖÐÐÔ£¬¼ÌÐøÏò·´Ó¦ºóµÄÈÜÒºÖеÎÈëÇâÑõ»¯±µµÄÀë×Ó·½³Ìʽ
                                                                                ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ijÈÜÒº¼×ÖпÉÄܺ¬ÓÐÏÂÁÐÀë×ÓÖеļ¸ÖÖ£ºK+¡¢NO¡¢SO¡¢NH¡¢CO£¨²»¿¼ÂÇÈÜÒºÖÐÓÉË®µçÀëµÄÉÙÁ¿µÄH+ºÍOH£­£©£¬È¡200mL¸ÃÈÜÒº£¬·ÖΪÁ½µÈ·Ý½øÐÐÏÂÁÐʵÑ飺
ʵÑé1£ºµÚÒ»·Ý¼ÓÈë×ãÁ¿µÄÉռ¼ÓÈÈ£¬²úÉúµÄÆøÌåÔÚ±ê×¼×´¿öÏÂΪ672mL£»
ʵÑé2£ºµÚ¶þ·ÝÏȼÓÈë×ãÁ¿µÄÑÎËᣬÎÞÏÖÏó£¬ÔÙ¼ÓÈë×ãÁ¿µÄBaCl2ÈÜÒº£¬µÃ¹ÌÌå2.33g¡£
£¨1£©¼×ÈÜÒºÖÐÒ»¶¨´æÔÚµÄÀë×ÓÊÇ                  £»
£¨2£©¼×ÈÜÒºÖÐÒ»¶¨²»´æÔÚµÄÀë×ÓÊÇ                 £»
£¨3£©¼×ÈÜÒºÖпÉÄÜ´æÔÚµÄÀë×ÓÊÇ                      £»ÄãµÃ³ö´Ë½áÂÛµÄÀíÓÉÊÇ                                                ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÓÐÒÔϼ¸ÖÖÎïÖÊ ¢Ù̼ËáÇâÄƾ§Ì壻¢ÚҺ̬ÂÈ»¯Ç⣻¢ÛÌú£»¢ÜÕáÌÇ£»¢ÝÒÒ´¼£»¢ÞÈÛÈÚµÄK2SO4£»¢ß¸É±ù£»¢àʯī£»¢á°±Æø¡£Ìî¿Õ»Ø´ð£º£¨ÌîÐòºÅ£©
£¨1£©ÒÔÉÏÎïÖÊÄܵ¼µçµÄÊÇ                ¡£
£¨2£©ÒÔÉÏÎïÖÊÖÐÊôÓÚµç½âÖʵÄÊÇ                ¡£
£¨3£©ÒÔÉÏÎïÖÊÖÐÊôÓڷǵç½âÖʵÄÊÇ                 ¡£
£¨4£©ÒÔÉÏÎïÖÊÖÐÈÜÓÚË®ºóË®ÈÜÒºÄܵ¼µçµÄÊÇ              ¡£
£¨5£©·Ö±ðд³öÎïÖÊ¢Ù¡¢¢ÞÔÚË®ÈÜÒºÖеĵçÀë·½³Ìʽ                          ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ijÈÜÒºÖнöº¬Ï±íÀë×ÓÖеÄ5ÖÖÀë×Ó(²»¿¼ÂÇË®µÄµçÀë¼°Àë×ÓµÄË®½â)£¬ÇÒ¸÷Àë×ÓµÄÎïÖʵÄÁ¿¾ùΪ0.1mol¡£

ÒõÀë×Ó
SO42£­¡¢NO3£­¡¢Cl£­
ÑôÀë×Ó
Fe3£«¡¢Fe2£«¡¢NH4+¡¢Cu2£«¡¢Al3£«
 
¢ÙÈôÏòÔ­ÈÜÒºÖмÓÈëKSCNÈÜÒº£¬ÎÞÃ÷ÏÔÏÖÏó£»
¢ÚÈôÏòÔ­ÈÜÒºÖмÓÈë¹ýÁ¿µÄÑÎËᣬÓÐÆøÌåÉú³É£¬ÈÜÒºÖÐÒõÀë×ÓÖÖÀ಻±ä£»
¢ÛÈôÏòÔ­ÈÜÒºÖмÓÈëBaCl2ÈÜÒº£¬Óа×É«³ÁµíÉú³É¡£
ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©ÈôÏòÔ­ÈÜÒºÖÐÏȼÓÈëÉÙÁ¿ÑÎËᣬÔÙµÎÈëKSCNÈÜÒº£¬ÊµÑéÏÖÏóÊÇ________________£»ÊµÑéÖÐÖÐËù·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ_________________________£»
£¨2£©Ô­ÈÜÒºÖÐËùº¬ÑôÀë×ÓÊÇ(дÀë×Ó·ûºÅ)___________________.
£¨3£©ÈôÏòÔ­ÈÜÒºÖмÓÈë×ãÁ¿NaOHÈÜÒº£¬³ä·Ö·´Ó¦ºó¾²ÖÃÒ»¶Îʱ¼ä£¬¹ýÂË¡¢Ï´µÓ¡¢×ÆÉÕ£¬×îÖÕËùµÃ¹ÌÌåµÄÖÊÁ¿ÊÇ________________g¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

(1)(4·Ö)д³öÏÂÁÐÎïÖÊÔÚË®ÈÜÒºÖеĵçÀë·½³Ìʽ£º
HNO3                                                      Ba(OH)2                                              
NaHCO3                                                  NaHSO4                               
(2)(4·Ö)ÔÚʵÑéÊÒÖƱ¸ÂÈÆøµÄ¹ý³ÌÖУ¬¶àÓàµÄÂÈÆøͨ³£ÊÇÓÃÇâÑõ»¯ÄÆÈÜÒº½øÐÐÎüÊÕ£¬Çëд³ö´Ë·´Ó¦µÄ»¯Ñ§·½³Ìʽ²¢±ê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿¡£                      
¸Ã»¯Ñ§·´Ó¦ÖУ¬Ñõ»¯¼ÁÊÇ        £¬»¹Ô­¼ÁÊÇ              ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÓÐÒ»°ü°×É«¹ÌÌ壬¿ÉÄܺ¬ÓÐCaCO3¡¢Na2SO4¡¢KNO3¡¢CuSO4¡¢BaCl2ÎåÖÖÎïÖÊÖеÄÒ»ÖÖ»ò¼¸ÖÖ¡£ÏÖ½øÐÐÒÔÏÂʵÑ飺
¢ÙÈ¡ÉÙÁ¿°×É«¹ÌÌå¼Óµ½×ãÁ¿µÄË®ÖУ¬µÃµ½°×É«³Áµí£¬ÉϲãÇåҺΪÎÞÉ«¡£
¢ÚÏòÉÏÊöÐü×ÇÒºÖмÓÈë×ãÁ¿µÄÏ¡ÏõËᣬ°×É«³ÁµíÏûʧ£¬²¢ÓÐÆøÅݲúÉú¡£
¢ÛÈ¡ÉÙÁ¿¢ÚµÄÈÜÒºµÎÈëÏõËá±µÈÜÒº£¬Óа×É«³ÁµíÉú³É£¬ÔÙ¼ÓÈëÏ¡ÏõËᣬ°×É«³Áµí²»Ïûʧ¡£
¸ù¾ÝÉÏÊöʵÑéÏÖÏóÅжϣº°×É«¹ÌÌåÖÐÒ»¶¨º¬ÓР               £¬
Ò»¶¨²»º¬ÓР                £¬ ¿ÉÄÜ»áÓР                 £»
ÉÏÊöʵÑéÖÐÓйط´Ó¦µÄÀë×Ó·½³Ìʽ                                       ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÖÜÆÚ±íÖÐÇ°36ºÅÔªËØA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢H£¬ËüÃǵÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÆäÖÐB¡¢C¡¢DΪͬһÖÜÆÚ£»E¡¢F¡¢GΪͬһÖÜÆÚ£»AºÍE¡¢DºÍG·Ö±ðΪͬһÖ÷×壻AÓëB×é³ÉµÄ»¯ºÏÎïÊÇÒ»ÖÖÎÂÊÒÆøÌ壻DÔªËØÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ3±¶£»EÊÇËùÔÚÖÜÆÚÔ­×Ӱ뾶×î´óµÄÔªËØ£¨³ýÏ¡ÓÐÆøÌåÍ⣩£»FÔªËصÄÀë×Ӱ뾶ÊÇͬÖÜÆÚÔªËØÐγɵļòµ¥Àë×ÓÖÐ×îСµÄ£»HÔªËØ»ù̬ԭ×ÓµÄM²ãÈ«³äÂú£¬N²ãûÓгɶԵç×Ó£¬Ö»ÓÐÒ»¸öδ³É¶Ôµç×Ó¡£
£¨1£©E2D2ÎïÖÊÖл¯Ñ§¼üµÄÀàÐÍÊÇ__________________
£¨2£©Ò»¶¨Ìõ¼þÏ£¬A2ÆøÌåÓëC2ÆøÌå³ä·Ö·´Ó¦¿ÉÉú³É6.8 gµÄÆøÌ壬·Å³ö18.44 kJÈÈÁ¿£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º______________________________________________________£»Éú³ÉÎï·Ö×ӵĿռ乹ÐÍΪ_________________£¬ÆäÖÐCµÄÔÓ»¯·½Ê½Îª_______________¡£
£¨3£©CºÍE×é³ÉµÄÒ»ÖÖÀë×Ó»¯ºÏÎÄÜÓëË®·´Ó¦Éú³ÉÁ½Öּ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                                         ¡£
£¨4£©HµÄ»ù̬ԭ×ӵĵç×ÓÅŲ¼Ê½Îª__________________________ÒÑÖªH2+ÄÜÓ루2£©ÖеÄÉú³ÉÎïµÄË®ÈÜÒºÐγÉÅäºÏÎÇëд³ö¸ÃÅäºÏÎïÖÐÑôÀë×ӵĽṹ¼òʽ£º_________________£¬ÔÚ´ËÅäºÏÎïµÄË®ÈÜÒºÖмÓÈëÒÒ´¼£¬ÏÖÏóÊÇ_______________________________________¡£
£¨5£©Ä³ÎÞÉ«ÈÜÒº¿ÉÄÜ´æÔÚÈçÏÂÀë×Ó£ºAg£«¡¢Ba2£«ºÍÓÉÉÏÍƳöµÄÔªËØ×é³ÉµÄÀë×ÓE£«¡¢F3£«¡¢FD2¨D¡¢G2¨D¡¢BD32¨D¡¢GD32¨D¡¢GD42¨D£¬ÏÖÈ¡¸ÃÈÜÒº½øÐÐÓйØʵÑ飬½á¹ûÈçÏÂͼËùʾ¡£

¢ÙÉú³Éµ­»ÆÉ«³ÁµíµÄÀë×Ó·½³ÌʽΪ                                    ¡£
¢ÚÓÉÈÜÒº¼×Éú³É³ÁµíÒÒµÄÀë×Ó·½³Ìʽ                                     ¡£
¢Û×ÛºÏÉÏÊöÐÅÏ¢£¬¿ÉÒԿ϶¨´æÔÚµÄÀë×ÓÓР                        ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ

ij½á¾§Ë®ºÏÎﺬÓÐÁ½ÖÖÑôÀë×ÓºÍÒ»ÖÖÒõÀë×Ó¡£³ÆÈ¡Á½·ÝÖÊÁ¿¾ùΪ45.3 gµÄ¸Ã½á¾§Ë®ºÏÎ·Ö±ðÖƳÉÈÜÒº¡£ÏòÆäÖÐÒ»·ÝÖðµÎ¼ÓÈëNaOHÈÜÒº£¬¿ªÊ¼·¢ÏÖÈÜÒºÖгöÏÖ°×É«³Áµí²¢Öð½¥Ôö¶à£»Ò»¶Îʱ¼äºóÓÐÆøÌåÒݳö£¬¸ÃÆøÌåÓд̼¤ÐÔÆø棬ÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£¬¼ÓÈȺ󹲼ƿÉÊÕ¼¯µ½2.24 L¸ÃÆøÌå(±ê×¼×´¿ö)£»×îºó°×É«³ÁµíÖð½¥¼õÉÙ²¢×îÖÕÏûʧ¡£
ÁíÒ»·ÝÖðµÎ¼ÓÈëBa(OH)2ÈÜÒº£¬¿ªÊ¼ÏÖÏóÀàËÆ£¬µ«×îÖÕÈÔÓа×É«³Áµí£»¹ýÂË£¬ÓÃÏ¡ÏõËá´¦Àí³ÁµíÎ¾­Ï´µÓºÍ¸ÉÔµÃµ½°×É«¹ÌÌå46.6 g¡£
Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©ÊÔͨ¹ý¼ÆËãÈ·¶¨¸Ã½á¾§Ë®ºÏÎïµÄ»¯Ñ§Ê½Îª          £»
£¨2£©¼ÙÉè¹ý³ÌÖÐÏò¸ÃÈÜÒºÖмÓÈëµÄBa(OH)2ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ2.0 mol¡¤L-1¡£
¢Ù¼ÓÈëÉÙÁ¿Ba(OH)2ÈÜÒº£¬Ôò·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                        £»
¢Ú¼ÓÈëÒ»¶¨Á¿µÄBa(OH)2ÈÜÒººó£¬ÈôËùµÃ³ÁµíµÄ×ÜÎïÖʵÄÁ¿×î´ó£¬Ôò·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                                  £»
¢ÛÈô¼ÓÈë75 mLµÄBa(OH)2ÈÜÒº£¬ÔòµÃµ½µÄ³ÁµíÖÊÁ¿Îª     ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸