£¨16·Ö£©Ä³Í¬Ñ§Ïëͨ¹ýÏÂͼװÖ㨼гÖ×°ÖÃÒÑÂÔÈ¥£©ÊµÑ飬̽¾¿SO2ÓëNa2O2·´Ó¦µÄ²úÎ

    ¢ñ£®×°ÖÃBµÄ×÷Óà                                                   £®

    ×°ÖÃDµÄ×÷Óà                                                   £®

¢ò£®ÈçºÎ¼ìÑé·´Ó¦ÖÐÊÇ·ñÓÐO2Éú³É

                                                                        £®

¢ó£®¶ÔCÖйÌÌå²úÎïÌá³öÈçϼÙÉ裺

        ¼ÙÉè1£ºÖ»ÓÐNa2SO3             

¼ÙÉè2£ºÖ»ÓÐNa2SO4

        ¼ÙÉè3£º                         £®

£¨1£©¼ÙÉè2µÄ·´Ó¦·½³ÌʽΪ                                            £®

£¨2£©ÈôNa2O2·´Ó¦ÍêÈ«£¬ÎªÈ·¶¨CÖйÌÌå²úÎïµÄ³É·Ö£¬¼×Éè¼ÆÈçÏÂʵÑ飺

µÃ³ö½áÂÛ£º²úÎïÊÇNa2SO4£®

¸Ã·½°¸ÊÇ·ñºÏÀí      £¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©£¬ÀíÓÉÊÇ                           £®

£¨3£©Éè¼ÆʵÑéÑéÖ¤¼ÙÉè3£ºÈ¡ÉÙÁ¿CÖйÌÌå²úÎïÓÚÊÔ¹ÜÖУ¬¼ÓÈëÊÊÁ¿µÄÕôÁóË®Èܽ⣬                                                        £¬Ôò¼ÙÉè3³ÉÁ¢£®

 

¡¾´ð°¸¡¿

£¨16·Ö£©

¢ñ£®B£º¸ÉÔïSO2ÆøÌ壬·ÀÖ¹½Ï¶àµÄË®ÕôÆøÓëNa2O2·´Ó¦¡­¡­¡­¡­£¨2·Ö£©

D£º·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆøºÍ¶þÑõ»¯Ì¼½øÈëC×°ÖÃÓëNa2O2·´Ó¦£»Í¬Ê±ÎüÊÕ¹ýÁ¿µÄSO2£¬ÒÔÃâÎÛȾ¿ÕÆø¡£¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­£¨2·Ö£©

¢ò£®ÓôøÓûðÐǵÄľÌõ¿¿½ü¸ÉÔï¹Ü¿Úa£¬¹Û²ìÆäÊÇ·ñȼÉÕ¡£¡­¡­¡­¡­¡­¡­¡­£¨2·Ö£©

 ¢ó£®ÓÐNa2SO3ºÍNa2SO4  ¡­¡­£¨1·Ö£© 

£¨1£©Na2O2 + SO2 = Na2SO4 ¡­¡­£¨2·Ö£©

£¨2£©·ñ¡­¡­£¨1·Ö£©   

HNOÓÐÑõ»¯ÐÔ£¬¾Ý´Ë²»ÄÜÈ·¶¨²úÎïÊÇNa2SO»¹ÊÇNa2SO4»ò¶þÕß¼æÓС£¡­£¨2·Ö£©

£¨3£©ÏȼÓÈë¹ýÁ¿µÄÏ¡ÑÎËᣬ²úÉúØݼ¤ÐÔÆøζÆøÌ壬ÔÙ¼ÓÈëÊÊÁ¿µÄBaCl2ÈÜÒº£¬ÓÖ²úÉú°×É«³Áµí¡££¨»òÏȼÓÈë¹ýÁ¿BaCl2ÈÜÒº£¬²úÉú°×É«³Áµí£»ÔÙ¼ÓÈë¹ýÁ¿µÄÏ¡ÑÎËᣬ°×É«³Áµí²¿·ÖÈܽ⣬²¢²úÉúØݼ¤ÐÔÆøζÆøÌå¡££©¡­¡­£¨ÊÔ¼ÁµÄÑ¡ÔñºÍʵÑéÏÖÏó¸÷2·Ö¹²4·Ö£©

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

ijͬѧÏëͨ¹ýÏÂͼװÖ㨼гÖ×°ÖÃÒÑÂÔÈ¥£©ÊµÑ飬̽¾¿SO2ÓëNa2O2·´Ó¦µÄ²úÎ
¢ñ£®×°ÖÃDµÄ×÷ÓÃ
ÎüÊÕ¶þÑõ»¯ÁòβÆø£¬·ÀÖ¹ÎÛȾ
ÎüÊÕ¶þÑõ»¯ÁòβÆø£¬·ÀÖ¹ÎÛȾ
£®
¢ò£®ÈçºÎ¼ìÑé·´Ó¦ÖÐÊÇ·ñÓÐO2Éú³É
½«´ø»ðÐǵÄľÌõ¿¿½ü¹Ü¿Úa£¬ÈôľÌõ¸´È¼£¬ËµÃ÷ÓÐÑõÆøÉú³É
½«´ø»ðÐǵÄľÌõ¿¿½ü¹Ü¿Úa£¬ÈôľÌõ¸´È¼£¬ËµÃ÷ÓÐÑõÆøÉú³É
£®
¢ó£®¶ÔCÖйÌÌå²úÎïÌá³öÈçϼÙÉ裺
¼ÙÉè1£ºÖ»ÓÐNa2SO3
¼ÙÉè2£ºÖ»ÓÐNa2SO4
£¨1£©×°ÖÃCÖУ¬¼ÙÉè2µÄ·´Ó¦·½³ÌʽΪ
Na2O2+SO2=Na2SO4
Na2O2+SO2=Na2SO4
£®
£¨2£©ÒÒͬÕë¶ÔÒÔÉÏÁ½¸ö¼ÙÉ裬Ìá³öÁËÁ½¸öʵÑé·½°¸·½°¸
¢ÙÔÚNa2O2·´Ó¦ÍêÈ«ºó£¬Îª½øÐÐÈçÉÏͼʵÑ飺
CÖеĹÌÌåÅä³ÉÈÜÒº¼ÓBa£¨NO3£©2ÈÜÒº³Áµí²»Èܽâ°×É«³Áµí¼Ó×ãÁ¿Ï¡HNO3µÃ³ö½áÂÛ£º²úÎïÊÇNa2SO4£®¸Ã·½°¸ÊÇ·ñºÏÀí
·ñ
·ñ
 £¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©£¬ÀíÓÉÊÇ
Ï¡ÏõËáÄܽ«Éú³ÉµÄBaSO3Ñõ»¯ÎªBaSO4¶øʹ³Áµí²»ÈÜÓÚÏ¡ÏõËá
Ï¡ÏõËáÄܽ«Éú³ÉµÄBaSO3Ñõ»¯ÎªBaSO4¶øʹ³Áµí²»ÈÜÓÚÏ¡ÏõËá
£®
·½°¸¢ÚÔÚ·´Ó¦½øÐÐÒ»¶Îʱ¼äºó£¬È¡ÉÙÁ¿CÖйÌÌå·ÅÈëBaCl2ÈÜÒºÖУ¬³ä·Ö·´Ó¦ºóÔÙ¼ÓÈë×ãÁ¿Ï¡ÑÎËᣬÈç¹ûÈÜÒºÖгöÏÖ°×É«³Áµí£¬¿ÉµÃ³ö½áÂÛ£¬²úÎïÊÇNa2SO4£¬¼ÙÉè2³ÉÁ¢£¬´Ë·½°¸ÊÇ·ñºÏÀí
·ñ
·ñ
£¨ÌÊÇ¡±»ò¡±·ñ¡±£©ÀíÓÉÊÇ
Èô¹ÌÌåCÖÐÊ£ÓàNa2O2£¬²úÎïΪNa2SO3ʱ£¬½«¹ÌÌåCÈÜÓÚBaCl2ÈÜҺʱ£¬Na2O2ÓëË®·´Ó¦²úÉúµÄÑõÆøÄܽ«Na2SO3Ñõ»¯ÎªNa2SO4£¬¶ø²úÉú²»ÈÜÓÚÑÎËáµÄBaSO4°×É«³Áµí£®
Èô¹ÌÌåCÖÐÊ£ÓàNa2O2£¬²úÎïΪNa2SO3ʱ£¬½«¹ÌÌåCÈÜÓÚBaCl2ÈÜҺʱ£¬Na2O2ÓëË®·´Ó¦²úÉúµÄÑõÆøÄܽ«Na2SO3Ñõ»¯ÎªNa2SO4£¬¶ø²úÉú²»ÈÜÓÚÑÎËáµÄBaSO4°×É«³Áµí£®
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijͬѧÏëͨ¹ýÏÂͼװÖÃʵÑ顢̽¾¿SO2ÓëNa2O2·´Ó¦µÄ²úÎ£¨¼Ð³Ö×°ÖÃÒÑÂÔÈ¥£¬×°ÖõÄÆøÃÜÐÔÁ¼ºÃ£©

¢ñ£®×°ÖÃBµÄ×÷ÓÃÊÇÎüÊÕË®£¬¸ÉÔïSO2ÆøÌ壬ÆäÔ­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£º
2Na2O2+2H2O=4Na++4OH-+O2¡ü
2Na2O2+2H2O=4Na++4OH-+O2¡ü
£»
×°ÖÃD³ýÁËÎüÊÕ¹ýÁ¿µÄSO2£¬±ÜÃâÎÛȾ¿ÕÆøÍ⣬»¹Æðµ½µÄ×÷ÓÃÊÇ£º
·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆøºÍ¶þÑõ»¯Ì¼½øÈëC×°ÖÃÓëNa2O2·´Ó¦
·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆøºÍ¶þÑõ»¯Ì¼½øÈëC×°ÖÃÓëNa2O2·´Ó¦
£®
¢ò£®¶ÔCÖйÌÌå²úÎïÌá³öÈçϼÙÉ裺
¼ÙÉè1£ºÖ»ÓÐNa2SO3¼ÙÉè2£ºÖ»ÓÐNa2SO4¼ÙÉè3£º
º¬ÓÐNa2SO3ºÍNa2SO4
º¬ÓÐNa2SO3ºÍNa2SO4
£®
£¨1£©Èô¼ÙÉè2³ÉÁ¢£¬Ð´³öËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ
Na2O2+SO2=Na2SO4
Na2O2+SO2=Na2SO4
£®
£¨2£©ÈôNa2O2·´Ó¦ÍêÈ«£¬ÎªÈ·¶¨CÖйÌÌå²úÎïµÄ³É·Ö£¬¼×Éè¼ÆÈçÏÂʵÑ飺

µÃ³ö½áÂÛ£º²úÎïÊÇNa2SO4£®¸Ã·½°¸ÊÇ·ñºÏÀí£¿´ð£º
·ñ
·ñ
£¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©£®
£¨3£©Éè¼ÆʵÑé·½°¸ÑéÖ¤¼ÙÉè3£¬½øÐÐʵÑ飮ÔÚϱíÖÐд³öʵÑé²½ÖèÒÔ¼°Ô¤ÆÚÏÖÏóºÍ½áÂÛ£®
ÏÞÑ¡ÊÔ¼Á£º1mol?L-1 BaCl2ÈÜÒº¡¢1mol?L-1 Ba£¨NO3£©2ÈÜÒº¡¢1mol?L-1Ï¡ÑÎËá¡¢1mol?L-1Ï¡ÏõËá
ʵÑé²½Öè Ô¤ÆÚÏÖÏóºÍ½áÂÛ
¢ÙÈ¡ÉÙÁ¿CÖйÌÌå²úÎïÓÚÊÔ¹ÜÖУ¬¼ÓÈëÊÊÁ¿µÄÕôÁóË®Èܽâ
¢Ú
¢Û

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijͬѧÏëͨ¹ýÏÂͼװÖ㨼гÖ×°ÖÃÒÑÂÔÈ¥£©ÊµÑ飬̽¾¿SO2ÓëNa2O2·´Ó¦µÄ²úÎ
¾«Ó¢¼Ò½ÌÍø
¢ñÈçºÎ¼ìÑé·´Ó¦ÖÐÊÇ·ñÓÐO2Éú³É
 
£®
¢ò×°ÖÃD³ýÆðÁË·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆøºÍ¶þÑõ»¯Ì¼½øÈëC×°ÖÃÓëNa2O2·´Ó¦×÷ÓÃÍ⣬»¹¿ÉÒÔ
 
£®
¢ó¶ÔCÖйÌÌå²úÎïÌá³öÈçϼÙÉ裺
¼ÙÉè1£ºÖ»ÓÐNa2SO3    ¼ÙÉè2£ºÖ»ÓÐNa2SO4   ¼ÙÉè3£º
 
£®
£¨1£©¼ÙÉè1µÄ·´Ó¦·½³Ìʽ£º2SO2+2Na2O2=
 

£¨2£©ÈôNa2O2·´Ó¦ÍêÈ«£¬ÎªÈ·¶¨CÖйÌÌå²úÎïµÄ³É·Ö£¬¸ÃͬѧÉè¼ÆÈçÏ£¬ÇëÄúÀûÓÃÏÞÑ¡ÊÔ¼ÁºÍÒÇÆ÷°ïÖúËûÍê³É¸Ã̽¾¿¹ý³Ì£¬²¢½«´ð°¸Ð´ÔÚ´ðÌ⿨ÏàӦλÖã®ÏÞÑ¡ÊÔ¼ÁºÍÒÇÆ÷£ºËáÐÔKMnO4ÈÜÒº¡¢Ba£¨NO3£©2ÈÜÒº¡¢BaCl2ÈÜÒº¡¢1mol/L HNO3ÈÜÒº¡¢4mol/LÑÎËá¡¢ÊԹܡ¢½ºÍ·µÎ¹Ü
ʵÑé²Ù×÷ Ô¤ÆÚÏÖÏó ½á ÂÛ
²½ÖèÒ»£ºÈ¡ÉÙÁ¿CÖйÌÌå²úÎïÓÚÊÔ¹ÜÖУ¬¼ÓÈëÊÊÁ¿µÄÕôÁóË®Èܽ⣬·Ö±ðÈ¡ÉÙÁ¿ÓÚA¡¢BÊÔ¹ÜÖÐ ¹ÌÌåÍêÈ«Èܽ⣬µÃµ½ÎÞɫ͸Ã÷ÈÜÒº /
²½Öè¶þ£ºÈ¡ÊÔ¹ÜA£¬ÏòÈÜÒºÖмÓÈë
 
£¬Õñµ´£¬¹Û²ìÈÜÒºÑÕÉ«±ä»¯£®
 
¼ÙÉè1 »ò¼ÙÉè3³ÉÁ¢£»ÈôûÓиÃÏÖÏóÔò¼ÙÉè2³ÉÁ¢£®
²½ÖèÈý£ºÈ¡ÊÔ¹ÜB£¬ÏòÆäÖÐÏȼÓÈë
 
£¬
ÔÙ¼ÓÈë
 
£®
²úÉú
 
£¬
ÔÙ¼ÓÈëÊÔ¼Á¿´µ½²úÉú°×É«³Áµí£®
¼ÙÉè3³ÉÁ¢£®ÈôÎÞ°×É«³Áµí²úÉúÔò¼ÙÉè1³ÉÁ¢£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÕã½­Ê¡¸ßÈýÉÏѧÆÚµÚ¶þ´ÎͳÁ·»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨16·Ö£©£®Ä³Í¬Ñ§Ïëͨ¹ýÏÂͼװÖ㨼гÖ×°ÖÃÒÑÂÔÈ¥£©ÊµÑ飬̽¾¿SO2ÓëNa2O2·´Ó¦µÄ²úÎï¡£

¢ñ£®×°ÖÃBµÄ×÷Óà                                                    ¡£

    ×°ÖÃDµÄ×÷Óà                                                    ¡£

¢ò£®ÈçºÎ¼ìÑé·´Ó¦ÖÐÊÇ·ñÓÐO2Éú³É

                                                              ¡£

¢ó£®¶ÔCÖйÌÌå²úÎïÌá³öÈçϼÙÉ裺

        ¼ÙÉè1£ºÖ»ÓÐNa2SO3

¼ÙÉè2£ºÖ»ÓÐNa2SO4

        ¼ÙÉè3£º                                                 ¡£

    £¨1£©¼ÙÉè2µÄ·´Ó¦·½³ÌʽΪ                                            ¡£

£¨2£©ÈôNa2O2·´Ó¦ÍêÈ«£¬ÎªÈ·¶¨CÖйÌÌå²úÎïµÄ³É·Ö£¬¼×Éè¼ÆÈçÏÂʵÑ飺

µÃ³ö½áÂÛ£º²úÎïÊÇNa2SO4¡£

¸Ã·½°¸ÊÇ·ñºÏÀí         £¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©£¬ÀíÓÉÊÇ                           ¡£

     £¨3£©Éè¼ÆʵÑéÑéÖ¤¼ÙÉè3£ºÈ¡ÉÙÁ¿CÖйÌÌå²úÎïÓÚÊÔ¹ÜÖУ¬¼ÓÈëÊÊÁ¿µÄÕôÁóË®Èܽ⣬                                                      £¬Ôò¼ÙÉè3³ÉÁ¢¡££¨Ð´Ã÷²Ù×÷Óë¶ÔÓ¦µÄÏÖÏó£©

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê¹ã¶«Ê¡¸ßÈý9ÔÂÔ¿¼»¯Ñ§ÊÔÌâ ÌâÐÍ£ºÊµÑéÌâ

£¨16·Ö£©Ä³Í¬Ñ§Ïëͨ¹ýÏÂͼװÖÃʵÑ顢̽¾¿SO2ÓëNa2O2·´Ó¦µÄ²úÎï¡£

£¨¼Ð³Ö×°ÖÃÒÑÂÔÈ¥£¬×°ÖõÄÆøÃÜÐÔÁ¼ºÃ£©

¢ñ£®×°ÖÃBµÄ×÷ÓÃÊÇÎüÊÕË®£¬¸ÉÔïSO2ÆøÌ壬ÆäÔ­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©

                                                    ¡£

×°ÖÃD³ýÁËÎüÊÕ¹ýÁ¿µÄSO2£¬±ÜÃâÎÛȾ¿ÕÆøÍ⣬»¹Æðµ½µÄ×÷ÓÃÊÇ

                                                    ¡£

¢ò£®Ä³Í¬Ñ§Ïëͨ¹ýÉÏͼʵÑé×°Ö㬼ìÑé·´Ó¦ÖÐÊÇ·ñÓÐO2Éú³Éʱ£¬ÆäʵÑé²Ù×÷²½ÖèÊÇ£º

¢Ù       ÏÈ                

¢ÚÔÙÓôø»ðÐǵÄľÌõ¿¿½ü¸ÉÔï¹Ü¿Úa£¬¹Û²ìÆäÊÇ·ñ¸´È¼¡£

¢ó£®¶ÔCÖйÌÌå²úÎïÌá³öÈçϼÙÉ裺

        ¼ÙÉè1£ºÖ»ÓÐNa2SO3

¼ÙÉè2£ºÖ»ÓÐNa2SO4

        ¼ÙÉè3£º                         ¡£

£¨1£©Èô¼ÙÉè2³ÉÁ¢£¬Ð´³öËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ

                                            ¡£

    £¨2£©ÈôNa2O2·´Ó¦ÍêÈ«£¬ÎªÈ·¶¨CÖйÌÌå²úÎïµÄ³É·Ö£¬¼×Éè¼ÆÈçÏÂʵÑ飺

µÃ³ö½áÂÛ£º²úÎïÊÇNa2SO4¡£

¸Ã·½°¸ÊÇ·ñºÏÀí         £¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©¡£

£¨3£©Éè¼ÆʵÑéÑéÖ¤¼ÙÉè3µÄʵÑé²½ÖèÈçÏ£º

ʵÑé²½Öè

ʵÑéÏÖÏó

¢ÙµÎ¼ÓÈë¹ýÁ¿µÄÏ¡ÑÎËá

²úÉúØݼ¤ÐÔÆøζÆøÌå

¢ÚµÎ¼ÓÈëÊÊÁ¿µÄBaCl2ÈÜÒº

²úÉú°×É«³Áµí¡£

¢ÛÈ¡ÉÙÁ¿CÖйÌÌå²úÎïÓÚÊÔ¹ÜÖУ¬¼ÓÈëÊÊÁ¿µÄÕôÁóË®Èܽâ

 

Èô¼ÙÉè3³ÉÁ¢£¬ÕýÈ·µÄʵÑé²Ù×÷˳ÐòÊÇ                           

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸