Question

20．方程组$\left\{\begin{array}{l}3x+5y+6=0\\ 4x-3y-7=0\end{array}\right.$的增广矩阵是$[\begin{array}{l}{3}&{5}&{-6}\\{4}&{-3}&{7}\end{array}]$．

Answer 1

分析 利用增广矩阵的定义求解．

解答 解：方程组$\left\{\begin{array}{l}3x+5y+6=0\\ 4x-3y-7=0\end{array}\right.$的增广矩阵是：$[\begin{array}{l}{3}&{5}&{-6}\\{4}&{-3}&{7}\end{array}]$．
故答案为：$[\begin{array}{l}{3}&{5}&{-6}\\{4}&{-3}&{7}\end{array}]$．

点评 本题考查增广矩阵的求法，是基础题，解题时要认真审题，注意增广矩阵的定义的合理运用．