·ÖÎö £¨1£©Á£×ÓÔڵ糡ÖмÓËÙÔ˶¯£¬µç³¡Á¦×öµÄ¹¦µÈÓÚÁ£×Ó¶¯ÄܵÄÔö¼Ó£¬ÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦£¬¸ù¾Ý¼¸ºÎ¹ØÏµÇó³ö°ë¾¶£¬×îºó¸ù¾Ý°å³¤Óë¹ìµÀ°ë¾¶µÄ¹ØÏµ£¬Çó³ö°å³¤
£¨2£©´Å¸ÐӦǿ¶È¼Ó±¶£¬°ë¾¶±äΪÔÀ´$\frac{1}{2}$£¬¾ØÐδų¡±ß½çÎÊÌ⣬Á£×ÓÉäÈëºÍÉä³öÓë±ß½ç¼Ð½ÇÏàµÈ£¬×÷³öËÙ¶È×î´óµÄÁ£×ÓÔ˶¯¹ì¼£Í¼£¬ÀûÓü¸ºÎ¹ØÏµÇó³ö¾ØÐεij¤ºÍ¿í£¬½ø¶øÇó³öÃæ»ý£®
½â´ð
½â£º£¨1£©¾×î´ó¼ÓËÙµçѹ¼ÓËÙµÄÁ£×Ó½øÈë´Å³¡µÄËÙ¶È×î´ó
$q{U}_{0}^{\;}=\frac{1}{2}m{v}_{m}^{2}$µÃ${v}_{m}^{\;}=\sqrt{\frac{2q{U}_{0}^{\;}}{m}}$
´ËÁ£×Ó½øÈë´Å³¡ºó¸ÕºÃÄÜ´¹Ö±´òÔÚµ²°åÉÏ£¬Ôò´ËÁ£×ÓÔڴų¡ÖÐ×öÔ²ÖÜÔ˶¯µÄÔ²ÐÄÔÚAµã£¬°ë¾¶µÈÓÚOAµÄ³¤£¬$q{v}_{m}^{\;}B=m\frac{{v}_{m}^{2}}{{R}_{1}^{\;}}$£¬${R}_{1}^{\;}=\frac{m{v}_{m}^{\;}}{qB}=\frac{1}{B}\sqrt{\frac{2m{U}_{0}^{\;}}{q}}$
ÓÉÓÚOµãÊÇM°åµÄÖе㣬Òò´ËM°åµÄ³¤¶ÈΪd=2${R}_{1}^{\;}$=$\frac{2}{B}\sqrt{\frac{2m{U}_{0}^{\;}}{q}}$
£¨2£©Èç¹û¼ÓÒ»·´ÏòµÄ´Å¸ÐӦǿ¶ÈΪ2BµÄ¾ØÐÎÔÈÇ¿´Å³¡£¬ËÙ¶È×î´óµÄÁ£×ÓÔÚÆäÖÐ×öÔ²ÖÜÔ˶¯µÄ°ë¾¶${R}_{3}^{\;}=\frac{1}{2}{R}_{1}^{\;}=\frac{1}{2B}\sqrt{\frac{2m{U}_{0}^{\;}}{q}}$
ÓÉͼ¿ÉÖª£¬¾ØÐδų¡ab±ßµÄ³¤Îª$2{R}_{3}^{\;}$£¬bc±ßµÄ³¤Îª${R}_{3}^{\;}+{R}_{3}^{\;}cos30¡ã$£¬Òò´Ë¾ØÐδų¡µÄÃæ»ýÖÁÉÙΪ
$S=2{R}_{3}^{\;}£¨{R}_{3}^{\;}+\frac{\sqrt{3}}{2}{R}_{3}^{\;}£©$=$£¨2+\sqrt{3}£©{R}_{3}^{2}=\frac{£¨2+\sqrt{3}£©m{U}_{0}^{\;}}{2q{B}_{\;}^{2}}$
´ð£º£¨1£©M°åµÄ³¤¶È$\frac{2}{B}\sqrt{\frac{2m{U}_{0}^{\;}}{q}}$£»
£¨2£©¾ØÐδų¡µÄÃæ»ýÖÁÉÙΪ$\frac{£¨2+\sqrt{3}£©m{U}_{0}^{\;}}{2q{B}_{\;}^{2}}$
µãÆÀ ±¾Ìâ¹Ø¼üÊÇ·ÖÎöÁ£×ÓµÄÇé¿ö£¬È·¶¨ÆäÔ˶¯µÄ¹ì¼££¬½âÌâʱҪעÒâÈÏÕæÉóÌâ£¬Ñø³É»²ÝͼµÄϰ¹ß£¬Ã÷È·ÌâÒâ²ÅÄÜ׼ȷÀûÓÃÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦¼°¼¸ºÎ¹ØÏµ½øÐÐÇó½â£®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ΪʵÏÖ¶Ô½Ó£¬Á½ÕßÔËÐÐËٶȵĴóСӦ½éÓÚµÚÒ»ÓîÖæËٶȺ͵ڶþÓîÖæËÙ¶ÈÖ®¼ä | |
| B£® | ΪʵÏÖ¶Ô½Ó£¬ÔØÈË·É´¬±ØÐëµã»ð¼ÓËÙ£¬²ÅÄÜ×·ÉÏǰ·½µÄÌ칬һºÅ | |
| C£® | ÓԱ½øÈëÌ칬һºÅºó£¬´¦ÓÚÍêÈ«Ê§ÖØ×´Ì¬£¬Òò¶ø²»ÊÜÖØÁ¦×÷Óà | |
| D£® | ÓÉÓÚÏ¡±¡ÆøÌåµÄ×èÁ¦×÷Óã¬Èç¹û²»¼Ó¸ÉÔ¤£¬Ì칬һºÅµÄ¸ß¶È½«Öð½¥±äµÍ£¬·ÉÐÐËٶȽ«Ô½À´Ô½´ó |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | ͼ¼×µÄÔÀíºÍ¹âµ¼ÏËά´«Ë͹âÐźŵÄÔÀíÒ»Ñù | |
| B£® | ͼÒÒµÄÔÀíºÍÓêÌìË®ÍÝÖвÊÉ«ÓÍĤµÄÔÀíÒ»Ñù | |
| C£® | ͼ±ûµÄÔÀíºÍÕÕÏà»ú¾µÍ·±íÃæÍ¿ÉÏÔö͸ĤµÄÔÀíÒ»Ñù | |
| D£® | ͼ¶¡µÄÔÀíºÍÓñê×¼Æ½Ãæ¼ì²é¹âÑ§Æ½ÃæµÄƽÕû³Ì¶ÈµÄÔÀíÒ»Ñù |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ´ÓOÖÁAµÄ¹ý³ÌÖÐÔ˶¯Ô±´¦ÓÚÊ§ÖØ×´Ì¬ | |
| B£® | ´ÓAÖÁBµÄ¹ý³ÌÖÐÔ˶¯Ô±´¦ÓÚ³¬ÖØ×´Ì¬ | |
| C£® | ´ÓAÖÁCµÄ¹ý³ÌÖÐÔ˶¯Ô±ÏȶԵ¯ÐÔÉþÊ©¼ÓÁ¦£¬¶øºóµ¯ÐÔÉþ¶ÔÔ˶¯Ô±Ê©¼ÓÁ¦ | |
| D£® | Ô˶¯Ô±Ô˶¯ÖÁCµãʱµÄËÙ¶ÈΪ0£¬ËùÒÔÔ˶¯Ô±ÔÚCµãûÓйßÐÔ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ÓõçÁ÷±í²â¸ÃµçÁ÷ÆäʾÊýΪ14.1 A | |
| B£® | ¸Ã½»Á÷µçÁ÷µÄƵÂÊΪ100 Hz | |
| C£® | ¸Ã½»Á÷µçÁ÷ͨ¹ý10¦¸µç×èʱ£¬µç×èÏûºÄµÄµç¹¦ÂÊΪ1000 W | |
| D£® | ¸Ã½»Á÷µçÁ÷¼´Ê±Öµ±í´ïʽΪi=10$\sqrt{2}$sin628t£¨A£© |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com