10£®ÈçͼËùʾ£¬ÖÊÁ¿mΪ5kgµÄÎï¿é£¨¿É¿´×öÖʵ㣩ÔÚÍâÁ¦F1ºÍF2µÄ×÷ÓÃÏÂÕýÑØÄ³Ò»Ë®Æ½ÃæÏòÓÒ×öÔÈËÙÖ±ÏßÔ˶¯£®ÒÑÖªF1´óСΪ50N£¬·½ÏòбÏòÓÒÉÏ·½£¬ÓëË®Æ½Ãæ¼Ð½ÇΪ37¡ã£¬F2´óСΪ30N£¬·½ÏòˮƽÏò×ó£¬Îï¿éµÄ³õËÙ¶Èv0´óСΪ11m/s£®µ±ÎïÌåÔ˶¯µ½¾à³õʼλÖþàÀëx0=5mʱ£¬³·µôF1£¬Ôò
£¨1£©ÇóÎï¿éÓëˮƽµØÃæÖ®¼äµÄ¶¯Ä¦²ÁÒòÊý¦Ì£»
£¨2£©Çó³·µôF1ÒÔºó£¬Îï¿éÏòÓÒÔ˶¯ËٶȱäΪÁãµÄʱ¼ä£¿
£¨3£©Çó³·µôF1ÒÔºó£¬Îï¿éÔÚ6SÄ©¾à³õʼλÖõľàÀ룿

·ÖÎö £¨1£©Îï¿é×öÔÈËÙÔ˶¯£¬¸ù¾Ý¹²µãÁ¦µÄƽºâÌõ¼þºÍĦ²ÁÁ¦µÄ¼ÆË㹫ʽÇó½â¶¯Ä¦²ÁÒòÊý£»
£¨2£©¸ù¾ÝÅ£¶ÙÔ˶¯¶¨ÂÉÇó½â³·µôF1ºó¼õËÙÔ˶¯µÄ¼ÓËٶȺͼõËÙÔ˶¯Ê±¼ä£»
£¨3£©ÏÈÓÉÔ˶¯Ñ§µÄ¹«Ê½Çó³ö¼õËÙµÄÎ»ÒÆ£»ÔÙÇó³öÏò×ó¼ÓËÙÔ˶¯µÄÎ»ÒÆ£¬È»ºóÇó½âÎï¿éÔÚ6SÄ©¾à³õʼλÖõľàÀ룮

½â´ð ½â£º£¨1£©Îï¿é×öÔÈËÙÔ˶¯£¬¸ù¾Ý¹²µãÁ¦µÄƽºâÌõ¼þ¿ÉµÃ£ºf+F2=F1cos¦Á£¬
Ħ²ÁÁ¦Îª£ºf=¦Ì£¨mg-F1sin¦Á£©£¬
ÁªÁ¢µÃ£º¦Ì=0.5£»
£¨2£©³·µôF1ºó¼õËÙÔ˶¯µÄ¼ÓËÙ¶ÈΪ£º${a}_{1}=\frac{{F}_{2}+¦Ìmg}{m}=\frac{30+25}{5}m/{s}^{2}=11m/{s}^{2}$
Éè¾­¹ýt1ÏòÓÒÔ˶¯ËٶȱäΪ0£¬ÓУº${t}_{1}=\frac{{v}_{0}}{{a}_{1}}=\frac{11}{11}s=1s$£¬
£¨3£©´ËʱÏòÓÒÎ»ÒÆ£¬ÓУº${x}_{1}=\frac{{v}_{0}}{2}{t}_{1}=\frac{11}{2}¡Á1=5.5m$
ºó5sÎï¿éÏò×óÔ˶¯µÄ¼ÓËÙ¶ÈΪ£º${a}_{2}=\frac{{F}_{2}-¦Ìmg}{m}=\frac{30-25}{5}=1m/{s}^{2}$
ºó5sÏò×óÎ»ÒÆÎª£º${x}_{2}=\frac{1}{2}{a}_{2}{t}_{2}^{2}=\frac{1}{2}¡Á1¡Á{5}^{2}=12.5m$
Îï¿éÔÚ6SÄ©¾à³õʼλÖõľàÀëΪ£º¡÷x=x2-£¨x0+x1£©12.5-£¨5+5.5£©=2m£®
´ð£º£¨1£©Îï¿éÓëˮƽµØÃæÖ®¼äµÄ¶¯Ä¦²ÁÒòÊýΪ0.5£®
£¨2£©³·µôF1ÒÔºó£¬Îï¿éÏòÓÒÔ˶¯ËٶȱäΪÁãµÄʱ¼äÊÇ1s£»
£¨3£©³·µôF1ÒÔºó£¬Îï¿éÔÚ6SÄ©¾à³õʼλÖõľàÀëΪ2m£®

µãÆÀ ¶ÔÓÚÅ£¶ÙµÚ¶þ¶¨ÂɵÄ×ÛºÏÓ¦ÓÃÎÊÌ⣬¹Ø¼üÊÇŪÇå³þÎïÌåµÄÔ˶¯¹ý³ÌºÍÊÜÁ¦Çé¿ö£¬ÀûÓÃÅ£¶ÙµÚ¶þ¶¨ÂÉ»òÔ˶¯Ñ§µÄ¼ÆË㹫ʽÇó½â¼ÓËÙ¶È£¬ÔÙ¸ù¾ÝÌâĿҪÇó½øÐнâ´ð£»ÖªµÀ¼ÓËÙ¶ÈÊÇÁªÏµ¾²Á¦Ñ§ºÍÔ˶¯Ñ§µÄÇÅÁº£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ

12£®Ôڹ⻬µÄË®Æ½ÃæÉϾ²Ö¹ÓÐÖÊÁ¿Îªm1=1kgµÄµ¯ÐÔСÇòA£¬ÁíÒ»¸öÖÊÁ¿Îªm2=2kg¡¢ºÍСÇòAµÈ´óСµÄµ¯ÐÔСÇòBÒÔv0=9m/sµÄËÙ¶ÈÔ˶¯£¬ºÍСÇòA·¢Éúµ¯ÐÔÕýÅö£®Çó
¢ÙA¡¢BÁ½Çò×é³ÉµÄϵͳµÄ×ܶ¯ÄܵÄ×îСֵ
¢ÚСÇòB¶¯ÄܵÄ×îСֵ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

13£®Èçͼ£¬´Ö²ÚµÄˮƽµØÃæÉÏÓÐһбÅü£¬Ð±ÅüÉÏÒ»Îï¿éÕýÔÚÑØÐ±ÃæÒÔËÙ¶Èv0ÔÈËÙÏ»¬£¬Ð±Åü±£³Ö¾²Ö¹£¬ÔòÎï¿éÊܵ½µÄÁ¦ÓÐÄÄЩ£¨¡¡¡¡£©
A£®ÖØÁ¦¡¢ÑØÐ±ÃæÏòÏµĻ¬¶¯Ä¦²ÁÁ¦¡¢Ð±ÃæµÄÖ§³ÖÁ¦
B£®ÖØÁ¦¡¢ÑØÐ±ÃæÏòÉϵϬ¶¯Ä¦²ÁÁ¦¡¢Ð±ÃæµÄÖ§³ÖÁ¦
C£®ÖØÁ¦¡¢ÑØÐ±ÃæÏòϵÄÏ»¬Á¦¡¢ÑØÐ±ÃæÏòÉϵϬ¶¯Ä¦²ÁÁ¦
D£®ÖØÁ¦¡¢ÑØÐ±ÃæÏòϵÄÏ»¬Á¦¡¢ÑØÐ±ÃæÏòÉϵÄĦ²ÁÁ¦¡¢Ð±ÃæµÄÖ§³ÖÁ¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

10£®Ä³Í¬Ñ§Õ¾ÔÚÉÏÉýµÄµçÌÝÄÚ£¬ÒÑÖª¸ÃͬѧÌåÖØÎª600N£¬ÔÚµçÌݼõËÙÖ±ÖÁֹͣǰµÄ¹ý³ÌÖУ¬ÒÔÏÂ˵·¨²»ÕýÈ·µÄÊÇ£¨gÈ¡10m/s2£©£¨¡¡¡¡£©
A£®¸Ãͬѧ¶ÔµçÌݵذåѹÁ¦µÈÓÚ600 NB£®¸ÃͬѧÌåÖØÐ¡ÓÚ600 N
C£®¸Ãͬѧ¶ÔµçÌݵذåѹÁ¦´óÓÚ600 ND£®¸Ãͬѧ¶ÔµçÌݵذåѹÁ¦Ð¡ÓÚ600 N

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

5£®ÈçͼËùʾ£¬Ä¾¿éÖÊÁ¿m=2kg£¬ÔÚÓëˮƽ·½Ïò³É¦È=37¡ã¡¢Ð±ÏòÓÒÉÏ·½µÄºã¶¨À­Á¦F×÷ÓÃÏ£¬ÒÔa=2.0m/s2µÄ¼ÓËÙ¶È´Ó¾²Ö¹¿ªÊ¼×öÔȼÓËÙÖ±ÏßÔ˶¯£¬ÔÚ3sĩʱ³·È¥À­Á¦F£®ÒÑ֪ľ¿éÓëµØÃæ¼äµÄ¶¯Ä¦²ÁÒòÊý¦Ì=0.4£¬È¡ÖØÁ¦¼ÓËÙ¶Èg=10m/s2£¬sin37¡ã=0.6£¬cos37¡ã=0.8£®Çó£º
£¨1£©À­Á¦FµÄ´óС£»
£¨2£©ÎïÌåÔÚ5sÄÚ»¬ÐеÄ×ÜÎ»ÒÆ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

15£®Ò»ÀíÏë±äѹÆ÷Ô­¡¢¸±ÏßȦµÄÔÑÊý±ÈΪn1£ºn2£¬ÄÇô£¬Ô­¡¢¸±ÏßȦÖдÅͨÁ¿±ä»¯ÂÊÖ®±È$\frac{¡÷{¦µ}_{1}}{¡÷t}$£º$\frac{¡÷{¦µ}_{2}}{¡÷t}$ӦΪ£¨¡¡¡¡£©
A£®n1£ºn2B£®n2£ºn1C£®1£ºn1n2D£®1£º1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

2£®ÈçͼËùʾµÄˮƽ´«ËÍ×°Öã¬AB¼ä¾àΪL£¨L×ã¹»³¤£©£¬´«ËÍ´øÒÔvÔÈËÙÔËת£¬°ÑÒ»ÖÊÁ¿ÎªmµÄÁã¼þÎÞ³õËٶȵطÅÔÚ´«ËÍ´øµÄA´¦£¬ÒÑÖªÁã¼þÓë´«ËÍ´øÖ®¼äµÄ¶¯Ä¦²ÁÒòÊýΪu£¬ÔòÁã¼þ´ÓAµ½BµÄ¹ý³ÌÖУ¬¼ÓËÙʱ¼äΪ¦Ìg£¬Ä¦²ÁÁ¦¶ÔÁã¼þËù×öµÄ¹¦Îª$\frac{1}{2}m{v}^{2}$£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

19£®ÈçͼΪij½¨Öþ¹¤µØµÄ½Á°è»ú£¬Æä¹¤×÷Ô­ÀíΪµ×¶ËÓÐÁ½¸öÖ÷¶¯ÂÖ£¬¿ª¹ØÆô¶¯ºóÁ½Ö÷¶¯ÂÖ¿¿³ÝÂÖ´«¶¯Ê¹¹öͲÕý³£¹¤×÷£¬ÒÑÖª¹öͲµÄÖ±¾¶ÎªD£¬Ö÷¶¯ÂÖµÄÖ±¾¶Îªd£¬ÖØÁ¦¼ÓËÙ¶ÈÓÃg±íʾ£¬¼ÙÉè¹öͲÔÚÊúÖ±Æ½ÃæÄÚת¶¯£¬ÔÚij´Î½Á°è»ìÄýÍÁʱ£¬ÎªÁËʹ»ìÄýÍÁ½ôÌù¹öͲµÄÄÚ±Ú¶ø²»ÍÑÂ䣬ÔòÖ÷¶¯ÂֵĽÇËÙ¶ÈÖÁÉÙΪ£¨¡¡¡¡£©
A£®$\sqrt{\frac{2g}{D}}$B£®$\frac{\sqrt{2gD}}{d}$C£®$\sqrt{\frac{g}{D}}$D£®$\frac{\sqrt{gD}}{\sqrt{2}d}$

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

20£®ÔÚÀûÓÃÖØ´¸ÏÂÂäÑéÖ¤»úеÄÜÊØºã¶¨ÂɵÄʵÑéÖУº
£¨1£©ÊµÑéÖж¯ÄܵÄÔö¼ÓÁ¿Ó¦ÂÔСÓÚ£¨Ñ¡Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©ÖØÁ¦ÊÆÄܵļõÉÙÁ¿£¬ÆäÖ÷ÒªÔ­ÒòÊÇC£®
A£®ÖØÎïÏÂÂäµÄʵ¼Ê¾àÀë´óÓÚ²âÁ¿Öµ     B£®ÖØÎïÏÂÂäµÄʵ¼Ê¾àÀëСÓÚ²âÁ¿Öµ
C£®ÖØÎïÏÂÂäÊܵ½×èÁ¦                 D£®ÖØÎïµÄʵ¼ÊÄ©ËÙ¶È´óÓÚ¼ÆËãÖµ
£¨2£©ÈçͼËùʾ£¬ÓÐÒ»ÌõÖ½´ø£¬¸÷µã¾àAµãµÄ¾àÀë·Ö±ðΪd1£¬d2£¬d3£¬¡­£¬¸÷ÏàÁÚµã¼äµÄʱ¼ä¼ä¸ôΪT£¬µ±µØÖØÁ¦¼ÓËÙ¶ÈΪg£®ÒªÓÃËüÀ´ÑéÖ¤ÎïÌå´ÓBµ½G´¦µÄ»úеÄÜÊÇ·ñÊØºã£¬ÔòBµãµÄËٶȱí´ïʽΪvB=$\frac{{d}_{2}^{\;}}{2T}$£¬GµãµÄËٶȱí´ïʽΪvG=$\frac{{d}_{7}^{\;}-{d}_{5}^{\;}}{2T}$£¬£¨4£©ÈôBµãºÍGµãµÄËÙ¶ÈvB¡¢vG¼°BG¼äµÄ¾àÀëh¾ùΪÒÑÖªÁ¿£¬Ôòµ±Âú×ã${v}_{G}^{2}-{v}_{B}^{2}=2gh$ʱ£¬ÎïÌåµÄ»úеÄÜÊØºã£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸