Question

1£®Ò»¸öÓÐÒ»¶¨ºñ¶ÈµÄÔ²ÅÌ£¬¿ÉÒÔÈÆͨ¹ýÖÐÐÄ´¹Ö±ÓÚÅÌÃæµÄˮƽÖáת¶¯£¬Ô²Å̼ÓËÙת¶¯Ê±£¬½ÇËٶȵÄÔö¼ÓÁ¿¡÷¦ØÓë¶ÔӦʱ¼ä¡÷tµÄ±ÈÖµ¶¨ÒåΪ½Ç¼ÓËٶȦ£®ÎÒÃÇÓõç´Å´òµã¼ÆʱÆ÷¡¢Ã׳ߡ¢Óα꿨³ß¡¢Ö½´ø¡¢¸´Ð´Ö½À´Íê³ÉÏÂÊöʵÑ飺£¨´òµã¼ÆʱÆ÷Ëù½Ó½»Á÷µçµÄƵÂÊΪ50Hz£¬A¡¢B¡¢C¡¢D¡­Îª¼ÆÊýµã£¬ÏàÁÚÁ½¼ÆÊýµã¼äÓÐËĸöµãδ»­³ö£©

¢ÙÈçͼ¼×Ëùʾ£¬½«´òµã¼ÆʱÆ÷¹Ì¶¨ÔÚ×ÀÃæÉÏ£¬½«Ö½´øµÄÒ»¶Ë´©¹ý´òµã¼ÆʱÆ÷µÄÏÞλ¿×£¬È»ºó¹Ì¶¨ÔÚÔ²Å̵IJàÃ棬µ±Ô²ÅÌת¶¯Ê±£¬Ö½´ø¿ÉÒÔ¾íÔÚÔ²Å̲àÃæÉÏ£»
¢Ú½ÓͨµçÔ´£¬´òµã¼ÆʱÆ÷¿ªÊ¼´òµã£¬Æô¶¯¿ØÖÆ×°ÖÃʹԲÅÌÔȼÓËÙת¶¯£»
¢Û¾­¹ýÒ»¶Îʱ¼ä£¬Ô²ÅÌֹͣת¶¯ºÍ´òµã£¬È¡ÏÂÖ½´ø£¬½øÐвâÁ¿£®
£¨1£©ÈçͼÒÒËùʾ£¬Ô²Å̵ÄÖ±¾¶dΪ4.00cm£»
£¨2£©ÓÉͼ±û¿ÉÖª£¬´òϼÆÊýµãDʱ£¬Ô²ÅÌת¶¯µÄ½ÇËÙ¶ÈΪ1.945rad/s£®
£¨3£©½Ç¼ÓËÙ¶ÈÊǽÇËٶȱ仯µÄ¿ìÂý£¬ÔòÔ²ÅÌת¶¯µÄ½Ç¼ÓËٶȦ´óСΪ29.5rad/s²£®

Answer 1

·ÖÎö £¨1£©¿Ì¶È³ßµÄ¶ÁÊýÐè¶Áµ½×îС¿Ì¶ÈµÄÏÂһλ£®
£¨2£©¸ù¾Ýƽ¾ùËٶȵÈÓÚÖмäʱ¿Ì˲ʱËÙ¶ÈÇó³öDµãµÄ˲ʱËٶȣ¬È»ºó¸ù¾Ýv=¦ØrÇó½â½ÇËٶȣ»
£¨3£©ÓÃÖð²î·¨Çó½â³ö¼ÓËٶȣ¬ÔÙ¸ù¾Ý¼ÓËٶȵÈÓڽǼÓËÙ¶ÈÓë°ë¾¶µÄ³Ë»ýÀ´¼ÆËã½Ç¼ÓËٶȣ¬´Ó¶ø¼´¿ÉÇó½â£®

½â´ð ½â£º£¨1£©ÓÉͼ¿ÉÖª£¬Ô²Å̵ÄÖ±¾¶d=6.00-2.00cm=4.00cm£®
£¨2£©DµãµÄ˲ʱËÙ¶È${v}_{D}=\frac{{x}_{CE}}{2T}=\frac{0.1319-0.0541}{0.2}m/s$=0.389m/s£¬ÔòÔ²ÅÌת¶¯µÄ½ÇËÙ¶È$¦Ø=\frac{{v}_{D}}{r}=\frac{0.389}{0.02}=1.945rad/s$£®
£¨3£©¸ù¾Ý¡÷x=aT²£¬ÔËÓÃÖð²î·¨µÃ£¬a=$\frac{{x}_{CE}-{x}_{AC}}{4{T}^{2}}$=$\frac{£¨0.1319-0.0541£©-0.0541}{4¡Á0.01}$=0.59m/s²£¬
½Ç¼ÓËÙ¶È$¦Ñ=\frac{¡÷¦Ø}{¡÷t}$£¬$¦Ø=\frac{v}{r}$£¬¿ÉÖª$¦Â=\frac{a}{r}=\frac{0.59}{0.02}=29.5rad/{s}^{2}$£®
¹Ê´ð°¸Îª£º£¨1£©4.00£¬£¨2£©1.945£¬£¨3£©29.5£®

µãÆÀ ±¾Ìâ¸ù¾Ý¸ù¾ÝÌâÒâÖнǼÓËٶȵĶ¨Ò壬ͬʱ½áºÏÖ½´ø´¦ÀíÖмÓËٶȺÍËٶȵÄÇ󷨽øÐзÖÎö´¦Àí