Question

12£®ÈçͼÊÇijͬѧ²âÁ¿ÔȱäËÙÖ±ÏßÔ˶¯µÄ¼ÓËÙ¶Èʱ£¬´ÓÈô¸ÉÖ½´øÖÐÑ¡ÖеÄÒ»ÌõÖ½´øµÄÒ»²¿·Ö£¬Ëûÿ¸ô4¸öµãÈ¡Ò»¸ö¼ÆÊýµã£¬Í¼ÉÏ×¢Ã÷ÁËËû¶Ô¸÷¼ÆÊýµã¼ä¾àÀëµÄ²âÁ¿½á¹û£®

£¨1£©ÎªÁËÑé֤С³µµÄÔ˶¯ÊÇÔȱäËÙÔ˶¯£¬Çë½øÐÐÏÂÁмÆË㣬ÌîÈë±íÄÚ£¨µ¥Î»£ºcm£©

X2-X1	X3-X2	X4-X3	X5-X4	X6-X5	$\overline{¡÷X}$

¸÷λÒƲîÓëƽ¾ùÖµ×î¶àÏà²î0.05cm£¬ÓÉ´Ë¿ÉÒԵóö½áÂÛ£ºÔÚÎó²î·¶Î§ÄÚ£¬Ð¡³µµÄλÒÆÔÚÈÎÒâÁ½¸öÁ¬ÐøÏàµÈµÄʱ¼äÀïλÒÆÖ®²îÏàµÈÏàµÈ£¬ËùÒÔС³µµÄÔ˶¯ÊÇÔȼÓËÙÖ±ÏßÔ˶¯£®
£¨2£©¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯µÄ¹æÂÉ£¬¿ÉÒÔÇóµÃÎïÌåµÄ¼ÓËÙ¶Èa=$\frac{¡÷x}{T^2}$=1.58m/s²£®
£¨3£©¸ù¾Ýa_n-3=$\frac{{{x_n}-{x_{n-3}}}}{{3{T^2}}}$£¬¿ÉÇó³öa₁=$\frac{{{x_4}-{x_1}}}{{3{T^2}}}$=1.59m/s²£¬a₂=$\frac{{{x_5}-{x_2}}}{{3{T^2}}}$=1.57m/s²£¬a₃=$\frac{{{x_6}-{x_3}}}{{3{T^2}}}$=1.59m/s²£¬ËùÒÔ£¬$\overline a$=$\frac{{{a_1}+{a_2}+{a_3}}}{3}$=1.58m/s²£®

Answer 1

·ÖÎö ¸ù¾ÝÁ¬ÐøÏàµÈʱ¼äÄÚµÄλÒÆÖ®²îÊÇ·ñÏàµÈÈ·¶¨Ð¡³µµÄÔ˶¯¹æÂÉ£¬Í¨¹ýÖð²î·¨Çó½â¼ÓËٶȵĴóС£®

½â´ð ½â£º£¨1£©x₂-x₁=1.60cm£¬x₃-x₂=1.55cm£¬x₄-x₃=1.62cm£¬x₅-x₄=1.53cm£¬x₆-x₅=1.61cm£¬
¸÷λÒƲîµÄƽ¾ùÖµ¡÷x=$\frac{1.60+1.55+1.62+1.53+1.61}{5}$=1.58cm£¬
¿ÉÖª¸÷λÒƲîÓëƽ¾ùÖµ×î¶àÏà²î0.05cm£¬Ð¡³µÔÚÈÎÒâÁ½¸öÁ¬ÐøÏàµÈʱ¼äÄÚµÄλÒÆÖ®²îÔÚÎó²îÔÊÐíµÄ·¶Î§ÄÚÏàµÈ£¬ËùÒÔС³µ×öÔȼÓËÙÖ±ÏßÔ˶¯£®
£¨2£©Ã¿¸ô4¸öµãÈ¡Ò»¸ö¼ÆÊýµã£¬ËùÒÔÏàÁڵļÆÊýµã¼äµÄʱ¼ä¼ä¸ôT=0.1s£¬
¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯µÄ¹æÂÉ£¬¿ÉÒÔÇóµÃÎïÌåµÄ¼ÓËÙ¶È
a=$\frac{¡÷x}{T^2}$=1.58m/s²£®
£¨3£©¸ù¾Ýa_n-3=$\frac{{{x_n}-{x_{n-3}}}}{{3{T^2}}}$£¬¿ÉÇó³öa₁=$\frac{{{x_4}-{x_1}}}{{3{T^2}}}$=$\frac{0.0757-0.0280}{3¡Á0.01}$=1.59m/s²£¬
a₂=$\frac{{{x_5}-{x_2}}}{{3{T^2}}}$=$\frac{0.091-0.044}{3¡Á0.01}$=1.57m/s²£¬
a₃=$\frac{{{x_6}-{x_3}}}{{3{T^2}}}$=$\frac{0.1071-0.0595}{3¡Á0.01}$=1.59m/s²£¬
ËùÒÔ£¬$\overline a$=$\frac{{{a_1}+{a_2}+{a_3}}}{3}$=$\frac{1.59+1.57+1.59}{3}$=1.58m/s²£®
¹Ê´ð°¸Îª£º£¨1£©0.05£¬ÈÎÒâÁ½¸öÁ¬ÐøÏàµÈµÄʱ¼äÀïλÒÆÖ®²îÏàµÈ£¬ÔȼÓËÙÖ±ÏßÔ˶¯£»
£¨2£©1.58£»
£¨3£©1.59£¬1.57£¬1.59£¬1.58£®

µãÆÀ ÒªÌá¸ßÓ¦ÓÃÔȱäËÙÖ±ÏߵĹæÂÉÒÔ¼°ÍÆÂÛ½â´ðʵÑéÎÊÌâµÄÄÜÁ¦£¬ÔÚƽʱÁ·Ï°ÖÐÒª¼ÓÇ¿»ù´¡ÖªÊ¶µÄÀí½âÓëÓ¦Óã®