·ÖÎö £¨1£©½«³õËÙ¶È·Ö½âΪ´¹Ö±µçºÉƽÐе糡·½Ïò£¬¸ù¾ÝÔ˶¯Ñ§¹«Ê½ÁÐʽ¼´¿ÉÇó³öE£»
£¨2£©½øÈë´Å³¡ºó×öÔÈËÙÔ²ÖÜÔ˶¯£¬¸ù¾Ý¼¸ºÎ¹ØÏµÇó³ö°ë¾¶£¬Óɰ뾶¹«Ê½Çó³öB£»
½â´ð
½â£º£¨1£©Á£×ÓÔڵ糡ÖÐÔ˶¯Ê±£¬Êܵ½µç³¡Á¦×÷Ó㬽«³õËÙ¶È·Ö½âΪ´¹Ö±Óڵ糡·½ÏòºÍƽÐÐÓڵ糡·½Ïò
´¹Ö±Óڵ糡·½ÏòÔÈËÙÖ±ÏßÔ˶¯£¬·ÖËÙ¶ÈΪ£º${v}_{1}^{\;}={v}_{0}^{\;}cos30¡ã=\frac{\sqrt{3}}{2}{v}_{0}^{\;}$
ƽÐÐÓڵ糡·½ÏòÔȱäËÙÖ±ÏßÔ˶¯£¬·ÖËÙ¶ÈΪ£º${v}_{2}^{\;}={v}_{0}^{\;}sin30¡ã=\frac{1}{2}{v}_{0}^{\;}$
ˮƽ·½Ïò£º$L={v}_{1}^{\;}t$=$\frac{\sqrt{3}}{2}{v}_{0}^{\;}t$¡¢Ù
ÊúÖ±·½Ïò£º$-\frac{1}{2}{v}_{0}^{\;}=\frac{1}{2}{v}_{0}^{\;}-\frac{Eq}{m}t$¡¢Ú
Óɢٵãº$t=\frac{2L}{\sqrt{3}{v}_{0}^{\;}}$¡¢Û
¢Û´úÈë¢ÚµÃ£º$E=\frac{\sqrt{3}m{v}_{0}^{2}}{2qL}$
£¨2£©¸ù¾ÝÁ£×ÓÔ˶¯µÄ¹ì¼££¬Óɼ¸ºÎ¹ØÏµÖª£¬R=L
¸ù¾Ý¶Ô³ÆÐÔ£¬Á£×Ó½øÈë´Å³¡Ê±ËÙ¶È´óСµÈÓÚ${v}_{0}^{\;}$£¬¸ù¾ÝÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦£¬ÓУº
$q{v}_{0}^{\;}B=m\frac{{v}_{0}^{2}}{R}$
µÃ£º$R=\frac{m{v}_{0}^{\;}}{qB}=L$
½âµÃ£º$B=\frac{m{v}_{0}^{\;}}{qL}$
´ð£º£¨1£©µç³¡Ç¿¶ÈEµÄ´óС$\frac{\sqrt{3}m{v}_{0}^{2}}{2qL}$£»
£¨2£©ÒªÊ¹Á£×ÓÄÜÔٴξ¹ýPµã£¬Ôò´Å¸ÐӦǿ¶ÈBӦΪ$\frac{m{v}_{0}^{\;}}{qL}$
µãÆÀ ±¾Ìâ¹Ø¼ü½«Á£×ÓµÄÔ˶¯·ÖΪ´Å³¡ÖеÄÔ˶¯ºÍµç³¡ÖеÄÔ˶¯£¬¶ÔÓڴų¡ÖеÄÔ˶¯¸ù¾ÝÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦ÁÐʽ£¬Í¬Ê±½áºÏ¼¸ºÎ¹ØÏµ·ÖÎö£»¶ÔÓڵ糡ÖеÄÔ˶¯£¬Í¨³£¶¼ÎªÀàÆ½Å×Ô˶¯£¬È»ºó¸ù¾ÝÕý½»·Ö½â·¨·Ö½âΪֱÏßÔ˶¯Ñо¿£®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | Èç¹û²¨ÏòÓÒ´«²¥£¬²¨ËÙÒ»¶¨Îª1m/s | |
| B£® | Èç¹û²¨ÏòÓÒ´«²¥£¬²¨ËÙ¿ÉÄÜΪ5m/s | |
| C£® | Èç¹û²¨Ïò×ó´«²¥£¬×îС²¨ËÙΪ3m/s | |
| D£® | Èç¹û²¨Ïò×ó´«²¥£¬²¨ËÙÒ»¶¨ÊÇ3m/sµÄÕûÊý±¶ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | »¬¿éÑØ¸Ë¼ÓËÙÉÏ»¬ | B£® | »¬¿éÑØ¸Ë¼ÓËÙÏ»¬ | ||
| C£® | »¬¿éÑØ¸Ë¼õËÙÉÏ»¬ | D£® | »¬¿éÑØ¸Ë¼õËÙÏ»¬ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | Îï¿éAÏȵ½´ï´«ËÍ´øµ×¶Ë | |
| B£® | Îï¿éABͬʱµ½´ï´«ËÍ´øµ×¶Ë | |
| C£® | ´«ËÍ´ø¶ÔÎï¿éABµÄĦ²ÁÁ¦¶¼ÑØ´«ËÍ´øÏòÉÏ | |
| D£® | Îï¿éAÏ»¬¹ý³ÌÖÐÏà¶Ô´«ËÍ´øµÄÎ»ÒÆÐ¡ÓÚÎï¿éBÏ»¬¹ý³ÌÖÐÏà¶Ô´«ËÍ´øµÄÎ»ÒÆ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | »¬¶¯±ä×èÆ÷»¬Æ¬ÏòÏÂÒÆ¶¯Ê±£¬RXÁ½¶Ëµçѹ±äС | |
| B£® | »¬¶¯±ä×èÆ÷»¬Æ¬ÏòÏÂÒÆ¶¯Ê±£¬RXÁ½¶Ëµçѹ±ä´ó | |
| C£® | »¬¶¯±ä×èÆ÷»¬Æ¬Î»ÓÚÖмäʱ£¬RXÁ½¶ËµçѹСÓÚ$\frac{U}{2}$ | |
| D£® | »¬¶¯±ä×èÆ÷»¬Æ¬Î»ÓÚÖмäʱ£¬ÈôCD¼ä¸Ä½ÓΪÄÚ×èΪRXµÄµç¶¯»ú£¬µç¶¯»úÇ¡ÄÜÕý³£¹¤×÷£¬Ôò´Ëµç¶¯»úÏûºÄµÄÈȹ¦ÂÊСÓÚ$\frac{{U}^{2}}{4{R}_{X}}$ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ¿âÂØÀûÓÃʵÑé½ÏΪ׼ȷµØ²â³öÁËÒýÁ¦³£Á¿GµÄÊýÖµ | |
| B£® | ¸ù¾ÝËٶȶ¨Òåʽv=$\frac{¡÷x}{¡÷t}$£¬µ±¡÷t·Ç³£·Ç³£Ð¡Ê±£¬$\frac{¡÷x}{¡÷t}$¿ÉÒÔ±íʾÎïÌåÔÚtʱ¿Ì˲ʱËÙ¶È | |
| C£® | ¿ªÆÕÀÕÈÏΪֻÓÐÔÚÒ»¶¨Ìõ¼þÏ£¬µ¯»ÉµÄµ¯Á¦ÓëÐαäÁ¿³ÉÕý±È | |
| D£® | ÑÇÀïÊ¿¶àµÂÊ×ÏÈÌá³öÁ˹ßÐԵĸÅÄî |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com