£¨1£©ÔÚ×ö¡°Ì½¾¿Ð¡³µËÙ¶ÈËæʱ¼ä±ä»¯µÄ¹æÂÉ¡±µÄʵÑéÖУ¬Ê¹Ð¡³µÍ£ÔÚ¿¿½ü´òµã¼ÆʱÆ÷´¦£¬ÏÈ______£¬ÔÙ______£¬ÈÃС³µÔÚ¹³ÂëÇ£ÒýÏÂÔ˶¯£®
£¨2£©ÔÚʵÑéµÃµ½Ö½´øÉÏÈ·¶¨Æ߸ö¼ÆÊýµãA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G£¬ÈçͼËùʾ£¬Ã¿Á½¸öÏàÁڵļÆÊýµãÖ®¼äµÄʱ¼ä¼ä¸ôΪT=0.10s£¬²âµÃCD¼äµÄ¾àÀëΪx3=5.20cm£¬DE¼äµÄ¾àÀëΪx4=5.99cm£¬FG¼äµÄ¾àÀëΪx6=7.62cm£®

¢Ù¸ù¾Ýx3ºÍx4¼ÆËãDµãµÄ˲ʱËÙ¶ÈvD=______m/s£¨¼ÆËã½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©£®
¢ÚʵÑé×÷³öС³µÔ˶¯µÄËÙ¶ÈͼÏóÊÇÒ»ÌõÇãбÏòÉϵÄͼÏߣ¬ËµÃ÷С³µËÙ¶ÈËæʱ¼äÔÚ______µØ±ä»¯£¬Ð¡³µ¼ÓËÙ¶È______£¬×ö______Ö±ÏßÔ˶¯£»
¢Û¶ÔÓÚÔȱäËÙÖ±ÏßÔ˶¯µÄÅбðʽ¡÷x=aT2¿ÉÍƹ㵽²»ÏàÁÚµÄÁ½¶ÎÏàµÈʱ¼äÄÚµÄλÒƲxn-xm=(n-m)aT2£¬£¨n£¬m±íʾ²»Îª0µÄ×ÔÈ»Êý£¬Èç1£¬2£¬3¡­£¬n£¾m£©ÊÔÓôËÍƹãʽ£¬ÀûÓÃÒÑÖªµÄx3ºÍx6£¬´ÖÂÔÇóС³µµÄ¼ÓËÙ¶Èa=______m/s2£¨¼ÆËã½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©£®
¢ÜijͬѧÓÃÁ½ÖÖ·½·¨´¦ÀíÊý¾ÝÇóС³µ¼ÓËÙ¶È
·½·¨A£ºÔËÓá÷x=aT2£¬ÓÉ a1=
x2-x1
T2
£¬a2=
x3-x2
T2
£¬¡­£¬a5=
x6-x5
T2
Çóƽ¾ùÖµ
.
a
=
a1+a2+¡­+a5
5
£¬
·½·¨B£ºÔËÓÃxn-xm=(n-m)aT2£¬ÓÉa1=
x4-x1
3T2
£¬a2=
x5-x2
3T2
£¬a3=
x6-x3
3T2
£¬Çóƽ¾ùÖµ
.
a
=
a1+a2+a3
3

·½·¨AÇóµÃ¼ÓËٶȵÄ×îÖÕ±í´ïʽΪa=______£»·½·¨BÇóµÃ¼ÓËٶȵÄ×îÖÕ±í´ïʽΪa=______£®ÎªÊ¹Ã¿¶ÎλÒƶ¼Óõ½£¬¼õСżȻÎó²î£¬Ñ¡Ôñ______·½·¨£¨Ìî¡°A¡±»ò¡°B¡±£©¸üºÏÀí£®
£¨1£©ÈôÏÈÊÍ·ÅÖ½´ø£¬ÔÚ´òµã¼ÆʱÆ÷¹¤×÷֮ǰ£¬Ö½´øÉÏûÓдòµã£¬ÓÐÒ»¶Î¿Õ°×µÄÖ½´ø£»
£¨2£©¢ÙÔȱäËÙÖ±ÏßÔ˶¯ÖУ¬Æ½¾ùËٶȵÈÓÚÖмäʱ¿ÌµÄ˲ʱËٶȣ¬¹Ê£º
vD=
x3+x4
2T
=
0.0520+0.0599
2¡Á0.1
=0.560m/s

¢ÚʵÑé×÷³öС³µÔ˶¯µÄËÙ¶ÈͼÏóÊÇÒ»ÌõÇãбÏòÉϵÄͼÏߣ¬½áºÏÔȱäËÙÖ±ÏßÔ˶¯µÄËÙ¶Èʱ¼ä¹Øϵ¹«Ê½v=v0+at¿ÉÖª£¬Ð¡³µÊÇÔȼÓËÙÖ±ÏßÔ˶¯£¬¹Ê¼ÓËٶȺ㶨£¬ËٶȾùÔÈÔö¼Ó£»
¢Û¸ù¾Ý¹«Ê½xn-xm=(n-m)aT2£¬ÓУº
x6-x3=3aT2
½âµÃ£º
a=
x6-x3
3T2
=
0.0762-0.0520
0£®12
=0.807m/s2
¢Ü·½·¨A£º
ÔËÓá÷x=aT2£¬ÓÉ a1=
x2-x1
T2
£¬a2=
x3-x2
T2
£¬¡­£¬a5=
x6-x5
T2
£¬µÃµ½£º
.
a
=
a1+a2+¡­+a5
5
=
x6-x1
5T2
£»
·½·¨B£º
ÔËÓÃxn-xm=(n-m)aT2£¬ÓÉa1=
x4-x1
3T2
£¬a2=
x5-x2
3T2
£¬a3=
x6-x3
3T2
£¬µÃµ½£º
.
a
=
a1+a2+a3
3
=
(x4+x5+x6)-(x1+x2+x3)
(3T)2
£»
Ϊʹÿ¶ÎλÒƶ¼Óõ½£¬¼õСżȻÎó²î£¬Ñ¡ÔñB·½·¨¸ü¼ÓºÏÀí£»
¹Ê´ð°¸Îª£º
£¨1£©¿ªÆôµçÔ´£¨»ò½Óͨ´òµã¼ÆʱÆ÷£©£»ÊÍ·ÅС³µ£»
£¨2£©¢Ù0.560£»
¢Ú¾ùÔÈ£»²»±ä£»ÔȼÓËÙ£¨ÔȱäËÙ£©£»
¢Û0.807£»
¢Ü
x6-x1
5T2
£¬
(x4+x5+x6)-(x1+x2+x3)
(3T)2
£¬B£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©ÔÚ̽¾¿Ð¡³µËÙ¶ÈËæʱ¼ä±ä»¯µÄ¹æÂɵÄʵÑéÖУ¬Ëã³ö¸÷¼ÆÊýµãС³µµÄ˲ʱËÙ¶ÈÈçÏÂ±í£º
¼ÆÊýµãÐòºÅ123456
¼ÆÊýµã¶ÔÓ¦µÄʱ¿Ìt/s0.10.20.30.40.50.6
С³µµÄ˲ʱËÙ¶Èv/£¨cm?s-1£©44.062.081.0100.0120.0168.0
ΪÁËËã³öС³µµÄ¼ÓËٶȣ¬×îºÃµÄ·½·¨ÊÇ
A£®¸ù¾ÝÈÎÒâÁ½¸ö¼ÆÊýµãµÄËٶȣ¬Óù«Ê½a=
¡÷v
¡÷t
Ëã³ö¼ÓËÙ¶È
B£®ÒÀ´ÎËã³öÁ¬ÐøÁ½¸ö¼ÆÊýµã¼äµÄ¼ÓËٶȣ¬Ëã³öƽ¾ùÖµ×÷ΪС³µµÄ¼ÓËÙ¶È
C£®¸ù¾ÝʵÑéÊý¾Ý»­³öv-tͼÏó£¬Á¿³öÆäÇã½Ç¦Á£¬Óɹ«Ê½a=tan¦ÁËã³ö¼ÓËÙ¶È
D£®¸ù¾ÝʵÑéÊý¾Ý»­³öv-tͼÏó£¬ÓÉͼÏóÉÏÈÎÒâÁ½µãËù¶ÔÓ¦µÄËٶȣ¬Óù«Ê½a=
¡÷v
¡÷t
Ëã³ö¼ÓËÙ¶È
£¨2£©µç»ð»¨´òµã¼ÆʱÆ÷£¬ÊÇÒ»ÖÖʹÓý»Á÷µçÔ´µÄ¼ÆʱÒÇÆ÷£¬¹¤×÷µçѹΪ220V£¬µ±µçԴƵÂÊΪ50Hzʱ£¬Ëüÿ¸ô______s´òÒ»´Îµã£®ÏÂͼÊÇijͬѧÑо¿ÔȱäËÙÖ±ÏßÔ˶¯µÄÒ»ÌõʵÑéÖ½´ø£¬A¡¢B¡¢C¡¢D¡¢EΪ¼ÆÊýµã£¬ÏàÁÚÁ½¼ÆÊýµãÖ®¼ä»¹ÓÐËĸöµãδ±ê³ö£¬ÓÉÓÚCµã²»¹»ÇåÎú£¬Ö»Á¿µÃÈý¸öÊý¾ÝÈçͼËùʾ£¬Ôò´ËС³µÔ˶¯µÄ¼ÓËÙ¶ÈΪ______m/s2£¬CµãµÄËÙ¶ÈvCµÄ´óСµÈÓÚ______m/s£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

ÈçͼËùʾÊÇÑо¿ÎïÌå×öÔȱäËÙÖ±ÏßÔ˶¯µÄʵÑéµÃµ½µÄÒ»ÌõÖ½´ø£¨ÊµÑéÖдòµã¼ÆʱÆ÷Ëù½ÓµÍѹ½»Á÷µçÔ´µÄƵÂÊΪ50ºÕ×È£©£¬´ÓOµãºó¿ªÊ¼Ã¿5¸ö¼ÆʱµãÈ¡Ò»¸ö¼ÆÊýµã£¬ÒÀÕÕ´òµãµÄÏȺó˳ÐòÒÀ´Î±àΪ0¡¢1¡¢2¡¢3¡¢4¡¢5¡¢6£¬²âµÃs1=5.18cm£¬s2=4.40cm£¬s3=3.62cm£¬s4=2.84cm£¬s5=2.06cm£¬s6=1.28cm£®

£¨1£©ÏàÁÚÁ½¼ÆÊýµã¼äµÄʱ¼ä¼ä¸ôΪ______s£®
£¨2£©ÎïÌåµÄ¼ÓËٶȴóСa=______m/s2£¬·½Ïò______£¨ÌîA¡úB»òB¡úA£©£®
£¨3£©´òµã¼ÆʱÆ÷´ò¼ÆÊýµã3ʱ£¬ÎïÌåµÄËٶȴóСv3=______m/s£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

ͼΪÊÇijͬѧÓôòµã¼ÆʱÆ÷Ñо¿Ð¡³µ×öÔȱäËÙÖ±ÏßÔ˶¯Ê±µÃµ½µÄÒ»ÌõÖ½´ø£®Í¼ÖÐA¡¢B¡¢C¡¢D¡¢EÊÇ°´´òµãÏȺó˳ÐòÒÀ´ÎÑ¡È¡µÄ¼ÆÊýµã£¬ÏàÁÚ¼ÆÊýµã¼äµÄʱ¼ä¼ä¸ôT=0.1s£¬Ôò¼ÆÊýµãA¡¢C¶ÔÓ¦µÄʱ¼ä¼ä¸ôÄÚС³µµÄƽ¾ùËٶȴóСvAC=______m/s£¬´òµã¼ÆʱÆ÷´òµ½DµÄ˲ʱËٶȴóСvD=______m/s£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

µç»ð»¨¼ÆʱÆ÷ÊÇÒ»ÖÖ______µÄÒÇÆ÷£¬¹¤×÷µçѹÊÇ______£¬´òµãʱ¼ä¼ä¸ôΪ______Ã룮ÔÚ×ö¡°Ñо¿ÔȱäËÙÖ±ÏßÔ˶¯¡±µÄʵÑéʱ£¬Ä³Í¬Ñ§µÃµ½Ò»ÌõÖ½´ø£¬ÈçͼËùʾ£¬²¢ÇÒÿ¸ôËĸö¼ÆʱµãÈ¡Ò»¸ö¼ÆÊýµã£¬ÒÑ֪ÿÁ½¸ö¼ÆÊýµã¼äµÄ¾àÀëΪs£¬ÇÒs1=2.28cm£¬s2=3.04cm£¬s3=3.82cm£¬s4=4.58cm£¬s5=5.36cm£¬s6=6.14cm£¬µç´Å´òµã¼ÆʱÆ÷µÄµçԴƵÂÊΪ50Hz£®´ËÖ½´øµÄ¼ÓËٶȴóСa=______m/s2£¬´ò¼ÆÊýµã4ʱֽ´øµÄËٶȴóСv=______m/s£®£¨¼ÆËã½á¹û±£Áô3λÓÐЧÊý×Ö£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

ÔÚ¡°Ì½¾¿Ð¡³µËÙ¶ÈËæʱ¼ä±ä»¯µÄ¹æÂÉ¡±µÄʵÑéÖп´µ½Ò»ÌõÈçͼËùʾµÄ¼Ç¼С³µÔ˶¯Çé¿öµÄÖ½´ø£¬Í¼ÖÐA¡¢B¡¢C¡¢D¡¢EΪÏàÁڵļÆÊýµã£¬Ã¿ÏàÁÚµÄÁ½¸ö¼ÆÊýµãÖ®¼ä»¹ÓÐËĸöµãûÓл­³ö£¬½»Á÷µçµÄƵÂÊΪ50Hz£¬ÔòС³µËù×öµÄÔ˶¯______£¨£¨Ìî¡°ÊÇ¡±»ò¡°²»ÊÇ¡±£©ÔȱäËÙÔ˶¯£¬´òµã¼ÆʱÆ÷´òCµãʱµÄËÙ¶ÈΪ______m/s£¬Ð¡³µÔ˶¯µÄ¼ÓËÙ¶ÈΪ______m/s2£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

µç´Å´òµã¼ÆʱÆ÷ÊÇÒ»ÖÖʹÓÃ______£¨Ìî¡°¸ß¡±»ò¡°µÍ¡±£©Ñ¹½»Á÷µçÔ´µÄ¼ÆʱÒÇÆ÷£»ÈôµçÔ´µÄƵÂÊΪ50Hz£¬ÊµÑéÕßÔÚ´¦ÀíʵÑéÊý¾Ýʱ£¬½«Ã¿¸ô3¸ö¼ÆʱµãÈ¡Ò»¸ö¼ÆÊýµã£¬ÔòÿÁ½¸ö¼ÆÊýµã¼äµÄʱ¼ä¼ä¸ôӦΪ______s£»Èç¹ûÔڲⶨÔȱäËÙÖ±ÏßÔ˶¯µÄ¼ÓËÙ¶Èʱ£¬ÊµÑéÕßÈç²»ÖªµÀ¹¤×÷µçѹµÄƵÂʱäΪСÓÚ50Hz£¬ÕâÑù¼ÆËã³öµÄ¼ÓËÙ¶ÈÖµÓëÕæʵֵÏà±ÈÊÇ______£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÈçͼËùʾ£¬ÎïÌåµÄÔ˶¯·ÖÈý¶Î£¬µÚ0¡«2sΪµÚ¢ñ¶Î£¬µÚ2¡«4sΪµÚ¢ò¶Î£¬µÚ4¡«5sΪµÚ¢ó¶Î£¬ÔòÏÂÊö˵·¨ÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®µÚ1sÓëµÚ5sµÄËٶȷ½ÏòÏà·´
B£®µÚ1sµÄ¼ÓËٶȴóÓÚµÚ5sµÄ¼ÓËÙ¶È
C£®µÚ¢ñ¶ÎÓëµÚ¢ó¶ÎµÄƽ¾ùËÙ¶ÈÏàµÈ
D£®µÚ¢ñ¶ÎÓëµÚ¢ó¶ÎµÄ¼ÓËÙ¶ÈÓëËٶȵķ½Ïò¶¼Ïàͬ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸