4£®Èçͼ£¬Ò»Ö»¼×³æÔÚ5¡Á5µÄ·½¸ñ£¨Ã¿Ð¡¸ñ±ß³¤Îª1¸öµ¥Î»³¤¶È£©ÉÏÑØ×ÅÍø¸ñÏßÔ˶¯£¬Ëü´ÓA´¦³ö·¢È¥¿´ÍûB¡¢C¡¢D´¦µÄÆäËü¼×³æ£®¹æ¶¨£ºÏòÉÏÏòÓÒ×ßΪÕý£¬ÏòÏÂÏò×ó×ßΪ¸º£®Èç¹û´ÓAµ½B¼ÇΪ£ºA¡úB£¨+1£¬+4£©£¬´ÓDµ½C¼ÇΪ£ºD¡úC£¨-1£¬+2£©£¬ÆäÖеÚÒ»¸öÊý±íʾ×óÓÒ·½Ïò£¬µÚ¶þ¸öÊý±íʾÉÏÏ·½Ïò£®
£¨1£©Í¼ÖÐA¡úC¿ÉÒÔ¼ÇΪ£¨+3£¬+4£©£¬B¡úC¿ÉÒÔ¼ÇΪ£¨+2£¬0£©£®
£¨2£©D¡úA¿ÉÒÔ¼ÇΪ£¨-4£¬-2£©£®
£¨3£©ÈôÕâÖ»¼×³æµÄÐÐ×ß·ÏßΪA¡úB¡úC¡úD£¬Çë¼ÆËã¸Ã¼×³æ×ß¹ýµÄ·³Ì³¤¶ÈΪ10£»
£¨4£©ÈôÕâÖ»¼×³æ´ÓA´¦È¥¼×³æP´¦µÄÐÐ×ß·ÏßÒÀ´ÎΪ£¨+1£¬+3£©£¬£¨+3£¬-2£©£¬£¨-2£¬+1£©£¬ÇëÔÚͼÖбê³öPµÄλÖã®

·ÖÎö ¸ù¾ÝÌâÒâ¿ÉÒԵõ½£¨1£©£¨2£©£¨3£©µÄ´ð°¸£»
¸ù¾ÝµÚ£¨4£©ÎʵÄ˵Ã÷¿ÉÒÔÏÈ»­³öÐÐ×ߵķ¾¶£¬ÔÙ»­³öËùÇóµÄµã£®

½â´ð ½â£º£¨1£©ÓÉÌâÒâ¿ÉµÃ£¬Í¼ÖÐA¡úC¿ÉÒÔ¼ÇΪ£¨+3£¬+4£©£¬B¡úC¿ÉÒÔ¼ÇΪ£¨+2£¬0£©£¬
¹Ê´ð°¸Îª£º+3£¬+4£»+2£¬0£»
£¨2£©ÓÉͼ¿ÉÖª£¬ÓÉD¡úA¿ÉÒÔ¼ÇΪ£¨-4£¬-2£©£¬
¹Ê´ð°¸Îª£ºA£»
£¨3£©ÓÉͼ¿ÉÖª£¬ÕâÖ»¼×³æµÄÐÐ×ß·ÏßΪA¡úB¡úC¡úD£¬¸Ã¼×³æ×ß¹ýµÄ·³Ì³¤¶ÈΪ£º1+4+2+1+2=10£¬
¹Ê´ð°¸Îª£º10£»
£¨4£©ÈçÏÂͼËùʾ£¬

µãÆÀ ±¾Ì⿼²éÕýÊýºÍ¸ºÊý£¬½âÌâµÄ¹Ø¼üÊÇÃ÷È·ÕýÊýºÍ¸ºÊýÔÚÌâÄ¿ÖбíʾµÄʵ¼ÊÒâÒ壮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

14£®£¨1£©ÏÈ»¯¼ò£¬ÔÙÇóÖµ£ºx2+£¨-x2+3xy+2y2£©-£¨x2-xy+2y2£©£¬ÆäÖÐx=1£¬y=3£®
£¨2£©ÏÈ»¯¼ò£¬ÔÙÈÎѡһ¸öÊʵ±µÄaÖµ´úÈëÇóÖµ£º3a2+[a2+£¨5a2-2a£©-3£¨a2-3a£©]£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

15£®Ä³µØµç»°²¦ºÅÉÏÍøÓÐÁ½ÖÖÊÕ·Ñ·½Ê½£ºA¼ÆÊ±ÖÆ£º1.5Ôª/ʱ£¬B°üÔÂÖÆ£º50Ôª/Ô£¬´ËÍâÿÖÖÉÏÍø·½Ê½¶¼Òª¼ÓÊÕͨѶ·Ñ1Ôª/ʱ£®
£¨1£©Ä³Óû§Ä³ÔÂÉÏÍøµÄʱ¼äΪxСʱ£¬Çëд³öÁ½ÖÖÊÕ·Ñ·½Ê½Ï¸ÃÓû§Ó¦¸ÃÖ§¸¶µÄ·ÑÓã»
£¨2£©Ä³Óû§¹À¼ÆÒ»¸öÔÂÉÏÍøµÄʱ¼äΪ30Сʱ£¬ÄãÈÏΪѡÔñÄÄÖÖ·½Ê½ºÏË㣿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

12£®Ä³Ð£¹æ¶¨Ñ§ÉúÆÚĩӢÓï³É¼¨µÄ¹¹³ÉÈçͼ£¬ÈôСÃ÷µÄƽÈճɼ¨¡¢¾íÃæ³É¼¨¡¢¿ÚÓï²âÊԳɼ¨ÒÀ´ÎΪ100£¬88£¬94£¬ÔòËûÕâѧÆÚÆÚÄ©µÄÓ¢Óï×ÜÆÀ³É¼¨Îª90.4£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

19£®Ð¡»ªÔÚijÔµÄÈÕÀúÉÏȦ³öÏàÁÚµÄËĸöÊý£¬Ëã³öÕâËĸöÊý×ֵĺÍΪ36£¬ÄÇôÕâËĸöÊýÔÚÈÕÀúÉÏλÖõÄÐÎʽÊÇ£¨¡¡¡¡£©
A£®B£®C£®D£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

9£®ÏÂÁмÆËã²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®$\sqrt{4}$=¡À2B£®$\sqrt{£¨-9£©^{2}}$=$\sqrt{81}$=9C£®$\root{3}{0.064}$=0.4D£®$\root{3}{-216}$=-6

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

16£®ÏÈ»¯¼ò£¬ÔÙÇóÖµ£®
£¨1£©5x£¨2x+1£©-£¨2x+3£©£¨5x-1£©£¬ÆäÖÐx=2£®
£¨2£©£¨a+b£©£¨a-b£©+£¨a+b£©2£¬ÆäÖÐa=3£¬b=-$\frac{1}{3}$£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

13£®·Öʽ$\frac{2}{x-1}$ÓÐÒâÒåµÄÌõ¼þÊÇx¡Ù1£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

14£®Èçͼ£¬¡ÏACD=¡ÏA£¬¡ÏBCF=¡ÏB£¬Ôò¡ÏA+¡ÏB+¡ÏACBµÈÓÚ180¡ã£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸